who is smart ???

12-12+1+1+3-18=

Answer:

(-3,8)

Step-by-step explanation:

Given the coordinates of the endpoints of EF are E( – 9,11) and F(1,6). Point G is on EF and divides it such that EG:FG is 2:3.

Coordinate of G is expressed as shown;

X = ax1+bx2/a+b

X = -9(2)+3(1)/2+3

X = -18+3/5

X = -15/5

X = -3

Similarly;

Y = ay1+by2/a+b

Y = 2(11)+6(3)/2+3

Y = 22+18/5

Y = 40/5

Y = 8

Hence the coordinate of point G is at (-3,8)

Answer:

Hello! answer: 22.96

Step-by-step explanation:

Area is base × height × 1/2 or base × height ÷ 2

Im going to use the second method.

8.2 × 5.6 = 45.92 45.92 ÷ 2 = 22.96 therefore the answer is 22.96

Answer:

top x=22°

bottom x= 45°

m=22°

Step-by-step explanation:

The diagrams were lacking typical symbols in these types of problems so I made a few assumptions if it was drawn to scale.

Answer:

Adult tickets= 390

Student ticket= 410

Step-by-step explanation:

4A + 2.5S= 2585

A+ S = 800

A= 800-S

Substitute into the first equation

Answer:

is there anything else that can help?

Step-by-step explanation:

Answer:

Do you have a picture to see the triangles

Step-by-step explanation:

Answer:

A) the down payment was $ 1,746, B) the total amount of the montly payments is $ 11,632.32, C) the total cost is $ 13,378.32, and D) the finance charge is 14.93%.

Step-by-step explanation:

Given that Carl bought a sailboat for $ 11,640 on the installment plan, and the installment agreement included a 15% down payment and 18 monthly payments of $ 646.24 each, to determine A) how much is the down payment, B) what is the total amount of the monthly payments, C) what is the total cost she paid for the sailboat on the installment plan, and D) what is the finance charge, the following calculations must be performed:

A) 11,640 x 0.15 = 1,746

B) 18 x 646.24 = 11,632.32

C) 11,632.32 + 1,746 = 13,378.32

D) 11,640 = 100

     13,378.32 = X

     13,378.32 x 100 / 11,640 = X

     1,337,832 / 11,640 = X

     114.93 = X

Therefore, A) the down payment was $ 1,746, B) the total amount of the montly payments is $ 11,632.32, C) the total cost is $ 13,378.32, and D) the finance charge is 14.93%.

[tex]5x + 3y = 25 \\ 5x = 25 - 3y \\ x = \frac{25 - 3y}{5} \\ x = \frac{25}{5} - \frac{3y}{5} \\ x = 5 - \frac{3y}{5} \\ 3x + 4y = 26 \\ 3 (5 - \frac{3y}{5} ) + 4y = 26 \\ 15 + \frac{11y}{5} = 26 \\ \frac{11y}{5} = 26 - 15 \\ \frac{11y}{5} = 11 \\ \frac{5}{11} \times \frac{11y}{5} = 11 \times \frac{5}{11} \\ y = 5 \\ x = 5 - \frac{3y}{5} \\ x = 5 - \frac{3(5)}{5} \\ x = 2[/tex]

(x,y)—> (2,5)

Answer:

tan r = 35/12

Step-by-step explanation:

you use the rule tan=opposite/adjacent

The required ratio equivalent to tan(R) for triangle RTS is 35 / 12.

A triangle RTS is given with perpendicular = 35 base = 12 and the hypotenuse = 37

The triangle is a geometric shape that includes 3 sides and the sum of the interior angle should not be greater than 180°

The process in mathematics to operate and interpret the function to make the function or expression simple or more understandable is called simplifying and the process is called simplification.

Here,
In order to find out the ratio equivalent to tan(R).0
We know that,
tan(r) = perpendicular  / base
from given,
tan (R) = 35 / 12

Thus, the required ratio equivalent to tan(R) for triangle RTS is 35 / 12.

Learn more about triangles here: https://brainly.com/question/2773823

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Answer:

c is correct

Step-by-step explanation:

Answer:

earthquake

Step-by-step explanation:

I think it's right

Answer:

x  ≤ − 9

Step-by-step explanation:

x + 5 ≤ − 4

Subtract 5 from each side

x + 5-5 ≤ − 4-5

x  ≤ − 9

Answer:

39 sq km

Step-by-step explanation:

SA = area of the base + 1/2(perimeter of the base)(slant height)

= 3² + 1/2(3×4)(5)

= 9 + 6(5)

= 39

Answer:

28

Step-by-step explanation:

Tan-1(8 / 15)

The highlighted part is called Ray.

Answer:

12

Step-by-step explanation:

Since this is a right triangle, we can use the Pythagorean theorem

a^2 + b^2 = c^2  where a and b are the legs and c is the hypotenuse

a^2 + 9^2 = 15^2

a^2 +81 =225

Subtract 81 from each side

a^2 = 225-81

a^2 = 144

Take the square root of each side

sqrt(a^2) = sqrt(144)

a=12

Answer:

a = 12 meters

Step-by-step explanation:

Use pythagorean theorem to identify the missing leg

pythagorean theorem = [tex]a^2+b^2=c^2[/tex]

In this case, we are looking for a so...

[tex]a^2+b^2=c^2[/tex]

[tex]a^2+9^2=15^2[/tex]

[tex]a^2+81=225[/tex]

[tex]a^2=225-81[/tex]

[tex]a^2=144[/tex]

It doesn't make sense for a to be equal to 144 so we must square root 144

144 = [tex]12^{2}[/tex] meters

Final Answer: 12 meters

Answer:

[tex]\frac{8}{15}[/tex]

Step-by-step explanation:

2 x 4 = 8

3 x 5 = 15

8/15

Answer:

x = -1

Step-by-step explanation:

Answer:

Step-by-step explanation:

X=-1

Because,

If we add 1+(-1)

It would be 0.

Answer:c and f

Step-by-step explanation:

6.1E-4= 6.1 x 10^⁴ =0.00061

Answer:

Angle NKQ is 68 Degrees.

Step-by-step explanation:

With this, consider the arc that Angle NPQ is making. It is making an arc of 112 degrees since the Angle is coming out from the radius of the circle.

Now, there is also the arc 248 degrees for the remainder of the circle that is not within this angle's reach.

Since Angle NKQ shares these arcs, we can use the equation:

Big Arc + Small Arc / 2

to get the measure of this angle

(248 - 112) / 2

With this, Angle NKQ is 68 degrees.

Answer:

75.36.

Step-by-step explanation:

C= Pi D (Pi times diameter) so you do 3.14x 24 which then you get your answer of 75.36.

Answer:15

Step-by-step explanation: this is an equilateral triangle and 45-15-15=15 so no matter what it would be 15

Answer:

It's 15

Step-by-step explanation:

perimeter is sum of all the sides

15+15+v = 45

30+v = 45

subtract 30 from both sides

v = 45-30

= 15mm

Answer:

(5, - 3 )

Step-by-step explanation:

Under a refection in the line y = x

a point x, y ) → (y, x ), then

(- 3, 5 ) → (5, - 3 )

The reflection vector is (5, -3) after reflecting over line y = x the answer is (5, -3).

It is defined as the change in coordinates and the shape of the geometrical body. It is also referred to as a two-dimensional transformation. In the geometric transformation, changes in the geometry can be possible by rotation, translation, reflection, and glide translation.

We have:

The vector is (-3, 5)

The reflection line is y = x

The transformation rule:

(x, y) → (y, x)

(-3, 5) → (5, -3)

Thus, the reflection vector is (5, -3) after reflecting over line y = x the answer is (5, -3).

Learn more about the geometric transformation here:

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Answer:

The angle formed is ∠LMK and the intercepted arc is LK.

Step-by-step explanation:

The given figure shows a circle of radius M. L and K are other points on the circle.

The distance from the center of the circle to a point on the circle is called radius.

LM and MK are the radius of the circle or

LM = MK

The angle formed is ∠LMK.

The intercepted arc is LK.

Find the scale using the two bases:

9/12 = 3/4

The smaller triangle is 3/4 of the larger one.

Multiply the known side by 3/4

X = 8 x 3/4 = 6

X= 6

Answer:

4'999 + 664 = 5663

Step-by-step explanation:

all chickens laid one egg so that is 4'999 then the next day 664 of them laid one egg that is how I know what it is.

your  welcome for the help.

Answer:

See the attached image for the graph of the first system.

Step-by-step explanation:

Here's how to graph the first system.

Start with the inequality [tex]-y \le -2x-3[/tex].  You can make this easier to work with by multiplying through by -1.  Remember to switch the inequality sign when multiplying by a negative number.  OK, you get the inequality

[tex]y \ge 2x+3[/tex].

The graph will be a half-plane -- all the points on one side of a line.  The line that is the boundary of the half-plane has an equation:  [tex]y=2x+3[/tex] -- just use an  =  sign instead of the inequality sign.

Graph the line.

The equation of the line is in slope-intercept form:  y = mx + b, so you can tell the y-intercept is 3 and the slope is 2 (think of it as a fraction 2/1).  Graph the line by going to the point (0, 3) -- the y-intercept -- then use the slope 2/1 interpreted as "rise over run" to go up 2 units and right 1 unit, arriving at the point (1, 5).  Draw the line through those points, (0, 3) and (1, 5).

Now you have to decide which side of the line the inequality [tex]y \ge 2x+3[/tex] is describing. To do this, pick a point which is not on the line, plug its coordinates into the inequality; if the result is true, shade the side of the line the point you picked is on (if false, shade the other side!)

An easy point to pick in this case is the origin, (0, 0).  Put zeros in for x and y in the inequality, and you'll get the statement [tex]0 \ge 2(0)+3 \, \Rightarrow \, 0 \ge 3[/tex].  That's false, so shade the side of the line not containing the origin.  In the image below, the shading is in purple.

All right, now for the other inequality, [tex]x+2\le 0[/tex].  Subtract 2 from both sides and the inequality becomes [tex]x \le -2[/tex].  This, too, graphs as a half-plane whose boundary line has equation [tex]x=-2[/tex].  Graph the line.  A line with an equation that has  x  in it but not  y is a vertical line with all its x-coordinates equal to the number on the right side of the equation.  This line is vertical and goes through points such as (-2, 0).

Pick a point not on the line (the origin works again).  Put the coordinates into the inequality to get [tex]0\le -2[/tex] which is false.  Shade the side of the vertical line which does not contain the origin.  In the image below, the shading is in black.

Finally,  YAY!  \o/ ,  the solutions to the system are all the points in the plane that got shaded twice.  In the image, they are the cross-hatched points above the purple line and to left of the black line.

Note: If you get a system with three inequalities, you'll be graphing three half-planes and looking for points that got shaded three times!

Note: One of your questions has the inequalities [tex]x \ge 0[/tex] and [tex]y \ge 0[/tex] in it.  These two inequalities say that the x and y coordinates are both positive or zero, confining your attention to Quadrant I in the upper-right part of a graph, above the x-axis and to the right of the y-axis.