Write a compound inequality that the graph could represent.

Write A Compound Inequality That The Graph Could Represent.

Answers

Answer 1

Answer:

k < -4 or k > 13

Step-by-step explanation:

Let's take a look at the graph, we can see that the arrows point towards both directions, both dots are open, meaning that we can only have < and > signs. We can see that the arrow pointing to the left contains numbers that are less than -4, so that part of the compound inequality must be k < -4. And on the other side, they are numbers that are greater than 13, so that part must be k > 13. Thus, the answer must be d.

Hopes this helps.


Related Questions

how to graph transformations of quadratic functions

Answers

Answer:

Shift "h" units to the right, "k" units up, and reflect over the x or y axis when needed.

Step-by-step explanation:

1) I want to talk about reflections first.

Reflections across the x-axis --> [tex]y = ax^2[/tex], a is the coefficient. if a is negative, then the equation should be reflected across the x-axis. This is known as a vertical reflection. Reflections across the y-axis --> [tex]y=a(bx)^2[/tex], b is the coefficient. If b is negative, then reflect the equation over the y-axis. There are cases where the reflection across the y-axis does not change anything. But, let's say its [tex]y=(x-3)^2[/tex]... the reflection across the y-axis is different (that equation is: [tex]y=(-x-3)^2[/tex] )

2) Rigid transformations

Horizontal transformations (to the left or right): [tex]y=a(bx-h)^2[/tex], factor out b from "bx-h" and whatever h equals is the units to the right. If h is a negative number, then you move to the left. Vertical transformations (up and down): [tex]y = a(bx-h)^2+k[/tex]... k is just the units up... if k is negative then we move it down.

Example (check image for visual)

We transform [tex]y = x^2[/tex] to [tex]y = -(-x-3)^2+3[/tex] , you move right 3, then reflect across the x-axis, then reflect across y-axis, then move 3 up.

--------------------------------------------------------------------------------------------------------------

Note: In the image, the red line is the original function, the blue one is the transformed function. See if you can follow along with the verbal instructions I gave above.

The length of a certain rectangular prism is 3 less than twice the width. The height of the same prism is 4 more than
the width. Write an expression to represent the volume of the rectangular prism in terms of width (w).
V=2w? + 5w-12
V= -2w3 + 11w2 + 12w
V=2w3 +5w? - 12w
В.
С.
D
V=4w + 1

Answers

Answer:

it is c

Step-by-step explanation:

me big brain

HELP ASPAP!! ANSWER CORRECLTY

Answers

Answer:

17

Step-by-step explanation:

Answer:

plot 17

Step-by-step explanation:

12-(-5) = 12+5 = 17

What is the length of DF?
F
За
IT
E
G
a +6
D
DF =

Answers

Answer:

  18

Step-by-step explanation:

Triangles FEG and DEG are congruent by SAS, so DG = FG.

  a+6 = 3a

  6 = 2a

  3 = a

  3a = 3·3 = 9 = FG = DG

DF = 9+9 = 18

What is the value of the expression shown below, when p= 1 and q= 4

Answers

Answer:

The correct answer is 5.

Step-by-step explanation:

I got 100% on the assignment

1. Rosie orders dessert at the cafe. The total bill is $50. She tips the waiter 10%.
How much money does the waiter get?

Answers

Answer:

5

Step-by-step explanation:

this means it'll be $55

7 Point Question Tyler was trying to prove that all rhombuses are similar. He thought, “If I draw 2 rhombuses, I can find dilations that will take one rhombus exactly onto the other.” Then he wrote a proof. However, all rhombuses are not similar. Which steps in Tyler’s proof have flaws? Explain what is wrong with each step that is wrong. Step 1: Let ABCD and WXYZ be rhombuses. By the definition of a rhombus, AB≅BC≅CD≅DA and WX≅XY≅YZ≅ZW. Step 2: Dilate rhombus ABCD by the scale factor given by $$ WX AB​. Side A'B' will be the same length as WX because of how I chose the scale factor. Because all sides of a rhombus are congruent, B'C' will be the same length as WX and therefore the same length as XY, C'D' will be the same length as YZ, and A'D' will be the same length as WZ. That means all the corresponding sides of A'B'C'D' and WXYZ will be the same length. Step 3: If all the sides in 2 figures are proportional, then those 2 figures are similar, so there must be a sequence of transformations that take ABCD onto WXYZ using dilations and rigid motions. Step 4: Translate A'B'C'D' by the directed line segment A'W so that A″ and W coincide. Step 5: Rotate A″B″C″D″ by angle B″WX so that B‴ and X coincide. Now segments A‴B‴ and WX coincide. Step 6: If needed, reflect A‴B‴C‴D‴ over segment WX so that D⁗ and Z are on the same side of WX. Now segments A⁗D⁗ and WZ coincide. Step 7: Once 3 vertices of the rhombus are lined up, the other vertex has to line up as well or else the shapes wouldn’t be rhombuses. So, we have shown we can use rigid motions and dilations to line up any 2 rhombuses, and therefore, all rhombuses are similar. (Select all that apply.) Step 1 is incorrect. The definition of a rhombus does not say that all the sides are equal. Step 2 is incorrect. The scale factor is not $$ . Step 3 is incorrect. It is only true for triangles that if all the side lengths in a figure are proportional, the figures must be similar. Step 4 is incorrect. Translating by the directed line segment

Answers

A rhombus can have the same shape and dimension as a square or a

parallelogram, therefore, all rhombuses are not similar.

A step in the proof that have flaws is step 3.

Reasons:

By reading through the given steps, we have, the first step that is incorrect

is step 3.

Step 3: The requirement for the similarity of two figures based on the

proportionality of the corresponding sides of the figures is related with

triangles as given by the triangle proportionality theorem.

This is so because, the lengths of the sides of a triangle depends on the

opposite interior angle, while the side of a rhombus can have a

combination of large length and and acute angle.

Two rhombuses that have proportional sides may be dissimilar,

because they can have different interior angles.

Therefore;

The step in Tyler's proof that have a flaw is Step 3

Learn more about similarity between geometric figures here:

https://brainly.com/question/10270676

Which type of laboratory is not required to have coved floors (where the floor runs continuous for the wall for a few inches)

Answers

The type of laboratory that is not required to have coved floors is a BSL2.

Safety in laboratories is measured through the Biosafety Level scale. This scale evaluates how much protection do people working in the laboratory need to avoid any risks while working with pathogens or toxins.

This scale goes from 1 to 4 and the 4 level represents labs in which extremely dangerous pathogens are studied, and therefore labs with the highest safety protocols.

In this context, coved floors are not required for labs classified in Biosafety level 2 because in these labs pathogens have only a moderate risk, therefore some precautions such as the coved floors are not required.

Learn more about labs in: https://brainly.com/question/14428286

Solve this system of equations using the Substitution method. Don't forget to write your final answer as a coordinate point.

3x + y = -2

y = 2x + 3

Answers

Answer:

(x, y) = (-1, 1)

Step-by-step explanation:

Harry had $32. He spent all the money buying three notebooks for x dollars each and four packs of index cards for y dollars each. If Harry had bought five notebooks and five packs of index cards, he would have run short by $18. The following system of equations models this scenario: 3x 4y = 32 5x 5y = 50 Use the system of equations to solve for x and y. (8, 2) (1, 5) (2, 8) (5, 1).

Answers

Answer:

x = notebooks

y = indexboks

3x+4y=32 ( here is spent all money so I add 32 here )

5x+5y=50

by elemination method

3x+4y=32×5

5x+5y=50×4 ( here I'm going to eliminate y )

15 x+20y= 160

20x+20y= 200

- - = -

____________

-5x = -40

x = - 40 / -5

x = 8

here - × - = + so iam taking positive 8

now substitute the value of x in any equation

3×8+4y = 32

24 + 4y = 32

4y = 32-24

y = 8 / 4

y = 2

CHECKING

SUBSTITUTE BOTH VALUES IN ANY EQUATION

5×8+5×2 = 50

40 + 10 = 50

50 = 50

I SUBSTITUTE IN 2ND EQUATION

Answer:

(8,2)

Step-by-step explanation:

Given that:

3x + 4y = 32  --------- eq1

5x + 5y = 50 --------- eq2

From taking 5 common from eq2:

x + y = 10

Or it can also be written as:

x = 10 - y ----------eq3

Now put this value of x in eq1

3(10 - y) + 4y = 32

By simplifying:

30 - 3y +4y= 32

30 +y = 32

Subtracting 30 from both sides:

y = 32 - 30

y = 2

Putting value of y in eq 3

x = 10 - 2

x = 8

Juan texts 20 messages in 5 minutes. At this rate how many text messages can he send in 30 minutes

Answers

Answer:

The answer 120 MESSAGES

First make a ratio from messages to mins:

Messages/mins = 20/5=messages/30

Messages = (30x20)/5 = 120

Final answer : 120 messages

Simplify this question

Answers

[tex]\\ \sf\longmapsto √64+√-81-i^2[/tex]

[tex]\\ \sf\longmapsto 8+√81i-(-1)[/tex]

[tex]\\ \sf\longmapsto 8+9i+1[/tex]

[tex]\\ \sf\longmapsto 9i+9[/tex]

Please write a rule for this table BEGGING

Answers

Answer:

y = 3x = 1

Step-by-step explanation:

Answer:

y = 3x - 1

Step-by-step explanation:

Check. Plug in the given x, and see if the result is the given y:

y = 3x - 1

When: (x = 8 , y = 23)

23 = 3(8) - 1

23 = (3 * 8) - 1

23 = (24) - 1

23 = 23 (True).

When: (x = 2 , y = 5)

5 = 3(2) - 1

5 = (3 * 2) - 1

5 = 6 - 1

5 = 5 (True)

When: (x = -3 , y = -10)

-10 = 3(-3) - 1

-10 = (3 * -3) - 1

-10 = (-9) - 1

-10 = -10 (True).

When (x = 9 , y = 26)

26 = 3(9) - 1

26 = (3 * 9) - 1

26 = (27) - 1

26 = 26 (True).

When you graph, simply graph the given points (bolded) onto the graph.

I need help with this

Answers

Answer:

512

Step-by-step explanation:

64 × 8 = 512

512

64 8

16 4 2

8 2 2 1

f (x) = 3x - 2 - g (x) = 2x + 1

Answers

Answer:

Step-by-step explanation:

The answer is easy it’s 24

alex is running in a clockwise direction around a circular track with radius 60 yards. he runs for 20 minutes at a speed of 4 yards per second. find the shortest distance between their starting point and their ending point measured along the track

Answers

Answer:

  100.9 yards

Step-by-step explanation:

One circuit of the track is a distance of ...

  C = 2πr = 2π(60 yd) = 120π yd.

At Alex's running rate, the distance covered in 20 minutes is ...

  (4 yd/s)(20 min)(60 s/min) = 4800 yd

The number of circuits will be ...

  (4800 yd)/(120π yd/circuit) = 40/π circuits ≈ 12.7324 circuits

The last of Alex's laps is more than half-completed, so the shortest distance to his starting point is 13 -12.7324 = 0.2676 circuits,

That distance is (0.2676 circuits)×(120π yd/circuit) ≈ 100.88 yd

The shortest distance along the track to Alex's starting point is about 100.9 yards.

_____

Additional comment

The exact distance is 120(13π-40) yards. The distance will vary according to your approximation for pi. If you use 3.14, this is about 98.4 yards.

Please quickly answer number 17&18 I will give brainliest

Answers

Answer: 17) 150°C 18) 17 minutes

Step-by-step explanation:

x represents time in minutes and y represents temperature in Celsius

17) y=10x+30

y=10(12)+30

y=120+30

y=150 - Therefore, the water temperature will be 150°C after 12 minutes

18) 200=10x+30

10x+30=200

10x+30-30=200-30

10x=170

x=17  - Therefore, the water temperature will reach 200°C after 17 minutes

Answer this please!!!

Answers

Answer:

$40

Step-by-step explanation:

h(x) = x^2 - 5x +7
Find h(-5)

Answers

Answer:

57

Step-by-step explanation:

h(-5) = (-5)^2 - 5(-5) + 7

h(-5) = 25 + 25 +7

h(-5) = 57

Answer:

[tex]\bold{h(-5)=57}[/tex]

Step-by-step explanation:

Substitute [tex]-5[/tex] for everywhere there is [tex]x[/tex]

[tex]h(x) = x^2 - 5x +7\\=-5^2 - 5(-5) +7[/tex]

[tex]-5^2 - 5(-5) +7[/tex]

PEMDAS order of operations

Parenthesis

[tex]\bold{-5\times(-5)}\\=25[/tex]

[tex]-5^2+25 +7[/tex]

Exponents

[tex]\bold{-5^2}\\=-5\times-5\\=25[/tex]

[tex]25+25 +7[/tex]

Addition

[tex]25+25+7\\=50+7\\=57[/tex]

Therefore, [tex]\bold{h(-5)=57}[/tex].

Please don’t answer just for point! I really need help~

Answers

Pink and yellow are perpendicular

PLEASE HELP ASAP GOD BLESS YOU If YOU HELP ME IT WILL RAISE MY GRADE

Answers

Answer:

Hi i think its option 3 maybe just wait until someone else helps but i say option 3 but gl anyways

Step-by-step explanation:

The Answer is Option 3.

Write a general rule for finding the sign in a multiplication or division problem with more than two integers​

Answers

When you multiply two integers with the same signs, the result is always positive, When you multiply two integers with different signs, the result is always negative.

Hope you find this helpful!
Brainliest and a like is much appreciated!

if laura has a school loan of $420,a car loan of $300 and rent of $550,what must she budget just to pay those expenses?

Answers

Answer:

1270

Step-by-step explanation:

420+300+550

$420+300=720+550=1270

help please i’m doing homework and i can’t fail this lesson.

Answers

Answer: y = 3x +1

Step-by-step explanation:

Find the factors of f(x) given that x = −3 is a zero.
f(x) = x^3 + 12x^2 + 47x + 60
(x + 3)(x + 4)(x − 5)
(x + 3)(x + 4)(x + 5)
(x − 3)(x + 5)(x + 6)
(x + 3)(x + 3)(x − 3)

Answers

[tex]x^3+12x^2+47x+60\\\\=x^3+3x^2 +9x^2+27x+20x+60\\\\=x^2(x+3) + 9x(x+3)+20(x+3)\\\\=(x+3)(x^2+9x+20)\\\\=(x+3)(x^2 + 4x +5x +20)\\\\=(x+3)[x(x+4)+5(x+4)]\\\\=(x+3)(x+4)(x+5)[/tex]

The standard form of a quadratic equation is given as y=ax^2+bx+c and vertex form is given as y=a(x−h)^2+k. Write a formula that relates the values of a,b, and c in y=ax^2+bx+c to the values of a,h, and k in y=a(x−h)^2+k. For instance, h=ax+b would be a formula that relates h to a and b.

Answers

Answers:

[tex]h = -\frac{b}{2a}\\\\k = \frac{-b^2+4ac}{4a}\\\\[/tex]

where 'a' cannot be zero.

=========================================================

Explanation:

The vertex is (h,k)

The x coordinate of the vertex is h which is found through this formula

[tex]x = -\frac{b}{2a}[/tex]

For example, if we had the quadratic [tex]y = 3x^2-6x+5[/tex], then we'll plug in a = 3 and b = -6 to get: [tex]h = -\frac{b}{2a} = -\frac{-6}{2*3} = 1[/tex]

------------

To find the value of k, we plug that h value into the original standard form of the quadratic and simplify.

[tex]y = ax^2+bx+c\\\\k = ah^2+bh+c\\\\k = a\left(\frac{-b}{2a}\right)^2+b\left(\frac{-b}{2a}\right)+c\\\\k = a*\frac{b^2}{4a^2}+\frac{-b^2}{2a}+c\\\\k = \frac{b^2}{4a}+\frac{-b^2}{2a}+c\\\\[/tex]

[tex]k = \frac{b^2}{4a}+\frac{-b^2}{2a}*\frac{2}{2}+c*\frac{4a}{4a}\\\\k = \frac{b^2}{4a}+\frac{-2b^2}{4a}+\frac{4ac}{4a}\\\\k = \frac{b^2-2b^2+4ac}{4a}\\\\k = \frac{-b^2+4ac}{4a}\\\\[/tex]

It's interesting how we end up with the numerator of [tex]-b^2+4ac[/tex] which is similar to [tex]b^2-4ac[/tex] found under the square root in the quadratic formula. There are other ways to express that formula above. We need [tex]a \ne 0[/tex] to avoid dividing by zero. The values of b and c are allowed to be zero.

Answer:

The minimum is at (1,-8). In the equation y = (x – 1)2 – 8, h = 1 and c = 8. So, the x-coordinate of the minimum is the same as the h-value in the equation, and the y-value of the minimum is the opposite of the c-value.

Step-by-step explanation:

plato

A half circle is joined to an equilateral triangle with side lengths of 12 units.

What is the perimeter of the resulting shape? Type your answer in the box below.

Answers

Answer:

P = 12 pi units + 24 units.

Step-by-step explanation:

All sides of an equilateral triangle are of the same length.  Here that length is 12 units.  We take a circle of diameter 12 units and cut it in half through its center.  Finally, we join the triangle (remembering that all of the side lengths are 12 units) to the half circle of diameter 12 units.

The half circle portion of the resulting shape has circumference 2(pi)(12 units) divided by 2, or 12 pi units.  This is half the formula C = 2(pi)(r).  The two non-attached sides of the triangle have a total length of 24 units.

Thus, the perimeter of the resulting figure is P = 12 pi units + 24 units.

What is the following product? Assume x greater-than-or-equal-to 0 (4 x StartRoot 5 x squared EndRoot 2 x squared StartRoot 6 EndRoot) squared.

Answers

The simplified expression for the product [tex](4x\sqrt{5x^2} )(2x^2\sqrt{6})[/tex] is:

[tex]8\sqrt{30} x^4[/tex]

The given expression is:

[tex](4x\sqrt{5x^2} )(2x^2\sqrt{6})[/tex]

Note that :

[tex]\sqrt{5x^2} = x\sqrt{5}[/tex]

The given expression can then be re-written as:

[tex](4x^2\sqrt{5} )(2x^2\sqrt{6})[/tex]

Multiplying like terms together:

[tex]8x^4\sqrt{30}[/tex]

Finally, the resulting expression can be written as:

[tex]8\sqrt{30} x^4[/tex]

Learn more here: https://brainly.com/question/25913492

Answer:

D 104 x Superscript 4 + 16 x Superscript 4 Baseline StartRoot 30 EndRoot

Step-by-step explanation:

Edg 2022

An ice cream store has 31 flavors of ice cream and 10 toppings. A regular sundae has one flavor of ice cream, one topping, and comes with or without whipped cream. How many different ice cream sundaes can be ordered?

Answers

10 because there is only 10 toppings and each only comes with one topping!

Answer:

610

Step-by-step explanation:

31 x 10= different flavour and topping combination

x2 = for the whipped cream different option

Solve for all values of y in simplest form.
|4 - 5y| = 16

Answers

Answer:

[tex]y=-\frac{12}{5}[/tex]

   

I think this is the correct answer

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