You may have to recrystallize any or all of the components of your extraction mixture, benzoic acid, ethyl-4-aminobenzoate and fluorenone, depending on their purity after isolation. You should have the recystallization solvents in your protocol. They are respectively:

Answers

Answer 1

Answer:

the Recrystallization solvents are;

-Sodium Hydroxide Base (NaOH)

- Hydrochloric Acid (HCl)

- Sand bath when acidic and basic components are removed.

Explanation:

Recrystallization is simply a technique used to purify an impure compound in a solvent.

Now, we want to purify the mixture of benzoic acid, Ethyl-4-aminobenzoate and fluorenone.

For the benzoic acid, it can be separated out of the mixture by addition of sodium hydroxide base (NaOH).

The Ethyl - 4 - aminobenzoate will be separated from the mixture by the addition of Hydrochloric Acid (HCl).

The fluorenone would be separated out by heating the mixture in a sand bath after the basic and acidic components have already been extracted out.

Thus, the Recrystallization solvents are;

-Sodium Hydroxide Base (NaOH)

- Hydrochloric Acid (HCl)

- Sand bath when acidic and basic components are removed.


Related Questions

Be sure to answer all parts.
Write a balanced equation for each reaction. Do not include states of matter to your equation.
H2 + O2 H20

Answers

Answer:

2H₂ + O₂       →     2H₂O

Explanation:

Chemical equation:

H₂ + O₂       →     H₂O

Balance chemical equation:

2H₂ + O₂       →     2H₂O

Step 1:

H₂ + O₂       →     H₂O

Left hand side                     Right hand side

H = 2                                    H = 2

O = 2                                    O = 1

Step 2:

H₂ + O₂       →     2H₂O

Left hand side                     Right hand side

H = 2                                    H = 4

O = 2                                    O = 2

Step 3:

2H₂ + O₂       →     2H₂O

Left hand side                     Right hand side

H = 4                                    H = 4

O = 2                                    O = 2

In which atmospheric layer is the ozone layer?
A.troposphere
B.mesosphere
C.stratosphere
D.thermosphere

Answers

Answer:

stratosphere

Explanation:

contains a high concentration of ozone in relation to other parts of the atmosphere, although still small in relation to other gases in the stratosphere.

Answer:

stratosphere

Explanation: Most atmospheric ozone is concentrated in a layer in the stratosphere, about 9 to 18 miles (15 to 30 km) above the Earth's surface. Ozone is a molecule that contains three oxygen atoms.

Please help
What is an element

Answers

Answer:

An element is atoms with the same number of protons.

Explanation:

Protons, electrons, and neutrons.

Protons and electrons and others

Identify the change of state occurring in each situation. your friend's perfume producing an aroma that fills the room making ice cream from milk in an ice cream maker formation of frost on a cold windshield overnight wax dripping from a candle naphthalene solid (found in moth balls) producing fumes in the closet to deter moths your breath fogging up on your car windshield on a cold winter day

Answers

Answer:

The solution to this question can be defined as follows:

Explanation:

[tex]W_{ax}[/tex] Naphthalene falls off from candle something, strong fumes-sublimation produces. On a rainy day in winter, the breath fogging up on your cor's windshield. Brost formation on an overnight deposition on a frozen windshield. Making milk ice cream freezing the perfuming scent that fills the creation of the room.

What types of materials are better at absorbing energy from radiation?

Answers

Answer:

Explanation:

Materials are clothes and heavy rope

What is the density of a block of gold that occupies 1000 ml and has a mass of 3.5 kg? Show your work

Answers

Answer:

Density of block of gold is 3.5 g/cm³.

Explanation:

Given data:

Volume of block = 1000 mL

Mass of block = 3.5 kg (3.5×1000 = 3500 g)

Density of block = ?

Solution:

Density of substance is calculated by dividing the mass of substance over its volume.

Formula:

d = m/v

d = 3500 g/ 1000 mL

d = 3.5 g/mL

or

d = 3.5 g/cm³             (1ml = 1cm³)

Which atom has exactly 15 protons?

Answers

Answer:

Phosphorus

Explanation:

Given the following equation:

4 NH_3(g) + 5 O_2(g) → 4 NO(g) + 6 H_2O(l)

How many grams of H_2O is produced if 66.60 grams of NO is produced?

Answers

178.55g of H_2O are produced. When you find the molecular mass of NH_3 and O_2 and multiply them by their coefficients, you get 245.15. The law of conservation of mass states that mass can’t be created or destroyed, so this mass is the same for both the reactants and products. 245.15-66.60= 178.55. Hope this helps!

A chemical engineer must calculate the maximum safe operating temperature of a high-pressure gas reaction vessel. The vessel is a stainless-steel cylinder that measures 41.0cm wide and 49.2cm high. The maximum safe pressure inside the vessel has been measured to be 3.70MPa. For a certain reaction the vessel may contain up to 2.50kg of dinitrogen difluoride gas.

Required:
Calculate the maximum safe operating temperature the engineer should recommend for this reaction. Write your answer in degrees Celsius. Be sure your answer has the correct number of significant digits.

Answers

Answer:

[tex]T=2.78x10^3 \°C[/tex]

Explanation:

Hello,

In this case, considering that the safe temperature may be computed via the ideal gas law as we now the pressure, mass and volume via the dimensions:

[tex]V=\pi r^2 h=\pi *(41.0cm)^2*49.2cm=2.60x10^5cm^3*\frac{1L}{1000cm^3} =260L[/tex]

The pressure in atm is:

[tex]P=3.70MPa*\frac{1x10^6Pa}{1MPa} \frac{1atm}{101325Pa} =36.5atm[/tex]

And the moles considering the mass and molar mass (66 g/mol) of dinitrogen difluoride (N₂F₂):

[tex]n_{N_2F_2}=2.50kg*\frac{1000g}{1kg}*\frac{1mol}{66g} =37.9mol[/tex]

In sich a way, by applying the ideal gas equation, which is not the best assumption but could work as an approximation due to the high temperature, the temperature, with three significant figures, will be:

[tex]T=\frac{PV}{nR}=\frac{36.5Pa*260L}{37.9mol*0.082\frac{atm*L}{mol*K} }\\ \\T=3053.6K-273.15\\\\T=2.78x10^3 \°C[/tex]

Best regards.

1. Which statement describes a compound?
A. It contains a solute.
B. Its composition can vary.
C. Its combination of atoms never changes.
D. Its components keep separate properties.
2. Which item is NOT a type of matter?
A. force
B. mixture
C. element
D. compound
3. Which combination can be used to classify all the matter on Earth?
A. forces and energy
B. atoms and elements
C. solvents and solutes
D. substances and mixtures

Answers

1— Its composition can vary.
2–Force
3—atoms and elements

Which of the following contribute(s) to most of the mass of an atom? Question 5 options: A) Neutrons only B) Protons and electrons C) Protons and neutrons D) Protons only

Answers

Answer:

C

Explanation:

Hope this helps :)

How many atoms are in caco4

Answers

Answer: 6

Explanation:

The lewis dot notation for two atoms is shown. What is represented by this notation? K loses one portion to CI, K gains one portion from CI, K loses one electron to CI, K gains one electron from CI

Answers

Answer:

K loses one electron to CI

Explanation:

The lewis electron dot notation shows only the chemical symbol of the element surrounded by dots to represent the valence electrons.

  We have atom of K with one valence electrons

   Cl with 7 valence electrons

For an electrostatic attraction to occur, both particles must be charged. To do this, one of the species must lose an electron, and the other gains it.

This will make both species attain a stable octet;

   Hence, K will lose 1 electron and Cl will gain the electrons.

Answer:

C: K loses one electron to CI

Explanation:

I took the test and got it correct!!

Calculate the mass of arsenic trihydride produced from 117.4 g of hydrogen gas with excess arsenic trioxide:

Answers

Answer: The mass of [tex]AsH_3[/tex] produced is, 1528.8 grams.

Explanation : Given,

Mass of [tex]H_2[/tex] = 117.4 g

Molar mass of [tex]H_2[/tex] = 2 g/mol

First we have to calculate the moles of [tex]H_2[/tex].

[tex]\text{Moles of }H_2=\frac{\text{Given mass }H_2}{\text{Molar mass }H_2}[/tex]

[tex]\text{Moles of }H_2=\frac{117.4g}{2g/mol}=58.7mol[/tex]

Now we have to calculate the moles of [tex]AsH_3[/tex]

The balanced chemical equation is:

[tex]6H_2+As_2O_3\rightarrow 2AsH_3+3H_2O[/tex]

From the reaction, we conclude that

As, 6 moles of [tex]H_2[/tex] react to give 2 moles of [tex]AsH_3[/tex]

So, 58.7 moles of [tex]H_2[/tex] react to give [tex]\frac{2}{6}\times 58.7=19.6[/tex] mole of [tex]AsH_3[/tex]

Now we have to calculate the mass of [tex]AsH_3[/tex]

[tex]\text{ Mass of }AsH_3=\text{ Moles of }AsH_3\times \text{ Molar mass of }AsH_3[/tex]

Molar mass of [tex]AsH_3[/tex] = 78 g/mole

[tex]\text{ Mass of }AsH_3=(19.6moles)\times (78g/mole)=1528.8g[/tex]

Therefore, the mass of [tex]AsH_3[/tex] produced is, 1528.8 grams.

Which pair of elements would most likely have a similar arrangement of outer
electrons and have similar chemical behaviors?
boron and aluminum
helium and fluorine
carbon and nitrogen
chlorine and oxygen

Answers

Answer:

Boron and Aluminum

Explanation:

If you write the electron configuration for boron and aluminum, you get:

[tex]1s^22s^22p^1[/tex] for boron and [tex]1s^22s^22p^63s^23p^1[/tex] for aluminum. Both have 3 valance electrons and has 2 electrons in a s-orbital and 1 in a p-orbital. These valance electron similarities are based on the column/group the elements are. Therefore, Boron and Aluminum have similar chemical behaviours and similar arrangement of outer/valance electrons.

Calculate the density of the aluminum cylinder with a diameter 0f 1.3 cm weighing 18 grams. Height of the cylinder is 5.2 Cm. Find percent error (Actual density of Aluminum is 2.7 g/cm3). (Formula for volume of cylinder is πr2h)

Answers

Answer:

Percent error = 3.7%

Explanation:

Given data:

Density of Al cylinder = ?

Weight of cylinder = 18 g

Diameter = 1.3 cm

Height = 5.2 cm

Actual density of Al = 2.7 g/cm³

Percent error = ?

Solution:

First of all we will calculate the volume of cylinder through given formula.

V = πr²h

r = diameter /2

V = 22/7 × (0.65 cm)²× 5.2 cm

V = 22/7 × 0.4225cm²× 5.2 cm

V = 6.89 cm³

Now we will calculate the density.

d = m/v

d = 18 g/ 6.89 cm³

d = 2.6 g/cm³

Percent error:

Percent error = measured value - actual value /actual value × 100

Percent error = 2.6g/cm³ - 2.7g/cm³ /2.7g/cm³  × 100

Percent error = 3.7%

Negative sign shows that measured or experimental value is less than actual value.





What is the density of a liquid with the same mass as in problem d, if it has a volume of 43.2 mL?
(part d: A liquid has a volume of 62.7 mL and a density of 2.59 g/mL. What is its mass?)

Answers

Answer:

3.76

Explanation:

You start by finding the mass of part d. Mass=  Density times Volume.In this case you would multiply 62.7 and 2.59 which is 162.393 rounded is 162.4. Then density= mass/ volume which is 162.4/ 43.2. density equals 3.76

The equilibrium constant _____________. For an ___________ reaction, heat is a reactant. An increase in temperature and heat favors the ____________ reaction and the value of K c _____________.

Answers

Answer:

The equilibrium constant change. For an endothermic reaction, heat is a reactant. An increase in temperature and heat favors the forward reaction and the value of Kc increases.

Explanation:

Hello.

In this case, regarding reactions in equilibrium in which heat is a reactant as those exemplified by:

[tex]Heat+Reactants \rightleftharpoons Products[/tex]

We infer that the heat of reaction is positive since the reactants have more energy in their ground state than the products making them endothermic. Moreover, since the Le' Chatelier's principle states that increasing the reaction temperature in endothermic reactions, the forward reaction (towards products) is favored because endothermic reactions absorb heat in the form temperature raise, the required statement is:

The equilibrium constant change. For an endothermic reaction, heat is a reactant. An increase in temperature and heat favors the forward reaction and the value of Kc increases.

Regards.

Answer:

The equilibrium constant increases. For an endothermic reaction heat is a reactant. An increase in temperature and heat favours the forward reaction and the value of KC increases.

Explanation:

Which of the following is an Elementary compound?

A. CO2

B. N2

C. SO2

D. H2S


heeeeeeeeeelp please please please ​

Answers

Answer:

Explanation:

In my opinion the answer should be SO2

Answer:

a should be answer i think.

This element has 4 more protons than Silicon

Answers

Answer:

Argon would be the correct choice.

Explanation:

Silicon has a total of 14 protons. If 4 protons would be added, you would now have argon, the 18th element.

argon is correct i think

When solid Fe metal is put into an aqueous solution of SnSO4, solid Sn metal and a solution of FeSO4 result. Write the net ionic equation for the reaction.

Answers

Answer:Fe(s) + Sn^2+(aq) ----> Fe^2+(aq) + Sn(s)

Explanation:

The net ionic equation involved is;

Fe(s) + Sn^2+(aq) ----> Fe^2+(aq) + Sn(s)

We must recall that iron is above tin in the electrochemical series. The implication of this is that, iron has a more negative reduction potential compared to tin.

A metal can displace metals below it in the electrochemical series from their aqeous solution. Hence, iron displaces tin from it's solution.

PLEASE PLEAS HELP Which of the following compounds is insoluble in water?
a) ZnSO4
b) K2SO4
c) Na2CO3
d) Ag2CO3

Answers

Answer:

Your answer is d

Explanation: silver carbonate Ag2CO3 is insoluble in water

Use the data in the Successive Ionization Energies and Electron Affinity tables to determine the following. (Assume the values in the Successive Ionization Energies table are given to the ones place.) (a) the electron affinity of Ar2+ kJ/mol (b) the electron affinity of Si + kJ/mol (c) the ionization energy of Cl − kJ/mol (d) the ionization energy of Cl kJ/mol (e) the electron affinity of Cl + kJ/mol

Answers

Answer:

Use the data in the Successive Ionization Energies and Electron Affinity tables to determine the following. (Assume the values in the Successive Ionization Energies table are given to the ones place.)

(a)

the electron affinity of Ar2+

kJ/mol

(b)

the electron affinity of S+

kJ/mol

(c)

the ionization energy of Cl−

kJ/mol

(d)

the ionization energy of Cl

kJ/mol

(e)

the electron affinity of Cl+

kJ/mol

Successive Ionization Energies in Kilojoules per Mole for the Elements in Period 3 General increase 13 14 Element 11 12 I. 16

Explanation:

Which phrase describes the element carbon-14?

Answers

We know that carbon -14 is a radioactive isotope of carbon

It is used in carbon dating to know the age of different forms of dead organism including plants...

So it is used for estimating the age of sedimentry rocks which contains dead debris of plants and animals,

it can be produced from N14 by radioactive reaction of N-14 with neutron.

It is found in organisms

Answer:

Found in organisms remains.

Explanation:

Hope this helped

How many liters of chlorine gas at 25°C and 0.950 atm can be produced by the reaction of 12.0 g of MnO2 with excess HCl(aq) according to the following chemical equation?
MnO2(s) + 4HCl(aq) → MnCl2(aq) + 2H2O(l) + Cl2(g)

Answers

Answer:

3.55 L.

Explanation:

We'll begin by calculating the number of mole in 12 g of MnO2. This can be obtained as follow:

Molar mass of MnO2 = 55 + (16×2)

= 55 + 32

= 87 g/mol

Mass of MnO2 = 12 g

Mole of MnO2 =...?

Mole = mass /Molar mass

Mole of MnO2 = 12 / 87

Mole of MnO2 = 0.138 mole

Next, we shall determine the number of mole Cl2 produced from the reaction. This is illustrated below:

The balanced equation for the reaction is given below:

MnO2(s) + 4HCl(aq) → MnCl2(aq) + 2H2O(l) + Cl2(g)

From the balanced equation above,

1 mole of MnO2 reacted to produce 1 mole of Cl2.

Therefore, 0.138 mole of MnO2 will also produce 0.138 mole of Cl2.

Finally, we shall determine the volume of Cl2 gas obtained from the reaction. This can be obtained as shown below:

Temperature (T) = 25 °C = 25 °C + 273 = 298 K

Pressure (P) = 0.950 atm

Number of mole (n) = 0.138 mole

Gas constant (R) = 0.0821 atm.L/Kmol

Volume (V) =.?

PV = nRT

0.950 × V = 0.138 × 0.0821 × 298

Divide both side by 0.950

V = (0.138 × 0.0821 × 298) / 0.950

V = 3.55 L

Therefore, 3.55 L of chlorine gas were obtained from reaction.

Describe the changes and challenges that today’s immigrant children experience

Answers

Explanation:

It can be a demanding undertaking to reach adulthood as the offspring of mothers who immigrated to america. In the u.s, something many see as a land of opportunities relative to the world they left behind, parents frequently place heavy pressure on their kids to excel.

These same relatives can know only conjectural English, whereas their offspring rapidly become fluent, requiring the children to take on adult roles as parents need to connect with outside the environment of the family.

Why can we hear different radio stations?

Answers

Your radio picks up those radio waves and channels them into electric circuits in your radio that convert them into sounds you can hear.

Methanol has a density of 0.79g/ml: Calculate the mass of 589ml of methanol.

Answers

Answer:

The answer is 465.31 g

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

mass = Density × volume

From the question we have

mass = 0.79 × 589

We have the final answer as

465.31 g

Hope this helps you


The prefix for one-millionth is micro-.
True
False

Answers

This is true, i double checked!!

When nitrogen, oxygen, fluorine, sodium, magnesium and aluminum ionize, they all will have:
a. different electron configuration from each other.
b. an unchanged electron configuration.
c. the same charge.
d. the same electron configuration (isoelectronic) as neon.
[Definition: The word isoelectronic means that when you write out the electron configuration they are the same. An exam would be He and Li whereby both of them have 2 electrons and therefore they are both are 1s2 in their electron configurations.]

Answers

Answer:

the same electron configuration (isoelectronic) as neon.

Explanation:

The electron configuration refers to the distribution of electrons of an atom or molecule in atomic or molecular orbitals. Electronic configuration is also known as an electronic structure.

When nitrogen, oxygen, fluorine, sodium, magnesium and aluminum ionize, they all will have the same electron configuration (isoelectronic) as neon.

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