What is the reciprocal of 5/6​

Answer:

taking cos

co62=b/h

cos 62=x/12

0.46947x12=x

so, x = 5.633

rounding off

x= 6

Answer:

x = 6.0

Step-by-step explanation:

Formula For Cos: cos (angle°) = adjacent/hypotenuse

Angle = 62

Adjacent = x

Hypotenuse = 12

cos (angle) = adjacent/hypotenuse

cos (62) = x/12

0.67350716232 = x/12

0.67 = x/12 (Rounded to make further calculations simpler)

12(x/12) = 12(0.67)

x = 8.04

x = 6.0 (Rounded to nearest tenth)

Therefore, x = 6.0

Hope this helped! <3

Answer:

Step-by-step explanation:

Hi,

1) Find z if the standard normal curve area between -z and z is 0.4530.

Y1 = normalcdf(-x,x,0,1) - .4530 and x = .60226

a. ± 0.118

b. ± 0.398

c. ± 0.602 <==ANSWER

d. ± 0.752

2) If a random variable has the normal distribution with μ = 104.3 and σ = 5.7, find the probability that the value will be greater than 112.3

normalcdf(112.3, 500, 104.3, 5.7) = .08023

a. 0.08 <==ANSWER

b. 0.09

c. 0.10

d. 0.11

3) Determine a 90% confidence interval for μ if σ = 5, \bar{x} = 70, and n = 82. Answer interval rounded to two decimal places.

70 ± 1.645 (5/√82) or 69.09 to 70.91 <==ANSWER

I hope that helps!! :-)

Answer:

4000

Step-by-step explanation:

20 to the power of 3 is 8000 and 8000/2 is 4000

Answer: I believe its 56

Step-by-step explanation:

Answer:

160 pounds

Step-by-step explanation:

If she has 3 boxes and there's 40 more pounds than if she had one, that means each box is 20 pounds so multiply 20 by 8 and you get 160 pounds

Answer: then its blue, 1/3

Step-by-step explanation: in a box there are 8 red, 7 blue and 6 green balls. one ball is picked up randomly. what is the probability that it is neither red nor green?

---

I guess the ball was blue.

P(blue) = 7/21 = 1/3

Answer:

infinity

Step-by-step explanation:

lol

Answer:

Factoring the trinomial: [tex]x^2+13x+12[/tex] we get the factors [tex]\mathbf{(x+1)(x+12)}[/tex]

Step-by-step explanation:

We need to factor the trinomial: [tex]x^2+13x+12[/tex]

We can factor the trinomial by breaking the middle term i.e 13x

Such that adding or subtracting gets the both terms we get 13x and multiplying both terms we get 12x^2

We can break 13x as: 12x and x

Adding them we get 13x and multiplying them we get 12x^2

So,

[tex]x^2+13x+12\\=x^2+12x+x+12\\=x(x+12)+1(x+12)\\=(x+1)(x+12)[/tex]

So, Factoring the trinomial: [tex]x^2+13x+12[/tex] we get the factors [tex]\mathbf{(x+1)(x+12)}[/tex]

Answer: B. 77

Sub x =6 into the given expression

4x^2 - 12x + 5

= 4(6)^2 - 12(6) + 5

= 144 - 72 + 5

= 77

[tex]\\ \sf\longmapsto 4x^2-12x+5[/tex]

[tex]\\ \sf\longmapsto 4(6)^2-12(6)+5[/tex]

[tex]\\ \sf\longmapsto 4(36)-72+5[/tex]

[tex]\\ \sf\longmapsto 144-67[/tex]

[tex]\\ \sf\longmapsto 77[/tex]

Answer:

Maximum amount of toppings is 14 inequality is t <=14

Step-by-step explanation:

let t be the amount of toppings on the pizza

0.75t + 2 <= 12.50

0.75t <= 10.50

t <= 14

Answer:

15 fifths

Step-by-step explanation:

Answer:

3

Step-by-step explanation:

3/2 is equal to 1.5 and 3 1.5s can fit in 5 equaling 4.5

Answer:

8000

Step-by-step explanation:

Answer:

21

Step-by-step explanation:

set up proportion and solve

18/12=x/14 (cross multiply)

252=12x

21=x

Answer:

I don't think so

Step-by-step explanation:

if the s has to be more than or equal to then s would have to equal 8 or more

;

Answer:

there is a graph first step to but I cannot draw it on here but you already have your answer without Step 2

Step-by-step explanation:

a simple path in a graph G that passes through every vertex exactly once is called a path . the graph G has no past because any past containing all vertices must contain one of the edges (e, c) (d, f ) and (B, G) move than once .

The scale factor of PQRS to JKLM is 4/5 and the values of w, x and y are 20, 12.5 and 20 respectively.

A scale drawing is a drawing made by enlarging or reducing the size of the original object.

The factor by which the drawing is enlarged or reduced is called the scale factor.

Given two quadrilaterals PQRS and JKLM.

Since the shape is similar, the angles are equal and thus are similar figures.

The corresponding sides of two similar figures are proportional.

Scale factor of PQRS to JKLM = QR / KL = 12 / 15 = 4/5

Using the proportional rule for similar figures,

KL / QR = LM /RS  = MJ / SP = JK / PQ

15 / 12 = x / 10 = y / 16 = 25 / w

Scale factor = 15/12 = 5/4

Consider 15 / 12 = x / 10.

12x = 150

x = 12.5

Consider 15 / 12 = y / 16

12y = 15 × 16

y = 20

Consider 15 / 12 = 25 / w

15w = 12 × 25

w = 20

Hence the option d is the correct answer.

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Answer:

Jug B can hold 2340 ml.

Step-by-step explanation:

Given

The amount in Jug A = 1800ml

To determine

How much does jug B hold?​

Give that the Jug B holds 3/10 more, i.e.

[tex]\frac{3}{10}\times \:1800=540[/tex]

Thus,

The total amount in Jug B = 540+1800

                                           = 2340 ml

Therefore, Jug B can hold 2340 ml.

Answer:

get into it

Step-by-step explana   tion:

Answer:

0.4

Step-by-step explanation:

Given :

To Find :

Answer :

Adding eqⁿ (ii) and eqⁿ (i) we get :

→ x + y + x - y = 4 + 1

→ 2x = 5

→ x = 5/2

→ x = 2.5

Now, put the value of x = 5/2 in eqⁿ (i) we get :

→ x + y = 4

→ 5/2 + y = 4

→ y = 4 - 5/2

→ y = 1.5

Answer:

x²/4 + y²/16 = 1

Step-by-step explanation:

Foci on the y axis: major axis parallel to y axis

x²/b² + y²/a² = 1

x²/4 + y²/16 = 1

The required equation of an ellipse is given by x²/4 + y²/16 = 1

Given that,
Length of the major axis: 4 Length of the minor axis: 2 Foci are on the y-axis with center (0,0)​, the equation of the ellipse is to be determined.0

Ellipse is defined as the cross-section of the cone when cutting it with a plane parallel to its base.

Here,
Standard equation of the ellipse with origin as the center,
x²/a² + y²/b² = 1
where a and b are the minor and major axis of the ellipse.
From the given, we have a = 2 and b = 4
So the equation of the ellipse,
x²/4 + y²/16 = 1

Thus, the required equation of an ellipse is given by x²/4 + y²/16 = 1.

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Answer:

D

Step-by-step explanation:

Connect the point already at (0, –2) to a new point at (2, 0), connect

(2, 0) to (2, 4), and then connect (2, 4) to (–2, 4).

Im pretty sure

Answer:

D

Step-by-step explanation:

Answer:

10x + 18

Step-by-step explanation:

First, we need to add like terms. Like terms are terms that are alike. For instance 8x and 2x are like terms. 15 and 3 are also like terms.

So, we have to add 8x plus 2x and 15 plus 3. That’s comes out to 10x plus 18.

Therefore, this expression is equivalent to 10x + 18.

Answer: the volume is 480 cm

Step-by-step explanation:

You find the volume of a shape by multiplying the base x width x height. In this case the height is 6 the width is 8 and the length is 10. 6x8x10= 480.

Answer:

lb×bh×hl

6×8×8×10×10×6

48×80×60

230400

Answer:

p(6,3)=120

Step-by-step explanation:

In the pic is how to do it

The value of the permutation expression P(6, 1) will be 6.

A permutation is an act of arranging items or elements in the correct order. Combinations are a way of selecting items or pieces from a group of objects or sets when the order of the components is immaterial.

Evaluate the expression P(6, 1).

We know that the formula for the permutation is given as,

ⁿPₓ = n! / (n - x)!

From the above, the value of n is 6 and the value of x is 1. Then we have

⁶P₁ = 6! / (6 - 1)!

⁶P₁ = 6! / 5!

⁶P₁ = 6 x 5! / 5!

⁶P₁ = 6

The value of the permutation expression P(6, 1) will be 6.

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[tex]{\underline{\underline{\bf{Given:}}}}[/tex]

[tex]{\underline{\underline{\bf{Need\:to\:find:}}}}[/tex]

[tex]{\underline{\underline{\bf{Formula\:to\:be\:used:}}}}[/tex]

Pythagorean Theorem:

[tex]\underline{\boxed{\sf{{Base}^{2}+{Perpendicular}^{2}={Hypotenuse}^{2}}}}[/tex]

[tex]{\underline{\underline{\bf{Solution:}}}}[/tex]

According to the given data, we know the measures of Perpendicular and Hypotenuse. Hence, the measure of the base (Side FE) can be found by substituting the given measures in Pythagorean Theorem.

[tex]\implies{\sf{{Base}^{2}+{Perpendicular}^{2}={Hypotenuse}^{2}}}[/tex]

[tex]\implies{\sf{{EF}^{2}+{DF}^{2}={DE}^{2}}}[/tex]

[tex]\implies{\sf{{EF}^{2}+{(13.6)}^{2}={(16.2)}^{2}}}[/tex]

[tex]\implies{\sf{ EF = \sqrt{ {(16.2)}^{2} - {(13.6)}^{2} } }}[/tex]

[tex]\implies{\sf{ EF = \sqrt{ 262.44 - 184.96 } }}[/tex]

[tex]\implies{\sf{ EF = \sqrt{77.48 } }}[/tex]

[tex]\implies{\sf{EF=\red{\underline{\underline{8.802\:m}}}}}[/tex]

[tex]{\underline{\underline{\bf{Required\:answer:}}}}[/tex]

Answer:

hope my answer is helpful to you

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As QR is parallel to ST Rs is parallel TU QS is congruent to SU the measure of their included angle is also same ∠QRS ≅ ∠STU.

We know two similar planer figures are congruent when we have sides or angles or both that are the same as the corresponding sides or angles or both.

Given, Line segment QR is parallel to line segment ST.

Line segment RS is parallel to line segment TU, And line segment QS is similar to line segment SU.

So, The included angle of two pairs of parallel lines will also be the same as

line segment QS is similar to line segment SU.

∴ ∠QRS is similar to ∠STU.

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