Which of the four is least like the other three? A)Platinum B)Ivory C)Silver D)Gold​

Answers

Answer 1

Answer:

B) Ivory

Explanation:

Ivory is a hard, white material from the tusks and teeth of animals, that consists mainly of dentine, one of the physical structures of teeth and tusks.

Platinum, Silver, and Gold are precious metals, meaning they are rare metallic chemical elements of high economic value, shiny, hard, strong with high melting points

Answer 2

Ivory is regarded as the least of the options. Ivory consists of dentine and

are usually found in the tusks and teeth of animals such as elephants. They

however don't have much value as the other metals in the options.

Precious metals  include the following:

PlatinumSilverGold

They are used for ornamental purposes. They are usually mined and refined

to produce a variety of objects.

Their use are however legal and they are expensive which makes the Ivory

the least out of the options provided.

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Related Questions

10. Based on their valence electrons, how many
atoms of chlorine are expected to bond
with each of the following elements?
a. carbon
b. nitrogen
c. aluminum
d. sulfur

Answers

will share 2 elctrons with 2 Cl to form

S in column 16 WILL SHARE 2 ELECTRONS WITH 2 /Cl to form

SCl2

,

Answer:

a. carbon    CCl4

b. nitrogen NCl3

c. aluminum AlCl3  

d. sulfur SCl2

Explanation:

10. Based on their valence electrons, how many

atoms of chlorine are expected to bond

with each of the following elements?

a. carbon    CCl4

b. nitrogen NCl3

c. aluminum AlCl3  

d. sulfur SCl2

Cl is in Periodic Table column 17, so it has 7 valence  and needs 1 more to have an electronic structure like its nearest noble gas, Ar.

It then has an oxidation state 0f -1.

Carbon in column  has  +/-4 charge, so 4 Cl will bond with 1 C to make

covalent CCl4

Nitrogen in column 15  is -3.  It will share 3 electrons with 3 Cl to form

covalent NCl3

Al in column 13 give away 3 electrons to 3 Cl to form

ionic AlCl3

S in column 16 will share 2 electrons with 2 Cl and frorm

SCl2

A scientist wants to make a solution of tribasic sodium phosphate, Na3PO4, for a laboratory experiment. How many grams of Na3PO4 will be needed to produce 400. mL of a solution that has a concentration of Na ions of 1.00 M

Answers

Answer:

21.86 grams

Explanation:

It is important to note that for every mol of Na3PO4 there is, 3 mols of Na ions are produced.

Na+=1m(0.4l), so mols of Na3PO4= 0.4/3= 0.13333... mols

the molar mass of Na3PO4 is 163.94 grams/mol. 0.1333*163.94=21.86 grams of Na3PO4.

Consider an ice cube and a hot radiator. Which has the higher thermal energy?

the ice cube

the radiator

Answers

The answer to your question is the radiator

The thermal energy of a material increases with temperature. Therefore, the radiator  has the higher thermal energy.

What is thermal energy?

When the temperature rises, a type of energy called thermal energy is produced. The amount of thermal energy usually directly inversely proportional to the object's change in temperature. Thermal energy takes the form of heat.

The thermal energy of a material increases with temperature. The quicker motions of the substance's atoms and molecules are what cause thermal energy to grow as temperature rises.

In some cases, a substance's molecules will separate from one another and leave because the temperature is just so high. Unexpectedly, thermal energy also affects the states of matter. The radiator  has the higher thermal energy.

Therefore, the radiator has the higher thermal energy.

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Compare the average motion of the particles in the 3 containers of water

Answers

Answer:

c>b=a

Explanation:

It is important to note that mass does not affect the average motion/energy per molecule, but temperature does. the higher the temperature the faster the particles are. A has the same temperature as B, so they have the same amount of motion. C is warmer than A and B, so the average motion of the particles in beaker C is the largest

Which scientific law describes the observation that energy cannot be created or destroyed?

Law of universal gravitation
Law of conservation of energy
Newton's first law of motion
Newton's third law of motion

Answers

Answer:

law of conservation of energy

A containing vessel holds a gaseous mixture of nitrogen and butane. Thepressure in the vessel at 126.9 Cis 3.0 atm. At 0 C, the butane completelycondenses and the pressure drops to 1.0 atm. Calculate the mole fraction of nitrogenin the original gaseous mixture.

Answers

A vessel that contains a mixture of nitrogen and butane has a pressure of 3.0 atm at 126.9 °C and a pressure of 1.0 atm at 0 °C. The mole fraction of nitrogen in the mixture is 0.33.

A vessel contains a gaseous mixture of nitrogen and butane. At 126.9 °C (400.1 K) the pressure is due to the mixture is 3.0 atm.

We can calculate the total number of moles using the ideal gas equation.

[tex]P \times V = n \times R \times T\\\\n = \frac{P \times V}{R \times T} = \frac{3.0 atm \times V}{0.082 atm.L/mol.K \times 400.1 K} = 0.091 mol/L \times V[/tex]

At 0 °C (273.15 K), the pressure due to the gaseous nitrogen is 1.0 atm.

We can calculate the moles of nitrogen using the ideal gas equation.

[tex]P \times V = n \times R \times T\\\\n = \frac{P \times V}{R \times T} = \frac{1.0 atm \times V}{0.082 atm.L/mol.K \times 400.1 K} = 0.030 mol/L \times V[/tex]

The mole fraction of nitrogen in the mixture is:

[tex]X(N_2) = \frac{0.030 mol/L \times V}{0.091 mol/L \times V} = 0.33[/tex]

A vessel that contains a mixture of nitrogen and butane has a pressure of 3.0 atm at 126.9 °C and a pressure of 1.0 atm at 0 °C. The mole fraction of nitrogen in the mixture is 0.33.

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Help pretty please :)

Answers

the answer is 15 bc you multiply the coefficient but the subscript

What is the reaction between CCl4 and H2O? ​

Answers

Answer:

At temperatures > 400 °C, CCl4 reacts with H2O over a MgO catalyst to yield HCl and CO2.

A city carrier resigns and trains as an office receptionist this is a person’s metabolism is likely to

Answers

Answer: results from a combination of a person’s metabolic heat and environmental heat

Identify the major ionic species present in an aqueous solution of C6H12O6 (glucose).
A. 6 C-
, 12 H+
, 6 O–
B. 6 C+
, 12 H+
, 6 O2–
C. 6 CH2+, 6 O2–
D. C6
+
, 12 H+
, 6 O2–
E. no ions are present

Answers

Glucose is a molecular substance therefore, there are no ionic species in glucose.

Ionic substances dissolve in water to yield ions. Molecular substances do not produce ions in solution. The conductivity of ionic solutions owes to the presence of ions in solutions. Molecular solutions do not conduct electricity due to the absence of ions.

Glucose is a molecular substance hence they are are no ions present hence glucose does not conduct electricity.

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An unknown hydrocarbon compound was analyzed for hydrogen by elemental analysis and results show that it contains 15.88 % H. What is the empirical formula

Answers

Answer:

C4H9

Explanation:

If H = 15.88%

Then C = 100.00 – 15.88 = 84.12

Divide each % value by respective atomic mass

H = 15.88/1 = 15.88

C = 84.12/12 = 7.01

Divide through by smaller value

H = 15.88/7.01 = 2.26

C = 7.01/7.01 = 1

Remove fraction , multiply by 4

H = 9

C = 4

Empirical formula = C4H9

The hydrocarbon could be ( C4H9)2 = C8H18 = octane.

What is the percent composition of Be(OH)2?

Answers

Answer:

Ba 80.148%. H 1.77% O 18.657%

The collision theory state that?

Answers

Answer:

Collision theory states that molecules must collide to react. For most reactions, however, only a small fraction of collisions produce a reaction.

please help me

Select the correct answer.

Who founded the specialized field of anatomy?

A. Herophilus

B. Aristotle

C. Claudius Galen

D. William Harvey​

Answers

Answer:

the correct answer is A. please mark me brainlist

Explanation:

Answer:

geon, Andreas Vesalius. Vesalius describes what he observes during the public dissection of human corpses. By dissecting human bodies, preparing muscles, tendons, and nerves down to the smallest detail, Vesalius is able to prove more than 200 errors in Galen’s anatomical works.

Explanation:

With his comprehensive scientific studies of human bodies, the young professor of medicine not only revolutionizes anatomy, but consequently, the whole science of medicine.

I know I never completely answered your question, I just wanted to explain it was E. None of the above.

Question 10
What is this structure name?
CH3 – CH2 - CH
CH – CH – CH2 - CH2
CH; CH – CH, -CH,
СН
CH3

Answers

cosh(-cosh(-CH

Simplify the expression using the symmetry of hyperbolic functions

cosh(cosh(CH))

Simplify the expression using the symmetry of hyperbolic functions

the answer is cosh(cosh(CH))

Place the events of a fight or flight situation in the correct order.

Question 3 options:

You spring into action

Your heart and lungs prepare to fight or run

You see the bear

Your brain sends signals to you adrenal and pituitary glands

Answers

Answer:

you see le bear

you brain sends signals

your heart and lungs receive said signals

spring to action

What is the balanced form of the chemical equation shown below?
C6H1206(s) + O2(g) → H20(1) + CO2(g)
-
+
A. C6H1206(s) + O2(g) → H2O(1) + CO2(9)
B. C6H1206(s) + 602(9) — 6H20() + 6C02(9)
C. CH2O(s) + O2(g) → H20(1) + CO2(9)
D. CH1206(s) + O2(g) – 12H20(1) + 6C02(9)

Answers

Answer:

B. C6H1206(s) + 602(9) → 6H20(l) + 6C02(9)

Explanation:

You can see that it's balanced;

C6H1206(s) + 602(g)           →            6H20(l) + 6C02(g)

 C  ⇒ 6                                                        C ⇒ 6

 H  ⇒ 12                                                       H ⇒ 6 x 2 = 12

 O  ⇒ 6 + (6 x 2) = 18                                  O ⇒ 6 + (6 x 2) = 18

what is another extraction that uses gravity filtration and describe it​

Answers

Answer -ˋˏ ༻༺ ˎˊ-

A common use for gravity filtration is for separating anhydrous magnesium sulfate (MgSO4) from an organic solution that it has dried (Figure 1.68b). Anhydrous magnesium sulfate is powdery, and with swirling in an organic solvent creates a fine dispersal of particles like a snow globe.

Consider the following chemical equation:

C2H8 + O2 --> CO2 + H2O

Which of the following would be the best practice(s) for balancing the equation? There may or may not be more than one correct answer.

A.Reduce the coefficients if possible.

B.Put a 2 in front of the hydrocarbon.

C.Split the hydrocarbon into individual elements.

D.Split the water into HOH.

E.Keep the hydrocarbon together.

Answers

The best way to balancing a combustion equation of an organic compound, like the one in the question, is to start balancing the carbon, then the hydrogen and finish with the oxygen. For that you have to split the hydrocarbon into individual elements. And once you have finished you shall always try to reduce the coefficient if possible. Therefore, the answers are A. and C.

Help with this please :) will mark Brainlyist if right

Answers

Answer:

3

Explanation:

Air is a mixture of (mostly) oxygen (molecular mass 16) and nitrogen (molecular mass 14) gases. At room temperature, which molecules in this room have more kinetic energy (on average)

Answers

The molecules of the two gases will have the same kinetic energy at room temperature.

The average kinetic energy of gaseous molecules can be calculated using the formula:

Kinetic Energy = 3/2RT, where R = constant and T = temperature in Kelvin

This means that the kinetic energy of a gaseous molecule is dependent on the temperature of the molecule only.

In other words, the molecular mass of molecules of gases has no bearing on the kinetic energy of each molecule.

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A 32.1 mole sample of gas has a temperature of 21 Celsius and a pressure of 2280.0 torr. What is the volume of the gas?

Answers

The volume of the gas is 27 ml

The calculation can be done as follows

The first step is to convert the pressure to atm

convert 2280 tors to atm

760 tors= 1 atm

= 2280/780

= 3 atm

The formula is

PV= nRT

The next step is to write out the parameters

Pressure= 3 atm

Temperature= 21 °C

no of moles= 32.1 mole

volume= ?

(r)constant= 8.314

3 × v= 32.1×8.314×21

3v= 81.080

V= 81.080/3

V= 27 ml

Hence the volume of the gas is 27 ml

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Suppose you are performing a titration. At the beginning of the titration, you read the titrant volume as 2.51 mL. After running the titration and reaching the endpoint, you read the titrant volume as 29.95 mL. What volume, in mL, of titrant was required for the titration

Answers

The volume of titrant required for the titration would be 27.44 mL

From the illustration, the initial titrant volume was 2.51 mL. This figure represents the initial reading on the burette.

In the same vein, the final volume of the titrant was 29.95 mL. This figure represents the final reading on the burette.

In order to get the volume of titrant used:

Volume of titrant used = final volume - initial volume

                             = 29.95 - 2.51

                                = 27.44 mL

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What would be the atomic number of this atom?

Answers

Answer:

1 would be the answer

protons = atomic # I think

Answer:

hydrogen

Explanation:

hydrogen has the atomic number of 1 which means that hydrogen has one proton and is neutral so it has one electron as well.

A carrot originally has a mass of 0.39g and after being left in a salt solution overnight it gained 0.3g. Calculate the percentage mass increase of the carrot.

Answers

Answer:

77%

Explanation:

The formula for finding percent change is change/original.

So, you have to do 0.3/0.39

You have to divide this to get 0.769 which can be rounded 0.77

0.77 as a percentage is 77%

So, the percentage mass increase of the carrot is 77%

how to experiment titration ​

Answers

Answer:

Add a volume of a solution of known concentration is added to a volume of another solution in order to determine its concentration. Solutions in which a few drops of phenolphthalein have been added turn from colorless to brilliant pink as the solution turns from acidic to basic.

If you want the method:

Method

1) Use a pipette and pipette filler to add 25 cm3 of alkali solution to a clean conical flask.

2) Add a few drops of a suitable indicator and put the conical flask on a white tile.

3) Fill the burette with dilute acid. Flush the tap through to remove any air bubbles. Ensure the burette is vertical.

4) Slowly add the acid from the burette to the conical flask, swirling to mix. (The mixture may at first change colour, and then back again when swirled.)

5) Stop adding the acid when the end-point is reached (when the colour first permanently changes). Note the final volume reading.

6) Repeat steps 1 to 5 until three results are repeatable (in close agreement). Ideally these should lie within 0.10 cm3 of each other.

I hope it helps.

Answer:

To conduct a titration experiment, first fill the burette with an acid or base solution of known concentration. After that, take a burette reading from the top of the miniscus down to the bottom. Then, underneath the burette, place a flask containing an unknown concentration of acid or base. After that, fill the flask halfway with the appropriate indicator and shake it up. Add your titrate to the flask one drop at a time while stirring constantly. Continue to add the titrate until the color change is noticeable. Finally, take one more look at the burette to make sure everything is correct.

Explanation:

Hope it helps:)

Help with this please

Answers

Answer:

12

Explanation:

There are 4 sulfur atoms in SO4

4×3=12

This means that it turns into 3×(SO4)

=3SO4

Elements that form diatomic molecules include
a oxygen
b hydrogen
C sodium
d two of the above

Answers

Answer:

D, two of the above, oxygen and hydrogen.

Explanation:

To solve this problem we can either use orbital stuff or common knowledge. Oxygen and hydrogen are known to form O2 and H2, while sodium forms metallic bonds between the atoms.

ethylene glycol, an antifreeze boils at 197 ⁰C. Convert 197 ⁰C to:
⁰F =
K =

Answers

[tex]\boxed{\sf °F=\dfrac{9}{5}°C+32}[/tex]

[tex]\\ \sf\longmapsto °F=\dfrac{9}{5}(197)+32[/tex]

[tex]\\ \sf\longmapsto °F=\dfrac{1773}{5}+32[/tex]

[tex]\\ \sf\longmapsto °F=354.6+32[/tex]

[tex]\\ \sf\longmapsto °F=386.6°F[/tex]

[tex]\rule{200pt}{5pt}[/tex]

[tex]\boxed{\sf K=°C+273}[/tex]

[tex]\\ \sf\longmapsto K=197+273[/tex]

[tex]\\ \sf\longmapsto K=470K[/tex]

If 22.5 L of nitrogen at 748 mm Hg are compressed to 725 mm Hg at constant temperature. What is the new volume?

Answers

Before

P1 : 748 mmHg

V1 : 22.5 L

After

P2 : 725 mmHg

V2 : ?

748 mmHg / 22.5 L = 725 mmHg / V2

Cross Multiply...

748 mmHgV2 = 16312.5 mmHgL

748 mmHgV2 / 748 mmHg = 16312.5 mmHgL / 748 mmHg

V2 = 21.808155 L

V2 = 21.8 L (sig figs)

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