When a cyclist is decelerating uphill the forces on him are balanced or unbalanced ​

Answers

Answer 1

Answer:

Unbalanced

Explanation:

A cyclist decelerating uphill has unbalanced forces acting on him. An unbalanced force acting on a body has a net force which is greater than zero. When a body is accelerating or decelerating, the forces are not balanced.

A body with a net force of zero has balanced forces acting on it. Such body is moving with constant acceleration. According to newton's first law of motion" a body will remain in state of rest or of uniform motion unless an external force acts on it". The external force causes acceleration to change drastically.

Related Questions

Please what is the work done by a man who is pulling a box of 45kg of mass by means of rope which makes angle of 45 degrees ?

Answers

Answer:

No work is done since no distance is given

Explanation:

Since no distance is given, the force is not doing any work

No work is done by the man since we do not know the distance or displacement.

Work is only said to be done when the force applied on an object moves it through a particular distance.

Work done  = Force x distance.

Since no distance is given in this problem, we can as well assume that the force applied is doing no work on the object.

a 30-kg child sitting in a chair applies a force of approximately 300 N downward. on the chair approximately how much force does the chair apply upward to the child

A. 10N
B. 30N
C. 300N
D .600N​

Answers

Answer:

moment's equilibrium required

moment = force x perpendicular distance from force's line of action (from pivot)

counter clockwise = clockwise moments

=> 15g(1.5) = F(0.3)

=> F = 15*9.81*5 = 735.75 ~= 736 N

Explanation:

It’s either A or B bro so I would probs wait till someone else answers it don’t guess

in which diagram 1 or 2 would the person be experiencing winter? explain​

Answers

Answer: Diagram 2

In diagram 1, the person in the northern hemisphere gets more sunlight compared to someone in the southern hemisphere. So diagram 1 has summertime in the northern hemisphere.

Conversely, diagram 2 has the southern hemisphere get more sunlight, so the northern hemisphere is experiencing winter.

Find the work done by a man who is pulling a box of 45kg of mass by means of rope which makes angle of 45 degrees.

Answers

Answer:

0

Explanation:

Since no distance is given, the force is not doing any work

No work is done by the man since we do not know the distance or displacement.

Work is only said to be done when the force applied on an object moves it through a particular distance.

 Work done  = Force x distance.

Since no distance is given in this problem, we can as well assume that the force applied is doing no work on the object.

A body moving in simple harmonic motion has an amplitude of 10cm and a frequency of 100Hz. Find i.mthe period of oscillation, ii. the acceleration at the maximum displacement, iii. the velocity at the centre of motion​

Answers

Explanation:

= 5 cm = 0.05 m

T = 0.2 s

ω=2π/T=2π/0.2=10πrad/s

When displacement is y, then acceleration, a=−ω2y

Velocity, V=ωr2−y2

Case (a)    When y=5cm=0.05m

a=−(10π)2×0.05=−5π2m/s2

V=10π×(0.05)2−(0.05)2=0

Case (b)    When y=3cm=0.03m

a=−(10π)2×0.03=−3π2m/s2

V=10π×(0.05)2−(0.03)2=10π×0.04=0.4π m/s

Case (c)    When y=0

a=−(10π)2×0=0

V=10π×(0.05)2−02=

hope it helps. pls follow and mark as brainliest

Se necesita subir una carga de 500 kg (4900 N) a una altura de 1.5 m deslizándola sobre una rampa inclinada. ¿Qué longitud debe tener la rampa si sólo se puede aplicar una fuerza de 1633.33 N?

Answers

Answer:

4.22 m

Explanation:

Una rampa es una máquina que se utiliza para levantar un objeto con una fuerza menor a la que realmente necesitarías. Cuanto mayor sea la longitud de la rampa, menor será la magnitud de la fuerza necesaria para levantar el objeto.

Dado que:

altura de la rampa = 1.5 m, carga = 4900 N, fuerza aplicada = 1633.33 N.

La fórmula de la rampa se da como:

fuerza aplicada * longitud de la rampa = peso de la carga * altura de la rampa

1633.33 * longitud de la rampa = 4900 * 1.5

longitud de la rampa = 4900 * 1.5 / 1633.33

longitud de la rampa = 4.22 m

A vector
of magnitude 5 units and another vector ū of magnitude 3 units point in directions
differing by 60°. Find out (a) the scalar product of the two vectors and (b) the vector product of the two vectors​

Answers

Answer:

7.5 units

13 units

Explanation:

[tex]|v|=5\ \text{units}[/tex]

[tex]|u|=3\ \text{units}[/tex]

[tex]\theta[/tex] = Angle between the vectors = [tex]60^{\circ}[/tex]

Scalar product is given by

[tex]u\cdot v=|u||v|\cos\theta\\ =3\cdot 5\cdot \cos60^{\circ}\\ =7.5\ \text{units}[/tex]

The scalar product of the vectors is 7.5 units.

Vector product is given by

[tex]u\times v=|u||v|\sin\theta\\ =3\times 5\sin60^{\circ}\\ =13\ \text{units}[/tex]

The vector product of the vectors is 13 units.

Derive Isothermal process through ideal gas.( derive it numerically)​

Answers

Explanation:

Hope it helps..........

When fireworks explode, sound and light are produced. These are examples of(1 point)

macroscopic inputs.

macroscopic outputs.

microscopic inputs.

microscopic outputs.

Answers

Answer: macroscopic outputs

Explanation:

When fireworks explode, sound and light are produced. These are examples of macroscopic outputs. Because, explosion from fireworks is an exothermic process which releases massive heat energy to the surroundings.

What is exothermic reaction?

Exothermic reaction are those which evolve heat energy to the surroundings.  The change in enthalpy of the reaction is negative here. Whereas, in an endothermic reaction energy is absorbed by the reactants.

Exothermic reactions sometimes results in massive explosion. The heat energy released to the surroundings from the fire works is macroscopic level.

The small scale process or quantity that cannot be measured using normal scales are called microscopic units. Therefore, the sound, light, and heat from the explosion all are macroscopic outputs.

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Can anyone help me with these questions? TIA!
(Don’t actually answer please! :) )

Answers

Hey There!_____________________________________Question 7:

 [tex]\huge\text{Graphs:}[/tex]

The graph of  

The I-V for Ohmic Metal wire conductor at constant temperature  always shows a straight line between the Current(I) plotted at Y axis and Voltage(V) plotted at X axis. Picture 1

The I-V graph for Diode shows that first the current is zero but as we increase the potential difference(voltage), it results in the increase in the current. Picture 2

_____________________________________ Question 8:

[tex]\Large\textbf{Diode:}[/tex]  

A diode is a device that allows current to flow in only one direction.

[tex]\Large\textbf{Forward and Reverse Biasing:}[/tex]  

Forward Bias, When a diode is forward bias (a voltage in the "forward" direction) then the P-side of the diode is attached to the positive terminal and N-side is fixed to the negative side of the battery which is connected, current flows freely through the device. The forward bias decreases the thickness of potential barrier(The potential barrier barrier in which the charge requires additional force for crossing the region)

Reverse Bias, When a diode is Reverse bias(a voltage in the "backward direction) then the P-side of the diode is connected to the negative terminal and N-side is connected to the positive terminal of the battery which is connected. The reverse bias increases the thickness of the potential barrier resulting in the flow of no current.

 [tex]\Large\textbf{Answer to the Question "Resistance"}[/tex]

The Forward bias decreases the resistance of the diode whereas the reversed bias increases the resistance of the diode. As in forward biasing the current is easily flowing through the circuit whereas reverse bias does not allow the current to flow through it.

_____________________________________ Best Regards, 'Borz'

If a car traveled 100 km in 2 hr, what was its average speed in km/hr?

average speed =
d =
t =

Answers

Answer:

Average speed will be 50km/hr

Explanation:

Distance/Time

100/2

50kmph

plz mark as brainliest

Answer:

50km/hr

Explanation:

avgspeed=Δdistance/Δtime

Δd=100km

Δt=2hr

=100km/2hr

=50km/hr

Helium ballon containing 5m3 of Gad at a pressure of 30pka is released. If the temperature is constant calculate the volume the balloon would have when the pressure inside the ballon has fallen to 5kpa answer in metres cubed

Answers

Answer:

30m³

Explanation:

Calculation for the volume the balloon would have

First step is to calculate the Constant

Constant=30pka*5m³

Constant=150m³

Now let calculate the Volume using this formula

Balloon Volume=Constant/ Pressure

Let plug in the formula

Balloon Volume=150m³/5kpa

Balloon Volume=30m³

Therefore the volume that the balloon would have when the pressure inside the ballon has fallen to 5kpa is 30m³

a train has an initial velocity of 44m/s and an accelaration of _4m/s calculate its velocity​

Answers

Complete question:

A train has an initial velocity of 44m/s and an acceleration of -4m/s². calculate its velocity​ after 10s ?

Answer:

the final velocity of the train is 4 m/s.

Explanation:

Given;

initial velocity of the train, u = 44 m/s

acceleration of the train, a = -4m/s² (the negative sign shows that the train is decelerating)

time of motion, t = 10 s

let the final velocity of the train = v

The final velocity of the train is calculated using the following kinematic equation;

v = u + at

v = 44 + (-4 x 10)

v = 44 - 40

v = 4 m/s

Therefore, the final velocity of the train is 4 m/s.

Two copper spheres are currently 0.5 meters apart. One sphere has a charge of
+3.4x10-4 C and the other has a charge of -5.6*10-4 C. What is the force between
the charged spheres? (k=8.89*10' Nm²/C2)
0 -6839.17 N
0 1200 N
0 5497.45 N
6839.17 N

Answers

Answer:

6839.17 N

Explanation:

From the question given above, the following information were obtained:

Distance apart (r) = 0.5 m

Charge 1 (q₁) = +3.4×10¯⁴ C

Charge 2 (q₂) = -5.6×10¯⁴ C

Electrical constant (K) = 8.98×10⁹ Nm²/C²

Force (F) =.?

F = Kq₁q₂ / r²

F = 8.98×10⁹ × 3.4×10¯⁴ × 5.6×10¯⁴ / 0.5²

F = 1709.792 / 0.25

F = 6839.17 N

Thus, the force of attraction between the two charged spheres is 6839.17 N

HELPPPPPPP !!!!!! PLS A 0.050 kg Truck moving right at 0.20 m/s collides with a toy race car weighing 0.015 kg initially at rest on a frictionless track. the truck keeps moving right at 0.15 m/s after Collision what is the final speed of the race car?

Answers

Answer:

[tex]v_f=0.15\:\mathrm{m/s}[/tex]

Explanation:

From the Law of Conservation of Momentum, we can write the following equation:

[tex]m_1v_1+m_2v_2=m_fv_f[/tex]

Because the toy car was initially at rest, [tex]m_2v_2=0[/tex].

Therefore, we can plug in given values and solve for [tex]v_f[/tex]:

[tex]m_1v_1=m_fv_f,\\0.050\cdot 0.20 = (0.050+0.015)v_f,\\v_f=\fbox{$0.15\:\mathrm{m/s}$}[/tex] (two significant figures).

The following number - 0.050437 - written to TWO significant figures would be

Answers

Answer:

0.050000

Explanation:

your welcome :)

HELLLPPPPPPPPPPPPPPPPPP

Answers

What’s wrong? R u ok

Answer:

If you going to ask a question ask it accurately.

Explanation:

Positive feedback caused his pancreas to stop secreting insulin. Negative feedback caused his pancreas to stop secreting insulin. Negative feedback caused his pancreas to produce more insulin. Positive feedback caused his pancreas to produce more insulin.

Answers

Answer:

Negative feedback caused his pancreas to produce more insulin.

Explanation:

Positive feedback is a feedback that causes an increase due to change, that is it results in more product while negative feedback is a feedback that causes a decrease due to change, that is it result in lesser product.

Blood sugar control in the body is a negative feedback, because as the blood sugar increases, the nerves sense a change which causes the pancreas to secrete insulin until homeostasis and then the secretion stops.

What word does this define..

The distance traveled per unit of time​

Answers

Answer:..........................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................Volosity???????

Explanation: THINK THATS IT PROBABLY MISPELLED IT SORRY IN ADVANCE IF WRONG

Answer:

Speed

Explanation:

The distance traveled by a body in one unit of time is called its speed. If a body covers distance s in time t then it's speed is given by s / t. It is a scalar quantity and it's SI unit's are m / s. velocity. Distance traveled by a body in a particular direction per unit time is called its velocity.

. Which Of The Following Will Produce Diffuse Reflection Of Light?
[A] Plane mirror and piece of paper
[B] Piece of paper and still water in lake
[C] Plane mirror and leather bag
[D] Piece of paper and leather bag​

Answers

Answer:

A. Plane mirror and piece of paper

Explanation:

Diffuse reflection is the reflection of light or other waves or particles from a surface such that a ray incident on the surface is scattered at many angles rather than at just one angle as in the case of specular reflection. An ideal diffuse reflecting surface is said to exhibit Lambertian reflection, meaning that there is equal luminance when viewed from all directions lying in the half-space adjacent to the surface.

please urgent please help

Two trucks with equal mass are attracted to each other with a gravitational force of 6.7 x 10^-4 N. The trucks are separated by a distance of 3.0 m. What is the mass of one of the trucks?

Answers

Answer:

9508.1kg

Explanation:

Given parameters:

Gravitational force  = 6.7 x 10⁻⁴N

Distance of separation  = 3m

Unknown:

Mass of one of the truck  = ?

Solution:

Let the mass of one of the truck be  = m

According to the Newton's law of universal gravitation:

   Fg  = [tex]\frac{G m1 m2}{d^{2} }[/tex]  

 G is the universal gravitation constant  = 6.67 x 10⁻¹¹

  m1 and m2 are the masses of the two bodies, here m1  = m2  = m

  d is the distance of separation between them

 6.7 x 10⁻⁴   = [tex]\frac{6.67 x 10^{-11} x m^{2} }{3^{2} }[/tex]  

          6.67 x 10⁻¹¹m²   = 9 x   6.7 x 10⁻⁴  

                          m   = 9508.1kg

The mass of one of the trucks is 9510 kg.

The problem above can be solved using the mathematical expression of newton's law of universal gravitation

Using Newton's law of universal gravitation,

F = Gm²/r²................... Equation 1

Where F = Gravitational force on the truck, m = mass of each truck, r = distance between the trucks, G = universal constant

make m the subject of the equation

m = √(Fr²/G)................ Equation 2

From the question,

Given: F = 6.7×10⁻⁴ N, r = 3.0 m.

Constant: G = 6.67×10⁻¹¹ Nm²/kg²

Substitute these values into equation 2

m = √[(6.7×10⁻⁴×3²)/(6.67×10⁻¹¹)]

m = √(9.04×10⁷)

m = 9.51×10³ kg.

m = 9510 kg

Hence, The mass of one of the trucks is 9510 kg

Learn more about Newtons law of universal gravitation here: https://brainly.com/question/9373839

A construction worker pushes a wheelbarrow with a total mass of 50.0 kg. What is the acceleration of the wheelbarrow if the net force on it is 75N? For physical science

Answers

Answer:

1.5m/s²

Explanation:

Given parameters:

Mass of the wheelbarrow = 50kg

Net force applied  = 75N

Unknown:

Acceleration of the barrow = ?

Solution:

From Newton's second law of motion, we know that:

       Force  = mass x acceleration

 Now insert the parameters and find the acceleration

       75  = 50 x acceleration

      Acceleration  = 1.5m/s²

if I accelerated at a rate of 20 mi/hr/s how fast would I be going after 5 seconds?

Answers

Answer: 100

Explanation: 20 *5=100

Hope this helps!!Brainlist?plz

Which two life functions of animals help maintain the water cycle by recycling water back into the environment?

Answers

Answer:

Respiration and excretion

Explanation:

Respiration. When animals breathe, their lungs release water vapour to the atmosphere.

Animals excrete water by respiration and by passing urine.

Please help i don't get it.
Which image matches the Topographic Map Shown?
Also, please explain how your answer is the correct answer. Why is your answer correct?

Answers

Answer:

the answer is 4

Explanation:

the picture matches eachother that's why I picked 4

Answer:

devils tower

Explanation:

on the topographic map the circular lines stop at at certain point because the moutain doesnt get any pointyer if you know what that means

in other words if the map continued with the circular lines all the way to the centerit would have been that snowny mountain

What could you do to find the density of a fork, knife, and a spoon?

Answers

Answer:

Density is equal to mass divided by volume.

Explanation:

Density = mass / volume

or

p=m/v

Answer:

Use the formula D=m/v

Explanation: In order to find the volume for these objects, use a ruler and measure the length, width, and height. Proceed to multiply them all together, L*W*H. To find the mass of an object, I would say to use a triple beam balance. After finding both the mass and volume of you object, use the formula D = m/v and you'll get your answer.

Question 1
3 pts
There is an apple with a mass of 14 kg that is attached to the tree 12
m above the ground (on earth). How much Gravitational Potential
Energy does the apple have? (Round to the nearest tenth)
Hint g= 9.8 (m/s^2)
*

Answers

Answer:

[tex]\boxed {\boxed {\sf 1646.4 \ J }}[/tex]

Explanation:

Gravitation potential energy can be found using this formula:

[tex]E_P=m*g*h[/tex]

where m is the mass, g is the gravtiational acceleration, and h is the height.

The mass of the apple is 14 kilograms and it is 12 meters above the ground. Since this is on Earth, the acceleration due to gravity is 9.8 m/s².

[tex]m= 14 \ kg \\g= 9.8 \ m/s^2 \\h= 12 \ m[/tex]

Substitute the values into the formula.

[tex]E_p= ( 14 \ kg )( 9.8 \ m/s^2)(12 \ m)[/tex]

Multiply.

[tex]E_p= (137.2 \ kg*m/s^2)(12 \ m )[/tex]

Multiply again.

[tex]E_P= 1646.4 \ kg*m^2/s^2[/tex]

1 kg*m²/s² is equal to 1 Joule. Our answer of 1646.4 kg*m²/s² is equal to 1646.4 Joules

[tex]E_p=1646.4 \ J[/tex]

This is already rounded to the tenth place, so it's the final answer.

The apple has 1,646.4 Joules of gravitational potential energy.

In a normal Earth atmosphere, a feather will free fall through the air more slowly than a brick because of what force?
A. Terminal velocity
B. Momentum
C. Weightlessness
D. Air Resistance

Answers

Answer:

Air Resistance

Explanation:

Because air gives a much greater resistance to the falling motion of the feather than it does to the brick.

3 write
down
two method to increase
any
the effiencey of a simple machine.
Ang two method to increase the effienee.
of a simple machine aree
ns
y of
1)​

Answers

Answer:

two method of increasing efficiency of machine are 1st is give lubricants to machine to reduce friction or heat loss and

2nd. is by increasing the input of energy

PLEASE HELP ASAP A ball is rolling on a flat, frictionless surface. What will happen to the ball if no unbalanced force acts on the ball?

A.
The ball will roll faster and faster.

B.
The ball will begin to roll in the opposite direction.

C.
The ball will begin to roll faster for a time and then begin to roll slower.

D.
The ball will continue to roll in the same direction and at the same speed.

Answers

the answer is A: the ball will roll faster and faster

Rolling friction causes a ball to roll more slowly when it rolls on a horizontal surface. Since static friction is to blame for the friction force, it produces no net work and has no effect on energy dissipation. Thus, option A is correct.

What happens to the ball if no unbalanced force on the ball?

On a frictionless horizontal surface, the ball could neither speed up no slow down because the horizontal surface was intermediate between downhill and uphill. Galileo concluded that in the absences of friction, a ball that once started rolling on a horizontal surface would roll forever.

Friction causes a ball rolling on a flat surface to slow down. The ball finally comes to a stop as a result of friction, which operates in opposition to the ball's motion. If not, it will continue to roll indefinitely.

Therefore, The friction force is brought on by static friction; it has no effect on releasing energy or producing net work.

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