what is the pressure exerted, what is the pressure exerted by 50kg girl as she places her weight on one shoe if the heels area is 0.002m²​

Answer:

The speed of the object at the lowest point in its trajectory is:

[tex]v=2.34\: m/s[/tex]

Explanation:

We can use the conservation of energy between the maximum point of swing and the lowest point of the pendulum.

[tex]P=K[/tex]

[tex]mgh=\frac{1}{2}mv^{2}[/tex] (1)

Where:

We can find h using trigonometry.

[tex]h=L-Lcos(30)=L(1-cos(30))[/tex]

[tex]h=2.1(1-cos(30))=0.28\: m[/tex]

Now, using equation (1) we can find v.

[tex]gh=\frac{1}{2}v^{2}[/tex]

[tex]2gh=v^{2}[/tex]

[tex]v=\sqrt{2gh}[/tex]

[tex]v=\sqrt{2(9.81)(0.28)}[/tex]

[tex]v=2.34\: m/s[/tex]

I hope it helps you!

Answer:

1.4×10⁵ m/s

Explanation:

Applying,

K = mv²/2............. Equation 1

Where K = Energy of the satellite, m = mass of the satellite, v = speed of the satellite.

make v the subject of the equation

v = √(2K/m)............ Equation 2

From the question,

Given: K = 9.8×10⁹ J, m = 1000 g = 1 kg

Substitute these values into equation 2

v = √(2×9.8×10⁹/1)

v = √(1.96×10¹⁰)

v = 1.4×10⁵ m/s

Answer:

A

Explanation:

Answer:

Net force is the vector sum of forces acting on a particle or body. The net force is a single force that replaces the effect of the original forces on the particle's motion. It gives the particle the same acceleration as all those actual forces together as described by Newton's second law of motion.

Explanation:

use this, but put it into you own words.

Answer:

The vector sum of forces acting on a particle or body is referred to as net force. The net force is a single force that replaces the effect of the original forces on the motion of the particle. It provides the particle with the same acceleration as all of the actual forces combined, as described by Newton's second law of motion.

°•°•°•°•°•°•°•°•°•°•°•°•°•°•°•°•

Hope it helps

Have a great day!!

Answer:

pretty sure its studying the atomic structure of a solid carbon dioxide. so c

Explanation:

Answer:

B. Studying the atomic structure of solid carbon dioxide

Explanation:

This is known as crystallography, the study of the arrangement of atoms in a solid, and it is a popular branch of solid-state physics.

Hope this helps :)

Answer:

i. 2.5 kHz ii. 5 kHz

Explanation:

The frequency of the wave in the rod is given by f = nv/2L where n = harmonic, v = speed of sound in rod = 5000 m/s and L = length of rod = 1 m

i. f1

For f1, n = 1

f1 = 1 × v/2L

= v/2L

Substituting the values of the variables into the equation, we have

= 5000 m/s ÷ (2 × 1 m)

= 5000 m/s ÷ 2 m

= 2500 /s

= 2500 Hz

= 2.5 kHz

ii. f2

For f2, n = 2

f2 = 2 × v/2L

= v/L

Substituting the values of the variables into the equation, we have

= 5000 m/s ÷ 1 m  

= 5000 /s

= 5000 Hz

= 5 kHz

Answer:

Last option

Explanation:

Energy released ,

[tex] = 3.789 \times {10}^{ - 12} [/tex] J

Answer:

Many digital consumer products in everyday life such as mobile phones / smartphones, digital cameras, televisions, washing machines, refrigerators and LED bulbs also use semiconductors.

Answer:

A longitudinal study is a research design that involves repeated observations of the same variables over short or long periods of time. It is often a type of observational study, although they can also be structured as longitudinal randomized experiments.

Explanation:

Answer:

P = 375 Pa

Explanation:

The question says that,"If a force of 150N was applied in an area of ​​0.4m², what will be the precious exerted?"

We have,

Force, F = 150 N

Area, A = ​​0.4m²

We need to find the pressure exerted. We know that,

Pressure = forece/area

So,

[tex]P=\dfrac{150\ N}{0.4\ m^2}\\\\P=375\ Pa[/tex]

So, the required pressure is equal to 375 pa.

Answer:

protects the surface from meteoroids and comets

Explanation:

Have a nice day

protects the surface from meteoroids and comets

Answer:

Explanation:

Let's analyze the situation presented in order to know which answer is correct.

When the stick collides with the puck, it exerts a force for a certain time and discants. / After this time the horizontal force decreases to zero and the disk continues to move by the action of the initial velocity on the x axis and the acceleration of gravity on the y axis.

Therefore, after the collision, the only force that acts on the disk is the gravitational attractive force (WEIGHT), directed on the axis and in a negative direction.

The correct answer is:

C)           Since there is no frictional force exerted on the puck, a normal force is not exerted on the puck, but the gravitational force is exerted on the puck

Answer:

See Explanation

Explanation:

The frequency of sound waves received by the microphone influences the output or pitch of the sound obtained from the microphone.

The higher the frequency of the sound received by the microphone, the higher the output of the microphone and vice versa. This is because, the higher the frequency of sound, the higher the oscillations produced and the greater the output of the microphone.

The rise and fall in the pitch of sound waves as the frequency of sound waves varies is called inflection.

Answer:

b

Explanation:

cuz im smart

Answer:

Explanation:

Considering the fact that we ave been given an angle of inclination here, we best use it! That means that the velocity of 23 m/s is actually NOT the velocity we need; I tell my students that it is a "blanket" velocity but is not accurate in either the x or the y dimension of parabolic motion. In order to find the actual velocity in the dimension in which we are working, which is the y-dimension, we use the formula:

[tex]v_{0y}=v_0sin\theta[/tex] and filling in:

[tex]v_{0y}=23sin(25)[/tex] which gives us an upwards velocity of 9.7 m/s. So here's what we have to work with in its entirety:

[tex]v_{0y}=9.7m/s[/tex]

a = -9.8 m/s/s

t = 2.8 seconds

Δx = ?? m

The one-dimensional motion equation that utilizes all of these variables is

Δx = [tex]v_0t+\frac{1}{2}at^2[/tex] and filling in:

Δx = [tex]9.7(2.8)+\frac{1}{2}(-9.8)(2.8)^2[/tex] I am going to do the math according to the correct rules of significant digits, so to the left of the + sign and to 2 sig fig, we have

Δx = 27 + [tex]\frac{1}{2}(-9.8)(2.8)^2[/tex] and then to the right of the + sign and to 2 significant digits we have

Δx = 27 - 38 so

Δx = -11 meters. Now, we all know that distance is not a negative value, but what this negative number tells us is that the ball fell 11 meters BELOW the point from which it was kicked, which is the same thing as being kicked from a building that is 11 meters high.

Answer:

h = 0.2 m

Explanation:

Given that,

A pendulum is moving 2.0 m/s at the bottom of its swing.

We need to find the height high it swing back. Let the height is h.

Using the conservation of energy such that,

[tex]\dfrac{1}{2}mv^2=mgh\\\\h=\dfrac{v^2}{2g}[/tex]

Put all the values,

[tex]h=\dfrac{(2)^2}{2\times 10}\\\\h=0.2\ m[/tex]

So, it will reach to a height of 0.2 m.

Answer: Step down

Explanation:

Given

No of turns on the primary coil is [tex]N_p=8000[/tex]

No of turns on the secondary coil is [tex]N_s=200[/tex]

Primary is connected to the voltage [tex]V_p=240\ V[/tex]

According to the turns rule

[tex]\Rightarrow \dfrac{N_p}{N_s}=\dfrac{V_p}{V_s}\\\\\Rightarrow \dfrac{8000}{200}=\dfrac{240}{V_s}\\\\\Rightarrow V_s=\dfrac{240}{40}\\\\\Rightarrow V_s=6\ V[/tex]

As the voltage drops from 240 V to 6 V. Therefore it is a step-down transformer.

Answer:

(C) 250

Explanation:

Given the following data;

Mass = 10 kg

Distance = 50 m

Force applied = 10 N

Angle = 60°

To find the work done on the box, we would first of all find the horizontal component of the force applied.

[tex] Horizontal force, Fx = mgCosd[/tex]

Where;

Fx represents the horizontal force.

m is the mass of an object.

g is the acceleration due to gravity.

d is the angle of inclination (theta).

mg = weight = 10 N

Substituting into the equation, we have;

[tex] Fx = 10 * Cos60 [/tex]

[tex] Fx = 125 * 0.5 [/tex]

Fx = 5 Newton

Next, we find the work done.

Mathematically, workdone is given by the formula;

[tex] Workdone = force * distance[/tex]

Substituting into the formula, we have;

[tex] Workdone = 5 * 50 [/tex]

Workdone = 250 Nm

Class 1 has the fulcrum placed between the effort and load. Class 2 has the load between the effort and the fulcrum. Class 3 has the effort between the load and the fulcrum.

...

Examples

Tweezers.

Stapler.

Mousetrap.

Broom.

Hockey stick.

Answer: 1200kg

Explanation:

KE = (1/2)mv^2

103kJ = 103000J

103000J = (1/2) * m * (13.1m/s)^2

Solve for m

A car has a kinetic energy of 103kJ, and the speed of the car is 13.1 m/s,then the mass of the car would have been 1200 kilograms.

Mechanical energy is the combination of all the energy in motion represented by total kinetic energy and the total stored energy in the system which is represented by total potential energy.

A car has a kinetic energy of 103 kJ. The speed of the car is 13.1 m/s,

The kinetic energy of the car = 1/2 × mass × velocity

                                     103000 =0.5 × mass × (13.1) ²

The mass of the car = 1200 Kilogram

Thus, if a car has a kinetic energy of 103kJ, and the speed of the car is 13.1 m/s,then the mass of the car would have been 1200 kilograms.

To learn more about mechanical energy, refer to the link;

https://brainly.com/question/2409175

#SPJ5

Answer:

tie hair back

only burn the amount of chemicals as

directed by the lab procedure

Explanation:

The correct safety precautions for Amelia to take from the options would be to tie her hair back and to only burn the amount of chemicals recommended by the lab procedure.

With her hair left flowing freely, Amelia runs the risk of the hair catching flame while trying to burn the chemicals according to the procedure. Hence, tying her hair up into one neat bunch will limit the risk of it catching fire while working in the lab.

Also, burning less or more than the amount of chemicals recommended by the procedure may be dangerous or hinder Amelia from getting the right result.

Answer:

1,3

Explanation:

just did it

If i understand your question clearly, The best choice in most scenarios is  copper.

Why?

Its due to copper's high conductive properties, its abundance, its low price compared to its fellow metal conductors, its ductile property, thermal resistance and immunity to oxidation ( rusting ).

Though Silver surpasses copper in conductivity, copper is shown to be more notable than its fellow conductors.

Answer:

a) The uniform velocity travelled by the car is 10 meters per second.

(Point b has been erased by the user)

c) The distance travelled by the car with uniform velocity is 100 meters.

Explanation:

a) Calculate the uniform velocity travelled by the car:

The uniform velocity is the final velocity ([tex]v[/tex]), in meters per second, of the the uniform accelerated stage:

[tex]v = v_{o} + a\cdot t[/tex] (1)

Where:

[tex]v_{o}[/tex] - Initial velocity, in meters per second.

[tex]a[/tex] - Acceleration, in meters per square second.

[tex]t[/tex] - Time, in seconds.

If we know that [tex]v_{o} = 0\,\frac{m}{s}[/tex], [tex]a = 2\,\frac{m}{s^{2}}[/tex] and [tex]t = 5\,s[/tex], then the uniform velocity is:

[tex]v = 0\,\frac{m}{s} + \left(2\,\frac{m}{s^{2}} \right)\cdot (5\,s)[/tex]

[tex]v = 10\,\frac{m}{s}[/tex]

The uniform velocity travelled by the car is 10 meters per second.

(Point b has been erased by the user)

c) The distance travelled by the car ([tex]\Delta x[/tex]), in meters, with uniform velocity is calculated by the following kinematic expression:

[tex]\Delta x = v\cdot t[/tex] (2)

If we know that [tex]v = 10\,\frac{m}{s}[/tex] and [tex]t = 10\,s[/tex], then the distance travelled is:

[tex]\Delta x = \left(10\,\frac{m}{s} \right)\cdot (10\,s)[/tex]

[tex]\Delta x = 100\,m[/tex]

The distance travelled by the car with uniform velocity is 100 meters.

Answer:

Which best describes the electric field created by a positive charge? ... Its rays point toward the charge.

Explanation:

thank me later

Answer:

5 m

Explanation:

We'll begin by calculating the original potential energy. This can be obtained as follow:

Mass (m) = 0.2 Kg

Height (h) = 20 m

Acceleration due to gravity (g) = 10 m/s²

Energy (E₀) =?

E₀ = mgh

E₀ = 0.2 × 10 × 20

E₀ = 40 J

Next, we shall determine the new energy of the ball.

Energy (E₀) = 40 J

Energy lost (Eₗ) = 30 J

New energy (E) =?

E = E₀ – Eₗ

E = 40 – 30

E = 10 J

Finally, we shall determine height of the ball on rebound. This can be obtained as follow:

New energy (E) = 10 J

Mass (m) = 0.2 Kg

Acceleration due to gravity (g) = 10 m/s²

Height (h) =?

E = mgh

10 = 0.2 × 10 × h

10 = 2 × h

Divide both side by 2

h= 10 / 2

h = 5 m

Thus, the height of the ball on rebound is 5 m

The electric force between two charges is:

F = (9 x 10⁹) Q₁ Q₂ / D²

F is the force, in Newtons

Q₁ and Q₂ are the two charges, in Coulombs

D is the distance between them, in meters

I'm going to assume that the first little 'c' in the question stands for "Coulombs", and the second little 'c' stands for "centimeters".  And now, I'll proceed to answer the question that I've just invented.

For these two electrons:

F = (9 x 10⁹) (1.6 x 10⁻¹⁹) (1.6 x 10⁻¹⁹) / (5.4 x 10⁻⁷)²

F = (9 x 1.6 x 1.6 x 10⁻²⁹) / (5.4² x 10⁻¹⁴)

F = (23.04 / 29.16) x 10⁻¹⁵

F = 7.9 x 10⁻¹⁶ of a Newton

EACH electron feels that same force, pushing it away from the other electron.

Answer:

Option (D), lunar eclipse

Explanation:

When the moon comes between the earth and sun, the lunar eclipse occurs, so D is the lunar eclipse. It is full moon day.

C is the position when there is new moon day and it is solar eclipse.

So, option (D) is correct.