7. A car is moving at 50.0 mph when the driver applies brakes. Determine the distance it
covers before coming to a halt. Coefficient of static friction between the tires and surface of
the road is 0.514. Mass of the car is 1000 kg.

Answers

Answer 1

Answer:

The distance to come to a halt is approximately 49.53 meters

Explanation:

Thee given parameters are;

The speed of the car, v = 50 mph = 22.35 m/s

The mass of the car, m = 1000 kg

The coefficient of friction,  = 0.514

The force of friction of the brake = Mass × Gravity × Friction = 1000 × 9.81 × 0.514 = 5042.34 N

The initial kinetic energy of the car = 1/2×m×v² = 1/2 × 1000 × 22.35² = 249761.25 J

The work done by the brake = Force of the brake × Distance, d, to come to halt

By conservation of energy, we have;

The work done by the brake = The initial kinetic energy of the car

∴ The initial kinetic energy of the car = Force of the brake × Distance, d, to come to halt

The initial kinetic energy of the car = 249761.25 J = 5042.34 N × Distance, d, to come to halt

∴The distance to come to a halt = 249761.25 J /(5042.34 N) ≈ 49.53 meters

The distance to come to a halt ≈ 49.53 meters.

Answer 2

The car will cover 49.65 m distance before stopping due to application of brake.

Given data:

The mass of car is, M = 1000 kg.

The initial speed of car is, u = 50.0 mph = (50)(0.447 m/s) = 22.35 m/s.

The coefficient of static friction is, [tex]\mu = 0.514[/tex].

The given problem can be solved using the third kinematic equation of motion. Which is,

[tex]v^{2}=u^{2}+2as[/tex] ....................................................(1)

Here, v is the final speed, v = 0 (Because car is finally stopping)

s is the distance covered before stopping and a is the magnitude of acceleration.

Now, since frictional force opposes the motion. Then,

[tex]F = f\\\\ma = \mu \times m \times g\\\\a = 0.514 \times 9.8\\\\a =5.03 \;\rm m/s^{2}[/tex]

Substituting the values in equation (1) as,

[tex]0^{2}=23.35^{2}+2(-5.03)s\\\\s = \dfrac{2500}{2 \times 5.03}\\\\ s=49.65 \;\rm m[/tex]

Thus, the car will cover 49.65 m distance before stopping due to application of brake.

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Related Questions

find weight of 45 kg at height 800 km from earth's surface?​

Answers

Answer:

The weight is 348.4 N

Explanation:

Effect of the Altitude on the Acceleration of Gravity

The effect of gravity decreases with altitude because greater altitudes mean greater distances from the Earth's center.

The practical formula to calculate the gravity as a function of the altitude h is:

[tex]{\displaystyle g_{h}=g_{0}\left({\frac {R_{\mathrm {e} }}{R_{\mathrm {e} }+h}}\right)^{2}}[/tex]

Where go is the conventional gravitational acceleration = [tex]9.80665\ m/s^2[/tex]

R is the Earth's mean radius at the equator = 6,378 Km

h is the altitude.

At a height of h=800 Km, the acceleration of gravity is:

[tex]{\displaystyle g_{h}=9.80665 m/s^2\left(\frac {6,378 Km }{6,378 Km+800Km}}\right)^{2}}[/tex]

Calculating:

[tex]g_h=7.74\ m/s^2[/tex]

The weight is the product of the acceleration of gravity by the mass of the object, thus:

[tex]W=45\ Kg\cdot 7.74\ m/s^2=348.4\ N[/tex]

The weight is 348.4 N

lists the 4 states of matter from most amount of thermal energy to least amount of thermal energy?

Answers

Answer:

Explanation:

plasma, gas, liquid, solid

10 N force is acting on the body of mass 5kg which is at rest. The velocity
gained by the body in 5 seconds is

Answers

Answer:

= 4m/s^2

Explanation:

Change in velocity is

20-0/5 = 4

4. Calculate the momentum for each scenario:
a. .02 kg mass moving at 300 m/s
b. 2 kg mass moving at 40 m/s
c. 200 kg mass moving at 4 m/s

Answers

a) Answer:

Momentum = 6 kgm/s

Explanation:

Momentum = mass × velocity

Given that,

mass = 0.02 kg velocity = 300 m/s

Therefore, momentum = (0.02 × 300)kgm/s

Momentum = 6 kgm/s

b) Answer:

Momentum =80 kgm/s

Explanation:

Momentum = mass × velocity

Given that,

mass = 2 kg velocity = 40 m/s

Therefore, momentum = (40 × 2)kgm/s

Momentum = 80 kgm/s

c) Answer:

Momentum = 800 kgm/s

Explanation:

Momentum = mass × velocity

Given that,

mass = 200 kg velocity = 4 m/s

Therefore, momentum = (200 × 4)kgm/s

Momentum =800 kgm/s

Which two options are forms of kinetic energy?
A. Sound energy
B. Elastic energy
C. Magnetic energy
D. Thermal energy
E. Chemical energy

Answers

Answer:

A, C

Explanation:

SOUND ENERGY - energy from sound

MAGNETIC ENERGY - energy with magnetism

Sound energy and magnetic energy are forms of kinetic energy. Option A and C are correct.

What is kinetic energy?

The energy of the body by the virtue of its motion is known as the kinetic energy of the body. It is defined as the product of half of mass and square of the velocity.

The passage of vibrations through matter is characterized as sound energy. When an item vibrates, sound energy is created, resulting in noise.

Sound vibrations induce pressure waves to flow through a material like air, water, wood, or metal.

Each magnetic field, also known as magnetic energy, includes energy. Electric currents create magnetic fields, magnetic energy is a kind of energy for transporting charge carriers.

Hence, the two options are A and C.

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Podbijest has a net force of 49 Nading on it and it is accelerating at a rate of 8 mil. What is its med
5 kg
8 kg
40 kg
48 kg

Answers

Answer:

6.125kg    

Explanation:

Given parameters:

  Force  = 49N

  acceleration  = 8m/s²

Unknown:

Mass of the object  = ?

Solution:

From newton's second law;

    Force  = mass x acceleratioin

    49 = mass x 8

       mass  = [tex]\frac{49}{8}[/tex]   = 6.125kg    

 

A person of 45 kg can accelerate at 1.5 m/s on a straight road. What is the force created?​

Answers

Answer:

The answer is 67.5 N

Explanation:

The force acting on an object can be found by using the formula

Force = mass × acceleration

From the question

mass = 45 kg

acceleration = 1.5 m/s²

We have

Force = 45 × 1.5

We have the final answer as

67.5 N

Hope this helps you

..................ok okokok

Answers

Are you good is every thing alr

Answer:

ok

Explanation:

How are Covalent bonds formed?

Answers

I believe it is introduced when the variation between the electronegativities of only two atoms is way too small for any transfer to take place to produce new ions.

Considering the definition of covalent bond, Covalent bonds are formed when valence electrons of non-metallic elements are shared and hold this elements together, forming a molecule.

Covalent bond

The covalent bond is the chemical bond between atoms where electrons are shared, forming a molecule.

Covalent bonds are established between non-metallic elements. These elements have many electrons in their outermost level (valence electrons) and have a tendency to gain electrons to acquire the stability of the electronic structure of noble gas. The shared electron pair is common to the two atoms and holds them together.

Summary

Covalent bonds are formed when electrons in the outermost level of non-metallic elements are shared and hold this elements together, forming a molecule.

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A driver of a car traveling at -15m/s applies the brakes, causing a uniform acceleration of +2.0m/s2. If the brakes are applied for 2.5s, what is the velocity of the car at the end of the braking period? How far has the car moved during the braking period?

Answers

Given :

Initial velocity, u = -15 m/s.

Acceleration , a = 2 m/s².

Time taken to applied brake, t = 2.5 s.

To Find :

The velocity of the car at the end of the braking period.

How far has the car moved during the braking period.

Solution :

By equation :

[tex]v = u+at\\\\v=-15 + 2\times 2.5\\\\v=-10 \ m/s[/tex]

Now, distance covered by car is :

[tex]s=ut+\dfrac{at^2}{2}\\\\s=(-15)(2.5)+\dfrac{2(2.5)^2}{2}\\\\s=-31.25\ m[/tex]

Hence, this is the required solution.

calculate your power in watts if you do 500 N*m of work picking up a dumbbell,and takes 5 s to perform that task?​

Answers

Answer:

100watts

Explanation:

Given parameters:

Workdone  = 500Nm

Time taken = 5s

Unknown:

Power in watts = ?

Solution:

Power is the rate at which work is done;

   Power  =[tex]\frac{workdone }{time}[/tex]

Input the parameters and solve;

   Power = [tex]\frac{500}{5}[/tex]  = 100watts

how big can a whale get

Answers

Answer:

Whale is the largest mammal in the world

Explanation:

you you know that the DNA of parent depend upon her babies.

so due to the DNA characteristics will get big one to another

Answer:

For example, in the North Atlantic and North Pacific, blue whales can grow up to about 90 feet, but in the Antarctic, they can reach up to about 110 feet and weigh more than 330,000 pounds. Like other baleen whales, female blue whales are generally larger than male    Blue whales are the largest animals ever known to have lived on Earth. These magnificent marine mammals rule the oceans at up to 100 feet long and upwards of 200 tons.

Explanation:

6. The race car in the previous problem slows from
36 m/s to 15 m/s over 3.0 s. What is its average
acceleration?

Answers

Answer:

a_AV - 15 m/s – 36 m/s =-70 m/s2. At. 3.0 s.

Explanation:

The average acceleration of the car as it slows down is  -5 m/s².

Given is a race car that slows down from 36 m/s to 15 m/s in 3 seconds.

initial velocity [u] = 36 m/s

final velocity [v] = 15 m/s

time taken [Δt] = 3 s

We can calculate the acceleration as follows -

a = Δv/Δt

a = (v - u) / Δt

a = (15 - 30)/3

a = -15/3

a = -5 m/s²

Therefore, the average acceleration of the car as it slows down is

-5 m/s².

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why can't you run from momentum ?

Answers

Two kids walk through the woods discussing momentum. I mean, who wouldn’t?
Okay, fine. It’s a basic introduction to the concept of momentum.

You and your friends are going on a picnic in a very small car. On your way, the car breaks down and you try to push it to get it to move but in vain. You ask your friends to help you and the car starts moving and revs up. How are you and your friends applying Newton's second law of motion here? What if the car you were traveling in was a large SUV?

Answers

Answer:

The pushing of the car by you and your friends is the applied force and when the car moves, it means that the velocity has changed thus causing the movement or acceleration.

Explanation:

Newton's work on forces regarding motion can never be neglected by scientists. Sir Isaac Newton when he was alive, among several of his works he proposed the three laws guiding the forces of motion. In this question we are only going to be treating only one out of the three Newton's Law of motion and that is the second Law Of Newton's laws of motion.

The second Law Of Newton's laws of motion states that the acceleration of an object is directly proportional to the applied force and inversely proportional to the object's mass.

(1). Now, to the question: " How are you and your friends applying Newton's second law of motion here? "

The pushing of the car by you and your friends is the applied force and when the car moves, it means that the velocity has changed thus causing the movement or acceleration.

According to the law, the more the Force, the more the acceleration.

(2). For the second part of the question, " What if the car you were traveling in was a large SUV?"

From the law stated above we see that the acceleration is inversely proportional to the mass, thus if the car is a large SUV, It means that more force is needed to change the car's velocity.

Answer:

When a friend joins you in pushing the small car, the net force on it increases. Therefore, it starts to move. The mass of a SUV is much greater than that of a small car. You would thus need the help of more friends to help push it.

Explanation:

Plato/Edmentum

A 10 kg box is resting on the table. What is the normal force on the box?

Answers

Answer:

normal force and gravitational force are equal. change kg to newtons

98N

Explanation:

The normal force on the box resting on the table is 98 N.

The given parameters;

mass of the box, m = 10 kg

The normal force on the box resting on the table is the force acting perpendicular to the box and it is calculated as follows;

Fₙ = mg

where;

m is the mass of the boxg is the acceleration the to gravity

Fₙ = 10 x 9.8

Fₙ = 98 N

Thus, the normal force on the box resting on the table is 98 N.

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HeLp AsAp!!!!!! How long would it take you to hop 30 meters based on your speed for the 5-meter trial? Show your work!

Hopping =

Distance-5 m

Time-3.41

Speed-1.46

Answers

Answer:

20.5s

Explanation:

Given parameters:

Distance = 30m

Unknown:

Time  = ?

Solution:

The time it will take to hop a distance of 30m using the speed for the 5m trial is the duration of the trip.

 The speed for the 5m trial  = 1.46m/s

Now;

    Speed  = [tex]\frac{distance}{time}[/tex]

      Distance = speed x time

      time  = [tex]\frac{distance }{speed}[/tex]

Input the parameters and solve;

     time  = [tex]\frac{30}{1.46}[/tex]   = 20.5s

A truck is traveling at a constant speed of 20 m/s through a school zone. At time t = 0 seconds, he passes a hidden police car that is at rest. Five seconds after the truck passes, the police car begins accelerating at a constant rate of 2 m/s in order to catch the truck.

Determine the time at which the speed of the truck is equal to the speed of the police car. Mark this time as t↓1. How will the positions of the police car and the truck compare when they have the same speed and why?​

Answers

Answer:

Let's define:

The position zero will be in the first point where the truck and police car meet. (So the initial position of both vehicles is zero)

Then, the position equation for the truck is:

T(t) = 20m/s*t

Where t is our variable, time in seconds.

Now, at t = 5s, the car starts accelerating.

Ac(t) = 2m/s^2                    for( t ≥ 5s)

For the velocity of the car, we must integrate that.

V(t) = (2m/s^2)*(t - 5)           for (t ≥ 5s)

Where i introduced a little change in the variable because the velocity of the car starts to increase for t larger than 5 seconds.

For the position of the car we integrate again.

C(t) = (1m/s)*(t - 5)^2            for (t ≥ 5s)

Now, let's answer the questions:

Determine the time at which the speed of the truck is equal to the speed of the police car.

Then we must have:

V(t) = (2m/s^2)*(t - 5)  = 20m/s.   (Remember that we only can use times requal or larger than 5 seconds).        

2m/s^2*t - 10m/s = 20m/s

2m/s^2*t = 30m/s

t = (30/2) s = 15s

The velocities of both vehicles will be the same after 15 seconds.

t1 = 15s

How the positions will compare at this time?

The easier thing will be to evaluate the position equation of each vehicle in this time:

T(15s) = 20m/s*15s = 300m

C(15s) = (1m/s^2)*(15s - 5s)^2 = (1m/s^2)*(10s)^2 = 100m.

Then we can see that the truck is 200m ahead of the car.

But remember that the police car is accelerating, so the velocity will keep increasing meaning that eventually, the car will catch the truck.

many atoms of each element are in one molecule of 2-heptanone?

Answers

A chemical structure of a molecule includes the arrangement of atoms and the chemical bonds that hold the atoms together. The 2-HEPTANONE molecule contains a total of 21 bond(s) There are 7 non-H bond(s), 1 multiple bond(s), 4 rotatable bond(s), 1 double bond(s) and 1 ketone(s) (aliphatic).

:/ hope this helps

A sprinter can run 100.0 meters in 10.4 seconds. Find the velocity of this runner. (Please put answer into ladder cancellation format!!)

Answers

Hope you get it thank you :)

A skateboarder rolls horizontally off the top of a staircase at a speed of
14.5 ms and lands at bottom of the stairs. The staircase has a horizontal length of
8.00m 8.00m8, point, 00, start text, m, end text. We can ignore air resistance. What is the skater's vertical displacement during the jump?

Answers

Answer:

The skater's vertical displacement during the jump is 1.49 meters

Explanation:

Horizontal Motion

When an object is thrown horizontally with a speed v from a height y, the range or maximum horizontal distance traveled by the object can be calculated as follows:

[tex]\displaystyle x=v\cdot\sqrt{\frac {2y}{g}}[/tex]

If we already know the value of x, we can solve the above equation for h:

[tex]\displaystyle y=\frac {x^2g}{2v^2}[/tex]

We use the given values v=14.5 m/s, x=8 m, [tex]g=9.8 m/s^2[/tex]:

[tex]\displaystyle y=\frac {8^2\cdot 9.8}{2\cdot14.5^2}[/tex]

y = 1.49 m

The skater's vertical displacement during the jump is 1.49 meters

Answer:

The answer is -1.49 m not 1.49 m

Explanation:

It is referencing displacement from a higher point to a lower.

If a train goes at constant speed of 40 miles per hour for one hour, then at constant
speed of 55 miles per hour for two hours, what is its average speed at the train?

Answers

Answer: because the train goes 72 mph for 2 hours

Explanation:

does the train go 72mph for 2 hours as well? if so the answer would be 324 because you have to add 90 twice scene it goes at that speed for 2 hours thats 180. assuming  the train goes 72 mph for 2 hours it would be 144. then add 180 and 144 and you get 324 merry christmas and a happy newyear to you and your family

An elevator ascends at a constant speed of 4 m/s. How much time is required for the elevator in order to travel 200m upwards?

Answers

Answer:

Explanation:

Hope this helps, cheers

Doe the baby diaper tabs go to the front or back. Huggies diaper.

Answers

Answer:

back lol

Explanation:

Pull the tabs and wrap around to stick to the front of the diaper:)

Answer:

Front of the diaper

You take the straps that are connected to the back of the diaper and pull the. forward to attach to the front.

hope this helps.


Suppose y = 2x + 10. Find y if x = -2

Answers

Answer:

y = 6

Explanation:

Given parameters:

        Given equation:

                     y = 2x + 10

And supposing; x = -2

Unknown:

y = ?

Solution:

 We are going to solve this problem by substitution;

           y = 2x + 10

  since x = -2; input this into the equation to solve for y;

           y  = 2(-2) + 10 = -4 + 10  = 6

The value of y = 6

what is a force that always resists the relative motion of objects or surfaces?

Answers

Friction is the resistance to motion of one object moving relative to another. It is not a fundamental force, like gravity or electromagnetism. Instead, scientists believe it is the result of the electromagnetic attraction between charged particles in two touching surfaces.

Select the correct answer.
Type O negative blood is considered the universal red blood cell donor because it
OA.
Has all 3 types of antigens.
OB.
Has all 3 types of antibodies.
Lacks all 3 types of antigens.
OD
Lacks all 3 types of antibodies.

Answers

Answer:

The answer is C.) Lacks all 3 types of antigens.

Consider a 400g baseball thrown from a height of 1.8m at 35m/s:

a. What is the gravitational potential energy of the baseball?

b. What is the elastic potential energy of the baseball?

c. What is the kinetic energy of the baseball?

d. What is the total mechanical energy of the baseball?

Answers

Answer:hhahe

Explanation:

6. Potential energy that depends on height is called *
O kinetic energy
O gravitational potential energy.
elastic potential energy.
O mechanical energy

Answers

B - gravitational potential energy

the heavier the object is above the ground, the more gravitational potential energy it holds

hope this helps :)

The potential energy that depends on height is called gravitational potential energy. (Option B)

What is gravitational potential energy?

Gravitational potential energy is a form of potential energy that an object possesses due to its position relative to a gravitational field.

When an object is raised to a certain height above the ground, it gains gravitational potential energy. The higher the object is raised, the greater its potential energy.

This potential energy is a measure of the work that would be required to move the object against gravity and bring it back down to its original position.

The formula for gravitational potential energy is;

Potential Energy (PE) = mg h

where;

PE is the gravitational potential energym is the mass of the objectg is the acceleration due to gravityh is the height or elevation of the object

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Please help my test is going on. Please answer both (i) and (ii). ​

Answers

Answer:

i. 7.5 m

ii. 15000 N

Explanation:

Area under vt graph shows the displacement

so area of triangle ABE= 1/2×15×2

=7.5 m

ii) F=ma

here, m=1000kg

and a=v-u/t

=15-0/1

a=15

F=1000×15=15000N

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