Answer:
1.0125 x 10^19
Explanation:
current flowing through conductive wire= 9mA = 9 x 10^ -3 A
charge passing per 3 min
Q = It
= 9 x 10^ -3 x (3 x 60)
= 1.620 C
no of electrons in charge
Q = ne
1.620 = n x 1.6 x 10 ^ -19
n. = 1.0125 x 10 ^19
If you drop a steel metal ball off a building and it takes 3 seconds to hit
the ground, how tall is the building?
Answer:
[tex]40\:\mathrm{m}[/tex]
Explanation:
We can use kinematics equation [tex]\Delta y={v_i}^2+\frac{1}{2}at^2[/tex] to solve this problem. Because the metal ball's initial velocity was 0, [tex]{v_i}^2=0[/tex].
Therefore, our equation becomes:
[tex]\Delta y=\frac{1}{2}at^2[/tex] (freefall equation).
[tex]t[/tex] is given as 3 seconds and [tex]a[/tex] is acceleration due to gravity ([tex]9.81\:\mathrm{m/s}[/tex]).
Therefore, our answer is:
[tex]\Delta y = \frac{1}{2}\cdot9.81\cdot3^2=44.145=\fbox{$40\:\mathrm{m}$}[/tex] (one significant figure).
A 1500kg car is at rest before it accelerates when the light turns green. If it covers 45.0 meters in 15.0 seconds, what is the net force applied to the car?
Answer:
300N
Explanation:
Given parameters:
Mass of car = 1500kg
Initial velocity = 0m/s
Distance covered = 45m
Time = 15s
Unknown:
Net force applied = ?
Solution:
From Newton's second law:
Force = mass x acceleration
Force = mass x [tex]\frac{v - u}{t}[/tex]
v is the final velocity
u is the initial velocity
t is the time taken
Final velocity = [tex]\frac{45}{15}[/tex] =3m/s
Force = 1500 x [tex]\frac{3 - 0}{15}[/tex] = 300N
a manor house was most similar to
Answer:
I don't know the multiple choices or if you have any but my best answer is castle.
I hope this helps!
A body moving in simple harmonic motion has an amplitude of 10cm and a frequency of 100Hz. Find i.mthe period of oscillation, ii. the acceleration at the maximum displacement, iii. the velocity at the centre of motion
Explanation:
= 5 cm = 0.05 m
T = 0.2 s
ω=2π/T=2π/0.2=10πrad/s
When displacement is y, then acceleration, a=−ω2y
Velocity, V=ωr2−y2
Case (a) When y=5cm=0.05m
a=−(10π)2×0.05=−5π2m/s2
V=10π×(0.05)2−(0.05)2=0
Case (b) When y=3cm=0.03m
a=−(10π)2×0.03=−3π2m/s2
V=10π×(0.05)2−(0.03)2=10π×0.04=0.4π m/s
Case (c) When y=0
a=−(10π)2×0=0
V=10π×(0.05)2−02=
hope it helps. pls follow and mark as brainliest
1. What causes electrical shock?
Current
Amperage
Voltage
Watts
Answer: A) Current
Current is the flow of electrons. The more electrons that flow, then the higher the amperage which measures this flow. If the current is high enough, then the electrical shock may cause damage of some kind.
"Amperage" is abbreviated as "Amp". You may see something like "milliamp" when it comes to measuring this amperage.
Un automobil pleacă din Alexandria la ora 23 și 25 de minute și ajunge la București la ora 0 și 20 de minute. Aflați durata mișcării. Dacă automobilul s-a deplasat cu viteza de 90 km/h, aflați distanța dintre localități.
Answer:
[tex]55\ \text{minut}[/tex]
[tex]82.5\ \text{km}[/tex]
Explanation:
Timpul când mașina părăsește Alexandria este [tex]23:25[/tex]
Ora sosirii mașinii la București este [tex]00:20[/tex]
Deci, timpul necesar pentru călătorie este [tex]60-25+20=55\ \text{minut}=\dfrac{55}{60}\ \text{ore}[/tex]
Viteza mașinii este de 90 km/h
Distanța este dată de produsul vitezei și al timpului
[tex]90\times \dfrac{55}{60}=82.5\ \text{km}[/tex]
Distanța dintre localități este [tex]82.5\ \text{km}[/tex].
Sound wave W has amplitude ‘A' and frequency ‘f'. Sound wave X is louder and lower in pitch than sound wave W. What can be said about the amplitude and frequency of sound wave X?
Answer:
Sound wave X amplitude is greater than 'A' and its frequency is lesser than
'f'
Explanation:
The pitch of a sound is dictated by the frequency of the sound wave, while the loudness is dictated by the amplitude.
A high pitch sound corresponds to a high frequency and a low pitch sound corresponds to a low frequency.
The larger the amplitude of the waves, the louder the sound and vice-versa.
From the question,
Sound wave W has amplitude ‘A' and frequency 'f' and
Sound wave X is louder and lower in pitch than sound wave W.
Since sound wave X is louder, this means its amplitude is greater than 'A'.
Also, since sound wave X is lower in pitch, this means its frequency is lesser than 'f'.
Answer:
Higher than A, Lower than F
Explanation:
4) Which is the BEST description of a tectonic plate? *
O A. Tectonic plates consist of the lithosphere and part of the asthenosphere.
O B.Tectonic plates are large pieces of mesosphere that never move.
C. Tectonic plates are large pieces of lithosphere that move on tope of the
asthenosphere.
O D. None of these answers is correct.
Answer:
The answer is A
Explanation: i took k12
If an atom gains a neutron, what happens to the atom?
Answer:
If an atom gains a neutron, the atom becomes an isotope, which means that it has the same atomic number (#of protons) but a different atomic mass because it has gained the mass of 1 neutron
If a car traveled 100 km in 2 hr, what was its average speed in km/hr?
average speed =
d =
t =
Answer:
Average speed will be 50km/hr
Explanation:
Distance/Time
100/2
50kmph
plz mark as brainliest
Answer:
50km/hr
Explanation:
avgspeed=Δdistance/Δtime
Δd=100km
Δt=2hr
=100km/2hr
=50km/hr
If Jerome is swinging on a rope and transferring energy from gravitational potential energy to kinetic energy, what is being done? compression work radiation energy creation
Answer: work
Explanation:
When Jerome swings on a rope and hence this leads to the transfer of energy from the gravitational potential energy to a kinetic energy, this implies that work is being done.
For work to be done, it simply means that one has to transfer energy from one particular form to another form. In this case, the energy was transferred from the gravitational potential energy to a kinetic energy.
Answer:
work
Explanation:
A tennis ball is served horizontally from 2.4m above the ground at net is 12m away and point 0.9 high will be ball clear the net where will be ball land
Explanation:
Let us first calculate long does it take to go 12m at 30m/s( assumed speed)
12/30 = 0.4 seconds
horizontal distance the ball drop in that time
H= (0)(0.4)+1/2(-9.8)(0.4)2
H= -0.78m
negative sign shows that the height of the ball at the net from the top.
Height of the ball at the net and from the ground= H1-H=2.4-0.78=1.62m
As 1.62m>0.9m so the ball will clear the net.
H_1= V0y t’ + ½ g t’^2
-2.4= (0)t’ + ½ (-9.8) t’^2
t’= 0.69s
X’=V0x t’
X’=(30)(0.96)
X’= 20.7m
plz hurry
Which of the following is a result of sterilizing wounds with chemicals?
increased rate of infection
reduced need for hand-washing
reduced rate of infection
increased death rate
Answer:
Sterilization is a common medical practice It decreased bacterial bloom and coverage Hence it reduced rate of infectionCan anyone help me with these questions? TIA!
(Don’t actually answer please! :) )
[tex]\huge\text{Graphs:}[/tex]
The graph of
• The I-V for Ohmic Metal wire conductor at constant temperature always shows a straight line between the Current(I) plotted at Y axis and Voltage(V) plotted at X axis. Picture 1
• The I-V graph for Diode shows that first the current is zero but as we increase the potential difference(voltage), it results in the increase in the current. Picture 2
_____________________________________ Question 8:[tex]\Large\textbf{Diode:}[/tex]
A diode is a device that allows current to flow in only one direction.
[tex]\Large\textbf{Forward and Reverse Biasing:}[/tex]
Forward Bias, When a diode is forward bias (a voltage in the "forward" direction) then the P-side of the diode is attached to the positive terminal and N-side is fixed to the negative side of the battery which is connected, current flows freely through the device. The forward bias decreases the thickness of potential barrier(The potential barrier barrier in which the charge requires additional force for crossing the region)
Reverse Bias, When a diode is Reverse bias(a voltage in the "backward direction) then the P-side of the diode is connected to the negative terminal and N-side is connected to the positive terminal of the battery which is connected. The reverse bias increases the thickness of the potential barrier resulting in the flow of no current.
[tex]\Large\textbf{Answer to the Question "Resistance"}[/tex]
The Forward bias decreases the resistance of the diode whereas the reversed bias increases the resistance of the diode. As in forward biasing the current is easily flowing through the circuit whereas reverse bias does not allow the current to flow through it.
_____________________________________ Best Regards, 'Borz'A physics student is driving his pick-up
truck down Lake Avenue. The pick-up is
equipped with a projectile launcher that
imparts a vertical velocity to a water-filled
rubber projectile. While traveling 20.0 m/s
in an eastward direction, the projectile is
launched vertically with a velocity of 58.8
m/s.
Fill in the table at the right. showing the
horizontal and vertical displacement of the
projectile every second for the first 12
seconds.
TOTAL FLIGHT TIME
Rising Projectile
vi = initial velocity = 58.8 m/s
vf = final velocity = 0
g = gravity acceleration = -9.81 m/s²
t = elapsed time = to be determined
vf = vi + gt
vf - vi = gt
(vf - vi)/g = t
t = (vf - vi)/g
t = (0 - 58.8)/-9.81
t = -58.0/-9.81
t = 5.99 s ≈ 6.00 s
Falling Projectile
vi = initial velocity = 0
vf = final velocity = 58.8 m/s
g = gravity acceleration = 9.81 m/s²
t = elapsed time = to be determined
vf = vi + gt
vf - vi = gt
(vf - vi)/g = t
t = (vf - vi)/g
t = (58.8 - 0)/9.81
t = 58.0/9.81
t = 5.99 s ≈ 6.00 s
t(total) = t(up) + t(down) = 6.00 s + 6.00 s = 12.0 s Total Flight Time
HORIZONTAL DISTANCE TRAVELED
v = velocity, horizontal = 20.0 m/s
d = to be determined
t = elapsed time = 12.0 s
v = d/t
vt = d
d = vt
d = (20.0 m/s)(12.0 s)
d = 240 m Horizontal Distance Traveled
00
A vertical spring with a force constant of 26 N/m has a relaxed length of 35 cm. A 200 g mass is then
attached to the end of the spring and is allowed to come to rest. (a) Find the length of the stretched spring.
(b) How much elastic potential energy is stored in the spring?
I just need the work please the answers is
(a) 45.2 J
(b) 0.0739
Answer:
(a) The length of the stretched string is approximately 42.53846 cm
(b) The elastic potential energy stored in the string is approximately 0.073877 Joules
Explanation:
(a) The given parameter are;
The force constant of the vertical spring, k = 26 N/m
The relaxed length of the spring, L = 35 cm = 0.35 m
The mass attached to the end of the spring, m = 200 g = 0.2 kg
By Hooke's law, we have;
F = k·x
Where;
F = The applied force on the sting = The weight of the attached mass, W
∴ F = W
The weight of the attached mass, W = m × g
Where;
g = The acceleration due to gravity ≈ 9.8 m/s²
Therefore, F = W = 0.2 kg × 9.8 m/s² = 1.96 N
From Hooke's law, we have;
x = F/k = 1.96 N/(26 N/m) ≈ 0.0753846 m
The extension of the stretched spring, x ≈ 0.0753846 m
The length of the stretched string, L[tex]_{stretched}[/tex] = L + x
∴ L[tex]_{stretched}[/tex] ≈ 0.35 m + 0.0753846 m ≈ 0.4253846 m
0.4253846 m = 42.53846 cm
The length of the stretched string ≈ 42.53846 cm
(b) The elastic potential energy stored in the string, U = 1/2·k·x²
By substituting the known values, we get;
U = 1/2 × 26 N/m × (0.0753849 m)² ≈ 0.073877 Joules
a cellphone weighing 80 g is flying to the air at 15 m/s what is it's kinetic energy
Answer:
9J
Explanation:
Given parameters:
Mass of cell phone = 80g
1000g = 1kg
80g is therefore 0.08kg
Velocity of the cellphone = 15m/s
Unknown:
Kinetic energy of the cellphone = ?
Solution:
The kinetic energy of a body is the energy due to its motion.
It is expressed as:
K.E = [tex]\frac{1}{2}[/tex] mv² = [tex]\frac{1}{2}[/tex] x 0.08 x 15² = 9J
When blue light (450 nm) is shone on a particular metal surface, electrons are ejected with a kinetic energy of 2.5 x 10-20 J. Calculate the work function for this metal.
Answer:
the work function of the metal is 4.167 x 10⁻¹⁹ J .
Explanation:
Given;
wavelength of the incident light, λ = 450 nm = 450 x 10⁻⁹ m
kinetic energy, K.E = 2.5 x 10⁻²⁰ J
The energy of the incident light is calculated as;
[tex]E = hf = \frac{h c}{\lambda} \\\\where;\\\\c \ is \ speed \ of \ light = 3 \times 10^8 \ m/s\\\\ h \ is \ Planck's constant = 6.626 \times 10^{-34} Js \\\\E = \frac{(6.626 \times 10^{-34})(3\times 10^8)}{450 \times 10^{-9}} \\\\E = 4.417 \times 10^{-19} \ J[/tex]
Apply Einstein photoelectric equation to determine the work function of the metal;
E = W + K.E
where;
W is the work function of the metal
W = E - K.E
W = 4.417 x 10⁻¹⁹ J - 2.5 x 10⁻²⁰ J
W = 44.17 x 10⁻²⁰ J - 2.5 x 10⁻²⁰ J
W = 41.67 x 10⁻²⁰ J
W = 4.167 x 10⁻¹⁹ J
Therefore, the work function of the metal is 4.167 x 10⁻¹⁹ J .
The work function of the photon is 4.167*10^19J
The energy of this photon can be calculated as
E = hc/λ
Data given;
λ = 450nm = 450*10^-9mh = 6.626*10^-34JSK.E = 2.5*10^-20Jc = 3.0*10^8m/sEnergy of the Photonsubstituting the values into the equation;
[tex]E = hc / y\\E = \frac{6.626*10^-^3^4*3.0*10^8}{450*10^-^9} \\E = 4.42*10^-^1^9J[/tex]
Work FunctionThe work function of the photon can be calculated as;
E = K.E + Ф
4.42*10^-19 = 2.5*10^-20 + Ф
Ф = [tex]4.42*10^-^1^9 - 2.5*10^-^2^0=4.167*10^-^1^9J[/tex]
The work function of the photon is 4.167*10^-19 J
Learn more on work function of a photon here;
https://brainly.com/question/11683155
a 30-kg child sitting in a chair applies a force of approximately 300 N downward. on the chair approximately how much force does the chair apply upward to the child
A. 10N
B. 30N
C. 300N
D .600N
Answer:
moment's equilibrium required
moment = force x perpendicular distance from force's line of action (from pivot)
counter clockwise = clockwise moments
=> 15g(1.5) = F(0.3)
=> F = 15*9.81*5 = 735.75 ~= 736 N
Explanation:
A 0.50-kilogram frog is at rest on the bank surrounding a pond of water. As the frog leaps from the bank, the magnitude of the acceleration of the frog is 4.0 meters per second².
Complete question:
A 0.50 kilogram frog is at rest on the bank surrounding a pond of water. As the frog leaps from the bank, the magnitude of the acceleration of the frog is 4.0 meters per second^2. Calculate The magnitude of the net force exerted on the frog as it leaps.
Answer:
2.0N
Explanation:
Given that,
Mass, m of the frog = 0.5 kg
The acceleration of the frog = 4.0 m/s².
We have been asked To find,
The magnitude of the net force exerted on the frog as it leaps.
So
We calculate this using the formula below :
F = ma
When we insert the values into the formula, we have:
F = 0.5 kg × 4 m/s²
F = 2.0 N
Therefore, the magnitude of net force is 2.0 N.
What energy is present when a magnet is moving?
Answer:
kinetic energy is when an object is moving
Two atoms each contain 6 protons, but one has 6 neutrons and the other has 8 neutrons. What are these atoms called? A. ions B. radicals C. isotopes D. binaries
Answer:
These atomos are called isotopes.
Explanation:
Each chemical element is characterized by the number of protons in its nucleus, which is called the atomic number (Z).
The number of neutrons in the nucleus can vary. There are almost always as many or more neutrons than protons. The atomic mass (A) is obtained by adding the number of protons and neutrons in a given nucleus.
The same chemical element can be made up of different atoms, that is, their atomic numbers are the same, but the number of neutrons is different. These atoms are called isotopes of the element. That is, isotopes are atoms whose atomic nuclei have the same number of protons but different numbers of neutrons.
So, these atomos are called isotopes.
TIMED URGENT! REALLY APPRECIATE HELP!! TYSM!!!!!
What is the average Speed of the roller coaster? *
20 meters per second
20 meters per minute
20 m/hr
Answer:
1st
Explanation:
20 meters per second
Explanation:
look at the chart
A glass test tube rubbed with silk and an acrylic rod rubbed with a paper towel become charged due to the process of charging by friction. How do the test tube and rod interact?
Answer:
Attraction.
Explanation:
Charging by friction involves rubbing of objects against one another so that one loses electron(s), while the other gains the electron(s). Thus, the objects would have opposite charges after the process.
The glass test tube rubbed with silk loses electron, thus becomes positively charged. While the acrylic rob rubbed with paper towel becomes negatively charged. Since the two rods have opposite charges, then the interaction between them would be attraction. A force of attraction between the rods would be experienced while the rods are brought to a required close range.
Can anyone prove ADIABATIC PROCESS ???
Answer:
The adiabatic process can be derived from the first law of thermodynamics relating to the change in internal energy dU to the work dW done by the system and the heat dQ added to it. The word done dW for the change in volume V by dV is given as PdV. Hence, the equation is true for an adiabatic process in an ideal gas.
Explanation:
Hope it helps......bro
Help! 5 questions for 25 points? Seems fair Please help
Answer:
ezrfdjhsetnhtjhsksdjghbksfneunaifghejbcifkikjayhr
Explanation:
Helium ballon containing 5m3 of Gad at a pressure of 30pka is released. If the temperature is constant calculate the volume the balloon would have when the pressure inside the ballon has fallen to 5kpa answer in metres cubed
Answer:
30m³
Explanation:
Calculation for the volume the balloon would have
First step is to calculate the Constant
Constant=30pka*5m³
Constant=150m³
Now let calculate the Volume using this formula
Balloon Volume=Constant/ Pressure
Let plug in the formula
Balloon Volume=150m³/5kpa
Balloon Volume=30m³
Therefore the volume that the balloon would have when the pressure inside the ballon has fallen to 5kpa is 30m³
Two trucks with equal mass are attracted to each other with a gravitational force of 6.7 x 10^-4 N. The trucks are separated by a distance of 3.0 m. What is the mass of one of the trucks?
Answer:
9508.1kg
Explanation:
Given parameters:
Gravitational force = 6.7 x 10⁻⁴N
Distance of separation = 3m
Unknown:
Mass of one of the truck = ?
Solution:
Let the mass of one of the truck be = m
According to the Newton's law of universal gravitation:
Fg = [tex]\frac{G m1 m2}{d^{2} }[/tex]
G is the universal gravitation constant = 6.67 x 10⁻¹¹
m1 and m2 are the masses of the two bodies, here m1 = m2 = m
d is the distance of separation between them
6.7 x 10⁻⁴ = [tex]\frac{6.67 x 10^{-11} x m^{2} }{3^{2} }[/tex]
6.67 x 10⁻¹¹m² = 9 x 6.7 x 10⁻⁴
m = 9508.1kg
The mass of one of the trucks is 9510 kg.
The problem above can be solved using the mathematical expression of newton's law of universal gravitation
Using Newton's law of universal gravitation,
F = Gm²/r²................... Equation 1
Where F = Gravitational force on the truck, m = mass of each truck, r = distance between the trucks, G = universal constant
make m the subject of the equation
m = √(Fr²/G)................ Equation 2
From the question,
Given: F = 6.7×10⁻⁴ N, r = 3.0 m.
Constant: G = 6.67×10⁻¹¹ Nm²/kg²
Substitute these values into equation 2
m = √[(6.7×10⁻⁴×3²)/(6.67×10⁻¹¹)]
m = √(9.04×10⁷)
m = 9.51×10³ kg.
m = 9510 kg
Hence, The mass of one of the trucks is 9510 kg
Learn more about Newtons law of universal gravitation here: https://brainly.com/question/9373839
what kind of plate boundary is ocean ocean?
Which two life functions of animals help maintain the water cycle by recycling water back into the environment?
Answer:
Respiration and excretion
Explanation:
Respiration. When animals breathe, their lungs release water vapour to the atmosphere.
Animals excrete water by respiration and by passing urine.