Write the equation of a line that is perpendicular to y=14x - 4 and passes through the point (28, 16)
Write a linear function for the values given in the table below
Answers
A function whose equation is of the form y = ax + b, where a and b are constants, a does not equal zero, and x is any real number, and whose graph is a straight line.
Given an equation y = 14x -4 there is an equation that is perpendicular to this given equation.
from the slope-intercept of a linear equation:
The linear function equation is the slope-intercept form. Thus, it is expressed as f(x) = mx + b where m is the slope and b is the y-intercept of the line.
thus the slope of the given equation is 14
The slope of the required equation = 1/14
Since both equations are perpendicular
From the slope intercept of the required line equation of a line:
y = 1/14x + c...(2)
Since, it passes through the point (28, 16)
Thus, 16 = 1/14 *28 + c
c = 16
from equation 2
y = 1/14 x + 14
from the table, two given coordinates of a linear function are (4, 36) and (6, 56)
thus slope of the line = (y₂ - y₁) / (x₂ - x₁)
Slope of the line = 20/2 = 10
Equation of a line:
y = 10x +c
Since, it passes through the point (4, 36)
Thus, 36 = 40 + c
c = -4
Therefore, the required equation from the table is y = 10x - 4
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Related Questions
Who can solve these equations?
Answers
let's hmmm hmmm multiply both sides by the LCD of all denominators, that way we do away with the denominators and see what "x" is
[tex]\cfrac{x+1}{2}+\cfrac{x+2}{3}=3-\cfrac{x+3}{4}\implies \stackrel{\textit{multiplying both sides by }\stackrel{LCD}{12}}{12\left( \cfrac{x+1}{2}+\cfrac{x+2}{3} \right)=12\left( 3-\cfrac{x+3}{4} \right)} \\\\\\ (6x+6)+(4x+8)=36-(3x+9)\implies 10x+14=36-3x-9 \\\\\\ 10x+14=27-3x\implies 10x=13-3x\implies 13x=13 \\\\\\ x=\cfrac{13}{13}\implies x=1 \\\\[-0.35em] ~\dotfill[/tex]
[tex]\cfrac{1-4x}{10}-\cfrac{2x+1}{2}=\cfrac{5x+1}{5}\implies \stackrel{\textit{multiplying both sides by }\stackrel{LCD}{10}}{10\left( \cfrac{1-4x}{10}-\cfrac{2x+1}{2}\right)=10\left( \cfrac{5x+1}{5} \right)} \\\\\\ (1-4x)-(10x+5)=10x+2\implies 1-4x-10x-5=10x+2 \\\\\\ -14x-4=10x+2\implies -4=24x+2\implies -6=24x \\\\\\ \cfrac{-6}{24}=x\implies -\cfrac{1}{4}=x[/tex]
two cards are drawn from a shuffled deck of 52 cards. what is the probability that the first card is a king and the second is a heart
Answers
On solving the provided question, we can say that the required probability is = 13/204.
What is probability?Probability theory, a subfield of mathematics, gauges the likelihood of an occurrence or a claim being true. An event's probability is a number between 0 and 1, where approximately 0 indicates how unlikely the event is to occur and 1 indicates certainty. A probability is a numerical representation of the likelihood or likelihood that a particular event will occur. Alternative ways to express probabilities are as percentages from 0% to 100% or from 0 to 1. the percentage of occurrences in a complete set of equally likely possibilities that result in a certain occurrence compared to the total number of outcomes.
probability of 1st card = 1/4
since the card is not replaced
total number remaining cards = 51
second card 13/51
the required probability is = 13/204
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Can someone help me find x for both
Answers
On solving the provided question, we can say that - the value of x in triangle ABD is = 60
What is triangle?Three sides and three vertices make up a triangle, which is a polygon. It is among the fundamental forms in geometry. Triangle ABC is the name given to a triangle with vertices A, B, and C. When the three points are not collinear, a unique plane and triangle in Euclidean geometry are found. A triangle is a polygon that has three sides and three corners. The spots where the three sides join end to end make up the triangle's corners. Three triangle angles added together equal 180 degrees.
here, in triangle ABD
x = 60
as its acute angle
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Find a basis for the eigenspace corresponding to each listed eigenvalue of A below.
A = 4 0 -1 14 5 -10 2 0 1 λ=5,2,3
A basis for the eigenspace corresponding to λ = 5 is { }. (Use a comma to separate answers as needed.) A basis for the eigenspace corresponding to λ = 2 is { }. (Use a comma to separate answers as needed.) A basis for the eigenspace corresponding to λ = 3 is . { }. (Use a comma to separate answers as needed.)
Answers
The basis for the eigenspace corresponding to lambda=5,1,4 are None,[tex]\left[\begin{array}{c}-1 \\\frac{1}{2} \\0\end{array}\right][/tex] and [tex]$\left[\begin{array}{l}2 \\ 1 \\ 1\end{array}\right]$[/tex]
[tex]$$A=\left[\begin{array}{ccc}5 & -12 & 10 \\0 & 7 & -3 \\0 & 6 & -2\end{array}\right]$$[/tex]
Eigenspace corresponding to lambda=5,1,4
The eigenspace E_lambda corresponding to the eigenvalue lambda is the null space of the matrix a [tex]\mathrm{A}-(\lambda) \mathrm{I}"[/tex]
for lambda=5
[tex]$$\mathrm{E}_5=\mathrm{N}(\mathrm{A}-5 \mathrm{I})$$[/tex]
Reducing the matrix A-5I by elementary row operations
[tex]$$\begin{aligned}A-5 I & =\left[\begin{array}{ccc}5-5 & -12 & 10 \\0 & 7-5 & -3 \\0 & 6 & -2-5\end{array}\right] \\& =\left[\begin{array}{ccc}0 & -12 & 10 \\0 & 2 & -3 \\0 & 6 & -7\end{array}\right] \\& \sim\left[\begin{array}{ccc}0 & -12 & 10 \\0 & 1 & -\frac{3}{2} \\0 & 6 & -7\end{array}\right] R_2 \rightarrow \frac{R_2}{2} \\& \sim\left[\begin{array}{ccc}1 & 0 & -8 \\0 & 1 & -\frac{3}{2} \\0 & 6 & -7\end{array}\right] R_1 \rightarrow R_1+2 R_2\end{aligned}$$[/tex]
[tex]\sim\left[\begin{array}{ccc}1 & 0 & -8 \\ 0 & 1 & -\frac{3}{2} \\ 0 & 0 & 2\end{array}\right] R_3 \rightarrow R_3-6 R_2$$\\\sim\left[\begin{array}{ccc}1 & 0 & -8 \\ 0 & 1 & -\frac{3}{2} \\ 0 & 0 & 1\end{array}\right] R_3 \rightarrow \frac{\mathrm{R}_3}{2}$$\\\sim\left[\begin{array}{ccc}1 & 0 & 0 \\ 0 & 1 & -\frac{3}{2} \\ 0 & 0 & 1\end{array}\right] \mathrm{R}_1 \rightarrow \mathrm{R}_1+8 \mathrm{R}_3$[/tex]
[tex]$\sim\left[\begin{array}{lll}1 & 0 & 0 \\ 0 & 1 & 0 \\ 0 & 0 & 1\end{array}\right] R_2 \rightarrow R_2+\frac{2 R_3}{2}$[/tex]
The solutions x of A-5I=0 satisfy x_1=x_2=x_3=0 that is, the null space solves the matrix
[tex]$$\left[\begin{array}{lll}1 & 0 & 0 \\0 & 1 & 0 \\0 & 0 & 1\end{array}\right]\left[\begin{array}{l}x_1 \\x_2 \\x_3\end{array}\right]=\left[\begin{array}{l}0 \\0 \\0\end{array}\right]$$[/tex]
Hence The null space is [tex]\left[\begin{array}{l}0 \\ 0 \\ 0\end{array}\right] E_5[/tex] has no basis
[tex]$$\begin{aligned}& \text { case: } 2 \\& \text { for } \lambda=1 \\& \mathrm{E}_5=\mathrm{N}(\mathrm{A}-(1) \mathrm{I})\end{aligned}$$[/tex]
we reduce the matrix A-I by elementary row operations as follows.
[tex]$$\begin{aligned}A-1 & =\left[\begin{array}{ccc}5-1 & -12 & 10 \\0 & 7-1 & -3 \\0 & 6 & -2-1\end{array}\right] \\& =\left[\begin{array}{ccc}1 & -3 & \frac{5}{2} \\0 & 6 & -3 \\0 & 6 & -3\end{array}\right] R_1 \rightarrow \frac{R_1}{4} \\& \sim\left[\begin{array}{ccc}1 & -3 & \frac{5}{2} \\0 & 1 & -\frac{1}{2} \\0 & 6 & -3\end{array}\right] R_2 \rightarrow \frac{R_2}{6}\end{aligned}[/tex]
[tex]$$$\sim\left[\begin{array}{ccc}1 & 0 & 1 \\ 0 & 1 & -\frac{1}{2} \\ 0 & 6 & -3\end{array}\right] R_1 \rightarrow R_1+3 R_2$\\$\sim\left[\begin{array}{ccc}1 & 0 & 1 \\ 0 & 1 & -\frac{1}{2} \\ 0 & 0 & 0\end{array}\right] R_3 \rightarrow R_3-6 R_2$[/tex]
Thus, the solutions x of (A-I) X=0 satisfy
[tex]$\left[\begin{array}{ccc}1 & 0 & 1 \\ 0 & 1 & -\frac{1}{2} \\ 0 & 0 & 0\end{array}\right]\left[\begin{array}{l}x_1 \\ x_2 \\ x_3\end{array}\right]=\left[\begin{array}{l}0 \\ 0 \\ 0\end{array}\right]$[/tex]
x_3=t
[tex]$\Rightarrow \mathrm{x}_1=-\mathrm{t}, \mathrm{x}_2=\frac{\mathrm{t}}{2}$[/tex]
[tex]$\vec{x}=\left[\begin{array}{c}-t \\ \frac{t}{2} \\ t\end{array}\right]=\left[\begin{array}{c}-1 \\ \frac{1}{2} \\ 1\end{array}\right] t$[/tex]
The Basis for the nullspace A-I will be: [tex]$\left.\left(\begin{array}{c}-1 \\ \frac{1}{2} \\ 1\end{array}\right]\right)$[/tex]
case:3
lambda=4
[tex]$$\mathrm{E}_5=\mathrm{N}(\mathrm{A}-(4) \mathrm{I})$$[/tex]
we reduce the matrix A-4I by elementary row operations as follows.
[tex]$\begin{aligned} A-4 \mid & =\left[\begin{array}{ccc}5-4 & -12 & 10 \\ 0 & 7-4 & -3 \\ 0 & 6 & -2-4\end{array}\right] \\ & =\left[\begin{array}{ccc}1 & -12 & 10 \\ 0 & 3 & -3 \\ 0 & 6 & -6\end{array}\right] \\ & \sim\left[\begin{array}{ccc}1 & -12 & 10 \\ 0 & 1 & -1 \\ 0 & 6 & -6\end{array}\right] R_2 \rightarrow \frac{R_2}{3}\end{aligned}$[/tex]
[tex]$\begin{aligned} & \sim\left[\begin{array}{ccc}1 & 0 & -2 \\ 0 & 1 & -1 \\ 0 & 6 & -6\end{array}\right] \mathrm{R}_1 \rightarrow \mathrm{R}_1+12 \mathrm{R}_2 \\ & \sim\left[\begin{array}{ccc}1 & 0 & -2 \\ 0 & 1 & -1 \\ 0 & 0 & 0\end{array}\right] \mathrm{R}_3 \rightarrow \mathrm{R}_3-6 \mathrm{R}_2\end{aligned}$[/tex]
Thus, the solutions x of (A-4IX)=0 satisfy
[tex]$$\left[\begin{array}{ccc}1 & 0 & -2 \\0 & 1 & -1 \\0 & 0 & 0\end{array}\right]\left[\begin{array}{l}x_1 \\x_2 \\x_3\end{array}\right]=\left[\begin{array}{l}0 \\0 \\0\end{array}\right]$$[/tex]
x_3=t
[tex]$\Rightarrow \mathrm{x}_1=2 \mathrm{t}, \mathrm{x}_2=\mathrm{t}$[/tex]
[tex]$$\vec{x}=\left[\begin{array}{c}2 t \\t \\t\end{array}\right]=\left[\begin{array}{l}2 \\1 \\1\end{array}\right] t$$[/tex]
The Basis for the nullspace A-4 I will be [tex]\left(\left[\begin{array}{l}2 \\ 1 \\ 1\end{array}\right]\right)[/tex]
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Solve.
7 Jordan shoots 100 3-point shots per basketball practice.
She makes 44 of these shots. What decimal represents the
number of shots she makes?
8 At a county fair, 9 people out of 1,000 earned a perfect score
in a carnival game. What decimal represents the number of
people who earned a perfect score?
Answers
Answer:
7. .44
8. .009
Step-by-step explanation:
7. 44 ÷ 100 = .44
8. 9 ÷ 1000 = .009
A wire 30 inches long is bent into a triangle with sides measuring 6 inches, 11 inches, and 13 inches Find the measure of the largest angle in the triangle.
Answers
The triangle's internal angles add up to 180 degrees. The biggest angle is then 95.22° in size.
What is trigonometry?
Trigonometry is the study of angles and the angular relationships between planar and three-dimensional shapes.
The cosecant, cosine, cotangent, secant, sine, and tangent are the trigonometric functions (sometimes known as the circle functions) that make up trigonometry.
These functions' inverses are designated by the notations csc(-1)x, cos(-1)x, cot(-1)x, sec(-1)x, sin(-1)x, and tan(-1)x.
Keep in mind that f(-1) here refers to the inverse function, not f to the -1 power.
According to our question-
the biggest angle on a wire that is 30 inches long and bent into a triangle with sides that measure 6 inches, 11 inches, and 13 inches.
cosine rule is given as
cosa= a^2 + b^2 + c^2/2ab
cosa = 36 + 121 - 169/132
a = 95.22°
Hence, The triangle's internal angles add up to 180 degrees. The biggest angle is then 95.22° in size.
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What number would you need to multiply the first equation by to eliminate the y variable when solving the system of equations by elimination?
Answers
We would need to multiply the first equation by -4 to eliminate the y variable when solving the system of equations by elimination.
The first equation is: 3x + 4y = 5
To eliminate the y variable when solving the system of equations by elimination, we need to multiply the first equation by -4. This is because when two equations are multiplied by the same number, any terms that have the same variable will be eliminated when the equations are added together.
Formula:
3x + 4y = 5
-4(3x + 4y = 5)
3x + 4y = 5
-12x - 16y = -20
Thus, we would need to multiply the first equation by -4 to eliminate the y variable when solving the system of equations by elimination.
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this diagram shows 3cm x 5 cm x 4 cm cubiod
find ac give your answer in 2 decimal place
Answers
The length AC will be 5.83 and the angle ACD will be 34.45°.
What is trigonometry?The branch of mathematics that sets up a relationship between the sides and the angles of the right-angle triangle are termed trigonometry.
The trigonometric functions, also known as a circular, angle, or goniometric functions in mathematics, are real functions that link the angle of a right-angled triangle to the ratios of its two side lengths.
The length AC will be calculated as,
AC² = 5² + 3²
AC = √ ( 25 + 9 )
AC = √34
AC = 5.83
The angle ACD will be,
tanθ = P / B
θ = tan⁻¹ = ( 4 / 5.83)
θ = 34.45°
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In the diagram, two circles, each with center $D$, have radii of $1$ and $2$. The total area of the shaded region is $\frac5{12}$ of the area of the larger circle. How many degrees are in the measure of (the smaller) $\angle ADC$
Answers
Angle ADC = 120 degrees.
What is area of sector?A certain portion of a circle that is created based on two radius of the same circle and one arc. Area of sector for a circle with radius r is given by π r²Ф/ 360°
What is the angle of ADC in the smaller circle?
Given, two circles of radius 1 unit and 2 unit which have same center D.
We know area of a circle = π r²
Area of larger circle = π 2² = 4π
it is said that the total area of the shaded region that means area of a particular sector is 1/12 of the area of the larger circle.
area of sector, ACD = 1/12 ×4π
as per the question, the ACD sector is located in the smaller circle that has radius 1 unit.
formula for area of sector ACD = π r² ×Ф/360°
where,Фis the central angle of ACD sector
and Ф = ADC
from the above statement, 4π/12 = π r² ADC/360
ADC = 1/3×360°
ADC = 120 degrees
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There are 7 1/2 pounds of potatoes. 1/6 of the potatoes are rotten. What is the weight of good potatoes. Fraction form
Answers
Answer:
6 1/4 pounds
Step-by-step explanation:
There are 7 1/2 pounds of potatoes, which is equivalent to 7 1/2 = 7.516=120
120 ounces of potatoes.
If 1/6 of the potatoes are rotten, then 1/6*120 = 20
20 ounces of potatoes are rotten.
Thus, the weight of the good potatoes is 120-20 = 100
100 ounces.
Converting this back to pounds, we get
100/16 = 6 1/4
6 1/4 pounds.
The foundation for a new high school building is rectangular in shape, and the area is [tex]5x^3 + 4x^2 - 10x - 8[/tex] square meters. Factor by grouping to find expressions for the dimensions of the building
Answers
The dimensions of the building are (x² - 2)(5x + 4). The result is obtained by using the expression for the dimensions.
How to factor by grouping?Grouping is a specific technique used to factor polynomial equations. You can use it with quadratic equations and polynomials that have four terms. The method is slightly different.
Here is how to factor by grouping:
Look at the equation and find the master product (ac).Find the factors of ac that the sum is equal to b.Split the center term into two factors.Group the terms to form pairs.Factor out each pair and factor out the shared parentheses.The area of the new high school building in a rectangular shape is 5x³ + 4x² - 10x - 8. Factor by grouping to find the dimensions!
Follow the steps on how to factor by grouping.
5x³ + 4x² - 10x - 8
= (5x³ + 4x²) - (10x - 8)
= x²(5x + 4) - 2(5x - 4)
= (x² - 2)(5x + 4)
Hence, the dimensions of the building are (x² - 2)(5x + 4).
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What is the estimated perimeter of an ellipse if the major axis has a length of 15 ft and the minor axis has a length of 7.5 ft
Answers
The estimated perimeter of an ellipse if the major axis has a length of 15 ft and the minor axis has a length of 7.5 ft id found to be 37.3 feet .
Perimeter is calculated as
= 2*pi*r*r
= 2 *3.14 * sqrt (15/2² +7.5/2²)/2
= 6.28 x sqrt (56.25+14.0625/2 6.28) *sqrt (35.15625) 6.28 * 5.929270613
= 37.235 feat
An ellipse is the locus of all the points on a plane whose distances from two fixed points in the plane are always same. The fixed points, which are encompassed by the curve, are known as foci , singular of focus.
The constant ratio is the eccentricity of the ellipse and the fixed line is directrix. Eccentricity is an element of ellipse which denotes elongation and is symbolized by the letter 'e'.
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please help:
find BP
Answers
Answer:
so i will be honest I've done this before and it may be 64 or 120
Step-by-step explanation:
It may be one of these answers I'm doing as much as I can to help
Can you help me with this
Answers
Answer: slope=2
Step-by-step explanation:
using y=mx+b, we know the equation of the line is y=2x. The slope is the m term so we know that the slope is 2.
Is the simplified form of 2 square foot 3. Square Foot 12 rational
Answers
The simplified form of the given radical expression is rational.
What is exponent ?Exponent can be defined as the method of expressing large numbers in terms of powers. Exponent refers to how many times a number multiplied by itself. For example, 6 is multiplied by itself 4 times, i.e. 6 × 6 × 6 × 6.
We are asked to determine whether the simplified form of 2√3.√12
To solve our given problem we will use exponent property for radicals
√m.√n = a√m.n
2√3.√12=2√3.12
2√3.√12=2√36
2√3.√12=2×6
2√√3.√12=12
The simplified form of the given radical expression is rational.
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Since our given radical expression simplifies to a rational, therefore, our answer is yes
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When Souta went to Sweden, 1 Swedish krona was worth about 0. 12 US
dollar. He took d dollars on the trip. Which equation could be used to find
the value in Swedish krona, k, of the dollars?
A
k = 0. 12d
B
d
k=
0. 12
с
0. 12
k=
d
D k= 1. 12d
Answers
If 1 Swedish krona was worth 0.12 US dollar , and if he took d dollars for the trip then the equation that is used to find the value in Swedish krona (k) of the dollars is option (a) [tex]k = 0.12\times d[/tex] .
The value of 1 Swedish krona is = 0.12 US dollar ,
the number of dollar that Souta took on the trip is = d dollars ;
we have to find the equation that can be used to find the equation in Swedish krona "k" of the dollars ,
According to the question ,
the equation for Swedish krona can be represented as [tex]k = 0.12\times d[/tex] ;
Therefore , the required equation is [tex]k = 0.12\times d[/tex] .
The given question is incomplete , the complete question is
When Souta went to Sweden, 1 Swedish krona was worth about 0.12 US dollar. He took d dollars on the trip. Which equation could be used to find the value in Swedish krona, k, of the dollars ?
(a) k = 0.12d
(b) dk = 0.12
(с) 0.12k = d
(d) k = 1.12d
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Mi Morgan i a cience teacher he found that 30% of her 120 tudent are athlete and Mr. Gregory i a math teacher he found that 27 or 15% of hi tudent are athlete
Answers
Of the part, the whole, and the percent, a. the exact number of students that are athletes is unknown to Ms. Morgan, which is 36, and b. the total strength of the students is unknown to Mr. Gregory which is 180.
Here we need to know 3 things- the total no. of students each teacher has, the percentage of athletes, and no. of students that are athletes.
a)
As we can see in the case of Ms. Morgan, we know the total strength of the students and the percentage of the students that are Athletes. Hence what we don't know here is the exact number of students that are athletes.
Hence we need to find 30% of 120
= 30/100 X 120
= 36 students.
b)
Here, in Mr. Gregory's case, we know the percentage and the actual number of students that are athletes. Hence, here we don't know the total strength of the students Mr. Gregory has.
Total strength = no. of athletes X 100/percent of athletes
= 27 X 100/15
= 180 students.
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Complete Question
Ms. Morgan is a science teacher. She found that 30% of her 120 students are athletes. Mr. Gregory is a math teacher. He found that 27, or 15%, of his students, are athletes. a. Of the part, the whole, and the percent, which information is still unknown to Ms. Morgan? Find this unknown value. b. Of the part, the whole, and the percent, which information is still unknown to Mr. Gregory? Find this unknown value.
How do you find the two missing sides of an acute triangle?
Answers
Using the Pythagorean Theorem (a2 + b2 = c2), plug in the known side lengths to solve for the two unknown sides of an acute triangle.
1. Identify the two known side lengths of the triangle.
2. Plug the known side lengths into the Pythagorean Theorem equation (a2 + b2 = c2).
3. Solve for the two unknown sides of the triangle.
4. The two unknown sides are the lengths of the missing sides of the triangle.
5. To solve for the unknown side lengths, first, calculate the hypotenuse (the longest side) by finding the square root of the sum of the squares of the two shorter sides.
6. Then, calculate the shorter sides by subtracting the square of the hypotenuse from the sum of the squares of the two shorter sides.
7. Finally, use the Pythagorean Theorem to calculate the missing side lengths.
8. The two missing side lengths will be the unknown side lengths of the triangle.
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Barrett earns $15 per hour cutting grass and $10 per hour tutoring reading. In one month, Barrett
needs to save at least $400 for a new lawnmower but does not want to work more than 35 hours.
Part A: Let x represent the hours cutting grass and y represent the hours tutoring. Given x ≥ 0 and
y ≥ 0, select all the inequalities that represent the situation.
A. x + y ≥ 35
B. 15x + 10y ≤ 400
C. x + y ≤ 35
D. 15x + 10y ≥ 400
E. 25x + 25y ≤ 400
F. 15x + 10y ≤ 35
Part B: Determine whether each point is a viable or nonviable solution according to the above scenario.
Viable Nonviable
(10, 25)
(10, 20)
(20, 12)
(35, 0)
(20, 20)
Answers
The inequalities that represent the situation are 15x + 10y ≥ 400 and x + y ≤ 35 and the viable solutions are (10, 25), (20, 12), (35, 0) and (20, 20)
The inequalities that represent the situation.From the question, we have the following parameters that can be used in our computation:
Earnings from cutting = $15Earning from tutoring = $10Number of hours = not more than 35Total earnings = At least $400These parameters above mean that
15x + 10y = Total earnings
x + y = Number of hours
So, we have
15x + 10y ≥ 400
x + y ≤ 35
The above represent the inequalities of the situation
The viable solutionsIn (a), we have
15x + 10y ≥ 400
x + y ≤ 35
Next, we test the options
(10, 25)
15 * 10 + 10 * 25 ≥ 400 ⇒ 400 ≥ 400
10 + 25 ≤ 35 ⇒ 35 ≤ 35
True
(10, 20)
15 * 10 + 10 * 20 ≥ 400 ⇒ 350 ≥ 400
10 + 20 ≤ 35 ⇒ 30 ≤ 35
False
(20, 12)
15 * 20 + 10 * 12 ≥ 400 ⇒ 420 ≥ 400
20 + 12 ≤ 35 ⇒ 32 ≤ 35
True
(35, 0)
15 * 35 + 10 * 0 ≥ 400 ⇒ 525 ≥ 400
35 + 0 ≤ 35 ⇒ 35 ≤ 35
True
(20, 20)
15 * 20 + 10 * 20 ≥ 400 ⇒ 500 ≥ 400
20 + 20 ≤ 35 ⇒ 40 ≤ 35
False
Hence, the viable solutions are (10, 25), (20, 12), (35, 0) and (20, 20)
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What is the smallest positive multiple of $13$ that is greater than $500?$
Answers
500 divided by 13 is a little over 38 so multiplying 13 by 38 will give you 494 and multiplying 13 by 39 will give you 507
Answer:
Step-by-step explanation:
The smallest possible multiple of 13 dollars greater than 500 dollars would be 507 which is 13*39 (i assume you mean whole numbers when you say positive numbers, if not the other answer would be 13*38.461)
I need help with polynomials
Here is the equation
Answers
The solution to the polynomial is x = -1, x = 1/2 and x = -1
How to solve the polynomial expressionFrom the question, we have the following parameters that can be used in our computation:
2x³ - x² - 2x + 1
Expand
2x³ - x² - 2x + 1 = 2x³ - x² - 2x + 1
Factorize the expression
This gives
2x³ - x² - 2x + 1 = x²(2x - 1) - 1(2x - 1)
Factor out 2x - 1
2x³ - x² - 2x + 1 = (x² - 1)(2x - 1)
Express x² - 1 as difference of two squares
2x³ - x² - 2x + 1 = (x - 1)(x + 1)(2x - 1)
So, we have
(x - 1)(x + 1)(2x - 1) = 0
Solve for x
x = 1, x = -1 and x = 1/2
Reorder the solutions
x = -1, x = 1/2 and x = -1
Hence, the solution is x = -1, x = 1/2 and x = -1
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How do you explain irrational numbers to children?
Answers
The irrational numbers to children can be explained as the numbers that can be written as a nonrepeating or nonterminating decimal .
What are Irrational Numbers ?
The real numbers that can be represented as a nonrepeating or a nonterminating decimal but not as a fraction, and the decimal that goes on forever without repeating.
For Example : [tex]\sqrt{2} , \sqrt{5} , \sqrt{7}[/tex] are few example of irrational numbers .
In simpler words : the irrational number is a number that is not rational. which means It is a number which cannot be written as a ratio of two integers or cannot be written as fraction.
and If a fraction has a 0 in the denominator , it is an irrational number .
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what are the properties of rational exponents and how are they used to solve problems
Answers
The properties of the rational exponents are given and a rational equation is of the form b = aˣ
What are the laws of exponents?When you raise a quotient to a power you raise both the numerator and the denominator to the power. When you raise a number to a zero power you'll always get 1. Negative exponents are the reciprocals of the positive exponents.
The different Laws of exponents are:
mᵃ×mᵇ = mᵃ⁺ᵇ
mᵃ / mᵇ = mᵃ⁻ᵇ
( mᵃ )ᵇ = mᵃᵇ
mᵃ / nᵃ = ( m / n )ᵃ
m⁰ = 1
m⁻ᵃ = ( 1 / mᵃ )
Given data ,
Let the rational exponent equation be A
Now , the properties of the exponent equations are
mᵃ×mᵇ = mᵃ⁺ᵇ
The powers of the exponents are added together
mᵃ / mᵇ = mᵃ⁻ᵇ
The powers of the exponents are subtracted together
( mᵃ )ᵇ = mᵃᵇ
The powers of the exponents are multiplied together
mᵃ / nᵃ = ( m / n )ᵃ
m⁰ = 1
Any number raised to the power of 0 is 1
m⁻ᵃ = ( 1 / mᵃ )
Hence , the exponents are solved
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n^2-2n-3=0 complete the square method
Answers
Answer:
n = - 1 , n = 3
Step-by-step explanation:
n² - 2n - 3 = 0 ( add 3 to both sides )
n² - 2n = 3
to complete the square
add ( half the coefficient of the x- term)² to bpth sides
n² + 2(- 1)n + 1 = 3 + 1
(n - 1)² = 4 ( take square root of both sides )
n - 1 = ± [tex]\sqrt{4}[/tex] = ± 2 ( add 1 to both sides )
n = 1 ± 2
Then
n = 1 - 2 = - 1
n = 1 + 2 = 3
The sun of a number, x, and 1/2 is equal to 4. What set of equations correctly repaints x
Answers
The set of equations correctly representing x are as follows:
(x + 1/2) and (x = 7/2).
What exactly is a set or group of equations?A set or group of equations that you solve all at once is referred to as a "system" of equations. The simplest linear system is one that has two equations as well as two variables. Linear equations (those that graph as straight lines) are easier to understand than non-linear ones.
What is the name of an equation system?Systems of equations in mathematics are a collection of relationships between different unknown variables that can be stated in terms of algebraic expressions. They are also known as simultaneous equations. Graphing, substitution, as well as elimination by addition, are methods that can be used to find the solutions to a basic system of equations.
According to the given information:Sum means addition (+).
Given that sum of a number, x and 1/2 is 4.
This means the adding two numbers
x+1/2=4
Now make x the subject of formula,
x=4-1/2
Finding the L.C.M = 8-1/2
x=7/2
∴ x=3 1/2
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A salesperson at a jewelry store earns 9% commission each week. Last week, sold $750
worth of jewelry. How much did make in commission? How much did the jewelry store make from sales?
Answers
The amount made in commission is $67.5.
The amount made in sales by the store is $682.5.
What is a percentage?The percentage is calculated by dividing the required value by the total value and multiplying by 100.
Example:
Required percentage value = a
total value = b
Percentage = a/b x 100
Example:
50% = 50/100 = 1/2
25% = 25/100 = 1/4
20% = 20/100 = 1/5
10% = 10/100 = 1/10
We have,
Amount sold last week = $750.
Commission = 9%
The amount of commission.
= 9/100 x 750
= $67.5
The sales made last week by the store.
= 750 - 67.5
= $682.5
Thus,
$67.5 was made in commission.
$682.5 was made from sales.
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Which expression is modeled by this set of arrows on the number line?
Answers
On solving the provided question, we can say that - here in number line we jump fron 2 to 7 as we have added +5
what is number line?A number line is a visual representation of real numbers used in introductory mathematics. It is an image of a magnitude line. On the number line, each point represents a real number, and each real number is taken to represent a point. Increments on a number line are separated by equal distances. You can only respond to the numbers on a line in the manner indicated by those numbers. How the number is utilized is determined by the question that goes with it. B: Make a point.
here,
we have +5
so 2+(+5) = 7
we will jump to 7 from 2
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jacks meeting stared at 2:45 pm and ended at 5:25 pm how long did the meeting last
Answers
Jacks meeting lasted for 160 min or 2 hrs 40 min.
What is Time?Time is the continued sequence of existence and events that occurs in an apparently irreversible succession from the past, through the present, into the future.
Given is that jacks meeting stared at 2:45 pm and ended at 5:25 pm.
The time for which the meeting lasted can be written as -
{i} = 2:45 pm
{i + 60 minutes} = 3:45 pm
{i + (2 x 60) minutes} = 4:45 pm
{i + (2 x 60 + 40) minutes} = 5:25 pm
{f} = 5 : 25 pm
The meeting lasted for -
2 x 60 + 40
160 minutes
or
2 hours 40 minutes
Therefore, Jacks meeting lasted for 160 min or 2 hrs 40 min.
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What are the 3 types of terms in quadratic equation?
Answers
The 3 types of terms in quadratic equation:
1) quadratic term,
2) linear term,
3) constant term.
We know that the second degree algebraic equation in x is a quadratic equation.
The standard form of quadrtic equation is ax^2 + bx + c = 0, where a, b, c are integers.
As thise is a quadratic equation, the value of a can not be zero. a ≠ 0
The term ax^2 is called the quadratic term.
From this term, the name given to the equation(quadrtic equation)
The term bx is called the linear term.
And the term c is called the constant term.
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What is the name of a 3 4 5 triangle?
Answers
The right angle triangle is the name of the 3, 4, and 5 triangles.
A right-angled triangle is a triangle with one of the angles at 90 degrees. A 90-degree angle is called a right angle.
The formula states that in a right triangle:
The square of the hypotenuse is equal to the sum of the square of the base and the square of the altitude.
(Hypotenuse)² = (Base)² + (Altitude)²
c²=a²+b²
The three numbers which satisfy the above formula are the Pythagorean triplets
Properties of right angle:
The largest angle is always 90º and called the hypotenuse which is always the side opposite to the right angle.
The measurements of the sides follow the Pythagoras rule, which cannot have any obtuse angle.
consider c=5 a=3, b=4 substitute in above formula:
5²=3²+4²
⇒25=9+16
⇒25=25
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