What is the weight on Earth of a girl with a mass of 30 Kg? The acceleration due to gravity on Earth is 9.8 m/ s 2.

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Answers

Answer 1

Answer: If, on earth, your mass is 30kg, then your weight is m*g which is mass (30kg) times Earth gravity (9.8m/s^2) = 294 N.

Step-by-step explanation:

Answer 2

The weight of a girl would be 294 N on Earth with a mass of 30 Kg.

What are Arithmetic operations?

Arithmetic operations can also be specified by the addition, subtract, divide, and multiply built-in functions.

+ Addition operation: Adds values on either side of the operator.

For example 4 + 2 = 6

- Subtraction operation: Subtracts the right-hand operand from the left-hand operand.

for example 4 -2 = 2

* Multiplication operation: Multiplies values on either side of the operator

For example 4*2 = 8

The weight on Earth of a girl would be the product of the mass and acceleration due to gravity on Earth

So the required solution would be:

⇒ weight  = mass × acceleration due to gravity on Earth

⇒ weight  = 30 × 9.8

⇒ weight  = 294 N.

Hence, the weight of a girl would be 294 N on Earth with a mass of 30 Kg.

Learn more about Arithmetic operations here:

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Given:

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Answers

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Answers

Answer:

The angles of the triangle are approximately 87.395º, 57.271º and 35.334º.

Step-by-step explanation:

From statement we know all sides of the triangle ([tex]a[/tex], [tex]b[/tex], [tex]c[/tex]), but all angles are unknown ([tex]A[/tex], [tex]B[/tex], [tex]C[/tex]). (Please notice that angles with upper case letters represent the angle opposite to the side with the same letter but in lower case) From Geometry it is given that sum of internal angles of triangles equal 180º, we can obtain the missing information by using Law of Cosine twice and this property mentioned above.

If we know that [tex]a = 19[/tex], [tex]b = 16[/tex] and [tex]c = 11[/tex], then the missing angles are, respectively:

Angle A

[tex]a^{2} = b^{2}+c^{2}-2\cdot b\cdot c \cdot \cos A[/tex] (1)

[tex]A = \cos^{-1}\left(\frac{b^{2}+c^{2}-a^{2}}{2\cdot b\cdot c} \right)[/tex]

[tex]A = \cos^{-1}\left[\frac{16^{2}+11^{2}-19^{2}}{2\cdot (16)\cdot (11)} \right][/tex]

[tex]A \approx 87.395^{\circ}[/tex]

Angle B

[tex]b^{2} = a^{2}+c^{2}-2\cdot a\cdot c \cdot \cos B[/tex] (2)

[tex]B = \cos^{-1}\left(\frac{a^{2}+c^{2}-b^{2}}{2\cdot a\cdot c} \right)[/tex]

[tex]B = \cos^{-1}\left[\frac{19^{2}+11^{2}-16^{2}}{2\cdot (19)\cdot (11)} \right][/tex]

[tex]B\approx 57.271^{\circ}[/tex]

Angle C

[tex]C = 180^{\circ}-A-B[/tex]

[tex]C = 180^{\circ}-87.395^{\circ}-57.271^{\circ}[/tex]

[tex]C = 35.334^{\circ}[/tex]

The angles of the triangle are approximately 87.395º, 57.271º and 35.334º.

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