Will someone PLEASSSSSSEEEEEEEE help me

Answer:

-28.50

Step-by-step explanation:

Given the algebraic expression, 2w² - 3x + y - 8z, where w = -0.5, x = 2, y= -3, and z = 2.5:

Substitute the given values for the variables to evaluate the algebraic expression.

2w² - 3x + y - 8z

= 2(-0.5)² - 3(2) + (-3) - 8(2.5)

= 2(0.25) - 6 - 3 - 20

= 0.50 - 6 - 3 - 20

= -28.50

Therefore, 2w² - 3x + y - 8z = -28.50.

Answer:

-28.5

Step-by-step explanation:

Substitute the values for their given variables and evaluate.

[tex]2w^2-3x+y-8z\\\\2(-0.5)^2-3(2)+(-3)-8(2.5)\\\\2(0.25)-6-3-20\\\\0.5-6-3-20\\\\-28.5[/tex]

Answer:

i believe the and\swe is g because it is located within the boundaries of plane p but is on a line (not the green segments) that goes outside of plane p

Step-by-step explanation:

Answer:

c = 105 degres

Step-by-step explanation:

When two lines cross like that and form an x, the opposite sides are equal (so the angle below the 75 degree one is also 75 degees). Using this, you can figure out the rest.

If both the top an bottom are equal, you know that 150 degres are taken (75+75) and you know that there can only be 360 degres in total here, so you subtract 150 from 360 and get 210. Now you know that the last two sides together are 210, and since they are equal, you divide it by two to get 105 degrees.

Answer:

huuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuh

Answer:

(Hope this helps can I pls have brainlist (crown)☺️)

Step-by-step explanation:

(1) mean value = 6

use excel function POISSON(x,mean,cumulative)

set x = 4, mean =6 and cumulative = TRUE

P(X>4) =1 -POISSON(4,6,TRUE) = 0.7149

(2) mean value = 6

use excel function POISSON(x,mean,cumulative)

set x = 1, mean =6 and cumulative = TRUE

P(X \le 1) =POISSON(1,6,TRUE) = 0.0174

Answer:

-14

Step-by-step explanation:

2c + d

We are given the values of c and d:

c = -9

d = 4

We substitute in these values

2(-9) + 4 = ?

2 times -9 is -18

-18 + 4 = -14

2c + d = -14

Answer:

2

Step-by-step explanation:

18,16,14,12,10,8,6,4,2

Answer:

$15540 is 2.1% of 740,000 which is the same percent as the 920,000 which was 2.1 percent so your answer is $15540

Step-by-step explanation:

Answer:

Answer:

60

Step-by-step explanation:

Given : On a very hot summer day, 5 percent of the production employees at Midland States Steel are absent from work. The production employees are randomly selected for a special in-depth study on absenteeism.

To find : What is the probability of randomly selecting 10 production employees on a hot summer day and finding that none of them are absent?

Answer:

B. $7.04

Step-by-step explanation:

5.28 / 3 = 1.76

1.76 x 4 = 7.04

Answer:

a. Volume = π15.02 9.0=6361.73

b. I am very sorry, I don't know

Step-by-step explanation:

Answer:

it would take 100 days for it to get better that just makes sense I think and for number two it would be 365% better

Step-by-step explanation:

Answer: C

Step-by-step explanation: Round to the nearest 100

97 degrees

add up the two and subtract by 180

Answer:

b

Step-by-step explanation:

the answer is no.b as P(A)*P(B)

Answer: 105

Step-by-step explanation: if you are using a calculator, simply enter 84÷80×100 which will give you 105 as the answer.

Answer:

The answer will be:-  ( 0.8 oz ).

Answer:

y = x + 1

Step-by-step explanation:

Slope: (1-2)/(0-1) = -1/-1 = 1

y-intercept: 1 - (-2)(0) = 1

y = x + 1

Answer:

what's the question...?

Step-by-step explanation:

Leave a comment?

-2 1/2 - (-1 3/4)

When subtracting a negative vile the equation becomes addition:

-2 1/2 + 1 3/4 = -3/4

Answer: -3/4

Answer:

6.72

Step-by-step explanation:

Answer:

B

Step-by-step explanation:

Answer:

Good luck on the test <333

Step-by-step explanation:

m<1 = ? // m<2 = ? // m<3 = ? // m<4 = ?

First I want to find the third angle because I see 93 degrees + 3 equals 180, so angle 3 is 87.

Now I find angle 2, because it seems as angle 2 is the same as 49 degrees.

Now for angle 1 and 4, we now that angles in a triangle sum to 180°. So for angle 1 the equation is 180 - (49 + 68), which is 63.

For angle 4 the equation is 180 - (49 + 87), which is 44.

Answer:

Step-by-step explanation:

slope m = Δy/Δx = (6 - (-6)) / (2 - (-4)) = 12/6 = 2

b is the y intercept when x = 0.

b = 2

y = 2x + 2

Answer:

altogether can hold 360 books. Graphically solve a system of equations in order to determine the number of small boxes sent, x, and the number of large boxes sent, y.

Step-by-step explanation:

Answer:

Let be x the number of small boxes sent and y the number of large boxes sent.

Since each small box can hold 30 books (30x), each large box can hold 45 books (45y)and altogether can hold a total of 360 books, we can write the following equation to represent this:

30x+45y=360

According to the information provided in the exercise, there were 4 times as many large boxes sent as small boxes. This can be represented with this equation:

y=8-2x/3

Brainliest plz

alternate entireror angles are congurent by this rule you can find your answer by solving the equation

Answer:

[tex](A) - \sqrt2[/tex]

Step-by-step explanation:

Let's find the velocity and acceleration first:

[tex]v(t) = \dot x(t) = cos\ t -( -sin \ t) = cos \ t + sin \ t\\a(t) = \ddot x(t) = -sin\ t + cos\ t = cos\ t - sin t[/tex]

(you can also rewrite the position as [tex]\sqrt 2 sin(t-\frac\pi4)[/tex] and determine velocity and acceleration from there, but I do prefer handling it as a sum for the sake of the derivatives)

At this point, the first time when the velocity is 0 is given by

[tex]cos\ t + sin\ t = 0 \rightarrow cos\ t = - sin t \rightarrow tan\ t = -1 \\t = \frac34 \pi = 2.36s[/tex]

At this point the acceleration is (let's use the first value of t for the sake of our sanity!)

[tex]cos (\frac34 \pi) - sin \frac 34 pi = -\frac1{\sqrt2} -\frac1{\sqrt2} = \sqrt 2 = -1.41[/tex]

Answer:

Im not sure about A but other then that B and D have greater values then one

Step-by-step explanation:

[tex]~\hspace{7em}\textit{negative exponents} \\\\ a^{-n} \implies \cfrac{1}{a^n} ~\hspace{4.5em} a^n\implies \cfrac{1}{a^{-n}} ~\hspace{4.5em} \cfrac{a^n}{a^m}\implies a^na^{-m}\implies a^{n-m} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \boxed{A}\qquad \cfrac{3^{-2}}{3^3}\implies \cfrac{~~\frac{1}{3^2} ~~}{3^3}\implies \cfrac{~~\frac{1}{3^2} ~~}{\cfrac{3^3}{1}}\implies \cfrac{1}{3^3\cdot 3^2}\implies \cfrac{1}{3^5}\implies \cfrac{1}{243}\qquad \textit{\large \checkmark}[/tex]

[tex]\boxed{B}\qquad \cfrac{5^3}{5^2}\implies 5^3\cdot 5^{-2}\implies 5^{3-2}\implies 5^1\implies 5\qquad \bigotimes \\\\\\ \boxed{C}\qquad 9^0\implies 1\qquad \bigotimes \\\\\\ \boxed{D}\qquad \cfrac{(2^3)^2}{2^2}\implies \cfrac{2^{3\cdot 2}}{2^2}\implies \cfrac{2^6}{2^2}\implies 2^6\cdot 2^{-2}\implies 2^4\implies 16\qquad \textit{\large \checkmark} \\\\\\ \boxed{E}\qquad \cfrac{2^3}{2^8}\implies 2^3\cdot 2^{-8}\implies 2^{3-8}\implies 2^{-5}\implies \cfrac{1}{2^5}\implies \cfrac{1}{32}\qquad \bigotimes[/tex]