Answer:
The distance is 45m. (s)
Acceleration is 9.8 m/s^2 (acceleration due to gravity). (a)
We have to find the time (t)
By the 3rd equation of motion,
s = ut + 1/2 at^2 (here u is the initial velocity of the ball)
Since the initial velocity was 0 m/s, the formula becomes s = 1/2 at^2.
(substituting the values in the formula)
45 = 1/2 x 9.8 x t^2
45 = 9.8/2 x t^2
45 = 4.9 x t^2 (9.8/2 = 4.9)
(divide 4.9 on both sides)
45/4.9 = 4.9 x t^2 / 4.9
9.1836 = t^2
3.030 = t
So it takes approximately 3 seconds for the ball to reach the surface of the earth (neglecting air resistance). You can try the same with 50 m .
The velocity of the ball the moment it hits the ground is equal to 31.3 m/s.
What is the equation of motion?Equation of motion has established a relation between the velocity of the body and acceleration of the body when the body is moving with uniform acceleration along a straight line. The distance traveled in a specific time has expressed a set of equations termed equations of motion.
The first equation of motion can be expressed as follows:
v = u + at
The second equation of motion can be expressed as follows:
S= ut + (1/2)at²
Where u is the initial velocity of a body, v is the final velocity, S is the distance, a is the acceleration and t is the time.
Given, the distance traveled by the ball, S = 50 m
and, the initial velocity of the ball, u = 0 as ball is at rest initially.
From the second equation of motion, find the value of 't':
50 = (0) t + (1/2)× (9.8) ×(t²)
t = 3.19 sec
Now from the first equation of motion, find the value of the final velocity of the ball:
v = (0) + (9.8) (3.19)
v = 31.3 m/s
Therefore, the ball hits the ground with a velocity of 31/3 m/s.
Learn more about the equation of motion, here:
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A skier rides horizontally off of a 200 meter high cliff. If he lands 25 meters away from the base of the cliff, how fast was he skiing as he went off the edge?
A. 0.91 m/s
B. 2.91 m/s
C. 3.91 m/s
D. 25.91 m/s
Answer:
the answers, the correct one is C, v₀ₓ = vₓ = 3.91 m / s
Explanation:
This is a projectile launching exercise, in this case they indicate that when leaving the cliff it goes horizontally, therefore the initial vertical speed is zero, let's find the time to reach the base
y = y₀ + [tex]v_{oy}[/tex] t - ½ g t²
at the base the height is zero (y = 0 m)
0 = y₀ + 0 - ½ g t²
t = √ (2y₀ / g)
we calculate
t = √ (2 200 / 9.8)
t = 6.389 s
with this time we calculate the horizontal speed
v₀ₓ = x / t
v₀ₓx = 25 / 6,389
v₀ₓ = vₓ = 3.91 m / s
When checking the answers, the correct one is C
During a tennis match, a player serves the ball at 23.6 m/s, with the center of the ball leaving the racquet horizontally 2.37 m above the court surface. The net is 12 m away and 0.90 m high. When the ball reaches the net,
(a) does the ball clear it and
(b) what is the distance between the center of the ball and the top of the net? Suppose that, instead, the ball is served as before but now it leaves the racquet at 5.00° below the horizontal. When the ball reaches the net,
(c) does the ball clear it and
(d) what now is the distance between the center of the ball and the top of the net?
Answer:
a
Yes it clears
b
[tex]b= 0.19 \ m[/tex]
c
No it does not clear
d
[tex]z= 0.86 \ m[/tex]
Explanation:
From the question we are told that
The speed at which the player serves the ball is [tex]v = 23.6 \ m/s[/tex]
The height of the ball above the ground is [tex]h = 2.3 7 \ m[/tex]
The distance of the net is [tex]d = 12 \ m[/tex]
The height of the net is [tex]H = 0.9 \ m[/tex]
Generally the time taken for the ball to reach the net is mathematically represented as
[tex]t = \frac{d}{v}[/tex]
=> [tex]t = \frac{12}{23.6}[/tex]
=> [tex]t = 0.508 \ s[/tex]
Generally the change in height of the ball after t is mathematically represented as
[tex]\Delta h = ut + \frac{1}{2} gt^2[/tex]
Here u is the initial velocity which is zero given that the ball was at rest initially
So
[tex]\Delta h = 0* t + \frac{1}{2} * 9.8 * 0.50 8^2[/tex]
=> [tex]\Delta h =1.28 \ m[/tex]
Generally the new height of the ball is mathematically evaluated as
[tex]s= h-\Delta h[/tex]
=> [tex]s = 2.37 - 1.28[/tex]
=> [tex]s = 1.09 \ m[/tex]
From the value obtained we see that [tex]s > H[/tex] hence the ball clears the net
Generally the distance between the center of the ball and the top of the net is mathematically represented as
[tex]b = s - H[/tex]
=> [tex]b = 1.09 - 0.90[/tex]
=> [tex]b= 0.19 \ m[/tex]
Given that the ball makes an angle of [tex]5^o[/tex] with the horizontal , the velocity along the x-axis is
[tex]v_x = v cos(5)[/tex]
=> [tex]v_x = 23.6 cos(5)[/tex]
=> [tex]v_x = 23.5 \ m/s[/tex]
The velocity along the y-axis is
[tex]v_y = v sin(5)[/tex]
=> [tex]v_y = 23.6 sin(5)[/tex]
=> [tex]v_y = 2.06 \ m/s[/tex]
Generally the time taken for the ball to reach the net is
[tex]t = \frac{d}{v_x}[/tex]
=> [tex]t = \frac{12}{23.5}[/tex]
=> [tex]t =0.508 \ s[/tex]
Generally the change in height of the ball after t seconds is
[tex]c = v_yt + \frac{1}{2}gt^2[/tex]
=> [tex]c = 2.06 * 0.508 + \frac{1}{2}* 9.8 * 0.508 ^2[/tex]
=> [tex]c = 2.33[/tex]
Generally the new height of the ball after time t seconds is
[tex]e = h - c[/tex]
=> [tex]e = 2.37 - 2.33[/tex]
=> [tex]e = 0.04 \ m[/tex]
From the value obtained we see that [tex]e < H[/tex] hence the ball does not clear the net
Generally the distance between the center of the ball and the top of the net is mathematically represented as
[tex]z = H-e[/tex]
=> [tex]z = 0.90 - 0.04[/tex]
=> [tex]z= 0.86 \ m[/tex]
(a) Yes, the ball clears the net.
(b) The distance between the center of the ball and the top of the net is 0.203 m.
(c) No, the ball does not clear the net.
(d) Now, the distance between the center of the ball and the top of the net is -0.85 m.
What is a Projectile motion?When any object or body is launched with some initial velocity and making some angle with the horizontal, the body travels in a parabolic path. It is known as the projectile motion.
Given,
The horizontal distance traveled by the ball is 12 m.
The height of the top of the net is 0.90 m.
The height of the horizontal launch of the ball is 2.37 m.
The time for the horizontal motion of the projectile that is the ball is,
[tex]\begin{aligned} {{v}_{0x}}&={{S}_{x}}t \\ t&=\dfrac{{{S}_{x}}}{{{v}_{0x}}} \\ &=\dfrac{{{S}_{x}}}{{{v}_{0}}\cos 0{}^\circ } \\ &=\dfrac{{{S}_{x}}}{{{v}_{0}}} \end{aligned}[/tex]
The equation for the vertical motion of the projectile can be solved by substituting the above result.
[tex]\begin{aligned} y&={{y}_{0}}+{{v}_{0y}}t-\frac{1}{2}g{{t}^{2}} \\ y&={{y}_{0}}+\left( {{v}_{0}}\sin 0{}^\circ \right)\left( \frac{{{S}_{x}}}{{{v}_{0x}}} \right)-\frac{1}{2}g{{\left( \frac{{{S}_{x}}}{{{v}_{0x}}} \right)}^{2}} \\ \left( 0.90\text{ m}+h \right)&=\left( 2.37\text{ m} \right)+0-\frac{1}{2}\left( 9.8\text{ m/}{{\text{s}}^{2}} \right){{\left( \frac{12\text{ m}}{23.6\text{ m/s}} \right)}^{2}} \\ h&=2.37\text{ m}-\text{1}\text{.267 m}-0.90\text{ m} \\ &=0.203\text{ m} \end{aligned}[/tex]
Now, consider the case when the ball is thrown with an angle [tex]\bold{5^{\circ}}[/tex] with the horizontal.
The horizontal component of the initial velocity is [tex]\bold{v_0 \cos 5{}^\circ.}[/tex]
The vertical component of the initial velocity is [tex]\bold{v_0 \sin 5{}^\circ.}[/tex]
For the horizontal distance traveled by the ball in this case, the time taken can be calculated as below,
[tex]\begin{aligned} {t}'&=\frac{{{{{S}'}}_{x}}}{{{{{v}'}}_{0x}}} \\ &=\frac{12\text{ m}}{\left( 23.6\text{ m/s} \right)\cos 5{}^\circ } \\ &=0.51\text{ s} \end{aligned}[/tex]
Now, the vertical distance above the ground, y’, traveled by the projectile till reaching the net can be determined as,
[tex]\begin{aligned} {y}'&={{{{y}'}}_{0}}+{{{{v}'}}_{0y}}{t}'-\frac{1}{2}g{{{{t}'}}^{2}} \\ &=0\text{ m}-\left( \left( 23.6\text{ m/s} \right)\sin 5{}^\circ \right)\left( 0.51\text{ s} \right)-\frac{1}{2}\left( 9.8\text{ m/}{{\text{s}}^{2}} \right){{\left( 0.51\text{ s} \right)}^{2}} \\ &=-1.05\text{ m}-1.28\text{ m} \\ &=-2.32\text{ m} \end{aligned}[/tex]
The height above the top of the net can be determined by adding the above result with (2.37 m - 0.90 m) which is the height of the net’s top relative to the launch position.
[tex]\begin{aligned} {h}'&=\left( 2.37\text{ m}-0.90\text{ m} \right)+{y}' \\ &=\left( 2.37\text{ m}-0.90\text{ m} \right)-2.32\text{ m} \\ &=-0.85\text{ m} \end{aligned}[/tex]
Thus, the distance between the center of the ball and the top of the net is -2,32 m.
When the ball leaves the racquet at 5.00° below the horizontal, the distance between the center of the ball and the top of the net is -0.85 m.
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I need help I do test I scared
Answer:
i think the answer is #3. :)
What is Humpty Dumpty's momentum if he has a mass of 56kg and is walking to the wall at a rate of 3 m/s?
Answer:
168
Explanation:
56 x 3
have a nice day
Select all the correct answers.
Which situations describe an elastic collision?
(A) Two glass marbles bounce off each other.
(B) Rodrick flops onto his sofa and sinks into the cushion.
(C) A tossed water balloon flattens when it lands on the grass.
D) A bowling ball knocks over five pins.
A beam of electrons moving with a velocity Of 101 m/s
enters midway between two horizontal parallel plates which
Que 5cm long. 2cm apart and have pod Of V volt
applied between them - Calculate v if the beam is deflected
so that it just grazes the edge of the lower plate.(e/m = 1.8×10^11 c/kg)
Answer:
Explanation:
electrical field in vertical direction = V / .02 , .02 is distance between plate and V is potential difference .
force on electrons = V x e / .02
acceleration of falling electrons
= V x e /( .02 x m )
= 50 x 1.8 x 10¹¹ V
a = 9 x 10¹² V .
Time to cover length of plate
t = .05 / 10⁷ = 5 x 10⁻⁹ s , velocity of electron = 10⁷ m /s .
vertical distance covered by electron s = .01 m with acceleration a in time t
s = 1/2 a t²
.01 = .5 x 9 V x 10¹² x ( 5 x 10⁻⁹ )²
10⁻² = 4.5 x 25 x 10⁻¹⁸ x 10¹² V
V = 10⁴ / (4.5 x 25)
= 88.89 Volt .
The space shuttle slows down from 1200 km/hr to 400 km/hr over 10 seconds. What is the space shuttles deceleration?
That's if the answer should be in m/s2.
Weight is proportional to but not equal to mass. In which of the following situations would a person show an increase in weight but not an increase in mass?
Group of answer choices
a Landing on a planet with more gravity.
b Traveling on the highway in a SUV.
c Living in a chamber in an underwater habitat.
d Climbing to the top of a mountain.
Answer: c living in a camber in an under water habitat
Explanation:
The sodium-potassium pump moves blank ions into the cell and blank ions out of the cell.
potassium ions into the cell and
outside
⇒ sodium ions out of the cell.
What is the force needed to move a 300 kg object if you have an acceleration of 8 m/s2?
Answer: mass = 10 kg, acceleration = 3 m/s2.
Explanation: I hope that helped!!
An airplane flies north at 300.0 km/h relative to the air and the wind is blowing south at 15.0 km/h. What is the airplane’s velocity relative to the ground? *
315 km/h North
15 km/h south
285 km/h North
300 km/h South
Answer:
285
Explanation:
read and alot jbgdxtffhgdae
PLSSSS HELPPP What effects do mutations have? Check all that apply.
A) could change protein shape
B)never change protein shape
C)might be neutral
D)always change the way a trait is observed
E)might be harmful
F)might be beneficial
Answer:
E, F, A, C
Explanation:
They cannot change the way a trait is observed
Mutations could change protein shape(A), could cause genetic disorders and harm you(E), could actually be beneficial and cause adaptations to your environment(F), or they could be neutral in which no changes are observantly notable(C).
Hope this helps
What is it called when we have two gears connected by a chain in when large gear turns wants to small gear turns two or more times
In a lacrosse game a ball is thrown with a force of 2000 N. The throwing force acted for 0.8 seconds. If the ball had a change in velocity, Δv, of 50 m/s, what is the mass of the ball?
Answer:
i beleive i cannot help you in physics
Explanation:
A group of students is making paper airplanes. They think that the kind of paper and the design of the airplane may affect how for each paper airplane fles. The students first test if the kind of paper affects how far the
airplane fies. They make
several otrplanes out of different kinds of paper, using
the same design Why is it important that all the airplanes have the same design?
Help please !!
Answer:
The reason why it is important that all the airplanes have the same design is that the students first test is an experiment to determine the effect of the paper kind on the distance the airplane flies
The first experiment, therefore measures the effect of the independent variable, which is the kind of paper on the dependent variable, which is how far the paper flies
The constant or the factor held constant in the experiment is the design of the airplane, so as to ensure that changes in the distance flown by the airplane are due to the changes in the kind of paper alone
Explanation:
An airplane is flying with velocity of 70km\hr in north east direction .The wind is blowing 30km\hr from north to south.What is the resultant displacement of the aeroplane in 4 h
Answer:
The resultant displacement of the airplane in 4 hours is 212.8 km.
Explanation:
The components of the airplane's velocity and wind's velocity are:
Airplane:
[tex] v_{a_{x}} = v_{a}cos(45) = 70 km/h*cos(45) = 49.50 km/h [/tex]
[tex] v_{a_{y}} = v_{a}sin(45) = 70 km/hsin(45) = 49.50 km/h [/tex]
Wind:
[tex] v_{w_{x}} = 0 [/tex]
[tex] v_{w_{y}} = v_{w} = -30 km/h [/tex]
Now, to know the new velocity of the airplane we to find the result vector:
[tex] v_{x} = v_{a_{x}} + v_{w_{x}} = 49.50 km/h + 0 = 49.50 km/h [/tex]
[tex]v_{y} = v_{a_{y}} + v_{w_{y}} = 49.50 km/h - 30 km/h = 19.50 km/h[/tex]
Now, the magnitude of the new speed of the airplane is:
[tex] v_{a} = \sqrt{v_{x}^{2} + v_{y}^{2}} = \sqrt{(49.50 km/h)^{2} + (19.50 km/h)^{2}} = 53.20 km/h [/tex]
Finally, after 4 hours the resultant displacement of the airplane is:
[tex] x = v*t = 53.20 km/h*4 h = 212.8 km [/tex]
Therefore, the resultant displacement of the airplane in 4 hours is 212.8 km.
I hope it helps you!
PLEASE HELP!!!!!!!!!
An objec with a mass of 7 kg accelerates 5m/s2 when an unknown force is applied to it.what is the magnitude of the unknown force?
Answer:
35 NExplanation:
The force acting on an object given it's mass and acceleration can be found by using the formula
force = mass × acceleration
From the question we have
force = 7 × 5
We have the final answer as
35 NHope this helps you
Why does it make sense that a 9 Liter pot of boiling water has more heat than a 1.5 L pot of boiling water?
Explanation:
because 9 is more than 1.5 and the more water, the more heat
Witch statement about electric force is true?
If white light is a mixture of all the primary colours of light, what is black?
Answer:
The primary colors of light are red, green, and blue. If you subtract these from white you get cyan, magenta, and yellow. ... Mixing these three primary colors generates black. As you mix colors, they tend to get darker, ending up as black.
State one way to decrease the moment of a given force about a given axis of rotation.
Answer:
The moment of a given force about a given axis of rotation can be decreased by decreasing the perpendicular distance of force from the axis of rotation.
Answer:
hope it helps...
Explanation:
The moment of a given force about a given axis of rotation can be decreased by decreasing the perpendicular distance of force from the axis of rotation.
What is cartilage?
7 points
the connective tissue that attaches muscles to bones
the connective tissue that's found between bones
the connective tissue found inside of bones
"The connective tissue that's found between bones."
An example would be between the vertabrae in the spine.
Like the other (inappropriate) answer said, a ligament is what attches muscles and bones.
Also, the tissue inside of bones is bone marrow.
If you know that, you can take out those two options (Option 1 and 3)
Answer:
firm, whitish, flexible connective tissue found in various forms in the larynx and respiratory tract, in structures such as the external ear, and in the articulating surfaces of joints. It is more widespread in the infant skeleton, being replaced by bone during growth
4
Select the correct answer.
What field(s) does a moving electron have?
OA
electric and gravitational fields
B. magnetic and gravitational fields
OC. gravitational, electric, and magnetic fields
OD.
electric field only
Reset
Next
Answer:
What field(s) does a moving electron have?
Explanation:
magnetic and gravitational fields
For Edmentem!
What is the weight of a 500g ball? (gravity is 9.8 m/s)
Answer:
4,900
Explanation:
you find the weight by multiplying the ball in grams to the gravity
The weight or force due to gravity of a 500 g ball is 4.9 N.
What is force?A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.
Given in the question a 500 g ball,
Weight = mass.gravity
Weight = .5*9.8
Weight = 4.9 N
The weight or force due to gravity of a 500 g ball is 4.9 N.
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Which refers to the ratio of output work to input work of a machine expressed as a percent?
total work
wattage
efficiency
power
Answer: C.) Efficiency
Explanation: Edge 2020 good luck ^__^
can somone pls help me??!! i’m very stuck
Answer:
b
Explanation:
A box with a weight of 100 N is at rest. It is then pulled by a 50 N horizontal
force. What is the mass of the box?
If the box weighs 100N on Earth, then its mass is 10.2 kg. A pulling force has nothing to do with it.
I will mark brainliest !!
Answer:
i think its b
Explanation:
When we describe both the speed and direction of motion, we are
descriting its acceleration.
True
False
Answer:
True
Explanation: