What will the final temperature of the a block of brass with a mass of 30.6 g is at 87.4°C
after it's added to 62.3 g of water at 28.3°C. The specific heat of aluminum is 0.380
J/gºC.

Answers

Answer 1

The final temperature of the block of brass with a mass of 30.6 g at 87.4°C is 30.82°C.

SPECIFIC HEAT CAPACITY:

The amount of heat absorbed or released by a substance can be calculated using the following formula:

Q = m × c × ∆T

Q(water) = - Q(metal)

(m × c × ∆T) water = - (m × c × ∆T) metal

According to this question;

METAL:

m = 30.6gc = 0.380 J/g°C∆T = T - 87.4°C

WATER:

m = 62.3gc = 4.184J/g°C∆T = T - 28.3°C

62.3 × 4.184 × (T - 28.3) = - {30.6 × 0.380 × (T - 87.4)}

260.7T - 7376.8 = - {11.63T - 1016.3}

260.7T - 7376.8 = -11.63T + 1016.3

260.7T + 11.63T = 1016.3 + 7376.8

272.33T = 8393.1

T = 8393.1 ÷ 272.33

T = 30.82°C

Therefore, the final temperature of the block of brass with a mass of 30.6 g at 87.4°C is 30.82°C.

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