What is the similarity between relative dating and radioactive dating? I will mark brainlest. I dont know how btw

A.)

Water is the name of the pure substance H₂O

B.)

Hydrogen and Oxygen are the compound of water

C.)

Yes, we can

D.)

This process known as Electrolysis

Answer:

Average velocity = 5.9 km/ hr (or 1.64 m/s).

Explanation:

Velocity = [tex]\frac{displacement}{time}[/tex]

It is a vector quantity and has an SI unit of m/s.

Displacement = [tex]\sqrt{x^{2} + y^{2} }[/tex]

x = 5 km east

y = 6 km north + 4 km north

  = 10 km north

So that,

Displacement = [tex]\sqrt{5^{2} + 10^{2} }[/tex]

                       = [tex]\sqrt{25 + 100}[/tex]

                       = [tex]\sqrt{125}[/tex]

                       = 11.1803

Displacement = 11.18 km = 11180 m

Time = 1.9 hr = 6840 seconds

Average velocity = [tex]\frac{11.180}{1.9}[/tex]

             = 5.8842

Average velocity = 5.9 km/ hr

The average velocity is 5.9 km/ hr (or 1.64 m/s).

Answer:

0.585V

Explanation:

Given that:

B = 3.00 × 10-5 T

l = 75.0 m

v = 260 m/s

From Blv = emf between the wing tips

= 3.00 × 10-5 T × 75×260

= 117/200

= 0.585V

Hence, the emf between the wing tips is 0.585V

Answer:

v₁ = 0.375 m / s ,   x = 0.335 m

Explanation:

Let's analyze this interesting exercise, the block moves and has a friction force with the tile, we assume that the speed of the block is constant, so the friction force opposes the block movement. For the only force that acts (action and reaction) this friction force exerted by the block that is in the direction of movement of the tile.

We can also see that the isolated system formed by the block and the tile will reach a stable speed where friction cannot give the system more energy, this speed can be found by treating the system with the conservation of linear momentum.

initial moment. Right at the start of the movement

       p₀ = m v₀ + 0

final moment. Just when it comes to equilibrium

      [tex]p_{f}[/tex] = (m + M) v₁

how the forces are internal

       p₀ =p_{f}

       m v₀ = (m + M) v₁

       v₁ = m /m+M    v₀

let's calculate

       v₁ = 0.4 /(0.4 + 2.8)  3

       v₁ = 0.375 m / s

Let's apply Newton's second law to the Block, to find the friction force

Y axis

       N - W = 0

       N = W

       N = m g

where m is the mass of the block

the friction force has the formula

      fr = μ N

      fr = μ m g

We apply Newton's second law to slab    

X axis

       fr = M a

where M is the mass of the slab

       μ m g = M a

       a = μ g m / M

let's calculate

       a = 0.15  9.8  0.4 / 2.8

       a = 0.21 m / s²

With kinematics we can find the position

       v²= v₀²+2 a x

as the slab is initially at rest, its initial velocity is zero

       v² = 2 a x

       x = v2 / 2a

let's calculate

        x = 0.375²/2 0.21

        x = 0.335 m

Answer:

A dump truck.

Explanation:

Inertia can be defined as the tendency of an object or a body to continue in its state of motion or remain at rest unless acted upon by an external force.

In physics, Sir Isaac Newton's first law of motion is known as law of inertia and it states that, an object or a physical body in motion will continue in its state of motion at continuous velocity (the same speed and direction) or, if at rest, will remain at rest unless acted upon by an external force.

Mathematically, it is given by the formula;

[tex] F = ma[/tex]

Where;

The inertia of an object such as a tractor trailer rig is greatly dependent or influenced by its mass; the higher quantity of matter in a dump truck, the greater will be its tendency to continuously remain at rest.

Hence, a dump truck would probably need the greatest force to overcome its inertia because it has more mass than all the other objects in the category. Also, the mass of an object is directly proportional to its inertia, as well as the force applied.

Answer:As one of Newton's Laws of Gravitational force The answer would Be a dump truck because it includes one of Newton's Laws of Gravitational force in the abstract Laws of gravity.

Answer:

s = 1190.3 m = 1.19 km

Explanation:

First we find the acceleration by using first equation of motion:

Vf = Vi + at

where,

Vf = Final Velocity = 74.44 m/s

Vi = Initial Velocity = 36.96 m/s

a = acceleration = ?

t = time = 21.37 s

Therefore,

74.44 m/s = 36.96 m/s + a(21.37 s)

a = (74.44 m/s - 36.96 m/s)/21.37 s

a = 1.75 m/s²

Now, we use 2nd equation of motion to find distance covered (s):

s = Vi t + (1/2)at²

s = (36.96 m/s)(21.37 s) + (1/2)(1.75 m/s²)(21.37 s)²

s = 789.83 m + 400.47 m

s = 1190.3 m = 1.19 km

Answer:

ΔP =  20000 N s

Explanation:

To solve this problem we use the relation between momentum and moment

         I = Δp

let's calculate the momentum

         I = ∫F dt

if we use the average force

       I = F t

       I = 10000 2

       I = 20000 N s

therefore with the first equation

        ΔP = I = 20000 N s

Answer:

s = 83.85 km

Explanation:

First we calculate the distance covered by car, while traveling at constant speed:

s₁ = v₁t₁

where,

s₁ = distance covered at constant speed = ?

v₁ = constant speed = 23 m/s

t₁ = time of travel at constant speed = 1 hr = 3600 s

Therefore,

s₁ = (23 m/s)(3600 s)

s₁ = 82800 m = 82.8 km

Now, we calculate the distance travelled in accelerated motion. First we use 1st equation of motion to find acceleration:

Vf = Vi + at₂

where,

Vf = Final velocity = 40 m/s

Vi = Initial Velocity = 30 m/s

a = acceleration = ?

t₂ = time = 30 s

Therefore,

40 m/s = 30 m/s + a(30 s)

a = 10 m/s/30 s

a = 0.33 m/s²

Now, we use 2nd equation of motion for distance:

s₂ = Vi t₂ + (1/2)at₂²

s₂ = (30 m/s)(30 s) + (1/2)(0.33 m/s²)(30 s)²

s₂ = 900 m + 150 m

s₂ = 1050 m = 1.05 km

So, the total distance covered was:

s = s₁ + s₂

s = 82.8 km + 1.05 km

s = 83.85 km

Answer:

The momentum of the car is 3190.74 kgm/s

Explanation:

Given;

weight of the car, w = 1,356 N

velocity of the car, v = 83 km/h = 23.06 m/s

The mass of the car is given by;

m = w/g

where;

g is acceleration due to gravity = 9.8 m/s²

m = 1356 / 9.8

m = 138.367 kg

The momentum of this car is given by;

P = mv

P = (138.367 x 23.06)

P = 3190.74 kgm/s

Therefore, the momentum of the car is 3190.74 kgm/s

Answer:

33 Inches

Explanation:

The movement of the ant is sketched in the attached image. The ant moved from the 19-inch mark to 27-inch mark covering a distance of 13 Inches (27 - 19). Finally, it moved from the 27-inch mark to 7-inch mark covering a distance of 20 Inches (27 - 7).

Total Distance covered = 13 + 20 = 33 Inches.

Hence, the total distance the ant traveled is 33 Inches.

Answer:

W = 1750 J

Explanation:

It is given that,

Weight of a computer, F = 50 N

A student wants to keep it on the 5th floor which is 35 meters up.

We need to find the work done by her to drag her computer up the stairs. Let it is W. Using the formula of work as follows :

W = F d

Put all the values,

W = 50 N × 35 m

W = 1750 J

So, 1750 J of work is done by her to drag the computer up the stairs.

Answer:

I found "As nouns the difference between resultant and equilibrium is that resultant is anything that results from something else; an outcome while equilibrium is the condition of a system in which competing influences are balanced, resulting in no net change. is following as a result or consequence of something."

Explanation:

Answer:

You will be very glad to know that my preparation for HSC examination is very good. I have prepared myself for the HSC Examination 2015. I am confident that I will obtain very good marks in the examination. I have revised them several times and I am hopeful of obtaining distinction marks in all the subjects.

Explanation:

This is from Brainly hope this person helped you

Answer:

Explanatio

Increasing the speed of the relative motion between the coil and the magnet – If the same coil of wire passed through the same magnetic field but its speed or velocity is increased, the wire will cut the lines of flux at a faster rate so more induced emf would be produced. 3)n:

Answer:

s = 6.25 10⁻²² m

Explanation:

Polarizability is the separation of electric charges in a structure, in the case of the atom it is the result of the separation of positive charges in the nucleus and the electrons in their orbits, macroscopically it is approximated by

                p = q s

               s = p / q

let's calculate

              s = 1 10⁻⁴⁰ / 1.6 10⁻¹⁹

              s = 0.625 10⁻²¹ m

              s = 6.25 10⁻²² m

We see that the result is much smaller than the size of the atom, therefore this simplistic model cannot be taken to an atomic scale.

Answer:

yes

Explanation:

people still skateboard that is an easy question

Complete Question

A rolling ball moves from [tex]x_1 = 8.0 \ cm[/tex] to [tex]x_2 = - 4.1 \ cm[/tex] during the time from [tex]t_1 = 2.9 s[/tex]  to  [tex]t_2 = 6.0s[/tex]

What is its average velocity over this time interval?

Answer:

The velocity is  [tex]v = 3.903 \ m/s[/tex]

Explanation:

From the question we are told that

    The first position of the ball is  [tex]x_1 = 8.0 \ cm[/tex]

    The second position of the ball is  [tex]x_2 = - 4.1 \ cm[/tex]

Generally the average velocity is mathematically represented as

       [tex]v = \frac{ x_1 - x_2}{t_2 - t_1}[/tex]

=>    [tex]v = \frac{ 8 - -4.1 }{ 6 - 2.9 }[/tex]

=>    [tex]v = 3.903 \ m/s[/tex]

A spring balance measures the weight of an object by opposing the force of gravity acting with force of an extending spring. May be used to determine mass as well as weight by recalibrating the scale. Some spring balances are available in gram or kilogram markings and are used to measure the mass of an object. Spring balances consist of a cylindrical tube with a spring inside. One end (at the top) is fixed to an adjuster which can be used to calibrate the device. The other end is attached to a hook on which you can hang masses etc.

Answer:

W = 0.49 N

τ = 0.4851 Nm

Force

Explanation:

The weight force can be found as:

W = mg

W = (0.05 kg)(9.8 m/s²)

W = 0.49 N

The torque about the pivot can be found as:

τ = W*d

where,

τ = torque

d = distance between weight and pivot = 99 cm = 0.99 m

Therefore,

τ = (0.49 N)(0.99 m)

τ = 0.4851 Nm

The pivot exerts a  FORCE on the meter stick because the pivot applies force normally over the stick and has a zero distance from stick.

Answer:easter

Explanation:

Answer:

Easter

Explanation:

did it on edge, and searched it up

Answer:

x' = 0.085 m = 8.5 cm

Explanation:

The law of conservation of energy says that:

Potential Energy Stored in Spring = Loss in Gravitational Potential Energy of Block

(1/2)kΔx² = mgh

where,

k = stiffness of spring = 1070 N/m

Δx = change in length of spring = ?

m = mass of block = 0.5 kg

g = 9.8 m/s²

h = height of block above spring = 0.6 m - 0.15 m = 0.45 m

Therefore,

(1/2)(1070 N/m)Δx² = (0.5 kg)(9.8 m/s²)(0.45 m)

Δx = √[2(2.205 Nm)/(1070 N/m)]

Δx = 0.064 m

but,

Δx = x - x' = 0.15 m - x' = 0.064 m

x' = 0.15 m - 0.064 m

x' = 0.085 m = 8.5 cm

Answer:

10 seconds

Explanation:

Answer:

The resistance of a wire decreases with increasing thickness.

Explanation:

Hope this helped!

Answer: C it allows electrons to flow more easily

Explanation:i got it right i hope this helps you

Answer:

$30

Explanation:

Given that,

Power of a water heater, P = 2000 Watts

It is on for a total of 150 hours a month.

2000 Watts = 2 kW

Time, t = 150 hours

Energy used by the water heater is given by :

[tex]E=P\times t\\\\E=2\ kW\times 150\ h\\\\E=300\ kWh[/tex]

It is also mentioned that the cost is 10 cents per kWhr.

Since, $1 = 100 cents

10 cents = $0.1

So, the total cost for the month is :

Cost = 300 × 0.1

Cost = $30

So, the required cost is $30.

Answer:

the answer is a time your welcome

Answer:

(1)

Explanation:

Answer:

a.  (VL)R/ωL[1 - cos[ωt]]  = (10.84 V)[1 - cos[(487rad/s)t]]

b. 1.084 mV

Explanation:

a. Since it is a series circuit, the current in the inductor is the same as the current in the resistor.

Now, the voltage across the inductor vL = -Ldi/dt.

So, the current, i = -1/L∫vLdt.

Now, vL = −(12.0V)sin[(487rad/s)t] and L = 0.200 H

Substituting these into i, we have

i = -1/L∫vLdt

= -1/0.200H∫[−(12.0V)sin[(487rad/s)t]]dt.

= -[−(12.0V)]/0.200H∫[sin[(487rad/s)t]]dt.

= 60V/H∫[sin[(487rad/s)t]]dt

Integrating i, we have

i = 60V/H ÷ [(487rad/s)[-cos[(487rad/s)t]] + C

at t = 0, i(0) = 0

0 = 60V/H ÷ [(487rad/s)[-cos[(487rad/s)× 0]] + C

0 = 60V/H ÷ [(487rad/s)[-cos[0]] + C

0 = 60V/H ÷ [(487rad/s)[-1]+ C

C = 60V/H ÷ [(487rad/s)

So, i = 60V/H ÷ [(487rad/s)[-cos[(487rad/s)t]] + 60V/H ÷ [(487rad/s)

i =  60V/H ÷ [(487rad/s)[1 - cos[(487rad/s)t]]

i = (0.123A)[1 - cos[(487rad/s)t]] = VL/ωL[1 - cos[ωt]] where ω = 487rad/s and VL = 12.0 V and L = 0.200 H

So, the voltage across the resistor vR = iR where R = resistance of resistor = 88.0 Ω

So, vR = iR = VL/ωL[1 - cos[ωt]] × R = (VL)R/ωL[1 - cos[ωt]]

=  (0.123A)[1 - cos[(487rad/s)t]] × 88.0 Ω

= (10.84 V)[1 - cos[(487rad/s)t]]

b. vR at t = 2.00 ms = 0.002 s

So, vR = (10.84 V)[1 - cos[(487rad/s)(0.002)]]

= (10.84 V)[1 - cos[0.974]]

= (10.84 V)[1 - 0.9999]

= (10.84 V)(0.0001)

= 0.001084

= 1.084 mV