Answer:
900
Explanation:
v = s / t = 9000m / 10 s = 900m/s
Explanation:
The speed of a rocket that travel 9km in 10 second is 900
A wagon with a weight of 300 N is accelerated across a level surface at 0.5 m/s2. What net force acts on the wagon?
9.0 N
15 N
150 N
610 N
Answer:
F = 15.29[m/s²].
Explanation:
To solve this problem we must use Newton's second law which tells us that the force is equal to the product of mass by acceleration.
ΣF =m*a
where:
m = mass [kg]
a = acceleration = 0.5 [m/s²]
Therefore we must find first the mass.
[tex]W =m*g\\m=W/g\\m = 300/9.81\\m = 30.58 [kg][/tex]
Now replacing in Newton's second law.
[tex]F = m*a\\F = 30.58*0.5\\F=15.29[m/s^{2}][/tex]
A beam contains 4.9 × 108 doubly charged positive ions per cubic centimeter, all of which are moving north with a speed of 4.6 × 105 m/s. What is (a) the magnitude of the current density and (b) direction of the current density (c) what additional quantity do you need to calculate the total current i in this ion beam?
Answer:
[tex]72.12\ \text{A/m}^2[/tex]
south
cross sectional area of the beam
Explanation:
v = Velocity of ions = [tex]4.6\times 10^5\ \text{m/s}[/tex]
Number of ions per [tex]\text{cm}^3[/tex] = [tex]4.9\times 10^8[/tex]
Charge density would be the product of number of ions per [tex]cm^3[/tex] and the charge of electrons multiplied by 2 as they are doubly charged.
[tex]\rho_q=4.9\times 10^8\times 10^6\times 2\times 1.6\times 10^{-19}\\\Rightarrow \rho_q=0.0001568\ \text{C/m}^3[/tex]
Current density is given by
[tex]J=\rho_qv\\\Rightarrow J=0.0001568\times 4.6\times 10^5\\\Rightarrow J=72.12\ \text{A/m}^2[/tex]
The current density is [tex]72.12\ \text{A/m}^2[/tex]
The direction of the current density is opposite to the movement of the charged particle. The particles are moving north so the direction of current density will be to the south.
Current is given by
[tex]I=JA[/tex]
where A is the cross sectional area of the beam .
So the cross sectional area of the beam is required to determine the total current in this ion beam.
Consider a compact car that is being driven
at 113 km/h. The acceleration of gravity is 9.8 m/s^2.
From what height would the car have to be
dropped to have the same kinetic energy?
Answer in units of m.
experiment to show that light travels in a straight line
A car slows from 37.3 m/s to 8.8 m/s with a constant acceleration of -3.3 m/s2. How long in seconds does it require?
Answer:
The time it takes the car to stop is 8.64 s.
Explanation:
Given;
initial velocity of the car, u = 37.3 m/s
final velocity of the car, v = 8.8 m/s
constant acceleration of the car, a = -3.3 m/s²
The time it takes the car to stop is given by;
[tex]t = \frac{v-u}{a}[/tex]
Substitute the givens;
[tex]t = \frac{v-u}{a}\\\\t = \frac{8.8-37.3}{-3.3}\\\\t = 8.64 \ s[/tex]
Therefore, the time it takes the car to stop is 8.64 s.
What is the similarity between relative dating and radioactive dating? I will mark brainlest. I dont know how btw
Answer:
relative dating and radioactive dating are two methods in archeaology to determine the age of fossils and rocks
Explanation:
the act of or study of fossils is important for the determination of the kind of organism it represents how the organism lived and how it was preserved on the Earth’s surface over the past 4600000000 years
The power of the situation represents
minority influence.
role expectations.
personal control.
social control
I think the answer is c but I'm not sure
premium
A student releases a marble from the top of a ramp. The marble increases speed
while on the ramp then continues across the floor. The marble travels a total of
150cm in 4.80s.
What was the marble's final speed?
Explanation:
the formula of speed is distance traveled by time it work
31.25 cm/sec
__________________________________________________________
Explanation:We are given:
Distance travelled = 150 cm
Time taken = 4.8 seconds
Final Speed of the Marble:
Speed of the marble = Distance travelled / Time taken
Speed of the marble = 150 / 4.8
Speed of the marble = 31.25 cm/sec
the distance from Alex home to his school is 1km and 560 cm. what is this distance?
Answer:
Required Answer:-1meter=100cm1km=1000m[tex]{:}\longrightarrow[/tex][tex]\sf 1km=1000×100cm [/tex]
[tex]{:}\longrightarrow[/tex][tex]\sf 1km=100000cm [/tex]
Total distance
[tex]{:}\longrightarrow[/tex][tex]\sf 100000+560=1000560cm [/tex]
[tex]{:}\longrightarrow[/tex][tex]\sf 1000.56m[/tex]
[tex]{:}\longrightarrow[/tex][tex]\sf 1.560km [/tex]
The radius of the earth’s orbit is r = 1.5 × 1011 m and its orbital period is T = 365.3 days. What is the radial acceleration (in m/s2) of the earth toward the sun, assuming a circular orbit?
A. 5.91 × 10−3 m/s2
B. 3.23 × 10−3 m/s2
C. 7.23 × 10−4 m/s2
D. 5.91 × 10−2 m/s2
The radial acceleration of a body a distance R from the center of a circular path and with period T has magnitude a such that
a = 4 π ² R / T ²
The given period is
T = 365.3 days ≈ 3.156 x 10⁷ s
(i.e. multiply the number of days by 24 hours/day and 3600 seconds/hour)
So the Earth's radial acceleration is
a = 4 π ² (1.5 x 10¹¹ m) / (3.156 x 10⁷ s)²
a ≈ 0.0059 m/s²
PLEASE HELP PLS ITS DUE IN 10 MINUTES!!
Suppose you’re standing at the top of a 100m high building. How much potential energy would you lose if you walked down the stairs by 20m?
You are now standing at a height of 80m. How much potential energy would you lose if you went down by 20m?
Suppose now you decide to go down by 20m more (you’re standing at 60m high). How much potential energy would you need to get to 40? Can you draw any conclusions about potential energy from this observation?
Answer:
I AM SO SORRY
but here is the answer
Explanation:
20 j
What is magnet made of
Answer:
metals like iron or nickel
Explanation:
PLEASEEE HELPPPPP does anyone know these answers?
Answer:
oof ok
Explanation:
Thank you :)
A hockey player skating at 21 m/s comes to a complete stop in 12.0 m.
a) What is its acceleration during this displacement?
b) How long did it take the hockey player to come to a stop?
Answer:
a. 18.375m/s²
b. 1.142s
Explanation:
A. Using v² = u² + 2as
Where;
V = final velocity (m/s)
u = initial velocity (m/s)
a = acceleration (m/s²)
s = distance (m)
In this question, v = 21m/s, u= Om/s, s = 12m
21² = 0² + 2 × a × 12
441 = 0 + 24a
441 = 24a
a = 18.375m/s²
B). Using V = u + at
21 = 0 + 18.375t
21 = 18.375t
t = 21/18.375
t = 1.142s
answer plese lang po
Answer:
hi
Explanation:
how to convert gumbauan baboy to kung burger p
A kid runs and slides down a slip-n-slide. Once the kid hits the slide they have 200N of friction force acting on them, and they decelerate at 2.5m/s. What is the mass of the kid?
Climate is the day-to day condition of an area including temperature, pressure, and precipitation. Weather is the usual pattern of temperature, pressure, and precipitation pf an area over time. True or False
Answer:
False
Explanation:
Weather is the day-to day condition of an area including temperature, pressure, and precipitation. Climate is the usual pattern of temperature, pressure, and precipitation pf an area over time.
It is true that the climate is the day-to day condition of an area including temperature, pressure, and precipitation. Weather is the usual pattern of temperature, pressure, and precipitation pf an area over time.
What is the relation between climate and weather?The weather is the current state of the atmosphere for a particular place and at a definite or short period of time. The atmospheric conditions which are considered are temperature, cloudiness, dryness, humidity, rain, sunshine and wind.
The climate is the atmospheric conditions of a particular place over a long time period.
It is the condition of the Earth and the atmosphere which tells us about the extent at either it is hot or cold, wet or dry, or it can be calm or stormy type. Basically the weather changes and happened at the least level of the atmosphere and the layer is known to be the troposphere that is found just below the stratosphere. Troposphere is the layer present in the most lower level forming the Earth's atmosphere. In this layer of has 75% mass out of atmospheric mass and 99% of the total mass of water vapor.
So, the given statement is true.
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Light passes through a 0.15 mm-wide slit and forms a diffraction pattern on a screen 1.25 m behind the slit. The width of the central maximum is 0.75 cm. What is the wavelength of the light?
a. 400nm
b. 450nm
c. 510nm
d. 600nm
Answer:
b. 450 nm
Explanation:
The wavelength of light can be calculated by using the formula derived in Young's double slit experiment. The formula is as follows:
Δx = λL/d
Δx/2 = λL/2d
where,
Δx/2 = half distance between consecutive dark fringes = width of central maximum = 0.75 cm = 0.0075 m
λ = wavelength of light = ?
L = Distance of Screen = 1.25 m
d = width of slit = 0.15 mm = 0.00015 m
Therefore,
0.0075 m = λ(1.25 m)/(0.00015 m)
λ = (0.0075 m)(0.00015 m)/2(1.25 m)
λ = 4.5 x 10⁻⁷ m = 450 nm
Thus, the correct option is:
b. 450 nm
Two blocks with different masses are dropped, hitting the ground with the same velocity. Which of the following is true?
They have same change in velocity but different changes in kinetic energy
The lighter object started at a smaller height.
The heavier object started at a smaller height
They started at the same height
They have same change in kinetic energy but different changes in velocity
Answer: • They have same change in velocity but different changes in kinetic energy
•They started at the same height.
Explanation:
First and foremost, we need to note that both balls have thesame acceleration due to gravity and due to this, even though they've different masses, they'll fall at same speed.
Also, since kinetic energy that's, the energy relating to motion of a mass, us dependent on mass and speed, their kinetic energy will be different.
Therefore, based in the explanation, the correct options are:
• They have same change in velocity but different changes in kinetic energy
•They started at the same height.
When a potential difference of 10 V is placed across a certain solid cylindrical resistor, the current through it is 2 A. If the diameter of this resistor is now tripled, the current will be:______.A) 18 A.
B) 2/3 A.
C) 3 A.
D) 2/9 A.
E) 2 A.
Answer:
sorry I wish I could it help you
a car with a mass of 1200 kg travels a distance of 150 M as it moves from one stoplight to the next at its fastest the car travels at 22 m per second what is its kinetic energy at this point
Answer:
ke = 1/2mv^2
= 1/2 * 1200 * 22^2
= 600 * 484
= 290400 J
Hope it helped u,
pls mark this as brainliest
and put thanks
^_^
Answer:
The kinetic energy at this point 290,400
A racecar accelerates from rest at 6.5 m/s2 for 4.1 s. How fast will it be going at the end of that time?
Answer:
The final velocity of the car is 26.65 m/s.
Explanation:
Given;
acceleration of the racecar, a = 6.5 m/s²
initial velocity of the car, u = 0
time of motion, t = 4.1 s
The final velocity of the car is given by;
v = u + at
where;
v is the final velocity of the car
suvstitute the givens
v = 0 + (6.5)(4.1)
v = 26.65 m/s.
Therefore, the final velocity of the car is 26.65 m/s.
(b) In the USA, drones are not allowed to be flown too high above the ground.
Suggest one possible risk of flying a drone too high above the ground.
Plz complete thank you in advance
The 400-foot altitude limit was put in place for the sake of airspace safety, and there is a risk to country security as well as the privacy of citizens.
What are drones?Unmanned aerial vehicles (UAVs), sometimes known as drones, are used for a variety of jobs, from routine to extremely dangerous. These robotic-looking planes can be seen practically everywhere, from delivering groceries to your home to rescuing avalanche victims.
The 400-foot altitude restriction was ultimately implemented for airspace safety. Given the breadth of the airspace above 400 feet, the likelihood of a drone colliding with a human aircraft is exceedingly remote, but the consequences might be disastrous.
Any aerial vehicle that uses software to fly autonomously or that may be controlled remotely by a pilot is referred to as a drone. Numerous drones come equipped with cameras to gather visual data and propellers to stabilize flying paths. Drone technology has been incorporated into industries like videography, search and rescue, agriculture, and transportation.
When in uncontrolled (Class G) airspace, your drone must be flown 400 feet above the ground or less.
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List at least 4 aspects to evaluate the quality of an internet site
Answer:
authority, accuracy, objectivity, currency, coverage, and appearance.
Explanation:
There are six (6) criteria that should be applied when evaluating any Web site. or each criterion, there are several questions to be asked. The more questions you can answer "yes", the more likely the Web site is one of quality.
A cow is given a growth hormone and then compared to another cow that was not given a growth hormone. Both cows were weighed at 2 years.
The complete question is as follows:
A cow is given a growth hormone and then compared to another cow that was not given a growth hormone. Both cows were weighed at 2 years. What is the independent variable?
if the cow is given growth hormone or not
weight of the cow
same cows
type of growth hormone
Answer:
The correct answer is - if the cow is given growth hormone or no
Explanation:
The independent variable is here is if the growth hormone is given or not as the variable which is subject to change or manipulated during an investigation and affects the dependent variable is known as the independent variable.
Due to this independent variable manipulation the weight of the cows might be different which makes the weights as the dependent variable.
what is the speed of rocket that travels 9km in 10 seconds
Answer:
900
Explanation:
v = s / t = 9000m / 10 s = 900m/s
plz mark Brainliest
Answer:
3240km/h. or, 900m/s.
Explanation:
plz mark mine as brainliest. i gave both.
A cathode ray tube is made of glass with a small amount of some kind of gas in it. It has metal electrodes at each end to pick up an electric current. The electrodes are named "positive” and "negative." What are one of the main uses of this device ? to speed up the flow of current flowing through a wire to examine a beam of charged particles to magnetize different atoms within a space to change the strength of a proton within an atom
One of the main uses of this device is to examine a beam of charged particles
The cathode ray tube is a device used to determine the charge flowing in a gas. When an electric field is set up with the help of metal electrodes, the cathode ray tends to bend towards the positive electrode.
Since the cathode ray bends towards the electrodes, it implies that it has a charge and the electrodes present help us determine the charge of the beam of charged particles and thus examine the beam of charged particles.
So, one of the main uses of this device is to examine a beam of charged particles.
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Answer:
B
Explanation:
Sandra pays $11 for 2.75 pounds of cheese. What is the cost per pound?
$0.40
x
$0.44
$4.00
$4.40
Hi
Answer:
$4.00
Explanation:
The cost per pound is $4.00, $11 divided by 2.75 is 4.
Answer:
Th cost per pound is $4.00.
Explanation:
11/2.75= 4
A 5.3 kg block rests on a level surface. The coefficient of static friction is μ_s=0.67, and the coefficient of kinetic friction is μ_k= 0.48 A horizontal force, x is applied to the block. As x is increased, the block begins moving. Describe how the force of friction changes as x increases from the moment the block is at rest to when it begins moving. Show how you determined the force of friction at each of these times ― before the block starts moving, at the point it starts moving, and after it is moving. Show your work.
As the pushing force x increases, it would be opposed by the static frictional force. As x passes a certain threshold and overcomes the maximum static friction, the block will start moving and will require a smaller magnitude x to maintain opposition to the kinetic friction and keep the block moving at a constant speed. If x stays at the magnitude required to overcome static friction, the net force applied to the block will cause it to accelerate in the same direction.
Let w denote the weight of the block, n the magnitude of the normal force, x the magnitude of the pushing force, and f the magnitude of the frictional force.
The block is initially at rest, so the net force on the box in the horizontal and vertical directions is 0:
n + (-w) = 0
n = w = m g = (5.3 kg) (9.80 m/s²) = 51.94 N
The frictional force is proportional to the normal force, so that f = µ n where µ is the coefficient of static or kinetic friction. Before the block starts moving, the maximum static frictional force will be
f = 0.67 (51.94 N) ≈ 35 N
so for 0 < x < 35 N, the block remains at rest and 0 < f < 35 N as well.
The block starts moving as soon as x = 35 N, at which point f = 35 N.
At any point after the block starts moving, we have
f = 0.48 (51.94 N) ≈ 25 N
so that x = 25 N is the required force to keep the block moving at a constant speed.
As x is increasing it will be opposed by a static frictional force and for the object to start moving and maintain its acceleration, the magnitude of x must exceed the magnitude of the static frictional force and kinetic frictional force
Magnitude of normal force ( object at rest ); n = 51.94 N Required magnitude of x before the movement of object ; x = 35 NMagnitude of x after object start moving x = 25 NGiven data :
mass of block at rest ( m ) = 5.3 kg
Coefficient of static friction ( μ_s ) =0.67
Coefficient of kinetic friction is ( μ_k ) = 0.48
Horizontal force applied to block = x
First step : magnitude of normal force ( n ) when object is at rest
n = w where w = m*g
n - w = 0
n - ( 5.3 * 9.81 ) = 0 ∴ n = 51.94 N
Second step : Required magnitude of x before the movement of object
F = μ_s * n
F = 0.67 * 51.94 = 34.79 N ≈ 35 N
∴ The object will start moving once F and x = 35 N
Final step : Magnitude of x after object start moving
F = μ_k * n
= 0.48 * 51.94 = 24.93 N ≈ 25 N
∴ object will continue to accelerate at a constant speed once F and x = 25N
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A projector lens projects an image from a 6.35 cm wide LCD screen onto a
screen 3.25 m wide. If the focal length of the projector lens is 13.8 cm, the screen
must be how far from the projector
Answer:
For any given projector, the width of the image (W) relative to the throw distance (D) is know as the throw ratio D/W or distance over width. So for example, the most common projector throw ratio is 2.0. This means that for each foot of image width, the projector needs to be 2 feet away or D/W = 2/1 = 2.0.