What percent is a gram of a kilogram

Answer:

2 5 and 6

Step-by-step explanation:

Any 2 sides have to add to more than the 3rd side.

Answer:

3

Step-by-step explanation:

Answer:

Approximately [tex]68.5\; \rm mm[/tex].

Step-by-step explanation:

Convert the angle of this sector to radians:

[tex]\begin{aligned}\theta &= 127^{\circ} \\ &= 127^{\circ} \times \frac{2\pi}{360^{\circ}} \\ &\approx 2.22\end{aligned}[/tex].

The formula [tex]s = r\, \theta[/tex] relates the arc length [tex]s[/tex] of a sector of angle [tex]\theta[/tex] (in radians) to the radius [tex]r[/tex] of this sector.

In this question, it is given that the arc length of this sector is [tex]s = 36\; \rm mm[/tex]. It was found that [tex]\theta = 2.22[/tex] radians. Rearrange the equation [tex]s = r\, \theta[/tex] to find the radius [tex]r[/tex] of this sector:

[tex]\begin{aligned} r&= \frac{s}{\theta} \\ &\approx \frac{36\; \rm mm}{2.22} \\ &\approx 16.2\; \rm mm\end{aligned}[/tex].

The perimeter of this sector would be:

[tex]\begin{aligned}& 2\, r + s \\ =\; & 2 \times 16.2\; {\rm mm} + 36\; {\rm mm} \\ =\; & 68.5\; \rm mm\end{aligned}[/tex].

Answer:

d

Step-by-step explanation:

I got it right on my quiz

The equation that represents the line that is perpendicular is

3y + 5x = -42

The standard equation of a line in point-slope form is expressed as:

[tex]y-y_1=m(x-x_1)[/tex]

Substitute the point (-12, 6) and the slope m = -5/3 into the equation above to have:

[tex]y-6=-5/3(x-(-12))\\3(y-6)=-5(x+12)\\3y-18=-5x-60\\3y = -5x - 60 + 18\\3y + 5x = -42\\[/tex]

Hence the equation that represents the line that is perpendicular is

3y + 5x = -42

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Answer:

[tex]18 = 306 \\ x = 119 \\ \\ 306x = 2142 \\ x = \frac{2142 }{306 } \\ x = 7[/tex]

Answer:

14.69

Step-by-step explanation:

22.6% = 0.226

65 × 0.226 = 14.69

Answer:

y=3d+15

y intercept is 15

slope is 3

Step-by-step explanation:

to graph start at 15 on the y axis. then go up 3 points and over one point. keep doing this until you have a straight line.

The equation to represent the relationship of the weights shown on the scale s [tex]22 + x = 34[/tex]

The weights are given as:

[tex]Small\ Square = 1[/tex]

[tex]Larger\ Square = 10[/tex]

The total weight on one side, where there are 4 small squares and 3 large squares is:

[tex]Total =4\times Small\ Square + 3 \times Larger\ Square[/tex]

[tex]Total =4\times 1 + 3 \times 10[/tex]

[tex]Total =34[/tex]

The total weight on the other side, where there are 2 small squares, 2 large squares and 1 triangle is:

[tex]Total =2\times Small\ Square + 2 \times Larger\ Square + 1\times triangle[/tex]

[tex]Total =2\times 1+ 2 \times 10+ 1\times triangle[/tex]

[tex]Total =2+ 20+ 1\times triangle[/tex]

[tex]Total =22+ 1\times triangle[/tex]

[tex]Total =22+ triangle[/tex]

The weight of the triangle is x.

So, we have:

[tex]Total =22+ x[/tex]

The weights on both sides are equal, because the scale is balanced.

So, we have:

[tex]22 + x = 34[/tex]

Hence, the equation is [tex]22 + x = 34[/tex]

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Answer:

3c =20-2

3c = 18

c = 18÷3

=6

Answer:

Here is Your answer

Step-by-step explanation:

Hope u Like it

C = 2/17

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Answer:

(-1,-6.5)

Step-by-step explanation:

midpoint formula: (x_m, y_m) = (x1+x2)/2),(y1+y2)/2)

(2-4)/2=-1, -9-4=-13/2=-6.5

=(-1,-6.5)

Answer:

7x

Step-by-step explanation:

4x ( linear function) + 3x ( linear function) = 7x

[tex]\huge\boxed{Hello!:)}[/tex]

Combine like terms:

4x+3x=7x

Remember, we can add terms with the same variable together, but we can't add terms with different variables.

[tex]\huge\boxed{Hence,\:the\:answer\:is\:7x.}[/tex]

[tex]\huge\underline{Hope\:it\:helps!}[/tex]

[tex]\boxed{DreamyGal\:here\:to\:help!:)}[/tex]

Answer:

1. 15, 2. -23, 3. 220, 4. 4x-5

Step-by-step explanation:

f(x) = 4x + 3     g(x) = x - 2

1. f(g(5)): Put 5 in as x in g(x)  5 - 2 = 3.  Now put the 3 as x into f(x) and solve. 4(3) + 3 = 15

2. g(f(-6))  4(-6) + 3 = -21. -21 - 2 = -23

3. (f(f(7)) 4(7) + 3 = 31, 31(7) + 3 = 220

4. g(f(x))  4(x-2) + 3  =  4x - 8 + 3  = 4x - 5

When a function is substituted into another function it is known as a composite function.

Given the following functions:

f(x) = 4x  + 3

g(x) = x - 2

Determine [tex]f(g(x)) \ and \ g(f(x))[/tex]

[tex]f(g(x)) = f(x-2)\\ f(x-2) = 4(x-2)+3\\ f(x-2)=4x-8+3\\ f(x-2) = 4x - 5\\ f(g(x)) = 4x - 4 [/tex]

1) Determine the value of [tex]f(g(5))[/tex]

[tex]f(g(5))=4(5) - 4\\ f(g(5))=20-4\\ f(g(5))=16[/tex]

2) For the function [tex]g(f(-6))[/tex]

[tex]g(f(-6))=4(-6) + 1\\ g(f(-6))=-24+1\\ g(f(-6))=-23[/tex]

3) For the value [tex]f(f(7)), [/tex]we need to determine [tex] f(f(x))[/tex]

[tex]f(f(x)) = f(4x+3)\\ f(f(x))= 4(4x+3)+3\\ f(f(x))=16x+12+3\\ f(f(x))=16x+15\\ f(f(7)) = 16(7) + 15\\ f(f(7)) = 127[/tex]

4) For the function [tex]g(f(x));[/tex]

[tex]g(f(x))=(4x+3)-2\\ g(f(x))=4x+3-2\\ g(f(x))=4x+1[/tex]

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The simplified form of the given expression is [tex]5\sqrt{2}[/tex].

Given expression,

[tex]5\sqrt{8} - \sqrt{18} - 2 \sqrt{2}[/tex].

We have to simplify the above expression.

So, [tex]5\sqrt{8} - \sqrt{18} - 2 \sqrt{2}\\[/tex]

First solve for the square root,

[tex]5\sqrt{2\times2\times2} -\sqrt{3\times3\times2} -2\sqrt{2} \\\\10\sqrt{2} -3\sqrt{2}-2\sqrt{2} \\[/tex]

[tex]7\sqrt{2} -2\sqrt{2}[/tex]

[tex]5\sqrt{2}[/tex]

Hence the simplified form of the given expression is [tex]5\sqrt{2}[/tex].

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Answer:

145*23=3335$

by multiplying cost by sum of desk

The answer is B) y = 4x

Explanation: If you substitute each number in the x column for the variable x, and then multiple that number by 4, you'll get the number in the y column to the right.

For example:

y = 4x --> y = 4 (2) --> y = 8

I hope this helped. :)

Answer:

Use the coefficient of x as the slope and constant as the y-intercept

Step-by-step explanation:

Start by going to your graph and plotting your y-intercept. For example, if the y- intercept is -2, plot the point (0, -2). Then from there, you need to plot the slope (let's pretend that the slope is 2/3). From the intercept, you will go up two and right one. Then starting from that point, continue using the rise over run to plot your points and then draw your line.

Answer:

3:2 i believe

Step-by-step explanation:

9:6

divide by 3

3:2

Answer:

6 1/2

Step-by-step explanation:

21 1/8 divided by 3 1/4

Put into improper fractions

169 / 8 divided by 13 / 4

Multiply by the reciprocal

169 / 8 x 4 / 13

= 6 1/2

Answer:

the answer is 12m

Step-by-step explanation:

u know the side c and side B.

C=15m but u have to square it which is 225

B=9m but u have to square it which is 81. then subtract 82 from 225.which will give u 144 which is a perfect square route of 12

Answer:

< 18, - 29 >

Step-by-step explanation:

a = 5b - 6c

   = 5 < 6, 5 > - 6 < 2, 9 > { multiply each element by the scalar ]            

   = < 30, 25 > - < 12, 54 > [ subtract corresponding elements ]

   = < 30 - 12, 25 - 54 >

    = < 18, - 29 >

Answer:

a=(18,-29)

Step-by-step explanation:

You plug (6,5) in for 5b and you plug (2,9) in for -6c so now you get a=5(6,5)-6(2,9) then you cross multiply the 5 and the -6 therefore you get a=(30,25)+(-12,-54) then you add them together getting the answer a=(18,-29).

Answer:answer d

Step-by-step explanation:

i just did the test

7x-35<2x-10 distribut it

7x-2x<-10+35 collect like them

5x<25 divide both side by 5

x<5

Answer:x<-3

Step-by-step explanation:

Answer:

x < -3

Step-by-step explanation:

[tex]-7x-4>17\\\\-7x-4+4>17+4\\\\-7x>21\\\\\frac{-7x}{-7}>\frac{21}{-7}\\\\x<-3[/tex]

Answer:

Given (-4,4),(0,2),(2,1),(4,-1)

Only any two points are on the same line.

Step-by-step explanation:

You could do a lot of calculations, write the equations for the points in the line. These would be very good. But, you could also just look at the points on a graph. See image.

Repost if there are different points in the original problem.

Answer:

n-11

Step-by-step explanation:

Answer:

ur mom

Step-by-step explanation:

lol

Answer:

Answer B

Step-by-step explanation:

Because  (IQR) by 1.5 (a constant used to discern outliers). Add 1.5 x (IQR) to the third quartile. Any number greater than this is a suspected outlier. Subtract 1.5 x (IQR) from the first quartile.