Answer:
3rd law beacuse there a flies
HELPPPPPPP !!!!!! PLS A 0.050 kg Truck moving right at 0.20 m/s collides with a toy race car weighing 0.015 kg initially at rest on a frictionless track. the truck keeps moving right at 0.15 m/s after Collision what is the final speed of the race car?
Answer:
[tex]v_f=0.15\:\mathrm{m/s}[/tex]
Explanation:
From the Law of Conservation of Momentum, we can write the following equation:
[tex]m_1v_1+m_2v_2=m_fv_f[/tex]
Because the toy car was initially at rest, [tex]m_2v_2=0[/tex].
Therefore, we can plug in given values and solve for [tex]v_f[/tex]:
[tex]m_1v_1=m_fv_f,\\0.050\cdot 0.20 = (0.050+0.015)v_f,\\v_f=\fbox{$0.15\:\mathrm{m/s}$}[/tex] (two significant figures).
Derive Isothermal process through ideal gas.( derive it numerically)
Explanation:
Hope it helps..........
Se necesita subir una carga de 500 kg (4900 N) a una altura de 1.5 m deslizándola sobre una rampa inclinada. ¿Qué longitud debe tener la rampa si sólo se puede aplicar una fuerza de 1633.33 N?
Answer:
4.22 m
Explanation:
Una rampa es una máquina que se utiliza para levantar un objeto con una fuerza menor a la que realmente necesitarías. Cuanto mayor sea la longitud de la rampa, menor será la magnitud de la fuerza necesaria para levantar el objeto.
Dado que:
altura de la rampa = 1.5 m, carga = 4900 N, fuerza aplicada = 1633.33 N.
La fórmula de la rampa se da como:
fuerza aplicada * longitud de la rampa = peso de la carga * altura de la rampa
1633.33 * longitud de la rampa = 4900 * 1.5
longitud de la rampa = 4900 * 1.5 / 1633.33
longitud de la rampa = 4.22 m
. Which Of The Following Will Produce Diffuse Reflection Of Light?
[A] Plane mirror and piece of paper
[B] Piece of paper and still water in lake
[C] Plane mirror and leather bag
[D] Piece of paper and leather bag
Answer:
A. Plane mirror and piece of paper
Explanation:
Diffuse reflection is the reflection of light or other waves or particles from a surface such that a ray incident on the surface is scattered at many angles rather than at just one angle as in the case of specular reflection. An ideal diffuse reflecting surface is said to exhibit Lambertian reflection, meaning that there is equal luminance when viewed from all directions lying in the half-space adjacent to the surface.
From what Tim explains in the movie, what can you infer about the temperature inside a refrigerator?
Answer:
It's closest to 3 degrees celsius
Explanation:
A cell of e.m.f 1.5 v and internal resistance 2.5 ohm is connected in series with an ammeter of resistance 0.5 ohm and a resistor of resistance 7.0 ohm. Calculate the current in the circuit.
Answer:
The current in the circuit is 0.15 Ampere
Explanation:
The given parameters of the cell are;
The electromotive force (e.m.f.) of the cell, E = 1.5 V
The resistance of the cell, r = 2.5 ohm
The resistance of the ammeter = 0.5 ohm
The resistance of the resistor = 7.0 ohm
The formula for the e.m.f., E of a cell is given as follows;
e.m.f. E = I·(R + r)
Where;
I = The current in the circuit
R = The sum of the resistances in the circuit = 7.0 Ω + 0.5 Ω + 2.5 Ω = 10 Ω
Therefore, we have;
[tex]The \ current \ in \ the \ circuit, \ I = \dfrac{E}{R + r}[/tex]
Substituting the known values, gives;
[tex]I = \dfrac{1.5 \ V}{7 \ \Omega + 0.5 \ \Omega + 2.5 \ \Omega} = \dfrac{1.5 \ V}{10 \ \Omega} = 0.15 \ A[/tex]
The current in the circuit, I = 0.15 Ampere.
in which diagram 1 or 2 would the person be experiencing winter? explain
Answer: Diagram 2
In diagram 1, the person in the northern hemisphere gets more sunlight compared to someone in the southern hemisphere. So diagram 1 has summertime in the northern hemisphere.
Conversely, diagram 2 has the southern hemisphere get more sunlight, so the northern hemisphere is experiencing winter.
A 5.0\, \text {kg}5.0kg5, point, 0, start text, k, g, end text box is at rest on a table. The static friction coefficient \mu_sμ
s
mu, start subscript, s, end subscript between the box and table is 0.500.500, point, 50, and the kinetic friction coefficient \mu_kμ
k
mu, start subscript, k, end subscript is 0.300.300, point, 30. Then, a 20\,\text N20N20, start text, N, end text horizontal force is applied to the box.
What is the best estimate of the magnitude of the box’s acceleration?
Answer:
25 N
Explanation:
When a force is applied to an object, for it to move it has to overcome the frictional force. The frictional force is perpendicular to the surface on which it acts. For an object at rest, it is acted upon by static friction, this friction must be overcome before the object can move, while a moving object is resisted by kinetic friction that prevents it from moving.
Since the box is at rest, it is acted upon by a static friction.
mass = 5 kg, acceleration due to gravity = 10 m/s², static friction coefficient = 0.5
Weight of the box = mass * acceleration due to gravity = 5 * 10 = 50 N
The applied horizontal force (F) is:
[tex]F=\mu_s*weight=0.5*50\\\\F=25\ N[/tex]
Answer:
0 m/s^2
Explanation:
khan academy
Question 1
3 pts
There is an apple with a mass of 14 kg that is attached to the tree 12
m above the ground (on earth). How much Gravitational Potential
Energy does the apple have? (Round to the nearest tenth)
Hint g= 9.8 (m/s^2)
*
Answer:
[tex]\boxed {\boxed {\sf 1646.4 \ J }}[/tex]
Explanation:
Gravitation potential energy can be found using this formula:
[tex]E_P=m*g*h[/tex]
where m is the mass, g is the gravtiational acceleration, and h is the height.
The mass of the apple is 14 kilograms and it is 12 meters above the ground. Since this is on Earth, the acceleration due to gravity is 9.8 m/s².
[tex]m= 14 \ kg \\g= 9.8 \ m/s^2 \\h= 12 \ m[/tex]
Substitute the values into the formula.
[tex]E_p= ( 14 \ kg )( 9.8 \ m/s^2)(12 \ m)[/tex]
Multiply.
[tex]E_p= (137.2 \ kg*m/s^2)(12 \ m )[/tex]
Multiply again.
[tex]E_P= 1646.4 \ kg*m^2/s^2[/tex]
1 kg*m²/s² is equal to 1 Joule. Our answer of 1646.4 kg*m²/s² is equal to 1646.4 Joules[tex]E_p=1646.4 \ J[/tex]
This is already rounded to the tenth place, so it's the final answer.
The apple has 1,646.4 Joules of gravitational potential energy.
Can someone help? Please?
Answer:
A. Speed
Explanation:
Speed is the magnitude of velocity, which is given in the question. Velocity is a vector quantity and therefore has both a magnitude and a direction. Only the former is implied in the question.
A 30 kg dog runs at a speed of 15
What is the dog's kinetic energy?
A car starts from rest and accelerates at a constant rate of 3.5 m/s2. What is the car’s velocity after the car has traveled 800 m?
Answer:
Attached is the answer
Explanation:
The car’s velocity after the car has traveled 800 m is 74.83 m/sec.
What is velocity?When an item is moving, its velocity is the rate at which its direction is changing as seen from a certain point of view and as measured by a specific unit of time.
Using equation of motion, initial velocity u = 0 and acceleration a = 3.5 unit and distance travelled is 800 m.
v² = u² + 2as
v² = 0 + 2*3.5*800
v² = 5600
v = 74.83 m/sec
The car’s velocity after the car has traveled 800 m is 74.83 m/sec.
To learn more about velocity refer to the link
brainly.com/question/18084516
#SPJ2
PLZ PLZ PLZ PLZ PLZ PLZ PLZ HELPPPPPPPPPPPPPPPPP
Answer:
endoplasmic reticulum
In a normal Earth atmosphere, a feather will free fall through the air more slowly than a brick because of what force?
A. Terminal velocity
B. Momentum
C. Weightlessness
D. Air Resistance
Answer:
Air Resistance
Explanation:
Because air gives a much greater resistance to the falling motion of the feather than it does to the brick.
dew forms when humid air cools overnight. if the temperature falls below freezing, blank will form instead
Someone pls help me with this!
Answer:
F=8.87 N
Explanation:
Coulomb's Law
The electrostatic force between two charged objects is directly proportional to the product of their charges and inversely proportional to the square of the distance between the two objects.
Written as a formula:
[tex]\displaystyle F=k\frac{q_1q_2}{d^2}[/tex]
Where:
[tex]k=9\cdot 10^9\ N.m^2/c^2[/tex]
q1, q2 = the objects' charge in coulomb
d= The distance between the objects in meters
Object 1 has a charge of
[tex]q_1=-2.3\cdot 10^{-6}\ c[/tex]
Object 2 has a charge of
[tex]q_2=-4.2\cdot 10^{-6}\ c[/tex]
They are separated by a distance of
d = 0.099 m
Calculate the force:
[tex]\displaystyle F=9\cdot 10^9\frac{2.3\cdot 10^{-6}*4.2\cdot 10^{-6}}{0.099^2}[/tex]
F=8.87 N
Two copper spheres are currently 0.5 meters apart. One sphere has a charge of
+3.4x10-4 C and the other has a charge of -5.6*10-4 C. What is the force between
the charged spheres? (k=8.89*10' Nm²/C2)
0 -6839.17 N
0 1200 N
0 5497.45 N
6839.17 N
Answer:
6839.17 N
Explanation:
From the question given above, the following information were obtained:
Distance apart (r) = 0.5 m
Charge 1 (q₁) = +3.4×10¯⁴ C
Charge 2 (q₂) = -5.6×10¯⁴ C
Electrical constant (K) = 8.98×10⁹ Nm²/C²
Force (F) =.?
F = Kq₁q₂ / r²
F = 8.98×10⁹ × 3.4×10¯⁴ × 5.6×10¯⁴ / 0.5²
F = 1709.792 / 0.25
F = 6839.17 N
Thus, the force of attraction between the two charged spheres is 6839.17 N
Please help i don't get it.
Which image matches the Topographic Map Shown?
Also, please explain how your answer is the correct answer. Why is your answer correct?
Answer:
the answer is 4
Explanation:
the picture matches eachother that's why I picked 4
Answer:
devils tower
Explanation:
on the topographic map the circular lines stop at at certain point because the moutain doesnt get any pointyer if you know what that means
in other words if the map continued with the circular lines all the way to the centerit would have been that snowny mountain
The following number - 0.050437 - written to TWO significant figures would be
Answer:
0.050000
Explanation:
your welcome :)
A construction worker pushes a wheelbarrow with a total mass of 50.0 kg. What is the acceleration of the wheelbarrow if the net force on it is 75N? For physical science
Answer:
1.5m/s²
Explanation:
Given parameters:
Mass of the wheelbarrow = 50kg
Net force applied = 75N
Unknown:
Acceleration of the barrow = ?
Solution:
From Newton's second law of motion, we know that:
Force = mass x acceleration
Now insert the parameters and find the acceleration
75 = 50 x acceleration
Acceleration = 1.5m/s²
which wave carries the highest energy?
Answer:
Gamma rays
Explanation:
Compare between Convex lens and concave lens
Answer:
A convex lens or converging lens focuses the light rays to a specific point whereas a concave lens or diverging lens diverges the light rays. When these lenses are combined, they produce sharper images. Most of the eyeglass lenses use combinations of convex and concave lenses.
A person runs 15.0 km north then turns around and runs 10.0 Km south. what is his dstance
Answer:
25km
Explanation:
The person runs 15km Northward
Turns around and runs 10km southward
The distance is the length of path covered by the person running.
This is given as:
Distance = Distance North + Distance South
Distance = 15km + 10km = 25km
Answer:
25km
Explanation:
cant explain but ik
it serves as the fuctional unit of the nervous system
Answer:
i would say the neuron
What could you do to find the density of a fork, knife, and a spoon?
Answer:
Density is equal to mass divided by volume.
Explanation:
Density = mass / volume
or
p=m/v
Answer:
Use the formula D=m/v
Explanation: In order to find the volume for these objects, use a ruler and measure the length, width, and height. Proceed to multiply them all together, L*W*H. To find the mass of an object, I would say to use a triple beam balance. After finding both the mass and volume of you object, use the formula D = m/v and you'll get your answer.
a train has an initial velocity of 44m/s and an accelaration of _4m/s calculate its velocity
Complete question:
A train has an initial velocity of 44m/s and an acceleration of -4m/s². calculate its velocity after 10s ?
Answer:
the final velocity of the train is 4 m/s.
Explanation:
Given;
initial velocity of the train, u = 44 m/s
acceleration of the train, a = -4m/s² (the negative sign shows that the train is decelerating)
time of motion, t = 10 s
let the final velocity of the train = v
The final velocity of the train is calculated using the following kinematic equation;
v = u + at
v = 44 + (-4 x 10)
v = 44 - 40
v = 4 m/s
Therefore, the final velocity of the train is 4 m/s.
Microwaves are sent through a material causing the molecules in the material to twist and vibrate, causing the material to heat up. What is this twisting and vibration of the molecules creating heat an example of?(1 point)
a macroscopic change creating a macroscopic output
a microscopic change creating a macroscopic output
a macroscopic change creating a microscopic output
a microscopic change creating a microscopic output
Answer: The answer is C
Explanation:
Please what is the work done by a man who is pulling a box of 45kg of mass by means of rope which makes angle of 45 degrees ?
Answer:
No work is done since no distance is given
Explanation:
Since no distance is given, the force is not doing any work
No work is done by the man since we do not know the distance or displacement.
Work is only said to be done when the force applied on an object moves it through a particular distance.
Work done = Force x distance.
Since no distance is given in this problem, we can as well assume that the force applied is doing no work on the object.
Positive feedback caused his pancreas to stop secreting insulin. Negative feedback caused his pancreas to stop secreting insulin. Negative feedback caused his pancreas to produce more insulin. Positive feedback caused his pancreas to produce more insulin.
Answer:
Negative feedback caused his pancreas to produce more insulin.
Explanation:
Positive feedback is a feedback that causes an increase due to change, that is it results in more product while negative feedback is a feedback that causes a decrease due to change, that is it result in lesser product.
Blood sugar control in the body is a negative feedback, because as the blood sugar increases, the nerves sense a change which causes the pancreas to secrete insulin until homeostasis and then the secretion stops.
Find the work done by a man who is pulling a box of 45kg of mass by means of rope which makes angle of 45 degrees.
Answer:
0
Explanation:
Since no distance is given, the force is not doing any work
No work is done by the man since we do not know the distance or displacement.
Work is only said to be done when the force applied on an object moves it through a particular distance.
Work done = Force x distance.
Since no distance is given in this problem, we can as well assume that the force applied is doing no work on the object.