Which relation is correct
E ᾳ ѵ
ѵ = c / λ
both are correct
none
Answer:
geruow0irghvn3p0unhie0ghik
Explanation:
Robert was changing the oil in his truck. He dumped the used oil on the ground in his yard. He didn't know it, but Robert was hurting the environment because the oil-
HELP FAST
Answer:
goes deep into the ground and pollutes the groundwater.
In the reaction, 2HgO(s)⟶2Hg(s) O2(g). How many liters of oxygen, O2 measured at STP, would be produced from the decomposition of 111 g of mercury(II) oxide, HgO?
Answer:
5.74 L O₂
General Formulas and Concepts:
Chemistry - Gas Laws
Reading a Periodic TableUsing StoichiometrySTP (Standard Conditions for Temperature and Pressure) = 22.4 L per mole at 1 atm, 273 KExplanation:
Step 1: Define
RxN: 2HgO (s) → 2Hg (s) + O₂ (g)
Given: 111 g HgO
Step 2: Identify Conversions
STP
Molar Mass of Hg - 200.59 g/mol
Molar Mass of O - 16.00 g/mol
Molar Mass of HgO - 200.59 + 16.00 = 216.59 g/mol
Step 3: Stoichiometry
[tex]111 \ g \ HgO(\frac{1 \ mol \ HgO}{216.59 \ g \ HgO} )(\frac{1 \ mol \ O_2}{2 \ mol \ HgO} )(\frac{22.4 \ L \ O_2}{1 \ mol \ O_2} )[/tex] = 5.73988 L O₂
Step 4: Check
We are given 3 sig figs. Follow sig fig rules and round.
5.73988 L O₂ ≈ 5.74 L O₂
the position-time graph shows the motion of four people. label the lines on graph need on the motion description in this table.
Answer:
4,2,3,1
Explanation:
A typical coffee mug holds about 355,000 microliters of liquid. How many kiloliters of liquid does this mug hold expressed in standard Scientific notation?
Answer:
[tex]3.55\times 10^{-4}\ kL[/tex]
Explanation:
Given that,
A typical coffee mug holds about 355,000 microliters of liquid.
[tex]1\ \mu L=10^{-6}\ L[/tex]
Also, 1 L = 0.001 kL
[tex]10^{-6}\ L=0.001\times 10^{-6}\ kL\\\\=10^{-9}\ kL[/tex]
So, a typical coffee mug holds about [tex]355000 \times 10^{-9}\ kL[/tex] or [tex]0.000355\ kL[/tex] of liquid.
We need to convert it into Scientific notation.
We will shift 4 zeros to right. As a result,
[tex]V=3.55\times 10^{-4}\ kL[/tex]
So, the mug will hold [tex]3.55\times 10^{-4}\ kL[/tex] of liquid.
How long will it take to deposit 6.32 g of copper from a CuSO4(aq) solution using a current of 0.554 amps
Answer:
34672.96 s
Explanation:
m = Mass of copper = 6.32 g
M = Molar mass of copper = 63.5 g/mol
F = Faraday constant = 96500 C/mol
The electrode equation would be
[tex]Cu^{2+}(aq)+2e^{-}=Cu(s)[/tex]
Number of electrons = 2 = e
I = Current = 0.554 A
t = Time taken
Charge would be
[tex]Q=\dfrac{m}{M}eF\\\RightarrowQ=\dfrac{6.32}{63.5}\times 2\times 96500\\\Rightarrow Q=19208.82\ \text{C}[/tex]
Charge is given by
[tex]Q=It\\\Rightarrow t=\dfrac{Q}{I}\\\Rightarrow t=\dfrac{19208.82}{0.554}\\\Rightarrow t=34672.96\ \text{s}[/tex]
Time taken to deposit the copper is 34672.96 s.
2a Define Radioactivity?
Answer:
The emmision of ionizing radiation or particles caused by the spontaneous disintegration of atomic nuclei
or
the giving off of rays of energy or particles by the breaking apart of atoms of certain elements
28. Element X is powerful enough to reduce sodium ions to sodium metal. Barium is a strong enough reducing agent to reduce X +to X. What is the identity of element X? _____________
Answer:
hope it's correct.
Explanation:
element is nickel.
Draw the correct structure(s) for (2R,3S)‑2,3‑dibromobutane. Show stereochemistry clearly. To ensure proper grading, explicitly draw all four groups, including wedge/dash bonds, around a chirality center. Indicate whether the compound(s):_____.a. could exist in an optically active form.b. could exist in optically active form.b. cannot exist in optically active form.c. cannot be determined.
Answer:
b. cannot exist in optically active form
Explanation:
Stereochemistry is a branch of chemistry that involves the spatial arrangement of the atoms of molecules and studies how this affects the physical and chemical properties of such species.
The correct structure for (2R,3S)‑2,3‑dibromobutane can be seen in the image attached below. Since the compound is a meso compound due to the plane of symmetry. Thus, the compound is achiral. i.e. Compounds that are superimposable on its mirror image. The plane of symmetry is vertical inclined at 90°(i.e. perpendicular) to the page thus goes via the middle of the molecule.
For the following reaction in aqueous solution, identify all the species that will be spectator ions. 2KF + Mg(CH3COO)2---------- 2KCH3COO + MgF2 Choose one or more: a. F– b. K c. Mg2 d. KCH3COO e. Mg(CH3COO)2 f. CH3COO– g. KF h. MgF2
Answer:
b. K⁺.
f. CH3COO⁻.
Explanation:
Hello!
In this case, since the reaction:
[tex]2KF(aq) + Mg(CH_3COO)_2(aq)\rightarrow 2KCH_3COO(aq) + MgF_2(s)[/tex]
Has a precipitation product which is magnesium fluoride, it is not ionized so the ionic equation is:
[tex]2K^+(aq)+F^-(aq) + Mg^{2+}(aq)+2CH_3COO^-(aq)\rightarrow 2K^++2CH_3COO^-(aq)(aq) + MgF_2(s)[/tex]
Thus, since potassium and acetate ions are at both reactants and product sides, we infer they are the spectator ions; therefore the answer is b. K⁺ and f. CH3COO⁻.
Best regards!
The spectator ions are CH3COO– and K^+.
We must remember that spectator ions are the ions that do not undergo any change from left to right in the reaction equation.
The molecular reaction equation is;
2KF(aq) + Mg(CH3COO)2(aq)---------- >2KCH3COO(aq) + MgF2 (s)
Complete ionic reaction equation is;
2K^+(aq) + 2F^-(aq) + Mg^2+(aq) + 2CH3COO^-(aq) ----> 2K^+(aq) + 2CH3COO^-(aq) + MgF2 (s)
Eliminating the spectator ions, we have the net ionic reaction equation;
Mg^2+(aq) + 2F^-(aq) ------> MgF2 (s)
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What is the compound name for HgCl2
Answer:
Mercury Chloride
Explanation:
Trust me, this answer is correct.
A sample contains 16 mg of polonium-218. After 12 minutes, the sample will contain 1.0 mg of polonium-218. What is the half life of polonium-218?
Answer:
Half-life = 3 minutes
Explanation:
Using the radioactive decay equation we can solve for reaction constant, k. And by using:
K = ln2 / Half-life
We can find half-life of polonium-218
Radioactive decay:
Ln[A] = -kt + ln [A]₀
Where:
[A] could be taken as mass of polonium after t time: 1.0mg
k is Reaction constant, our incognite
t are 12 min
[A]₀ initial amount of polonium-218: 16mg
Ln[A] = -kt + ln [A]₀
Ln[1.0mg] = -k*12min + ln [16mg]
-2.7726 = - k*12min
k = 0.231min⁻¹
Half-life = ln 2 / 0.231min⁻¹
Half-life = 3 minutesIn the Energy and Specific Heat lab, you measure the temperature change of water to study the specific heat of a metal. What statement explains the relationship between the water and the metal you are studying
The question is incomplete, the complete question is;
In the Energy and Specific Heat lab, you measure the temperature change of water to study the specific heat of a metal. What statement explains the relationship between the water and the metal you are studying? Select one: O The heat lost by the metal plus the heat gained by the water equals 100. O The temperature change of the metal is equal to the temperature change of the water. O The heat lost by the metal is equal to the heat gained by the water. The initial temperature of the metal equals the initial temperature of the water
Answer:
The heat lost by the metal is equal to the heat gained by the water.
Explanation:
When the piece of metal is put into water, heat is lost by the metal and gained by the water.
Recall that energy is conserved hence heat lost by metal must be equal to heat gained by water.
Thus, the relationship between the metal under study and the water is that the metal looses heat to the water and heat lost by metal is equal to heat gained by water.
The statement that explains the relationship that lies between the water and the metal you are studying is that the heat lost by the metal is equal to the heat gained by the water.
The following information should be considered:
At the time when the metal piece place in the water so the heat should be lost via the metal and it should be gained by the water. The energy that recall should be conserved thus the heat that should lost by metal should be equivalent to the heat gained by water.Therefore we can conclude that the statement that explains the relationship that lies between the water and the metal you are studying is that the heat lost by the metal is equal to the heat gained by the water.
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8. Insecticides are most likely to be damaging when used incorrectly.
Answer:
True (see detailed explanation).
Explanation:
Hello!
In this case, since insecticides are substances that keep crops from insects that can eat or damage them, it has been acknowledged they are important for the agricultural industry and therefore the citizens sustainability.
However, since insecticides have really complex chemical structures, they are unlikely or sluggishly decomposed by the humans and other animals' cells, which can lead to irreversible genetic damage, cancer and other serious diseases; therefore, when they are used incorrectly, say higher amounts than necessary, spread on crops that are not significantly affected by insects or by any other reason, they are very likely to be damaging for us, animals and in general the environment.
Best regards!
35 POINTS Y'ALL
What is the difference in petroleum and natural gas?
thanks,
-throckmorton
Answer:
:)
Explanation:
Petroleum gas is mainly C3 and C4 based (propane and butane), whilst natural gas is predominantly C1 and C2 (methane and ethane). Petroleum gas is generally produced via the cracking of naphtha, which is one of the components separated during crude oil refining.
Petroleum is C3 or C4 (propane and butane) while Natural Gas is C1 and C2. (methane and ethane)
Petroleum is also produced differently then Natural Gas.
"Petroleum gas is generally produced via the cracking of naphtha, which is one of the components separated during crude oil refining." - socratic.org
iron chloride + sodium hydroxide
Answer:
Sodium hydroxide reacts with iron(III) chloride to produce iron(III) hydroxide and sodium chloride.
Hope this helps plz hit the crown :D
The pressure of a compressed gas is 1.45 atm. What is this pressure in kPa
Answer:
1.45 Atmospheres = 146.92125 Kilopascals, or about 146.9 Kilopascals
Explanation:
1 Atmosphere = 101.325 Kilopascals, so 101.325 Kilopascals x 1.45 Atmospheres = 146.92125 Kilopascals.
Using the conversion table, the pressure of the compressed gas at 1.45 atm when converted to kilopascal becomes 146.92 kPa.
How to convert from atm to kPa?
Atm is the standard atmosphere which is a unit of pressure.
From conversion table
1 atm atmospheric pressure is equivalent to 101.325 kPa ( kilopascal ).
Now, the pressure of the compressed gas at 1.45 atm will be;
P = 1.45 × 101.325 kPa
P = 146.92 kPa
Therefore, the pressure of the compressed gas at 1.45 atm when converted to kilopascal using the conversion table becomes 146.92 kPa.
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one parent has type AB blood while the other has Type O blood.Which two blood type could their children have?
A mother who is blood type O can only pass an O allele to her son or daughter. A father who is blood type AB could pass either an A or a B allele to his son or daughter. This couple could have children of either blood type A (O from mother and A from father) or blood type B
A graph of potential energy versus inter-nuclear distance for two chlorine atoms is given below
Answer:
Explanation:
The sketch of the curve for two Br atoms can be seen in the image attached below. From the image below, we can deduce the following:
On the periodic table, the Bromine (Br) atom is the fourth member in the halogen family group. The atomic size increases from top to bottom down the group, thus Br atom posses a larger atomic size than Cl atom. As a result of that, the bond length formation between the two Br atoms will be larger compared to that of the two Cl atoms.
Write the balanced equation for the neutralization reaction between H3PO4 and NaOH in an aqueous solution.
Answer:
H3PO4 + 3NaOH ==> Na3PO4 + 3H2O
The balanced equation for the given reaction is [tex]3NaOH+H_3PO_4---- > Na_3PO_4+3H_2O[/tex]
What is neutralization reaction?A chemical reaction in which an acid and a base react quantitatively with each other is known as neutralization.
In a water reaction, neutralization means that there is no excess of hydrogen or hydroxide ions in the solution.
A neutralization reaction occurs when an acid and a base react to form water and a salt through the combination of H+ ions and OH- ions. The pH of neutralization of a strong acid and a strong base is 7.
Three moles of sodium hydroxide are required for one mole of phosphoric acid. The balanced equation tells us the following: 1 mol of H3PO4 reacts with 3 mol of NaOH.
It can be written as
[tex]3NaOH+H_3PO_4---- > Na_3PO_4+3H_2O[/tex]
Thus, this is the balanced equation for the given neutralizing reaction.
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What can you say about the effect of sulfuric acid on the reaction between the alcohol and carboxylic acid?
Answer:
It provides hydrogen ions to favor the formation of ester.
Explanation:
Hello!
In this case, since the reaction between and alcohol and a carboxylic acid yields an ester and water as an organic acid-base neutralization reaction, represented via:
[tex]R_1-OH+R_2COOH\rightleftharpoons H_2O+R_2COO-R_1[/tex]
As you can see, this reaction is at equilibrium because the ester is able to come back to the initial reactants, it means that the addition of hydrogen ions favor the reaction towards the formation of more ester, effect that is attained via the addition of sulfuric acid, which acts as a catalyst in this reaction because it provides the hydrogen ions, this reaction needs.
Best regards!
A sample of Br2 gas has a volume of 29.0L and a pressure of 1.50 atm. If the initial temperature of the gas is 23 °C, what volume, in liters, will the gas occupy at 3.50 atm and 271 °C?
Answer:
V₂ = 22.84 L
Explanation:
Given data:
Initial volume = 20.0 L
Initial pressure = 1.50 atm
Initial temperature = 23 °C (23 +273 = 296 K)
Final temperature = 271°C (271+273 = 544 K)
Final pressure = 3.50 atm
Final volume = ?
Formula:
P₁V₁/T₁ = P₂V₂/T₂
P₁ = Initial pressure
V₁ = Initial volume
T₁ = Initial temperature
P₂ = Final pressure
V₂ = Final volume
T₂ = Final temperature
Solution:
V₂ = P₁V₁ T₂/ T₁ P₂
V₂ = 1.50 atm × 29.0L ×544 K / 296 K × 3.50 atm
V₂ = 23664 atm .L. K / 1036 atm.K
V₂ = 22.84 L
a. Explain why bicycle tires seem higher in the summer than in winter.
b. Explain why a can of soda pop explodes if left in the hot sun.
c. A rigid container filled with a gas is placed in ice (ex. nalgene bottle). What will happen to the pressure of the gas? What do you think will happen to the volume?
d. An infected tooth forms an abscess* that fills with gas. The abscess puts pressure on the nerve of the tooth, causing a toothache. While waiting to see a dentist, the person with the toothache tried to relieve the pain by treating the infected area with moist heat. Will this treatment help? Why or why not?
Answer:
a) When air inside the tires gets colder, it shrinks, so the tires seem flat, even though they haven't lost any air.
b) When the air inside the soda can gets hot, the molecules of gas move faster, exerting more and more and more pressure, eventually exploding the soda can.
c) When the nalgene is cooled, the air pressure inside will lower; the volume of the nalgene will stay the same, though, because the nalgene is a rigid container.
In a titration of monoprotic acids and bases, there is a large change in pHA. at the point where pH = pKa of the acid.B. when the volume of acid is exactly equal to the volume of base.C. when the concentration of acid is exactly equal to the concentration of base.D. when the number of moles of acid is exactly equal to the number of moles of base.E. at the point where pH = pKb of the
Answer:
D. when the number of moles of acid is exactly equal to the number of moles of base.
Explanation:
Regarding options A. and E., pKa and pKb would only be taken into consideration if the titrations were of weak acids and bases. However it is possible to have a titration of monoprotic acids and bases with strong acids and bases.
Another way of looking at the answer is identifying which one best describes the equivalence point.
1+1 hahahahahhhahahaahahahahahahahahahahahahahaha why u dumb
Answer:
1+1=2 Unless this is a trick question. Then it's most likely 11.
Explanation:
1 + 1 = 2
thxs for the points realy tho thxs
A seawater sample contains 2.7 mg chl [tex]m^{-3}[/tex]. What is the chlorophyll concentration in units of mg [tex]L^{-1}[/tex]?
Given :
A seawater sample contains 2.7 mg chlorophyll m⁻³.
To Find :
What is the chlorophyll concentration in units of mg L⁻¹.
Solution :
We know, 1 m³ = 1000 L .
So, 1 m⁻³ = 10⁻³ L⁻¹
Concentration is :
[tex]c = 2.7\ mg\ m^{-3}\\\\c = 2.7\times 10^{-3}\times \ mg\ L^{-1}\\\\c = 0.0027 \ mg\ L^{-1}\\\\c = 2.7\ \mu g \ L^{-1}[/tex]
Therefore, the chlorophyll concentration in units of mg L⁻¹ is [tex]2.7\ \mu g \ L^{-1}[/tex].
Hence, this is the required solution.
MULTIPLE CHOICE: For a combustion system, incorrect statement is?
Answer:
I THINK it's D, I could be incorrect, however.
Explanation:
C3H8O, as it is flammable, and thus I wouldn't imagine it being a product of combustion. I could be incorrect, so take my answer with a grain of salt.
what has a higher melting point KBr or CH3CH2CH2CH3
Answer:
i don't understand the question
Explanation:
Calculate the average kinetic and potential energies of a 2s electron in a hydrogenic atom of atomic number Z.
Answer:
z = 2s
Explanation:
This is the only info given.
A aliquot of solution containing of in required of EDTA solution for titration. How many milligrams of will react with of this EDTA solution?
Answer:
The answer is "[tex]\bold{1.39 \ mg}[/tex]".
Explanation:
Please find the complete question in the attached file.
Total Moles of [tex]Mg_2^{+}[/tex] = moles of [tex]MgSO_4[/tex]
[tex]= \frac{mass}{molar \ mass \ of MgSO_4}\\\\= \frac{0.450}{120.37}\\\\ = 0.0037385 \ mol[/tex]
[tex]Mg_2^{+} + EDTA4^{-} \longrightarrow Mg(EDTA)2^{-}[/tex]
EDTA mol in 37.6 mL of solution = 50.0 mL of [tex]Mg2^{+}[/tex]
[tex]= \frac{50.0}{500} \times[/tex] total moles of [tex]Mg2^{+}[/tex]
[tex]= \frac{50.0}{500} \times 0.0037385\\\\= 3.7385 \times 10^{(-4)} \ mol\\[/tex]
[tex]Ca2^{+} + EDTA4^{-} \longrightarrow Ca(EDTA)2^{-}[/tex]
[tex]CaCO_3 Moles = Ca2^{+} Moles =[/tex] EDTA moles in a solution of 1.40 mL
[tex]= \frac{1.40}{37.6} \times 37.6 \ mL[/tex] the solution of EDTA moles.
[tex]= \frac{1.40}{37.6} \times 3.7385 \times 10^{(-4)} \\\\= 1.392 \times 10^{(-5)}\ mol\\\\[/tex]
Mass of [tex]CaCO_3 =[/tex]mole[tex]\times[/tex] the molar mass of [tex]CaCO_3[/tex]
[tex]= 1.392 \times 10^{(-5)} \times 100.09\\\\= 0.00139 \ g\\\\ = 1.39 \ mg[/tex]