Write a Perl program that uses a hash and a large number of operations on the hash. For example, the hash could store people’s names and their ages. A random- number generator could be used to create three- character names and ages, which could be added to the hash. When a duplicate name was generated, it would cause an access to the hash but not add a new element. Rewrite the same program without using hashes. Compare the execution efficiency of the two. Compare the ease of programming and readability of the two.

Answer:

and?

Explanation:

Answer:

(a): The base case: if(n<1)

(b): The recursive statement: recur(n / 5)

(c): Parameter 10 returns 7

Explanation:

Given

The above code segment

Solving (a): The base case:

The base case is that, which is used to stop the recursion. i.e. when the condition of the base case is true, the function is stopped.

In the given code, the base case is:

if(n<1)

Solving (b): The recursive statement:

The recursive statement is the statement within the function which calls the function.

In the given code, the recursive statement is:

recur(n / 5)

Solving (c): A call to recur() using 10

The base case is first tested

if (n < 1); This is false because 10 > 1

So, the recursive statement is executed

recur(n/5) +2=> recur(10/5)+2 => recur(2)+2

2 is passed to the function, and it returns 2

if (n < 1); This is false because 2 > 1

So, the recursive statement is executed

recur(n/5) +2=> recur(2/5)+2 => recur(0)+2

2 is passed to the function, and it returns 2

if (n < 1); This is true because 0 < 1

This returns 3

So, the following sum is returned

Returned values = 2 + 2 + 3

Returned values = 7

Answer:

Explanation:

The correct piece of code for the generic method in the question would be the following...

public static <TheType extends Number> long avgNum(TheType item1, TheType item2, TheType item3)

This declaration of the avgNum method declares this method as a Generic TheType method that is a subclass of the Number class. It also takes in generic parameters which are the same as the Generic class that was declared. Finally, outputting a long value which would be tripleSum / 3

Explanation:

Answer:

Explanation:

on what device

Answer:

x = 40

y = 46

Explanation is in the image above.

Answer:

Explanation:

The following code is written in Python, the function creates various nested loops to loop through each individual string comparing letter by letter in order to find the longest common substring. Finally, returning the substring itself.

def shared_motif(dna_list):

   substr = ''

   if len(dna_list) > 1 and len(dna_list[0]) > 0:

       for x in range(len(dna_list[0])):

           for i in range(len(dna_list[0]) - x + 1):

               if i > len(substr) and all(dna_list[0][x:x + i] in y for y in dna_list):

                   substr = dna_list[0][x:x + i]

   return substr

arr = ["GATTACA", "TAGACCA", "ATACA"]

stems = shared_motif(arr)

print(stems)

Answer:

hope it is helpful to you

Answer:

the manufacture of extremely small versions of electronic devices.

Explanation:

asks

mxskssssksskwlwslskamzmzmsmsmz

Answer:

Security policy is the minimum

Explanation:

Answer:

True

Explanation:

The background will always just be the background. You cannot blend two images together to make two background because it would be considered one background nonetheless.

Answer:

PHP

Explanation:

The best way to answer this question is to interpret it as, which of the three is a scripting language.

Analyzing each of the languages

1. C#

C# is not a scripting language, but instead it is an object-oriented programming language. Also, c# is a compiled language and one of the features of scripting language is that, they are interpreted.

2. PHP

Basically, PHP are used for server side scripting language because it uses scripts and its programs are not for general purpose runtime environment (but instead for special runtime environments).

3. HTML

HTML is neither a programming language, nor a scripting language because its design pattern does not follow that or programming and scripting languages, and it can not perform what an actual programming and scripting language do.

Answer:

thanks to the great place

Explanation:

hottest year in hindi history and happiness and the world is not a big deal to me because I think it's a good thing for a woman who has been a good friend of yours and happiness and be happy with examples

I don't have that tamagotchi

But I do have 2 tamagotchi's

I think it's a cherry on your tamagotchi

Hoped this helped!

Have a wonderful day-

Answer:

Explanation:

Please specify which programming language this is supposed to be written in.

Without knowing that, only the last part can be answered "how many different initial speeds will you need to test this code?"

You will need to test at least 3 initial speeds: one below the lower-set-speed, one between the lower- and upper-set-speed and last one which is above the upper-set-speed.

Answer:

format floating-point numbers in fixed-point notation

Explanation:

Required

Function of fixed manipulator

This question will be answered from the perspective of C++ programming language (however, the explanation is applicable to programming languages that uses fixed manipulators)

Fixed manipulators in C++ is used to set floating point numbers to a stated  fixed point.

Take for instance;

double pi = 3.1415926534;

cout.precision(2);

cout<< fixed << pi;

The third line of the program where the fixed manipulator is used to format pi to 2 fixed point notation.

Hence, the output will be 3.14

Answer: True

Explanation:

The term floating point is derived from the fact that there is no fixed number of digits before and after the decimal point; that is, the decimal point can float. There are also representations in which the number of digits before and after the decimal point is set, called fixed-pointrepresentations.

Answer:

It's true

Explanation:

Answer:

The function in Python is as follows:

def search_file(filename,mystring):

my_dict = {}

count = 0

file = open(filename)

lines = file.readlines()

for line in lines:

 count+=1

 if mystring.lower() in line.lower():

  my_dict[count] = line.rstrip('\n')

return my_dict

Explanation:

This defines the function

def search_file(filename,mystring):

This initializes an empty dictionary

my_dict = {}

This initializes the number of lines to 0

count = 0

This opens the file

file = open(filename)

This reads the lines of the file

lines = file.readlines()

This iterates through the lines

for line in lines:

This increments the number line

 count+=1

This checks if the string exists in the line

 if mystring.lower() in line.lower():

If yes, the line number and the string are added to the dictionary

  my_dict[count] = line.rstrip('\n')

This returns the dictionary

return my_dict

Answer:ok

Explanation:

Answer:

index.html

Explanation:

The name of the html file for the homepage of a website is usually "index.html"

Answer:

Explanation:

The following code is written in Python. It is a loop that asks the user for an input. If it contains a comma then it removes whitespace, splits it into two words, and prints each word seperately, and exits the loop. If it does not contain a comma then it prompts the user for another input.

while True:

   string = input("Enter input string: ")

   if ',' in string:

       string = string.replace(" ", '')

       string_split = string.split(',')

       print("First word: " + string_split[0])

       print("Second word: " + string_split[1])

       break

PLEASE HELP ME FIX THIS CODE.

I WANT IT TO HAVE USER INPUT TO CHANGE AND IMAGE FILTER TO BLUE RED OR GREEN.

user_color = input("What color would you like to paint the canvas, blue, red or green?:")

def user_red(pixel):

pixel[0] = 100 + pixel[0]

pixel[1] = 100 - pixel[1]

pixel[2] = 100 - pixel[2]

return pixel

def user_green(pixel):

pixel[0] = 100 + pixel[0]

pixel[1] = 100 - pixel[1]

pixel[2] = 100 - pixel[2]

return pixel

def user_blue(pixel):

pixel[0] = 100 + pixel[0]

pixel[1] = 100 - pixel[1]

pixel[2] = 100 - pixel[2]

return pixel

def custom_filter(image, user_color):

for x in range(image.get_width()):

for y in range(image.get_height()):

pixel = image.get_pixel(x,y)

new_colors = invert_pixel(pixel)

image.set_red(x, y, new_colors[0])

image.set_green(x, y, new_colors[1])

image.set_blue(x, y, new_colors[2])

return image

def change_image():

global image

image = custom_filter(image, user_color)

timer.set_timeout(change_image, IMAGE_LOAD_TIME)

Answer:

B

Explanation:

Answer:

The program in C++ is as follows:

#include <iostream>    

using namespace std;

int perimeter(int side1, int side2, int side3){

return side1+side2+side3;

}

struct Triangle  {

int side1;  int side2;   int side3;

};

int main(void) {

int side1, side2, side3;

cout<<"Sides of the triangle: ";

cin>>side1>>side2>>side3;

struct Triangle T;

T.side1 = side1;

T.side2 = side2;

T.side3 = side3;  

cout << "Perimeter: " << perimeter(T.side1,T.side2,T.side3) << endl;

return 0;

}

Explanation:

See attachment for complete code where comments are as explanation

the location of the arrow determines it

Answer:

A. An analog audio signal is measured at regular intervals. Each measurement is stored as a sample, which is represented at the lowest level as a sequence of bits.

Explanation:

I took the test

The command interpreter or the command-line interface is one of the ways a user can interface with the operating system. The command interpreter's main task is to understands and executes commands which it turns into system calls. The kernel is the central module of an OS.

_________________

Brainliest would be greatly appreciated!

I found this!

_________________

#SpreadTheLove

#SaveTheTrees

- Mitsu JK

Answer:

The function is as follows:

import random

import string

def solution(riddle):

   s = list(riddle)

   for i in range(len(riddle)):

       alpha = "".join(random.choice(string.ascii_letters) for x in range(1))

       alpha = alpha.lower()

       if s[i] == '?':

           if i > 0 and i < len(s)-1:

               if s[i+1] != alpha:

                   s[i] = alpha

               elif s[i-1] != alpha:

                   s[i] = alpha

               else:

                   i=i

           else:

               if i == 0:

                   if s[1] != alpha:

                       s[i] = alpha

                   else:

                       i = i

               else:

                   if s[i-1] != alpha:

                       s[i] = alpha

                   else:

                       i = i

   riddle = ""

   for ele in s:

       riddle+=ele

   return riddle

Explanation:

See attachment for explanation where comments are used to explain some lines

In this exercise we have to use the knowledge of the python language to write the code, so we have to:

The code is in the attached photo.

So to make it easier the code can be found at:

import random

import string

def solution(riddle):

  s = list(riddle)

  for i in range(len(riddle)):

      alpha = "".join(random.choice(string.ascii_letters) for x in range(1))

      alpha = alpha.lower()

      if s[i] == '?':

          if i > 0 and i < len(s)-1:

              if s[i+1] != alpha:

                  s[i] = alpha

              elif s[i-1] != alpha:

                  s[i] = alpha

              else:

                  i=i

          else:

              if i == 0:

                  if s[1] != alpha:

                      s[i] = alpha

                  else:

                      i = i

              else:

                  if s[i-1] != alpha:

                      s[i] = alpha

                  else:

                      i = i

  riddle = ""

  for ele in s:

      riddle+=ele

  return riddle

See more about python at brainly.com/question/26104476

Answer:

Explanation:

Mechanical engineers give Presentations when they work on projects and Proposals. Often, professional Presentations require you to verbally and graphically present preliminary designs to colleagues.

Hope this helped!!!

Answer:

Explanation:

The following code is written in Java, it creates the entire complex class as requested so that it works with the main method that has been provided in the question without having to change anything in the main method. Proof of output can be seen in the attached picture below

import java.util.Scanner;

class Test implements Cloneable{

   public static void main(String[] args) {

       Scanner input = new Scanner(System.in);

       System.out.print("Enter the first complex number: ");

       double a = input.nextDouble();

       double b = input.nextDouble();

       Complex c1 = new Complex(a, b);

       System.out.print("Enter the second complex number: ");

       double c = input.nextDouble();

       double d = input.nextDouble();

       Complex c2 = new Complex(c, d);

       System.out.println("(" + c1 + ")" + " + " + "(" + c2 + ")" + " = " + c1.add(c2));

       System.out.println("(" + c1 + ")" + " - " + "(" + c2 + ")" + " = " + c1.subtract(c2));

       System.out.println("(" + c1 + ")" + " * " + "(" + c2 + ")" + " = " + c1.multiply(c2));

       System.out.println("(" + c1 + ")" + " / " + "(" + c2 + ")" + " = " + c1.divide(c2));

       System.out.println("|" + c1 + "| = " + c1.abs());

       Complex c3 = c1;

       System.out.println(c1 == c3);

       System.out.println(c3.getRealPart());

       System.out.println(c3.getImaginaryPart());

   }

}

class Complex implements Cloneable {

   public interface Cloneable { }

   private double realPart;

   public double getRealPart() {

       return realPart;

   }

   public void setReal(double real) {

       this.realPart = real;

   }

   private double imaginaryPart;

   public double getImaginaryPart() {

       return imaginaryPart;

   }

   public void setImaginary(double imaginary) {

       this.imaginaryPart = imaginary;

   }

   public Complex(double a, double b) {

       realPart = a;

       imaginaryPart = b;

   }

   public Complex(double a) {

       realPart = a;

       imaginaryPart = 0;

   }

   public Complex() { }

   public Complex add(Complex comp2) {

       double real1 = this.getRealPart();

       double real2 = comp2.getRealPart();

       double imaginary1 = this.getImaginaryPart();

       double imaginary2 = comp2.getImaginaryPart();

       return new Complex(real1 + real2, imaginary1 + imaginary2);

   }

   public Complex abs() {

       double real1 = Math.abs(this.getRealPart());

       double imaginary1 = Math.abs(this.getImaginaryPart());

       return new Complex(real1, imaginary1);

   }

   public Complex subtract(Complex comp2) {

       double real1 = this.getRealPart();

       double real2 = comp2.getRealPart();

       double imaginary1 = this.getRealPart();

       double imaginary2 = comp2.getRealPart();

       return new Complex(real1 - real2, imaginary1 - imaginary2);

   }

   public Complex multiply(Complex comp2) {

       double real1 = this.getRealPart();

       double real2 = comp2.getRealPart();

       double imaginary1 = this.getRealPart();

       double imaginary2 = comp2.getRealPart();

       return new Complex(real1 * real2, imaginary1 * imaginary2);

   }

   public Complex divide(Complex comp2) {

       double real1 = this.getRealPart();

       double real2 = comp2.getRealPart();

       double imaginary1 = this.getRealPart();

       double imaginary2 = comp2.getRealPart();

       return new Complex(real1 / real2, imaginary1 / imaginary2);

   }

   public String toString() {

       String result;

       result = realPart + " + " + imaginaryPart + "i";

       return result;

   }

}