Which event occurs during high tide?

All of Earth’s ocean levels rise.
The moon’s orbit is closer to Earth.
The gravity of the Sun and moon cause the Earth’s crust and water to bulge.
Earth’s crust and water are being pulled in opposite directions by the Sun and moon.

Answer:

they are all made of cells

Answer:

The work efficiency formula is efficiency = output / input, and you can multiply the result by 100 to get work efficiency as a percentage. This is used across different methods of measuring energy and work, whether it's energy production or machine efficiency.

Explanation:

Hope this helped!!!

Answer:

The force required will be "300 N".

Explanation:

The given values are:

Mass of object,

m = 300 kg

Acceleration,

a = 1 m/s

Now,

The force will be:

⇒  [tex]F=m\times a[/tex]

On substituting the values, we get

⇒      [tex]= 300\times 1[/tex]

⇒      [tex]=300 \ N[/tex]

Answer:

gravity...................

Answer:

Hope it help you

Answer: The green house effect is best described by option 4 (Energy given off by earth is reflected off of earth's atmosphere back down to the surface).

Explanation:

The green house effect can be described as the energy given off by earth is reflected off of earth's atmosphere back down to the surface.

When energy from the sun passes through the atmosphere, some are absorbed which keeps the earth surface warm. While the rest is reflected back largely by cloud.

The energy which is emitted from the earth surface is called the infrared radiation. Some of the infrared radiation passess through the atmosphere but most is absorbed and re- emitted in all directions by the greenhouse gas molecules and clouds. This effect warms the earth surface and the lower atmosphere. Therefore this statement (Energy given off by earth is reflected off of earth's atmosphere back down to the surface) is correct about greenhouse effect.

For the greenhouse effect to occur, greenhouse gas molecules are mostly needed. Examples of these gases include:

--> Carbon dioxide (CO2),

--> Water vapor (H2O), and

--> Methane (CH4)

Over the years, the excessive human activities has lead to increase in the greenhouse gas molecules which has negatively affected the greenhouse effects.

Answer:

a person pushes a 125 kg

Explanation:

The total translational kinetic energy of the object is 122.5 J.

Kinetic energy is defined as the energy possessed by a body by virtue of its motion.

Here,

Mass of the object, m = 125 kg

The final velocity of the object, v = 1.4 m/s

It is given that the object was initially at rest on a frictionless surface. When the object was pushed by the person, it gained some amount of kinetic energy and ended up with a final velocity of 1.4 m/s.

So, the expression for total translational kinetic energy of the object is given by,

KE = KEf + KEi

KE = 1/2m(v² + u²)

Since, the object was initially at rest, the initial velocity,

u = 0

Therefore, the kinetic energy of the object,

KE = 1/2 mv²

KE = 1/2 x 125 x (1.4)²

KE = 122.5 J

Hence,

The total translational kinetic energy of the object is 122.5 J.

To learn more about kinetic energy, click:

https://brainly.com/question/17143873

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Answer:

a) La aceleración angular es: [tex]\alpha=2\: rad/s^{2}[/tex]

b) El engranaje gira 125 radianes.

c) El engranaje hara aproximadamente 20 revoluciones.

Explanation:

a)

La aceleración angular se define como:

[tex]\alpha=\frac{\Delta \omega}{\Delta t}[/tex]

Donde:

[tex]\alpha=\frac{35-25}{5}[/tex]

[tex]\alpha=2\: rad/s^{2}[/tex]

b)

El desplazamiento angular puede ser calculado usando la siguiente ecuación:

[tex]\theta=\theta_{i}+\omega_{i}t+\frac{1}{2}\alpha t^{2}[/tex]

Aqui el angulo inicial es 0, por lo tanto.

[tex]\theta=20(5)+\frac{1}{2}(2)(5)^{2}[/tex]

[tex]\theta=125\: rad[/tex]

El engranaje gira 125 radianes.

c)

Lo que debemos hacer aquí es convertir radianes a revoluciones.

Recordemos que 2π rad = 1 rev

Entonces:

[tex]\theta=125\: rad \times \frac{1\: rev}{2\pi\: rad}=19.89\: rev[/tex]

Por lo tanto el engranaje hara aproximadamente 20 revoluciones.

Espero te haya sido de ayuda!

Answer:

P = 500 W

Explanation:

Given that,

Work done to lift a crate to a height of 5 m is 5000 J

It takes 10 s

We need to find the power of the crate. We know that power is the rate of doing work. Mathematically, it can be given by :

[tex]P=\dfrac{W}{t}\\\\P=\dfrac{5000}{10}\\\\P=500\ W[/tex]

So, the power of the crate is equal to 500 W.

Answer:

If you don't have autism/deaf/anything like that you should be able to speak

Explanation:

Answer:

Verbal and nonverbal

Explanation:

Took the test

Answer:

1) x rays

Explanation:

Honestly Gamma rays has the Highest frequency, but in your options, gamma rays is not among, so x rays has the highest frequency among your options.

by Manshow

Answer:

The answer is (X-rays)

number 1

Answer:

q = 1

Explanation:

Given that,

No. of electrons = -12

No. of protons = 13

We need to find the net charge on the balloon. We know that net charge is equal to the sum of proton and the electrons such that,

Net charge = No. of electrons + no. of protons

= -12 + 13

= 1

So, the net charge is equal to 1.

Answer:

42a. Ammeter 2 = 0.20 A

42b. Ammeter 3 = 0.20 A

42c. The current will remain the same i.e unchanged.

43. Equivalent resistance is 11780 Ω

46a. 11 V

46b. 7.5 V

46c. 18.5 V

47. 1.70 A

Explanation:

42a. Determination of ammeter 2

Ammeter 1 = 0.20 A

Ammeter 2 =?

Since the resistors are in series connection, the same current will pass through them. Thus, ammeter 2 will read 0.20 A.

Ammeter 2 = ammeter 1 = 0.20 A

42b. Determination of ammeter 3

Ammeter 1 = 0.20 A

Ammeter 3 =?

Since the resistors are in series connection, the same current will pass through them. Thus, ammeter 3 will read 0.20 A.

Ammeter 3 = ammeter 1 = 0.20 A

42c. Since the resistors are in series connection, the same current will pass through them. Therefore, the current will remain the same.

43. Determination of the equivalent resistance.

We'll begin by converting 1.1 KΩ and 10 KΩ to Ω. This can be obtained as follow:

1 KΩ = 1000 Ω

Therefore,

1.1 KΩ = 1.1 KΩ × 1000 Ω / 1 KΩ

1.1 KΩ = 1100 Ω

1 KΩ = 1000 Ω

Therefore,

10 KΩ = 10 KΩ × 1000 Ω / 1 KΩ

10 KΩ = 10000 Ω

Finally, we shall determine determine the equivalent. This can be obtained as follow:

Resistor 1 (R₁) = 680 Ω

Resistor 2 (R₂) = 1100 Ω

Resistor 3 (R₃) = 10000 Ω

Equivalent Resistance (Rₑq) =?

Rₑq = R₁ + R₂ + R₃

Rₑq = 680 + 1100 + 10000

Rₑq = 11780 Ω

Thus, the equivalent resistance is 11780 Ω

46a. Determination of the voltage across 22 Ω

Current (I) = 0.50 A

Resistor (R₁) = 22 Ω

Voltage (V₁) =?

NOTE: the current is the same since the resistor are in series connection.

V₁ = IR₁

V₁ = 0.5 × 22

V₁ = 11 V

46b. Determination of the voltage across 15 Ω

Current (I) = 0.50 A

Resistor (R₂) = 15 Ω

Voltage (V₂) =?

NOTE: the current is the same since the resistor are in series connection.

V₂ = IR₂

V₂ = 0.5 × 15

V₂ = 7.5 V

46c. Determination of the voltage of the battery.

Voltage 1 (V₁) = 11 V

Voltage 2 (V₂) = 7.5 V

Battery voltage (V) =?

V = V₁ + V₂

V = 11 + 7.5

V = 18.5 V

47. Determination of the current.

We'll begin by calculating the equivalent resistance. This can be obtained as follow:

Resistor 1 (R₁) = 22 Ω

Resistor 2 (R₂) = 4.5 Ω

Equivalent Resistance (R) =?

R = R₁ + R₂

R = 22 + 4.5

R = 26.5 Ω

Finally, we shall determine the current.

Voltage (V) = 45 V

Resistance (R) = 26.5 Ω

Current (I) =?

V = IR

45 = I × 26.5

Divide both side by 26.5

I = 45 / 26.5

I = 1.70 A

Answer:

Decreases the friction between the mallet and the pick.

Letter B

without a medium, there is nothing to compress, hence, no wave. A fast- medium like a gas (air) is easy to compress and allows waves to move through it easily. a slow medium, like a liquid, is still pretty fast, but not as fast as air.

Answer:

The correct answer is NONE the two forces must be equal and of opposite direction, the closest answer is D

Explanation:

In this exercise it is indicated that Jack pushes a car, it is desired that Jill pushes the car so that the speed is constant

take as positive the direction of Jack's thrust

             F_jack - F_jill = 0

              F_jill = F_jack

therefore the push of the two must be equal and Jill's push must have the opposite direction to Jack's push.

The correct answer is NONE the two forces must be equal and of opposite direction, the closest answer is D

Answer:

If you are talking about the experiment in which mouse and plants are kept in a closed glass jar in sunlight so in that case, they both survive because the CO2 released by the respiration of mouse is being utilized by the plants and fixed ( phosynthesis) and O2 is released as by product, which is taken by the mouse for respiration.

Explanation:

Answer:

W = 98 J

Explanation:

Given hat,

Force, F = 5 N

It is lifted 2 m off the ground.

We need to find the amount of work done. We know that, the work done by an object is given by the product of force and displacement. So,

W = Fd

or

W = mgd

Put all the values,

W = 5 × 9.8 × 2

W = 98 J

So, the work done is equal to 98 J.

Answer:

acceleration

Explanation:

acceleration determines whether you will be adding to or subtracting from the velocity. while negative acceleration means you will subtract from the current value of the velocity and a positive acceleration means you will add

Answer: Downwards

Explanation: Upwards is only at the start of a thunderstorm when air moves towards the poles. During the mature stage, air moves down towards the equator.

Answer:

60 kWh

Explanation:

The computation of the annual energy consumption in KW-h is shown below:

As we know that

1 kw = 1000 w

So, for 1400 W it would be

= 1,400 ÷ 1,000

= 1.4 kW

Now the number of hours it used in a year

= 7 minutes × 365 days ÷ 60 minutes

= 42.58333 hours

So in one year it used

= 1.4 kW × 42.58333

= 59.61 kWh

= 60 kWh

The question is incomplete, the complete question is;

During a heat wave, there is an increased demand for electricity to operate air conditioners. The basic design of a nuclear reactor that generates electricity is shown below. What is the best way for the power plant manager to modify the reactor to meet the demand for electricity?

a)lower the control rods, which will absorb more neutrons before they can split atoms

b)raise the control rods so that fewer neutrons are absorbed and more can split uranium atoms

c)remove some of the fuel rods, which will leave more room for additional neutrons to split atoms

d)add additional fuel rods to generate additional neutrons to split uranium atoms

Answer:

b)raise the control rods so that fewer neutrons are absorbed and more can split uranium atoms

Explanation:

A nuclear reactor uses a nuclear fuel to generate electricity. The nuclear reactor makes use of a fissile isotope such as Uranium-235 as nuclear fuel which is bombarded by neutrons and causes a nuclear fission to occur leading to a consequent initiation of a chain reaction.

Control rods are used to absorb some of the neutrons and keep the reaction under control.

When there is need to increase power generation, the control rods are raised so that less neutrons are absorbed by them and more of the uranium fuel is split.

Answer:

I would hope they can change this question

Answer:

average speed

= [(10-3)/12 km] / [(49.5-32.0)/60 hour]

= 5*7 / 17.5

= 2 km/h .

Answer:

All of these

Explanation:

Answer:

Explanation:

 Investigators  thought this meant that oxygen was eight times more massive than hydrogen. They presumed the  chem-ical form-ula for water to be H-O

Hope this helped!!!  .

Answer:

0.6Nm

Explanation

Given

Force = 3N

Distance = 20cm = 0.2m

Moment = Force * perpendicular distance

Substitute

Moment = 3N  * 0.2

Moment = 0.6Nm

Hence her moment is 0.6Nm

Answer:

The outside layer is the wettest.

Explanation:

Answer:

(i) Please see graph of the motion of the particles created with MS Excel and the calculations in the following sections

(ii) The time of collision is approximately 1.0 seconds

(iii) The common horizontal distance of point collision from the point of projection is approximately 25.2 meters

Explanation:

The velocity with which the first projectile was fired, v₁ = 21 m/s

The angle to the horizontal the particle is launched = 53.1°

The time at which the other particle was launched = 1 second later

The location from which the other particle was projected = 0.3 m below the first particle

The initial velocity of the second particle = 31.5 m/s

The angle to the horizontal at which the second particle was projected, θ = 36.9°

(i) The height reached, by each of the particle is given as follows;

y = u·t - 1/2·g·t²

For the first projectile, we have;

y = 21·(t₁+1)×sin(53.1°) - 9.81·(t₁+1)²/2 + 0.3

For the second projectile, we have;

y= 31.5·(t₁)×sin(36.9°) - 4.905·(t₁)²

If the two projectiles collide, we get;

21·(t₁+1)×sin(53.1°) - 9.81·(t₁+1)²/2 + 0.3  = 31.5·(t₁)×sin(36.9°) - 4.905·(t₁)²

Using a graphing calculator for simplifying, we get;

-11.93·t₁ + 12.2 = 0

t₁ = 12.2/11.93 ≈ 1.02

Therefore, at time t₁ = 1.02 seconds, after the launch of the second particle, the two particle will be at the same vertical height

However, whereby at the time, t₂, the particles collide, the horizontal distance travelled, 'x', will be equal;

We have;

x = u·cos(θ)·t₁

For the first particle, we have;

x₁₁ = 21 × cos (53.1°) × (t₂ + 1)

For the second particle, we have;

x₂₂ = 31.5 × cos (36.9°) × t₂

At the point of collision, we have;

x₁ = x₂

∴ 21 × cos (53.1°) × (t₂ + 1) = 31.5 × cos (36.9°) × t₂

31.5 × cos (36.9°) × t₂ - 21 × cos (53.1°) × t₂ = 21 × cos (53.1°)

t₂ = 21 × cos (53.1°)/(31.5 × cos (36.9°)  - 21 × cos (53.1°) ) = 1.00219236871

t₂ ≈ 1.0 seconds

Given that t₁ ≈ t₂, the particles reach the same height and the same horizontal distance at the same time, t₂ ≈ 1.0 and therefore, they collide.

(ii) The time of collision is found above as t₁ ≈ t₂ ≈ 1.0 seconds

(iii) The horizontal distance of the point of collision from the starting point, 'x', is given as follows;

x = 21 × cos (53.1°) × (1.0 + 1) ≈ 25.2

The horizontal distance of the point of collision from the starting point, x ≈ 25.2 meters

The vertical distance of the point of collision from the starting point of the second particle, 'y', is given as follows;

y = 21 × (1+1)×sin(53.1°) - 9.81 × (1+1)²/2 + 0.3 ≈ 14

The vertical distance of the point of collision from the starting point of the second particle, y ≈ 14 meters

The magnitude of the distance from the starting point of the second particle, r = √(25.2² + 14²) ≈ 28.8

The magnitude of the distance from the starting point of the second particle, r ≈ 28.4 meters.