What is the square root of ab2?

Answers

Answer 1

Answer:

ab

Step-by-step explanation:

The square root cancels out the squaring exponent


Related Questions

X^2 + 4x - 7x = 0
GIVE YOUR ANSWER TO THE CORRECT 2 DECIMAL PLACES

Answers

Answer:

x ≈ - 5.32, x ≈ 1.32

Step-by-step explanation:

x² + 4x - 7 = 0 ( add 7 to both sides )

x² + 4x = 7

To complete the square

add ( half the coefficient of the x- term )² to both sides

x² + 2(2)x + 4 = 7 + 4

(x + 2)² = 11 ( take the square root of both sides )

x + 2 = ± [tex]\sqrt{11}[/tex] ( subtract 2 from both sides )

x = - 2 ± [tex]\sqrt{11}[/tex]

Thus

x = - 2 - [tex]\sqrt{11}[/tex] ≈ - 5.32 ( to 2 dec. places )

x = - 2 + [tex]\sqrt{11}[/tex] ≈ 1.32 ( to 2 dec. places )

Answer:

x = -5.32, x = 1.32

Step-by-step explanation:

Ok. So to use the Complete the Square method, you divide the middle value by 2 and then square the number you get. This will give:

[tex](x^{2} + 4x + (\frac{4}{2}) ^2) - (\frac{4}{2}) ^2 -7 = 0[/tex]

[tex](x^{2} + 4x + 4) - 4 -7 = 0[/tex]

[tex](x^{2} + 4x + 4) - 11 = 0[/tex]

[tex](x^{2} + 4x + 4) = 11[/tex]      (now factor the left side)

[tex](x + 2)(x + 2) = 11[/tex]

[tex](x + 2)^{2} = 11[/tex]       (now square root both sides)

[tex]\sqrt{(x + 2)^{2}} = \sqrt{11}[/tex]

[tex]x + 2 = \sqrt{11}[/tex]

[tex]x = - 2 +/- \sqrt{11}[/tex]         (+/- = plus or minus)

x = -5.32, x = 1.32

HELP ME PLEASE I NEED HELP

Answers

try the other answer.

Answer:

a. x=2

b. y=5

Step-by-step explanation:

a. 2(11x+7)=58

22x+14=58

x=2

b. 16y+10=90

16y=80

y=5

Write this whole number as a product of prime numbers.
56

Answers

Answer:

The prime factorization of 56 is 2 * 2 * 2 * 7. This can also be written with exponents as 2^3 * 7.

Step-by-step explanation:

How do I do this I need help right now

Answers

To answer this (specifically the first one) you have to count how many spaces each point moves. (How many spaces up/down does it go? Left/right?) then you put rise (up/down) over run (left/right) and you should get the slope!

a car travels 180 miles in 3 hours at this rate how many miles will the? car travel in 6 hours ?

Answers

It will cover 360 miles in 6 hrs

Hope this helps

Pls give me BRAINLIEST

Plz help!! Meera is researching cruising speeds of different planes. Which airplanes has a greater cruising speed?

Answers

Answer:

The one on the graph

Step-by-step explanation:

In the past month, Heather rented 1 video game and 5 DVDs. The rental price for the video game was $3.30. The rental price for each DVD was$4.80 . What is the total amount that Heather spent on video game and DVD rentals in the past month?

Answers

Answer:

$27.30

Step-by-step explanation:

$4.80×5=$24.00+$3.30=$27.30

Your kite is stuck in a tree that is 40 feet tall. The angle your string makes with the ground is 72°. Rather than worrying about the kite, you decide to calculate how much string you have let out. Assuming the string is held tight and makes a straight line to the ground, how much string have you let out?

Answers

Answer:

42 feet of string

Step-by-step explanation:

First, draw a diagram of the string, the height and the angle.

the length of the string is equal to the hypotenuse of the triangle

let length of the string=x

sin(θ)=opp/hyp

sin(72°)=40ft/x

x=40ft/sin(72°)

x=42.05848897ft≈42ft

chloe is 5 feet 4 inches tall. there are 2.54 centimeters in 1 inch. what is chloe's height in centimeters?

Answers

Answer:

Her height would be 162.56 centimeters tall.

Step-by-step explanation:

There are 12 inches in 1 foot so that would mean that 1 foot has 30. 48 centimeters.

30.48 x 5 = 152.4

Add the 4 extra inches so 4 inches in centimeters is 10.16

152.4 + 10.16 = 162.56

Question 3 (2 points)

(04.07)

Two separate bacteria populations grow each month and are represented by the functions fx) = 3* and g(x) = 7x + 6. In what month is the f(x)
population greater than the g(x) population? (2 points)

Answers

Complete question is;

Two separate bacteria populations grow each month and are represented by the functions f(x) = 3^(x) and g(x) = 7x + 6. In what month is the f(x) population greater than the g(x) population?

A. Month 1

B. Month 2

C. Month 3.

D. Month 4

Answer:

Option D: Month 4

Step-by-step explanation:

We are given the functions;

f(x) = 3^(x)

And g(x) = 7x + 6

We want to find the month when f(x) > g(x)

Thus;

3^(x) > 7x + 6

For option A, month 1 means x = 1.thus;

LHS is 3¹ = 3

RHS = 7(1) + 6 = 13

Our LHS is not greater than RHS as the question demands, thus this option is not correct

For option B, month 2 means x = 2. thus;

LHS is 3² = 9

RHS = 7(2) + 6 = 20

Our LHS is not greater than RHS as the question demands, thus this option is not correct

For option C, month 3 means x = 3. thus;

LHS is 3³ = 27

RHS = 7(3) + 6 = 27

Our LHS IS equal to the RHS and not greater than RHS as the question demands, thus this option is not correct

For option D, month 4 means x = 4. thus;

LHS is 3⁴ = 81

RHS = 7(4) + 6 = 34

Our LHS is greater than RHS as the question demands, thus this option is correct

I need help with this please!! ​

Answers

Answer:

[tex] {6x}^{3} + {9x}^{2} - 18x + 3[/tex]

Step-by-step explanation:

1. Expand by distributing sum groups.[tex]3x( {2x}^{2} + 5x - 1) - 3( {2x}^{2} + 5x - 1)[/tex]

2. Expand by distributing terms.

[tex] {6x}^{3} + {15x}^{2} - 3x - 3( {2x}^{2} + 5x - 1)[/tex]

3.Expand by distributing terms.

[tex] {6x}^{3} + {15x}^{2} - 3x - ( {6x}^{2} + 15x - 3)[/tex]

4. Remove parentheses.

[tex] {6x}^{3} + {15x}^{2} - 3x - {6x}^{2} - 15x + 3[/tex]

5. Collect like terms.

[tex] {6x}^{3} + {15x}^{2} - {6x}^{2} ) + ( - 3x - 15x) + 3[/tex]

6. Simplify.

[tex] {6x}^{3} + {9x}^{2} - 18x + 3[/tex]

Thus. the answer is,

[tex] {6x}^{3} + {9x}^{2} - 18x + 3[/tex]

Evaluate
2-8÷-2-3-12÷-6×-2

Answers

Answer:

7

Step-by-step explanation:

2-8÷-2-3-12÷-6×-2

2 - -4 - 3 - 2 x -2

2 + 4 + -3 - -4

6 + -3 + 4

3 + 4

7 :)

Scientists are drilling a hole in the ocean floor to learn more about the Earth's history Currently, the hole is in
the shape of a cylinder whose volume is approximately 4200 cubic feet and whose height is 4.3 miles. Find
the radius of the hole to the nearest hundredth of a foot. (Hint: Make sure the same units of measurement are
used.)
The radius of the hole is
feet. (Round to the nearest hundredth.)

Answers

Answer:

The radius of the hole is 0.24 feet

Step-by-step explanation:

Firstly, we need to convert the miles to feet

Mathematically;

1 mile = 5,280 feet

4.3 miles is thus;

4.3 * 5,280 = 22,704 feet

Mathematically, the volume of a cylinder is;

V = pi * r^2 * h

here, we want to get r

4200 = 3.142 * r^2 * 22,704

r^2 = 4200/(3.142 * 22,704)

r = 0.24 feet

the product of 5 and a number is at least 20

Answers

this is the best thing i could find for you, good luck with your question,

5x is greater than or equal to -25

The product of 5 and a number is at least –25

we convert the given statement into inequality

product means multiplication

Let x be the unknown number

product of 5 and a number is 5x

5x is at least -25

For word at most we use <=

for word at least we use >=

So the expression becomes 5x <= -25

A Petri dish is growing bacteria. It starts with 3 cells on day 1, 9 cells on day 2, and continues tripling the number of cells every day after that. How many cells of bacteria are there on day 5? 3 5 5 3 15 18

Answers

Answer:

243

Step-by-step explanation:

Given that:

Day 1 = 3

Day 2 = 9

After the 2nd day, number of cells continue to triple ;

Day 3 = 9^3

P(t) = 9 * 3^3

P(t) = 9 * 27

= 243

(05.05) Which inequality matches the graph? (2 points)​

Answers

Answer: Choice C  [tex]-3x+2y \ge 7[/tex]

===================================================

Explanation:

The boundary line is solid, so that means we'll be dealing with "or equal to" as part of the inequality sign. The answer is between choice A and choice C because of this.

Note how the point (0,0) is not in the shaded region. This must mean that plugging x = 0 and y = 0 into the answer will lead to a false statement.

If we plug x = 0 and y = 0 into choice A, then we get...

[tex]3x-2y \le 7\\\\3(0)-2(0) \le 7\\\\0 \le 7\\\\[/tex]

Which is a true statement, implying that (0,0) is in the shaded region. However, we're after a false statement, so we can rule out choice A.

The answer must be choice C

Let's plug (x,y) = (0,0) into choice C

[tex]-3x + 2y \ge 7\\\\-3(0) + 2(0) \ge 7\\\\0 \ge 7\\\\[/tex]

That is false because 0 is not equal to 7, nor is it larger than 7.

This helps confirm that choice C is the answer.

Answer:

C it c because i took the test

Step-by-step explanation:

Summer (starting from rest) runs from the 20 m mark to the 35 m mark with an acceleration of .5 m/s2. What is her final velocity?​

Answers

the answer to your question is .5 x 25 over 20

If Summer (starting from rest) runs from the 20 m mark to the 35 m mark with an acceleration of 5 m/s². then 12.25 m/s is the final velocity.

What is Velocity?

Velocity is the distance covered by an object in unit time.

Given that,

Summer (starting from rest) runs from the 20 m mark to the 35 m mark with an acceleration of 5 m/s²

a=0.5 m/s²

s is distance=35-20=15

We have a formula with velocity, acceleration and distance

Now v²=2as

Here v is velocity=2

a is acceleration=5

s is the distance.=15

v²=2×5×15

The multiplication value of 2×5×15 is 150.

v²=150

Take square root on both sides

v=√150

v=12.25 m/s

Therefore final velocity is 12.25m/s.

To learn more on velocity click:

https://brainly.com/question/18084516

#SPJ2

The four walls and the ceiling of a cubical room need to be painted. If the height of the room is 4 m , and painting costs ₹ 20/m2 20 / m 2 , what is the total cost of painting the room?

Answers

Answer:

₹ 1920

Step-by-step explanation:

Since the room is cubical in nature, we will find the total surface area of the room

Total surface area of the cubical room = 6L²

L is the length of one side of the room

Given

L = 4m

Total surface area of the cubical room = 6(4)²

Total surface area of the cubical room = 6×16

Total surface area of the cubical room = 96m²

If the painting costs ₹ 20/m², this means;

₹ 20 = 1m²

For the total room:

x = 96m²

Divide both expressions

20/x = 1/96

x = 20×96

x = 1920

Hence the total cost of painting the room ₹ 1920

Pls help me with this math question. Explain your thinking pls.

Answers

Answer:

D.

Step-by-step explanation:

Compared to the others, it looks that steepest

Answer:

D by looking at it, it looks steeper

Step-by-step explanation:

PLEASE HELP!!! IS THIS CORRECT???

Answers

Answer:

yes

Step-by-step explanation:

good job, it's correct.

I need help ASAP! picture below is what I need​

Answers

Answer:

Evaluating the piecewise function when X =3, we get f(3) = 7

Step-by-step explanation:

Given the following piecewise function

f(x)= { 2x+1; where x > 0

         -3 when x ≤ 0

Evaluate the function when X = 3

We will evaluate f(x) =2x+1 where x > 0, because x = 3 and 3 <0

We can't use -3, because x ≤ 0, and 3 is not less than 0.

Now, evaluating the function:

[tex]f(x)=2x+1\\Put\:x=3\\f(3)=2(3)+1\\f(3)=6+1\\f(3)=7[/tex]

So, Evaluating the piecewise function when X =3, we get f(3) = 7

help please, i’m having trouble with this

Answers

Answer:

88

Step-by-step explanation:

88 Degrees

Answer:

92

Step-by-step explanation:

Corresding angles

I don’t understand this

Answers

Answer:

3 to 1

Step-by-step explanation:

The scale factor is the ratio of corresponding sides, image to original, that is

OA' : OA

= 27 : 9 ( divide both parts by 9 )

= 3 : 1

what is the solution to the equation below?

Answers

No solution !!!!!!!!!

Solve for x. Round your answer to 2 decimal places.

Answers

Answer:

93.99

Step-by-step explanation:

sin rule is:

sin A ÷ a = sin B ÷ b = sin C ÷ c

A B C are angles

a b c are the lengths opposite to each angle

to find angle opposite to x:

180- (90+57) = 33°

180: sum of angles in a traingle

90: since its a right angle traingle

to find x:

sin 57 ÷ 41 = sin 33 ÷ x

rearrange:

x= (sin 33 x 41) ÷ sin 57

x= 93.99 (2 d.p/2 decimal places)

1/3 divided by 4
2/5 divided by 4
4/7 divided by 4
2/5 divided by 3
5/6 divided by 5
5/8 divided by 10

Answers

1. 1/3 divided by 4 is 0.0833
2. 2/5 divided by 4 is 0.1
3. 4/7 divided by 4 is 0.1428
4. 2/5 divided by 3 is 0.1333
5. 5/6 divided by 5 is 0.1666
6. 5/8 divided by 10 is 0.0625

Answer:

1. 0.0833

2. 0.1

3.  0.1428

4.  0.1333

5. 0.1666

6.  0.0625

CAN YALL PLEASE HELP???

Answers

Answer:

x = 11, arc RB = 150°

Step-by-step explanation:

The secant- secant angle RDB is calculated as half the difference of its intercepted arcs, that is

∠ RDB = [tex]\frac{1}{2}[/tex] ( RB - EC ), that is

5x - 10 = [tex]\frac{1}{2}[/tex] ( 13x + 7 - 60 )

Multiply both sides by 2 to clear the fraction

10x - 20 = 13x - 53 ( subtract 13x from both sides )

- 3x - 20 = - 53 ( add 20 to both sides )

- 3x = - 33 ( divide both sides by - 3 )

x = 11

Thus

arc RB = 13x + 7 = 13(11) + 7 = 143 + 7 = 150°

Find the measure of

Answers

Answer:

119 is the answer

Step-by-step explanation:

use sum of angles on a straight line

Answer:

is the 3 one (119)

Because we all know that (B) is equal to 62 and (AB is 57 and if you add 62 + 57 = 119

Celine flipped a coin 100 times. She
flipped heads 41 times and tails 59 times.
What is the experimental probability that
the next flip will be heads?

Answers

Answer:

1/2

Step-by-step explanation:

What is this problem: It is also a rational function. 6 / x^2 - 9 - 1 / x - 3 = 1 Answers: A) -1+-sqr(73) / 2 B)-4 C)2 D)3 or -4

Answers

Answer:  B)-4

Step-by-step explanation:

The given equation: [tex]\dfrac{6}{x^2-9}-\dfrac{1}{x-3}=1[/tex]

Using identity: [tex]a^2-b^2=(a-b)(a+b)[/tex]

[tex]\dfrac{6}{(x-3)(x+3)}-\dfrac{1}{x-3}=1\\\\\Rightarrow\ \dfrac{6-(x+3)}{(x-3)(x+3)}=1\\\\\Rightarrow\ \dfrac{6-x-3}{(x-3)(x+3)}=1\\\\\Rightarrow\ 3-x=(x-3)(x+3)\\\\\Rightarrow\ (-1)(x-3)=(x-3)(x+3)\\\\\Rightarrow\ -1=x+3\\\\\Rightarrow\ x=-1-3=-4 \ \ \ [x\neq3][/tex]

Hence, the solution is : x=-4

The correct option is B.

Other Questions
PLZ ANSWER urgent need help and questions is at the bottom multiple choice.The paragraphsAnother thing that disturbed Polly was the want of exercise. To dress up and parade certain streets for an hour every day, to stand talking in doorways, or drive out in a fine carriage, was not the sort of exercise she liked, and Fan would take no other. Indeed, she was so shocked, when Polly, one day, proposed a run down the mall, that her friend never dared suggest such a thing again. At home, Polly ran and rode, coasted and skated, jumped rope and raked hay, worked in her garden and rowed her boat; so no wonder she longed for something more lively than a daily promenade with a flock of giddy girls, who tilted along in high-heeled boots, and costumes which made Polly ashamed to be seen with some of them. So she used to slip out alone sometimes, when Fanny was absorbed in novels, company, or millinery, and get fine brisk walks round the park, on the unfashionable side, where the babies took their airings; or she went inside, to watch the boys coasting, and to wish she could coast too, as she did at home . . .One afternoon, just before dinner, she felt so tired of doing nothing, that she slipped out for a run. It had been a dull day; but the sun was visible now, setting brightly below the clouds. It was cold but still and Polly trotted down the smooth, snow-covered mall humming to herself, and trying not to feel homesick. The coasters were at it with all their might, and she watched them, till her longing to join the fun grew irresistible. On the hill, some little girls were playing with their sleds, real little girls, in warm hoods and coats, rubber boots and mittens, and Polly felt drawn toward them in spite of her fear of Fan.questionChoose the sentence that best supports Pollys reasons for keeping her outings a secret from Fan.Answer choices for the above question1.On the hill, some little girls were playing with their sleds, real little girls, in warm hoods and coats, rubber boots and mittens, and Polly felt drawn toward them in spite of her fear of Fan.2.Indeed, she was so shocked, when Polly, one day, proposed a run down the mall, that her friend never dared suggest such a thing again.3.To dress up and parade certain streets for an hour every day, to stand talking in doorways, or drive out in a fine carriage, was not the sort of exercise she liked, and Fan would take no other.4.It was cold but still and Polly trotted down the smooth, snow-covered mall humming to herself, and trying not to feel homesick. 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