Answer:
friction
Explanation
Answer:
Friction
Explanation:
What force prevents an object at rest?
Sliding Friction While static friction keeps an object at rest, sliding friction slows down an object that slides. If you push an object across a room, you notice the sliding friction between the bottom of the object and the floor. You have to keep pushing to overcome the force of sliding friction.
An object is at rest. There are several forces acting on the object, but the net force is zero. If all the
forces acting on the object were to suddenly double in size, would the object start moving? Why or why not?
Answer:
no
Explanation:
because the heaver an object the harder it is to move s the force will not be able to move it
true or false
as mass increases the gravitational force decreases
In the diagram below if bulb 2 blew out what would happen to the VOLTAGE? (it’s not decreases that’s why it’s highlighted)
Answer:
apagado, así que lo más destacado es el problema, oh, está bien, esa es la respuesta, cariño.
What is gibbs free energy.
Answer:
It’s a
Explanation:
which chamber approves presidential nomination
Answer: The Senate provides advice and consent on presidential nominations.
A falling object with a weight of 15N is moving downwards towards earth at a steady speed. What is the size of the drag force on this object?
Answer:
15 N :D
Explanation:
The size of the drag force on this object falling at a constant speed is determined as 15 N.
Drag force on the objectThe drag force on the object is determined by calculating the net force on the object;
F(net) = W - D
where;
W is weight of the objectD is the drag force of airma = W - D
at constant speed, acceleration, a = 0
0 = W - D
W = D
15 N = D
Thus, the size of the drag force on this object falling at a constant speed is determined as 15 N.
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Lacie kicks a football from ground level at a velocity of 13.9 m/s and at an angle of 25.0° to the ground. You have determined that the football would travel 15.1 m before landing.
How would this value change if the football was kicked at an angle of 35.0°?Complete all equations without rounding and then round to the nearest tenth at the end.
From edge
Answer:
like 23 or something
Explanation:
help plz
Stop and go traffic means a lot of opportunities for acceleration. This assignment looks at a typical experience of a car in typical rush hour traffic. Calculate the different accelerations from the graph, interpret what your answers mean and show you really understand acceleration.
A car traveled through rush hour traffic in a city. There was a lot of starting and stopping. The graph below shows the motion of the car for a 16 second interval of time.
Explain what is going on between point B and C in terms of velocity and acceleration.
Velocity:
Acceleration:
A 50-n force is applied to a 10-kg chair, but the chair does not change its motion. What could explain this?.
Explanation:
it will not change it's motion because it's force is less than the force applied
the relationship between global warming and greenhouse gases is the _______.
how both affect the ozone layer and affect temperature in a grobal way
A bus slams on its breaks and goes from 30km/hr to 15km/hr in 4 seconds. What is its acceleration?
Answer:
− 2.08
Explanation:
a water skier has a mass of 80 kg and accelerates at 2 m/s2. What is the net force(F) acting on him?
Answer:
160 NExplanation:
The force acting on an object given it's mass and acceleration can be found by using the formula
force = mass × acceleration
From the question
mass = 80 kg
acceleration = 2 m/s²
We have
force = 80 × 2 = 160
We have the final answer as
160 NHope this helps you
What types of energy do you acquire when you eat a bowl of hot vegetable soup?
Answer:
you need kinetic energy because it is the energy that is used when In motion
The type of energy that one acquire when you eat a bowl of hot vegetable soup is chemical energy.
What is chemical energy?Chemical power the bonds of chemical molecules contain energy. Exothermic reactions are those in which chemical energy is released during the reaction, frequently in the form of heat.
Some of the heat energy needed for a reaction to continue can be stored as chemical energy in newly created bonds.
Food particles go through a chemical reaction that releases chemical energy when we eat it. The body then uses this energy to carry out its regular tasks.
As a result, when you eat a cup of vegetable soup, you also consume the chemical energy it contains.
Thus, the answer is chemical energy.
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How to find angular velocity of an object traveling at a constant speed.
I only know the formula which is ω = 2πf
What would a force diagram for something WHILE it is being thrown DOWNWARDS look like?
Ty
Answer:
it look the same just to tell you
what kind of frog species is this
Answer: i think its a bullfrog forgive me if im wrong i dont exactly know
Explanation:
Answer:
that is an African bullfrog
an electric charge (Q=-230nc) located at origin generate an electric field at point P located at (2 , 6)m(meter) find the electric filed at P *
How to find direction of magnetic field.
unlock your third eye and youll be able to see it
A man is sitting on a chair with wheels. He grabs a 2.1 kg book from the desk and throws
the book at a speed of 7.2 m/s. His chair moves backward. The man has a mass of 70 kg and
the chair has a mass of 9.2 kg. What is the speed of the man and the chair after the book is
thrown?
The speed of the man and the chair after the book is thrown is 0.2 m/s.
The given parameters:
mass of the book, m₁ = 2.1 kgspeed of the book, u₁ = 7.2 m/smass of the man, M = 70 kgmass of the book, m = 9.2 kgThe total mass of the man and the book is calculated as follows;
m₂ = 70 kg + 9.2 kg
m₂ = 79.2 kg
The speed of the man and the chair after the book is thrown is determined by applying the principle of conservation of linear momentum;
[tex]m_1 u_1 = m_2u_2\\\\u_2 = \frac{m_1u_1}{m_2} \\\\u_2 = \frac{2.1 \times 7.2}{79.2} \\\\u_2 = 0.2 \ m/s[/tex]
Thus, the speed of the man and the chair after the book is thrown is 0.2 m/s.
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A force of 6.0 N acts on a 4.0 Kg object for 10.0s. What is the object's change in momentum?
Answer:
60 Ns
Explanation:
change in momentum = Fxt
6*10
60 Ns
A force of 6.0 N acts on a 4.0 Kg object for 10.0 s. The object's change in momentum is 60 kg-m/sec.
What is force?A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.
change in momentum = force . time
change in momentum = 6 . 10 = 60
A force of 6.0 N acts on a 4.0 Kg object for 10.0 s. The object's change in momentum is 60 kg-m/sec.
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what third force must be added to the two forces 30 Newton at 30 degree and 80 Newton at 135 degree the resolution for equal to zero
Answer:
Resolve the vectors:
F1 = 30 cos 30 i + 30 sin 30 j = 26 i + 15 j
F2 = 80 cos 135 i + 80 sin 135 j = -56.6 i + 56,6 j
F1 + F2 = (26 - 56.6) i + (15 + 56.6) j = -30.6 i + 71.6 j
The offsetting force would be
F3 = 30.6 i - 71.6 j
The magnitude of this vector is (30.6^2 + 71.6^2)^1/2 = 77.9
cos theta 3 = 30.6 / 77.9 = 66.9 deg
Check:
77.9 * sin 66.9 = 71.6 agreeing in magnitude with F3
Now we need the quadrant of the offsetting vector
sin theta 3 = - cos theta 3 = +
This occurs in the fourth quadrant and theta 3 = 360 - 66.9 = 293.1 deg
You discover a planet orbiting a distant star that has about the same mass as the sun, with an orbital period of 53 days. What is the planet’s orbital distance?.
Answer:
G M1 m1 / R1^2 = G M2 m2 / R2^2 gravitational equation
We can try Kepler's harmonic law
P2^2 = K R2^3
P1^2 = K R1^3 for earth
(P2 / P1)^2 = (R2 / R1)^3 dividing equations
R2^3 = (P2 / P1)^2 * R1^3
R2^3 = (53 / 365)^2 * R1^3
R2^3 = .145 R1^3
R2 = .526 R1
If one uses 93E6 miles as distance of sun from earth then
R2 = 49E6 miles
Please help me on this 1 assignment im giving 25 points GOOD LUCK!
Answer:
Explanation:
im sorry if this doesn't help but i think its A
a race car traveling at 44m/s slows at a constant rate to a velocity of 22m/s over 11 seconds , how far does it move during this time
find distance and acceleration
PLEASEEEE HELP I HAVE A PHYSICS EXAM TOMORROW AND IM STRUGGLING
Answer:
add 44m/s and 22m/s then multiply it by 11
Explanation:
A race car traveling at 44m/s slows at a constant rate to a velocity of 22m/s over 11 seconds, Acceleration is -2 m/s² (deceleration), and distance is 242 meters.
To solve this problem, it is given:
Initial velocity ([tex]\(v_i\)[/tex] ) = 44 m/s
Final velocity ([tex]\(v_f[/tex] ) = 22 m/s
Time ([tex]\(t\)[/tex] ) = 11 s
We have two tasks: finding the acceleration (a) and then using it to calculate the distance (d).
1. Calculate Acceleration (a):
[tex]\[a = \frac{v_f - v_i}{t} \\\\= \frac{22 \, \text{m/s} - 44 \, \text{m/s}}{11 \, \text{s}} \\\\= -2 \, \text{m/s}^2\][/tex]
The negative sign indicates deceleration (slowing down).
2. Calculate Distance (d):
Using the kinematic equation:
[tex]\[d = v_i \cdot t + \frac{1}{2} \cdot a \cdot t^2\][/tex]
Plugging in the values:
[tex]\[d = (44 \, \text{m/s}) \cdot (11 \, \text{s}) + \frac{1}{2} \cdot (-2 \, \text{m/s}^2) \cdot (11 \, \text{s})^2\][/tex]
Calculating the first part:
[tex]\[d = 484 \, \text{m} - 121 \, \text{m} \\\\= 363 \, \text{m}\][/tex]
Calculating the second part:
[tex]\[d = 363 \, \text{m} + \frac{1}{2} \cdot (-2 \, \text{m/s}^2) \cdot (121 \, \text{s}^2) \\\\= 363 \, \text{m} - 121 \, \text{m} \\\\= 242 \, \text{m}\][/tex]
The total distance the race car moves during this time is 242 meters.
Thus, acceleration is -2 m/s² (deceleration), and distance is 242 meters.
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How are earthquakes at continental plate boundaries different from earthquakes at mid-ocean ridges?
Differences between earthquakes at continental plate boundaries and earthquakes at mid-ocean ridges discussed in the answer.
What is earthquakes at continental plate boundaries and earthquakes at mid-ocean ridges?When plates travel in the same direction and collide, this happens. The thinner, denser, and more flexible oceanic plate dips beneath the thicker, more rigid continental plate when a continental plate meets an oceanic plate. It's known as subduction.
Deep ocean trenches, like the one that runs down South America's west coast, are created by subduction. The continent's undercut rocks start to melt. On occasion, a chain of volcanoes forms as the molten rock rises to the surface and passes through the continent. Nearly 80% of earthquakes happen along convergent borders, when plates are being forced together.
Shallow earthquakes, often less than 30 km deep, occur in small bands adjacent to plate borders along mid-ocean ridges and transform edges. There are earthquakes in subduction zones at various depths, some of which are more than 700 km deep. Because they occur everywhere throughout the subducting slab that stretches beneath the opposing plate, earthquake bands are wider along subduction zones. Wide areas of distributed earthquakes may be associated with collision zones between continents, such as those between the Eurasian plate and the plates to the south of the African, Arabian, and Indian tectonic arcs.
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What is the half-life for the radioactive decay of particle that
starts with 400.00 g and ends up with 12.50 g if the total time
was 50 minutes for the decay to occur?
Answer:
ytyug
Explanation:
1
A pencil weighing 1N is sitting on a desk.
Write down all the forces on the desk.
a.
b.
Draw a free body diagram of the desk.
c.
Add up the forces in the x-direction (horizontal) and the y-direction (vertical)
The force diagram on the desk consists of normal reaction and weight of the pencil.
The net force on the desk in vertical direction is 1 N.
The net force on the desk in horizontal direction is 0.
The given parameters;
weight of the pencil, W = 1 NThe force diagram of the desk is sketched as follows;
↑ N
⊕
↓ W
Where;
N is the normal reaction on the deskW is the weight of the ballThe net force on the desk in vertical direction = 1 N
The net force on the desk in horizontal direction = 0
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1. An object would have a different mass on Earth as it would have on the moon.
a. True
b. False
Answer:
a.true
Explanation:
because the gravitational strength of earth and moon is different
Two forces are applied to a 50-kg box. One is 60.0
N to the south and the other is 80.0 N to the east.
These are the only forces acting on the box. The
magnitude of the acceleration of the box is:
1. 20m/s^2
2. 1.5 m/s^2
3. 5.2 m/s^2
4. 0.50m/s^2
5. 10m/s^2
The magnitude of the acceleration of the box is 2 m/s².
The given parameters;
mass of the box, m = 50 kgfirst force, F₁ = 60 N southsecond force, F₂ = 80 eastThe resultant of the two given forces is calculated as follows;
[tex]F= \sqrt{F_1 ^2 + F_2 ^2} \\\\F = \sqrt{60^2 + 80^2} \\\\F = 100 \ N[/tex]
The magnitude of the acceleration of the box is calculated as follows;
[tex]F = ma\\\\a = \frac{F}{m} \\\\a = \frac{100}{50} \\\\a = 2 \ m/s^2[/tex]
Thus, the magnitude of the acceleration of the box is 2 m/s².
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PLEASE ANSWER NEED HELP!!!!!!!! PLEASE THE CORRECT ANSWER!!!!!!
Zhiyu wants to start an exercise program. He knows that he should talk to his doctor, but he cannot get an appointment for several weeks. He does not have any health conditions. What is the BEST advice for Zhiyu?
A.
All exercise needs to be medically supervised, so he must wait.
B.
There is always a risk of injury, so he needs professional advice before he starts.
C.
He can start slowly with low impact activity like walking or light weightlifting.
D.
He should do whatever he feels like; his body will let him know if he overdoes it.
PLEASE NO LINKS OR I WILL REPORT YOU
Answer:
c
Explanation: