What is the slope of this line?

Answer:

Step-by-step explanation:

I used the quadratic formula to find the roots of [tex]x^{2} + x -1[/tex]

[tex]a=\frac{-1-\sqrt{5}}{2} b=\frac{-1+\sqrt{5} }{2}[/tex]

[tex]\frac{1 }{\sqrt{3} } *(\frac{-1-\sqrt{5}}{2} )^{2} * \frac{-1+\sqrt{5}}{2}[/tex]

[tex]\frac{1 }{\sqrt{3} } *(\frac{-1-\sqrt{5}}{2} ) * \frac{-1+\sqrt{5}}{2}*(\frac{-1-\sqrt{5}}{2} )[/tex]

[tex]\frac{1 }{\sqrt{3} } *(\frac{-1-\sqrt{5}}{2} ) * \frac{-1+\sqrt{5}-\sqrt{5} -4}{4}[/tex]

[tex]\frac{1 }{\sqrt{3} } *(\frac{-1-\sqrt{5}}{2} ) * \frac{ -4}{4}[/tex]

[tex]\frac{1 }{\sqrt{3} } *(\frac{-1-\sqrt{5}}{2} ) * -1[/tex]

[tex]\frac{-1-1\sqrt{5} }{2\sqrt{3} }*-1[/tex]

[tex]\frac{-1-1\sqrt{5} }{2\sqrt{3} } = \frac{\sqrt{5}+1 }{2\sqrt{3} }[/tex]

Given:

The function is

[tex]f(x)=7x+11[/tex]

To find:

The domain, range, and intercepts of the function.

Solution:

We have,

[tex]f(x)=7x+11[/tex]

It is a linear function, and domain and range of these types of functions  are all real numbers.

[tex]Domain:(-\infty,\infty)[/tex]

[tex]Range:(-\infty,\infty)[/tex]

Put x=0 in f(x), to find the y-intercept.

[tex]f(0)=7(0)+11[/tex]

[tex]f(0)=0+11[/tex]

[tex]f(0)=11[/tex]

So, the y-intercept is 11.

Put f(x)=0 in f(x), to find the x-intercept.

[tex]0=7x+11[/tex]

[tex]0-11=7x[/tex]

[tex]-11=7x[/tex]

Divide both sides by 7.

[tex]\dfrac{-11}{7}=x[/tex]

So, the x-intercept is [tex]\dfrac{-11}{7}[/tex].

Therefore, [tex]Domain:(-\infty,\infty), Range:(-\infty,\infty), x-intercept : (\dfrac{-11}{7},0),[/tex] [tex]y-intercept :11[/tex].

Answer:

(0,6) and (-2, 0)

Step-by-step explanation:

All straight lines follow the equation, y = mx + c. where c is the y-intercept (the point where the line meets the y-axis) and m is the gradient.

In this equation, c = 6. So, the point where the line meets the y-axis is (0, 6).

Remember: the point where the line meets the y-axis always has an x-coordinate of 0 and the point where the line meets the x-axis has a y-coordinate of 0.

using this information, we can substitute y in the equation with 0 becoming

0 = 6 + 3x

now we can solve for x.

0 -6 = 3x

-6 / 3 = x

x = -2

the coordinate is (-2, 0)

Answer:

perimeter =22m

area=28square meter

perimeter of rectangle=4l

22m=4l

22÷4=l

5.5=l

l=5.5m

area of rectangle =l×b

28=5.5×b

28÷5.5=b

5.09=b

b=5.09m

length =5.5m and breadth =5.09m answer !!!!

Answer:

(x+1)(x-1) and x = -1, 1, 2

Step-by-step explanation:

x^2 - 1 factors to (x+1)(x-1)

x+1 = 0; x = -1

x-1 = 0; x = 1

x-2 = 0; x = 2

The percent increase in the temperature is 50%.

To understand more, check below explanation.

The temperature increases from 18° F to 27° F.

       Increase in temperature = 27 - 18 = 9

The percent increase in the temperature is computed as,

                                  [tex]=\frac{27-18}{18}*100\\ \\=\frac{9}{18}*100\\ \\=\frac{1}{2}*100=50\%[/tex]

Learn more about the percentage here:

https://brainly.com/question/24304697

Answer:

The height of the base if it is 2 in. Wide is 3 inches

Step-by-step explanation:

Volume of rectangular prism = [tex]\frac{1}{2} \times Length \times Base \times Height[/tex]

Volume of given rectangular prism = [tex]12 in^3[/tex]

Length of prism = 4 in

Base of prism = 2 in

Substitute the values in formula

So, [tex]12 = \frac{1}{2} \times 4 \times 2 \times Height[/tex]

[tex]\frac{12 \times 2}{4 \times 2}=Height[/tex]

3 = Height

Hence the height of the base if it is 2 in. Wide is 3 inches

Answer:

3 inches

Step-by-step explanation:

Answer:

0.36

Step-by-step explanation:

0.4=4/10

0.9=9/10

9/10 times 4/10= (9 times 4)/(10 times 10)=36/100=0.36

Another way you could've done it was to see that since there are 2 decimal points there, the product would also have to have 2 decimal points.

Answer:

.36

Step-by-step explanation:

Answer:

Step-by-step explanation:

If we know the slope and a point, we can easily write it in point-slope form

[tex]y - y_1 = m(x-x_1)\\y - 8 = -5(x-(-3))\\y - 8 = -5(x+3)[/tex]

Answer:

y + 5 = 2(x - 5)

Step-by-step explanation:

The equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

Here m = 2 and (a, b) = (5, - 5) , thus

y - (- 5) = 2(x - 5) , that is

y + 5 = 2(x - 5)

Answer:

A.

Step-by-step explanation:

You just plug in the numbers

y = x - 7

-5 = 2 - 7

- 5 = - 5

This makes this equation true.

Answer:

A

Step-by-step explanation:

1. Honestly, my course of action, if allowed to, would be to use my graphing calculator. Obviously, you can graph the first equation but the second one requires some rearranging, keeping in mind that we are isolating the y.

[tex]2y-2x=10[/tex]

[tex]2y=2x+10[/tex]

[tex]y=x+5[/tex]

So now we have an equation of the line. Simply enter both of these equations into your graphing calculator and you're all set.

I hope this helps!

Answer:

frame b because it takes up more room than the other some it forces the other to be smaller

Step-by-step explanation:

Answer:

Step-by-step explanation

It is Frame B trust me it is bigger.

Answer:

c=3

Step-by-step explanation:

Angle sum of a triangle is 180°

(19c+16)°+13c°+(17c+17)°=180°

collect the like terms i.e

19c+13c+17c+16+17=180°

49c°+33°=180°

49c°=180°-33°

49c°=147

dividing by 49 both sides

49c/49=147/49

c=3

Answer:

( -2,0,2 ) three

Step-by-step explanation:

HOPE THIS HELPS

Answer:

Answer: D. 2(V[x} + V{x - 2}) Step-by-step explanation: As hinted in the question, we have to simplify the denominator. To understand it easier, let's imagine we have x - y in the denominator. If we multiply it with x + y we'll get x? - y, right? Check the next line: (x - y) (x + y) = x² + xy -xy - y? = x² - y? If we have the square of those nasty square roots, it will be much simpler to deal with. So, let's multiply the initial fraction using x+y, but with the real values: 4 x-2 x+Vx-2 x-2 4(Va+v-2) (V#)² -(væ–2)² Then we simplify: 4(va+væ-2) 4(Va+va-2) (Væ)2-(Va-2)2 2(Va + Va – 2) 4(va+va-2) (x) -(x-2) 2 Answer is D. 2(V{X} + v{x - 2})

Answer:

d = dependant; t = independant

Step-by-step explanation:

The d value is dependant on the t value, therefore it is the dependant. The t is the only valuable that can be changed in the equation, therefore being the independant.

Answer:

[tex]D[/tex] = dependent; [tex]t[/tex] = independent

Step-by-step explanation:

[tex]D[/tex] is the independent variable since its value relies/depends on the value of [tex]t[/tex].

[tex]t[/tex] is the independent variable since it is the input variable which can be changed.

Hope this helps :)

Answer:

2x-6y=-24

2x=-24+6y

x=-24+6y÷2

x=-12+3y equation 1

x+(-5y)=-22

-12+3y-5y=-22

-13-2y=-22

-2y=-22+13

-2y=-9

y=-9÷2

y=4.5equation 2

putting value of equation 2 in equation 1

x=-12+3y

x=-12+3×4.5

x=-12+13.5

x=1.5 answer!!!

Answer:

-48-22i

Step-by-step explanation:

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[tex] \sqrt{17} ≈4.1[/tex]

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

The correct answer is Option Three .

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

Answer:

C

Step-by-step explanation:

Answer: -16.74

Step-by-step explanation:

Answer:-16.74

Step-by-step explanation:

Answer:

[tex] \huge{ \boxed{ \bold{ \tt{2 \sqrt{26}}} \: \: \text{units} } } [/tex]

Let the points be A and B. Now,

Use the distance formula to determine the distance between A ( 5 , -6 ) and B ( 3 , 4 ).

[tex] \boxed{ \underline{ \sf{distance = \sqrt{ {(x2 - x1)}^{2} + {(y2 - y1)}^{2} } }}}[/tex]

Substitute the actual value of the points into the distance formula and then simplify.

[tex] \dashrightarrow{ \sf{ \sqrt{ {(3 - 5)}^{2} + {(4 - ( - 6))}^{2} } }}[/tex]

Remember : The positive and negative integer are always subtracted but posses the sign of the bigger integer.

[tex] \dashrightarrow{ \sf{ \sqrt{ {( - 2)}^{2} + {(4 - ( - 6))}^{2} } }}[/tex]

Remember : ( - ) × ( - ) = ( + )

[tex] \dashrightarrow{ \sf{ \sqrt{ {( - 2)}^{2} + {(4 + 6)}^{2} } }}[/tex]

Add the numbers : 4 and 6

[tex] \longrightarrow{ \sf{ \sqrt{ {( - 2)}^{2} + {(10)}^{2} } }}[/tex]

Evaluate the power

[tex] \longrightarrow{ \sf{ \sqrt{4 + 100}}} [/tex]

Add the numbers : 4 and 100

[tex] \dashrightarrow{ \sf{ \sqrt{104}}} [/tex]

[tex] \dashrightarrow{ \boxed{ \sf{2 \sqrt{26} }}}[/tex] units

Therefore , The distance between ( 5 , -6 ) and ( 3 , 4 ) is [tex] \sf{2 \sqrt{26}} [/tex] units .

And we're done!

Hope I helped!

Have a wonderful time ! シ

~TheAnimeGirl

Answer:

Create a single variable linear equation that has no solution. Solve the equation algebraically to prove that it does not have a solution.

Create a single variable linear equation that has one solution. Solve the equation algebraically to prove that there is one distinct solution for the equation.

Create a single variable linear equation that has infinitely many solutions. Solve the equation algebraically to prove that there is an infinite number of solutions for the equation

Step-by-step explanation:

Answer:

n = ±7

General Formulas and Concepts:

Pre-Algebra

Algebra I

Step-by-step explanation:

Step 1: Define equation

-3n² + 147 = 0

Step 2: Solve for n

Answer:

no

Step-by-step explanation:

no

Answer:

Maisha ran the race in .36 seconds faster than Patti.

8.4 - 8.04 = .36

Answer:

B

Step-by-step explanation:

Which word best describe reflection

A.Line of symmetry

B.Mirror-image

C.identical

D.All of the above