A 50 km/hr wind is blowing due northwest what are the components of the wind in the northern
and western direction?
Answer:
The components of the wind in the northern direction is approximately 35.36 km/hr
Similarly, the components of the wind in the western direction is approximately 35.36 km/hr
Explanation:
The given parameters are;
The magnitude of the speed of the wind, v = 50 km/hr
The direction of the wind = The northwest direction
Therefore;
Given that the angle between the northern and western direction = 90°
The angle in the northwestern direction, θ = 90°/2 = 45°
Therefore;
The components of the wind in the northern direction = [tex]v_y[/tex] = v × sin(θ)
Substituting the values, we have;
The components of the wind in the northern direction = [tex]v_y[/tex] = 50 × sin(45°) = 50/√2 ≈ 35.36 km/hr.
Similarly, the components of the wind in the western direction = vₓ = 50 × cos(45°) = 50/√2 ≈ 35.36 km/hr
fr.shah visits patients at their homes. the equation y=150x + 50 represents the amount she charges, where y represents the total cost and x represents the number of hours she spends at the home. when the equation is graphed, what does the y-intercept represent?
Answer:
50 represent the initial fee or cost added to the total cost
Explanation:
y=150x + 50
y represents the total cost and
x represents the number of hours she spends at the home.
Just like the slope intercept form y=mx + b; where m is the slope of the rate of 150 per hour and y is the total cost.
50 represent the initial fee or cost added to the total cost; in order words, 50 is the b value or where the cost is at 0 hours.
Y is what she charges just to make the trip and show up.
The patient owes her that 50 as soon as she rings the doorbell, before she spends any time there.
A car has an acceleration of -6.5 mi/hr/s. Which of the statements below is true
Where are the answer choices
Why the car floated before it started to sink? Explain.
If a motorcyclist accelerates from rest to 40 m/s in 8 seconds, what is their acceleration?
Answer:
5 m/s²
Explanation:
Given:
v₀ = 0 m/s
v = 40 m/s
t = 8 s
Find: a
a = (v − v₀) / t
a = (40 m/s − 0 m/s) / 8 s
a = 5 m/s²
What is a transverse wave like?
Answer:
a transverse wave is a moving wave whose oscillations are perpendicular to the direction of the wave or path of propagation
Explanation:
wave oscillate along paths at right angles to the direction of the wave’s advance.
Explanation:
A 60.-kilogram physics student would weigh 1560
newtons on the surface of planet X. What is the
magnitude of the acceleration due to gravity on the
surface of planet X?
Answer:
26m/s²
Explanation:
Given parameters:
Mass of the student = 60kg
Weight = 1560N
Unknown:
Acceleration due to gravity = ?
Solution:
Weight is a force on a body due to gravity;
Weight = mass x gravity
Insert the given parameters and solve;
1560 = 60 x gravity
Gravity = [tex]\frac{1560}{60}[/tex] = 26m/s²
What is the mass of 2.5 mol of Ca, which has a molar mass of 40 g/mol?
Answer:100 g of ca
Explanation:
prove that:the unit of pressure is a derived units
Two bowling balls, each with a mass of 8.52 kg, are traveling toward each other. Find the total momentum of the system if both balls have a speed of 2.13 m/s, but are traveling opposite of one another.
a. 18.1
b. 36.3
c. 0.0
d. 17.4
b=36•3
momentum=mass×velocity
The total momentum of the given system is equal to zero. Therefore, option (C) is correct.
What is the law of conservation of momentum?The linear momentum can be described as the product of the mass times the velocity of that object. Conservation of momentum is a property of an object as the total amount of momentum stays the same.
According to the law of conservation of momentum, the sum of the momentum before and after the collision of the objects must be equal.
m₁ u₁ + m₂ u₂ = m₁ v₁ + m₂v₂
where u₁ and u₂ are initial speed while v₁ & v₂ is final speed and m₁ and m₂ is the mass of the collided objects.
The first ball, m = 8.52 g and v = 2.13 m/s
The momentum of the first ball = 18.15 g.m/s
The second ball is moving in the opposite direction w.r.t. first ball,
The second ball, m = 8.52 g and v = - 2.13 m/s
The momentum of the first ball = - 18.15 g.m/s
The total momentum of the system = 18.15 + (-18.15) = 0
Therefore, the total momentum of the given system is zero.
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What is the resistance of a 600 W kettle that draws a current of 5.0 A? please answer with steps
a change in the thermal energy of an object is related to the objects specific heat, heat temperature change, and mass. true or false
this is science BTW
true
think of a hurricane , for it to move it needs energy from the water (warm water).and one it gets on land which has less specific heat in it the hurricane ends
Answer:
True
Explanation:
Edge 2022
What acceleration will you give to a 27.8 kg
box if you push it with a force of 75.7 N?
Answer in units of m/s2.
Answer:
2.72m/s²
Explanation:
Given parameters;
Mass of box = 27.8kg
Force on box = 75.7N
Unknown:
Acceleration = ?
Solution:
Force is the product of mass and acceleration;
Force = mass x acceleration
Now insert the parameters and solve;
75.7 = 27.8 x a
a = [tex]\frac{75.7}{27.8}[/tex] = 2.72m/s²
3. A student fills a plastic bottle full of water. He make a hole in the bottle half-way up,
and another hole at the bottom.
(a) Does the water come faster out of the hole in the middle or the hole at the bottom?
Explain your answer.
Answer:
It would go out the bottom hole faster.
Explanation:
It goes down the bottom hole faster because the water would get poured out the bottom before they even flipped the water bottle.
Balanced Forces acting on an object will not change the object's motion. Unbalanced Forces acting on an object will change the change the object's motion.
Answer:
TRUE
Explanation:
The answer is true.
Balance forces acting on a body will not change the motion of the body because the body experiences no net resultant force in one direction. When any body experiences equal forces with opposite directions, the net force or the resultant force experience by the body is zero.
In case of an unbalanced forces, there is a net force acting in one direction and so it causes the body to change in its state of motion in the direction of the net force.
Which of the following statements does not describe the structure of an atom? (3 points) An atom has a small, dense center called the nucleus. Inside the nucleus of an atom are protons and electrons. Protons are positively charged sub-atomic particles. Electrons are negatively charged sub-atomic particles
Answer:
B is your answer
Explanation:
C, D, and A are true and protons are located inside the nucleus and electrons are located outside the nucleus which means B is your answer.
HELP PLEASEEEE How might the concept of momentum be applied to seafloor spreading?
Answer:
the momentum of the earthExplanation:
Answer:
please mark me as brainlest
11/28/20 2:14 pm name tom
hello i hope this is what you needed
What does seafloor spreading result in?
Explanation:
Seafloor spreading occurs at divergent plate boundaries. As tectonic plates slowly move away from each other, heat from the mantle's convection currents makes the crust more plastic and less dense. The less-dense material rises, often forming a mountain or elevated area of the seafloor. Eventually, the crust cracks.
A space vehicle is coasting at a constant velocity of 22.4 m/s in the y direction relative to a space station. The pilot of the vehicle fires a RCS (reaction control system) thruster, which causes it to accelerate at 0.206 m/s2 in the x direction. After 40.5 s, the pilot shuts off the RCS thruster. After the RCS thruster is turned off, find (a) the magnitude and (b) the direction of the vehicle's velocity relative to the space station. Express the direction as an angle (in degrees) measured from the y direction.
Answer:
a. 23.9 m/s b. 69.58°
Explanation:
a. Since the space vehicle is moving at a constant velocity of 22.4 m/s in the y direction relative to the space station, its initial vertical velocity v = 22.4 m/s.
Also, since the space vehicle moves in the y direction, its initial horizontal velocity u = 0 m/s.
Since its acceleration a = 0.206 m/s² for time, t = 40.5 s, we find the final horizontal velocity u' from u' = u + at.
Substituting the values of the variables into the equation, we have
u' = u + at
u' = 0 m/s + 0.206 m/s² × 40.5 s
= 8.343 m/s
≅ 8.34 m/s
The resultant velocity relative to the space station V = √(v² + u'²)
= √[(22.4m/s)² + (8.34 m/s)²]
= √[501.76 m²/s² + (69.56 m²/s²]
= √[571.32 m²/s²]
= 23.9 m/s
b. The direction of the vehicle's velocity relative to the space station is thus θ = tan⁻¹(v/u')
= tan⁻¹(22.4 m/s/8.34 m/s)
= tan⁻¹(2.6959)
= 69.58°
Two asteroids with masses 3.45 x 103 kg and 6.06 x 104 kg are separated by
a distance of 7,200 m. What is the gravitational force between the asteroids?
Newton's law of gravitation is F gravity =
Gm) m2. The gravitational constant
Gis 6.67 x 10-11 N.m2/kg?
O A. 4.03 N
O B. 2.69 x 10-10 N
O C. 3.38 x 1032 N
O D. 1.93 x 10-6N
The gravitational force between the asteroids is 2.7 × 10^-10 N.
What is gravitation?
Newton's universal law of gravitation states that the force of attraction between any two bodies is inversely proportional to the square of the distance between them and directly proportional to the product of their masses.
Given that:
Two asteroids with masses 3.45 x 10^3 kg and 6.06 x 10^4 kg are separated by a distance of 7,200 m.
Hence, the gravitational force between the asteroids:
F = GmM/r²
= ( 6.67 x 10^-11 × 3.45 x 10^3 × 6.06 x 10^4)/( 7,200)² N
= 2.7 × 10^-10 N.
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Answer:
B 2.69 x 10-10 N
Explanation:
test right yes yes
A 0.50-kg red cart is moving rightward with a speed of 50 cm/s when it collides with a 0.50-kg blue cart that is initially at rest. After the collision, the blue cart begins moving rightward with a speed of 40 cm/s. The red cart is still moving rightward but has slowed down to a speed of 10 cm/s. Enter the momentum values (in kg•cm/s) of each individual cart and of the system of two carts before and after the collision. Also indicate the change in momentum of each cart.
Explanation:
Step one:
given data
mass of red cart m1=0.5kg
initial velocity u1 of red cart=50cm/s
mass of blue cart m2=0.5kg
initial velocity u2 of blue cart= 0cm/s
final velocity v2 of blue cart= 40cm/s
final velocity v1 of red cart= 10cm/s
Step two:
Momentum values red cart before and after the collision.
Before collision
P1=m1u1
P1=0.5*50
P1=25kg•cm/s
After collision
P2=m1v1
P2=0.5*10
P2=5kg•cm/s
Change in momentum= P1-P2=25-5= 20kg•cm/s
Momentum values blue cart before and after the collision.
Before collision
P1=m1u1
P1=0.5*0
P1=0 kg•cm/s
After collision
P2=m1v1
P2=0.5*40
P2=20kg•cm/s
Change in momentum= P1-P2=0-20= -20kg•cm/s
The total momentum of the system of the carts before collision is 25 kgcm/s.
The total momentum of the system of the carts after collision is 25 kgcm/s.
The change in momentum of the red cart is -20 kgcm/s.
The change in momentum of the blue cart is 20 kgcm/s.
The given parameters;
mass of the red cart, m₁ = 0.5 kginitial speed of the red cart, u₁ = 50 cm/smass of the blue cart, m₂ = 0.5 kginitial velocity of the blue cart, u₂ = 0final velocity of the blue cart, v₂ = 40 cm/sfinal velocity of the red cart, v₁ = 10 cm/sThe momentum of the red cart before collision is calculated as follows;
[tex]P_r_1 = m_1u_1\\\\P_r_1 = 0.5 \times 50\\\\P_r_1 = 25 \ kgcm/s[/tex]
The momentum of the blue cart before collision is calculates as follows;
[tex]P_b_1 = m_2 u_2\\\\P_b_1 = 0.5 \times 0\\\\P_b_1 = 0 \ kgcm/s[/tex]
The momentum of the red cart after collision is calculated as follows;
[tex]P_r_2 = 0.5 \times 10\\\\Pr_2 = 5 \ kgcm/s[/tex]
The momentum of the blue cart after collision is calculated as follows;
[tex]P_2b_2 = 0.5 \times 40\\\\P_2b_2 = 20 \ kgcm/s[/tex]
The total momentum of the system before and after collision is calculated as follows;
[tex]P_1 = 25 \ kgcm/s \ + \ 0 = 25 \ kgcm/s\\\\P_2 = 5 \ kgcm/s \ + \ 20 \ kgcm/s = \ 25 \ kgcm/s[/tex]
The change in momentum of the red cart is calculated as follows;
[tex]\Delta P_r = Pr_2 - Pr_1\\\\\Delta P_r = 5 - 25 = - 20 \ kgcm/s[/tex]
The change in momentum of the blue cart is calculated as follows;
[tex]\Delta P_b = P_b_ 2 - P_b_1\\\\\Delta P_b = 20 - 0 \ = \ 20 \ kgcm/s[/tex]
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HELP THIS IS DUE IN 10 MINS
Find the definitions of the following terms.
A. Force of impact
B. Total Velocity
C. Horizontal Velocity
D. Vertical Velocity
100 points
you stole point from me, if you really didn't know the answer you shouldn't have wasted time.
Calculate the acceleration of gravity that the moon has, if an astronaut has a mass of 87 kg and the weight force he experiences on the moon is 141 N
Answer:
the acceleration of gravity is 1.62
Explanation:
w=mg
141=87g
141/87=87g/87
1.62=g
- An impulse is equivalent to
a. the change in mass of an object.
b. the change in volume of an object.
c. a force applied to an object for a period of time.
d. the original momentum of the object.
Answer:
c
Explanation:
impulse Is the product of force and distance so it's generally formula
The impulse should be equivalent to the option c. a force applied to an object for a period of time.
What is an impulse?Impulse of force represent the product of the resultant force ΣF and also the duration of the force Δt when the force should be constant. Also it should be lead to the changed to motion and changes to momentum
Therefore, The impulse should be equivalent to the option c. a force applied to an object for a period of time.
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A space shuttle travels around the Earth at a constant speed of 28000 kilometers per hour. If it takes 90 minutes to complete one orbit, how far is its journey around Earth?
I need the answer ASAP!
in the waves lab, you changed ____ to see how it would affect wave speed.
If an object is in free fall, on the way down it will
Answer:
It will find a worm when it hits the ground and starts Johnny sins fvcl<ing the worm
1. A motorcycle stunt driver rides his motorcycle off a small ledge
that is 8.4 meters high. His initial velocity as he rides off the cliff is
24 m/s in the horizontal direction.
a. How long does it take before he lands on the ground below?
b. How far away from the base of the cliff does he travel while in
the air?
Answer:
Explanation:
Given
Height S = 8.4m
Initial velocity u = 24m/s
Required
Time it will take to reach the ground
Using the equation of motion
S = ut +1/2gt²
8.4 = 24t + 1/2(9.8)t²
8.4 = 24t+4.9t²
4.9t²+24t - 8.4 = 0
Multiply through by 10
49t²+240t-84 = 0
Factorize
t = -240±√240²-4(49(-84)/2(49)
t = -240±√57600+16464/98
t = -240±√74064/98
t = -240±272.15/98
t = 32.15/98
t = 0.328seconds
Hence it takes 0.328seconds before it lands on the ground below.
b) The horizontal distance is the range expressed as;
R = u²/g
R = 27²/9.8
R = 729/9.8.
R = 74.39m
a. The time it took before the motorcycle stunt driver lands on the ground below is 1.31 seconds.
b. The distance from the base of the cliff that the motorcycle stunt driver traveled while in the air is 31.44 meters.
Given the following data:
Maximum height = 8.4 meters.Initial velocity = 24 m/s.We know that the acceleration due to gravity (g) of an object on planet Earth is equal to 9.8 [tex]m/s^2[/tex]
a. To determine how long (time) it took before the motorcycle stunt driver lands on the ground below:
At maximum height, time is given by the formula:
[tex]Time = \sqrt{\frac{2H}{g} }[/tex]
Where:
g is the acceleration due to gravity.H is the maximum height.Substituting the given parameters into the formula, we have;
[tex]Time = \sqrt{\frac{2\times 8.4}{9.8} }\\\\Time = \sqrt{\frac{16.8}{9.8} }\\\\Time =\sqrt{1.7413}[/tex]
Time = 1.31 seconds.
b. To determine how far (distance) away from the base of the cliff the motorcycle stunt driver traveled while in the air:
[tex]Horizontal\;distance = horizontal\;speed \times time\\\\Horizontal\;distance = 24 \times 1.31[/tex]
Horizontal distance = 31.44 meters.
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A roller coaster with a potential energy of 235,200 J sits at the top of a 30 m high hill. What is the mass of the roller
coaster? (Formula: PE = mgh)
O 800 kg
O 7,840 kg
O 8,000 kg
O 78,400 kg
Answer:
800 kg
Explanation:
I just did it :)
Which of the following best describes inertia?
A. Rowing a boat
B. Moving forward in your seat when the car suddenly stops
C. A rocket taking off from the launching pad
D. A bicycle requires less force to move than a car
find the mass of a car that is travelling at a velocity of 60m/a north. The car had 5,040,000 j of kinetic energy
Answer:
2800kg
Explanation: