You push your friend, whose mass is 54kg, down a hill so she can go sledding. Her acceleration is 3m/s2. Calculate the amount of force you applied to your friend.

Answer:

Hey Queen Messy here!

Work input

Explanation:

The work you do on a machine is called the work input. The force you apply to the machine to do the work is the input force. The work done by the machine on another object is called the work output. The force the machine applies to do this work is the output force.

Answer: c. 1.3 m/s^2

Explanation:

When he is at rest, is weight can be calculated as:

W = g*m

where:

m = mass of the man

g = gravitational acceleration = 9.8m/s^2

We know that at rest his weight is W = 824N, then we have:

824N = m*9.8m/s^2

824N/(9.8m/s^2) = m = 84.1 kg

Now, when the elevators moves up with an acceleration a, the acceleration that the man inside fells down is g + a.

Then the new weight is calculated as:

W = m*(g + a)

and we know that in this case:

W = 932N

g = 9.8m/s^2

m = 84.1 kg

Then we can find the value of a if we solve:

932N = 84.1kg*(9.8m/s^2 + a)

932N/84.1kg = 11.1 m/s^2 = 9.8m/s^2 + a

11.1 m/s^2 - 9.8m/s^2 = a = 1.3 m/s^2

The correct option is C

Answer:

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Answer:AAAAAAHHHHH scary :c

Explanation:

Answer:

Friction is the force that opposes movement between moving objects.

The angle at which one object starts to slip on the other is directly related to the coefficient. When the two objects are horizontal there is no frictional force. So, the coefficient of static friction is equal to the tangent of the angle at which the objects slide. A similar method can be used to measure μk.

Explanation:

Answer:

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Explanation:

The resistance that one surface or object encounters when moving over another

Answer:

The total mass of the atmosphere is  4.508 x 10⁹ kg

Explanation:

Given;

thickness of gas layer, h = 6.8 km

density of Earth's atmosphere, ρ = 1.3 kg/m³

the surface area of Earth is given as 5.10 x 10⁸ km²

Volume of the atmosphere is calculated as;

V = Ah

where;

A is the surface area of Earth

h is the thickness of gas layer

V = (5.10 x 10⁸ km²)(6.8 km)

V = 3.468 x 10⁹ km³

The total mass of the atmosphere is calculated as;

mass = density x volume

m = ρV

m = (1.3 kg/m³)(3.468 x 10⁹ km³)

m = 4.508 x 10⁹ kg

Therefore, the total mass of the atmosphere is 4.508 x 10⁹ kg.

slight reflect but most goes through because glass is transparent

Most of the light waves that strike a clear pane of glass reflects. Details about reflection can be found below.

Refection in physics is the property of a propagated wave being thrown back from a surface such as a mirror.

Mirror is an example of an object that could be hit by an incumbent wave, however, most of the light waves that hit the mirror surface gets reflected back.

Therefore, most of the light waves that strike a clear pane of glass reflects.

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Answer:

33.5 N

Explanation:

Given that

Mass of the sled is, m = 10 kg

Angle of slope, θ = 20°

The tension in the rope of its parallel to the slope is often given as

W * sinθ, where

W = Force on the rope and

θ = angle of the slope

Now, remember that

w = mg, where g = acceleration due to gravity, so

W = 10 kg * 9.81 m/s²

W = 98.1 N,

Going ahead to solve for tension in the slope, we have

T = W * sinθ

T = 98.1 * sin20

T = 98.1 * 0.342

T = 33.5 N

Tension in the slope is 33.5 N

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Explanation:

Given parameters:

Time of drop  = 3.82s

Unknown:

Final velocity of the ball  = ?

Height of fall  = ?

Solution:

To solve this problem, we apply the appropriate motion equation.

  To find the final velocity;

   v  = u + gt

v is the unknown final velocity

u is the initial velocity  = 0m/s

g is the acceleration due to gravity  = 9.8m/s²

t is the time

 v  = 0  + 9.8 x 3.82  = 37.4m/s

Height of drop;

       H  = ut + [tex]\frac{1}{2}[/tex]gt²  

So;

        H  = (0 x 3.82) + ( [tex]\frac{1}{2}[/tex] x 9.8 x 3.82²) = 71.5m

Answer:

335 ft/s

Explanation:

In this question, we have a very important factor missing. The equation of the projectile. So, in simplifying the question I'm going to assume an equation which you can correct thereafter

s(t) = -4.9t² + v(0)t + s0

From the question, we're told that v(0) = 384 ft/s, so if we apply that, we have

s(t) = -4.9t² + 384t + s0, where s0 = 0

On differentiating the equation, we have

s(t) = v(t) = -4.9(2t) + 384(1)

v(t) = -9.8t + 384

Now, at time t = 5 seconds, the velocity v =

v(t) = -9.8(5) + 384

v(t) = -49 + 384

v(t) = 335 ft/s

Therefore, the velocity of the projectile after 5 seconds is 335 ft/s. Please leave a like if it helped you.

Answer:

4.692m

Explanation:

The distance that this boy climbed = 12.0m

The velocity = 3.0m/s

We are to find how far forward this apple goes before it hits the ground.

We have y = 1/2gt²

X = v*t

T = 1.564 seconds

X = 3x1.564

X = 4.692m

Therefore the ball goes a distance of 4.692m forward before it then hits the ground.

Answer:

A,C

Explanation:

The amount of time it takes for a wave to return can be used to create an image

High--frequency sound waves are reflected by tissues in the body

Ultrasound technology produces an image of part of the body on: The amount of time it takes for a wave to return can be used to create an image and high-frequency sound waves are reflected by tissues in the body. So, option (A) and (C) is correct.

Sound waves are used in ultrasound imaging to create images of the inside of the body. It aids in determining the origins of discomfort, edema, and infection in the body's internal organs as well as the examination of a developing fetus in pregnant women.

The same concepts underlie sonar used by ships, bats, and fisherman as well as those used by ultrasound imaging. A sound wave echoes or bounces back when it encounters an object. These echo waves can be measured to obtain information on the object's size, shape, and consistency as well as its distance from the source. Whether the thing is solid or liquid is included in this.

The amount of time it takes for a wave to return helps to create an image and high-frequency sound waves are reflected by tissues in the body. So, option (A) and (C) is correct.

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Answer:

a refractor telescope

Explanation:

Answer:

a. refractor telescope

Answer:

can someone please answer this i need this for a mastery test aswell

Explanation:

it would be very appreciated

Answer:

3.45 inches = 8.763e-5 kilometers

Answer:

a)   w = 0.4726 rad / s,     b)  w_{f} = 4.56 rad / s

Explanation:

a) the two skaters have an angular momentum, for which we will form a system formed by the two of them, in this case when they collide the forces are internal and the moment is conserved.

Initial instant. When the skaters approach, just before touching

        L₀ = r p = r m v

in this case the result is the same if we take the reference system at the midpoint or on one of the skaters.    We place the reference system on one of the skaters

Final moment. After being joined by the pole

         [tex]L_{f}[/tex] = I w

as the forces are internal, the ngualr moment is conserved

         L₀ = L_{f}

         r m v = I w

suppose we approximate the skaters as particles

         I = m r²

we substitute

        r m v = m r² w

        w = v /r

we calculate

        w = 1.38 /2.92

         w = 0.4726 rad / s

What happens is that when the two skaters lower the pole, their velocity acts as a torque, creating a rotational movement with angular velocity w.

b) When the skaters who are at r₀ = 2.92 m approach [tex]r_{f}[/tex] = 0.940 m as the system is isolated, the angular momentum is conserved

initial instant. r₀ = 2.92

       L₀ = I w

final instant r_{f} = 0.940 m

       L_{f} = I_{f}  w_{f}

       L₀ = L_{f}

       I w = I_{f} w_{f}

let's approximate skaters as particles

       I = m r²

we substitute

     m r² w = m r_{f}² wf

     [tex]w_{f}[/tex] = [tex]\frac{r^{2} }{r_{f}^{2} } w[/tex]

we calculate

     w_{f} = [tex]\frac{2.92^{2} }{ 0.940^{2} }[/tex] 0.4726

     w_{f} = 4.56 rad / s

we see that the angular velocity increases

Answer:

The gravity is less in the moon as compared to Earth.

Answer:

The Moon's surface gravity is about 1/6th as powerful or about 1.6 meters per second per second. The Moon's surface gravity is weaker because it is far less massive than Earth. A body's surface gravity is proportional to its mass, but inversely proportional to the square of its radius

Explanation:

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Answer:

Ocean water is more dense because of the salt in it. ... Temperature has a greater effect on the density of water than salinity does. So a layer of water with higher salinity can actual float on top of water with lower salinity if the layer with higher salinity is quite a bit warmer than the lower salinity layer.

Answer:

Laws

Explanation:

Laws are a primary way discourage drinking and driving

A primary way to discourage drinking and driving is Law.

The person who takes in alcohol and then drives on the road. This is strictly prohibited.

Laws against the  'drinking and driving' will make people get scared of getting charged or sentenced to jail for some years. Lot of accidents have caused when there were no laws against the action.

Thus, Laws are a primary way to discourage drinking and driving.

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Answer:

pendulum

hope it helps! please mark me brainliest..

Thank you! have a good day ahead

Answer:

the second to last by the north pole

Explanation:

Answer: the friction force on the small block at t equals 1 second is 2N

Explanation:

Given the data in the question;

from the slope in the graph provided, we will get the acceleration of the slab

At t = 1 seconds

Slope = acceleration = ( 1 - 0) / ( 2 - 0 ) = 1/2 = 0.5 m/s²

Force = ma = 4 × 0.5 = 2 N

so by Newton's third law

Force on block will be same which is 2N

Therefore the friction force on the small block at t equals 1 second is 2N

Answer:

i cant make funny joke

Explanation:

but i can be alive.

wait no, im failing at that currently.

Answer:

Explanation:

F = -k*x

k = F/x = (0.323*9.8)/(0.35)

k = 9.04

The kinetic energy of the spring is equal to its elastic potential energy. From this we can determine the force constant k. The force, constant of the ball here is 509.4 N/m.

The applied force f on an elastic material like a spring is directly proportional  to the displacement x of the material.

Thus, f = -k x

here, the proportionality constant k is called spring constant or force constant. It can be defined as the force required to stretch or compress an elastic material by 1 m.

The elastic potential energy = 1/2 kx²

it is equal to the kinetic energy of the material if its move to form a wave like a spring.

Here, mass of the ball = 0.323 kg

velocity = 13.9 m/s

displacement = 0.350 m

then 1/2 mv² = 1/2 kx²

then k = mv²/x²

k = 0.323 kg × (13.9 m/s)²/ (0.35)² = 509.4 N/m

Therefore, the spring constant of the ball will be 509.4 N/m.

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Answer:

The correct answer is B. Mika, Chet, Sara, Bill

Explanation:

Look at the picture

hope this helps :)

The  list, that the students in order from the greatest amount of work done to the least, is: Mika, Chet, Sara, Bill.

We can state that Work is the product of the component of the force acting in the displacement's direction and its magnitude.

The joule (J), a unit of work used in the International System of Units (SI), is defined as the amount of work required to move an item one meter in the direction of a force of one newton.

Work done by Mika = 50 × 1.0 Joule = 50 Joule

Work done by Chet  = 40 × 2.0 Joule = 80 Joule

Work done by Sara  = 30 × 1.5 Joule = 45 Joule

Work done by Bill = 60 × 0.5 Joule = 30 Joule  

So, The  list, that the students in order from the greatest amount of work done to the least, is: Mika, Chet, Sara, Bill.

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First the aceleration:

Vf² = Vo² - 2ad

a = (Vf² - Vo²) / 2d

a = (0 m/s)² - (1,5 m/s)²) / 2 * 0,4 m

a = -2,25 m²/s² / 0,8 m

a = -2,81 m/s²

Now, for the net force, use 2nd law of Newton:

F = ma

F = 3,5 kg * (-2,81 m/s²)

F = -9,835 N

The force for stop the bowling ball is -9,835 Newtons.

Answer:

The answer is Spring Potential

Explanation:

Because all the others are a mechanical form of energy

Answer:

9.8

Explanation:

I searched it up

..........

....

Answer:

0J

Explanation:

No work is being done on the wall by the man pushing on it.

 Given parameters:

Mass of man  = 75kg

Mass of wall  = 500000kg

Time  = 250s

Unknown:

Work done  = ?

Solution:

Work done is the force applied on a body that moves it along a particular path.

For work to be done, distance must be move or displacement must occur.

Since the wall is not moving the distance is 0;

    Work done  = Force x distance

Since distance is 0m, work done is 0J

The work done on the wall by the man is 0 J.

To calculate the amount of work done by the man, we use the formula below.

Formula:

Where:

from the question,

Given:

Substitute these values into equation 1

Hence, the work done on the wall by the man is 0 J.

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