A builder needs to cover 10 square yards of floor with tile. red tile costs $60 per square yard, and white tole costs $40 per square yard. if the builder spends exactly $480 on tile, how much of the floor will be overed with RED tile?

Answers

Answer 1

Answer:40 square yards

Step-by-step explanation:

Given

Floor area A=10 square yards

Red tile costs [tex]\$ 60[/tex] per square yards

White tile costs [tex]\$40[/tex] per square yards

Total money spent=[tex]\$480[/tex] on tiles

Suppose red tiles cover an area of [tex]x[/tex] square yards

So, we can write

[tex]60\times x+40\times (10-x)=480\\60x+400-40x=480\\20x=80\\x=40\ \text{square yards}[/tex]

Red tiles cover an area of 40 square yards  


Related Questions

PLEASE HELP PLEASE 100 POINTS PLUS BRAINLIEST
(I had the answer already but it deleted and now I can’t find it)

Answers

Step-by-step explanation:

Area of Sector

= θ/360° * πr² (degrees) or 0.5r²θ (radians)

Question 11:

(88°)/360° * π(19)² = 277.23ft².

Question 12:

(260°)/360° * π(11)² = 274.54mi².

Question 13:

0.5(6.2)²(7π/12) = 35.22km².

Question 14:

0.5(7.1)²(5π/3) = 131.97cm².

Question 15:

(215°)/360° * π(4.5)² = 37.99yd².

Question 16:

0.5(21.4)²(13π/18) = 519.54m².

here is the answers!

Area of Sector

= θ/360° * πr² (degrees) or 0.5r²θ (radians)

Question 11:

(88°)/360° * π(19)² = 277.23ft².

Question 12:

(260°)/360° * π(11)² = 274.54mi².

Question 13:

0.5(6.2)²(7π/12) = 35.22km².

Question 14:

0.5(7.1)²(5π/3) = 131.97cm².

Question 15:

(215°)/360° * π(4.5)² = 37.99yd².

Question 16:

0.5(21.4)²(13π/18) = 519.54m².

Which of the following systems of linear inequalities is represented by the
solution graphed below?

Answers

Answer:

look it up

Step-by-step explanation:

Solve the matrix equation below

Answers

Answer:

We need to distribute the values Hence [-4 0: 0 - 2 ] +[0 -3: 5 -4] X + [ 0 -3: 5 -4 ] = [19 -27 : 10 -24]

The price of each box of Girl Scout
cookies is $ 20 - 4. Write an
expression using multiplication to
represent the total cost of 3 boxes of
cookies.

Answers

20-4 equals 16. So that means that’s our
answer of price per box. So 16 times 3 equals 48. A equation for this would be:
20-4=16X3=48

if something is plentiful, possession of it will not increase your power. A resource need to be perceived as _____ to create dependency.
= Scarce

Answers

Step-by-step explanation:

if something is plentiful, possession of it will not increase your power. A resource need to be perceived as scarce to create dependency.

what is 2+2-3+9-5+3=

Answers

Answer:

8

Step-by-step explanation:

Answer: the answer is 8

Step-by-step explanation: hope this helps :)

Marissa counted 29 coins in her change purse which contained, d, dimes and, q, quarters. The value of the coins is $5.00. How many dimes and how many quarters are in her change purse?

Answers

Answer:

i think the rubber ducky in the bath died on the celling so she was happy and then there was a puddle of tears on the ground so thats why u should never go to school

Step-by-step explanation:

The econ motel charges $260 for four nights at this rate how much would seven nights cost

Answers

Answer:

$455 for seven nights

Step-by-step explanation:

260/4= 65

65 is the cost for 1 night

65*7=455

Answer:

$455

Step-by-step explanation:

260 divided by 4 will give you how much for one night so then multiply that answer by 7 and you have your answer.

The table shows the regular price and percent of discount for four items. Write the correct sale price for each item. Round to the nearest cent if necessary.

Answers

Answer:

Step-by-step explanation:

A. $154.20 * 0.65   = $100.23

B. $91.96 * 0.70 = $64.37

C. $47.60 * 0.75 = $35.70

D. $84.60 * 0.80 = $67.68

10 pens for $8.99.
25 pens for $19.75

Answers

What is the question?

Step-by-step explanation:

Answer:

so you need to find the cost of one pen, which ever is cheaper pick that one

EMERGENCY IF you dont know the answer do not answer IT

Answers

Answer:

[tex]x^2+11x+24[/tex]

Step-by-step explanation:

The area of a rectangle is given by [tex]l\cdot w[/tex]. Plugging in our given values, we get:

[tex]A=(x+3)(x+8)=x^2+8x+3x+24=\fbox{$x^2+11x+24$}[/tex].

This is a polynomial in standard form [tex]\checkmark[/tex]

Answer:

x^2 + 11x + 24

Step-by-step explanation:

x times x is x^2

x times 8 is 8x

x times 3 is 3 x

8 times 3 is 24

add it all together and its x^2 + 11x + 24

True or false
$24 fir 6 ft of chain represents a rate of $4 per foot of chain

Answers

Answer:

I think its true but im not sure

Step-by-step explanation:

Which equation is modeled below?
O 2x+(-2)=-2x+
O 4x+(-2)=-2x+6
O 2x+4 = 6x + 2
O-2x+4=6x+(-2)​

Answers

Answer:

4x + (-2) = -2x+6

Step-by-step explanation:

im not gonna explain a diagram but it won't let me submit.

U-substitutions only work for specific kinds of expressions. Below, you are asked to choose a value of n for which u-substitutions will be a useful integration technique. Then, you are to compute the antiderivative with that specific n. (E.g., if n = 5 makes u-subs work, then solve the integral with a 5 in place of n).
(a) [ zºeke*+1 "'de
(b) /co cos(1/2) dr
(c) / r+n dr 22 + 8x - 4

Answers

Answer:

Step-by-step explanation:

(a) [tex]\int x^n e^{5x^4+1} \ dx[/tex]

Suppose [tex]5x^4 + 1 = f[/tex]

by differentiation;

[tex]\implies \ 20 x^3 dx = df --- (1)[/tex]

Suppose n = 3

Then, the integral

[tex]I = \int x^ 3 e^{5x^4 + 1} \ dx[/tex]

[tex]= \int e^f \ \dfrac{df}{20}[/tex]

[tex]= \dfrac{1}{20} \int e^f \ dt[/tex]

[tex]= \dfrac{1}{20} e^f + C[/tex]

recall that [tex]f = 5x^4 + 1[/tex]

Then;

[tex]\mathbf{ I = \dfrac{1}{20}e^{5x^4+1}+C}[/tex]

(b) [tex]\int \dfrac{cos (\dfrac{1}{x^3})}{x^n } \ dx[/tex]

suppose; [tex]\dfrac{1}{x^3} = f[/tex]

[tex]x^3 = f[/tex]

[tex]\implies -3x^{-4} \ dx = df[/tex]

[tex]\implies \dfrac{1}{x^4} \ dx =-\dfrac{1}{3} df[/tex]

If n = u, then the integration is:

[tex]I = \int \dfrac{1}{x^4} \ cos (\dfrac{1}{x^4}) \ dx[/tex]

[tex]= \int -\dfrac{1}{3} \ cos \ f \ df[/tex]

[tex]= -\dfrac{1}{3} \int \ cos \ f \ df[/tex]

[tex]= -\dfrac{1}{3} \ sin \ f + C[/tex]

Since;  [tex]x^3 = f[/tex]

Then;

[tex]\mathbf {I = -\dfrac{1}{3} \ sin \ \Big( \dfrac{1}{x^3}\Big) + C}[/tex]

(c) [tex]\int \dfrac{x+n}{x^2 + 8x -4} \ dx[/tex]

Suppose  [tex]x^2 + 8x - 4 = f[/tex]

Then, by differentiation of both sides

[tex](2x + 8) \ dx = df[/tex]

[tex](x + 4) \ dx = \dfrac{1}{2} \ df[/tex]

Suppose n = 4 in integration, then:

[tex]I = \int \dfrac{(x + 4) }{x^2 +8x -4} \ dx[/tex]

By substitution;

[tex]I = \int \dfrac{1}{2}\dfrac{1}{f} \ df[/tex]

[tex]= \dfrac{1}{2} \ \ { In |f|} + C[/tex]

[tex]\mathbf{= \dfrac{1}{2} \ \ { In |x^2+8x -4|} + C}[/tex]

The suitable substitutions of n are 3,4,4 respectively.

What is integration?

The process of finding integrals is called integration.

a)[tex]f(x)=\int\limits {x^3e^{5x^4+1} } \, dx[/tex]

Suppose

[tex]5x^4+1 =t\\20x^3 dx =dt[/tex]

So, we need n=3 for easy integration.

[tex]f(x)=\int\limits {x^3e^{5x^4+1} } \, dx[/tex]

[tex]I = \frac{1}{20} \int\limits {e^{t} } \, dt[/tex]

[tex]I=\frac{e^{t} }{20}[/tex]

[tex]I = e^{5x^{4}+1 }/20 +c[/tex]

b)Similarly for [tex]f(x) = \int\limits\frac{cos(\frac{1}{x^3} )}{x^n} \, dx[/tex]

n=4 is needed for easy integration.

I = [tex]\frac{-1}{3} sin(\frac{1}{x^3} ) +c[/tex]

c)For [tex]f(x) = \int\limits \frac{x+n}{x^{2} +8x-4} \, dx[/tex]

n=4 is needed for easy integration.

[tex]I = \frac{1}{2} log(x^{2} +8x-4)[/tex]

Hence, the suitable substitutions of n are 3,4,4 respectively.

To get more about integration visit:

https://brainly.com/question/2633548





HELP ASAP
What is the area of the shaded region?
(2571 - 48) cm
O (2517 - 30) cm
(2517 - 24) cm
(257-12) cm

Answers

Answer:

Step-by-step explanation:

We are given a circle with a partially shaded region. First, we need to determine the area of the whole circle. To do this, we need the measurement of the radius of the circle:

Use the Pythagorean theorem to solve for the other leg of the right triangle inside the circle:

5^2 = 3^2 + x^2

x = 4

The radius is 4 + 1 cm = 5 cm

So the area of the circle is A = pi*r^2

A = 3.14 * (5)^2  

A = 25pi cm^2

To solve for the area of the shaded region:

Ashaded = Acircle - Atriangles

we need to solve for the area of the triangles:

A = 1/2 *b*h

A = 1/2 *6 * 5

A = 15 cm^2

Atriangles = 2 * 15  

Atriangles = 30 cm^2

Ashaded = 25pi - 30

Find two consecutive whole numbers that 34 lies between.

Answers

Answer:

34 lies in between 5 and 6

5^2=25, 6^2=36, so sqrt(34) lies between 5 and 6

How many distinct ways can all the letters on "Geometry" be arranged to form a new "Word"?

Answers

Geo stands for science it’s a greek prefix and the suffix means nothing

A TV that usually sells for $171.38 is on sale for 15% off. If sales tax on the TV is 9%, what is the price of the TV, including tax?

Answers

Answer:

171.38 - 15% plus tax= 171.23

Hope this helped!

I got 15 but not sure

Madison is making a cleaning solution by mixing a multi-surface cleaner with water in the
ratio of 2 to 11. How many pints of the
cleaner and water does she need to make 39 pints of solution?
Cleaner:

Answers

Answer:

Im pretty sure its 33 and 6

Step-by-step explanation:

Answer:

Step-by-step explanation:

Set up a proportion

2/13 = x / 39                  Cross multiply

13*x = 2 * 39                  Combine the right

13x = 78                         Divide by 13

x = 78/13

x = 6

Why pick 13? Because the total must come to 39. You will make a mistake if you use 11 rather than 13. You must include the cleaner in the denominator. Very tricky question.

So the final answer is

Cleaner: 6

Water: 39 - 6 = 33 pints of water.

Very few of your classmates will get this if they are not in chemistry. You might even be told your answer is incorrect. It isn't.

Start with 2. Add 6 to each term to get the following term. What is the 6th term of the sequence?

Answers

Answer:

32

Step-by-step explanation:

We can either add all the terms.

2+6=8

2,8

8+6=14

2,8,14

14+6=20

2,8,14,20

20+6=6

2,8,14,20,26

26+6=32

2,8,14,20,26,32

The Sixth term is 32

or We can multiply 6 times 5 (30) and add 2, which would give us 32.

The reasoning behind this is that we are adding six five times (so six times five) and we are also adding the first term (2).

Part2
Please help I’ll make u brainly

Answers

Answer:

someone game me that same question but sadly i wasn't able to get the answer sorry for the inconvience

Step-by-step explanation:

Answer:

3. 2nd degree. Leading term:

[tex] {3x}^{2} [/tex]

Leading coefficient: 3x

Part 1:

[tex] {2x}^{2} + 11x + 15[/tex]

Part 2:

[tex] {3x}^{2} - x - 2[/tex]

Part 3:

[tex] - {x}^{2} + 12x + 17[/tex]

(Part 3 should be correct, double check it, I think it cancels out the minuses in the part 2 equation?)

P.S. I forgot to solve the equations on this and the first page, don't forget that and I can leave another answer for those if you need!

Will mark brainliest!!!solve for each variable

Answers

3j=5j-9 [Diagonals of a rhombus bisect each other]
3j-5j=9
2j=9
j=4.5

k+10=6k [Diagonals of a rhombus bisect each other]
10=5k
k=2

I will give a brainlist if someone could answer this problem with a explanation:)

Answers

Answer:

Step-by-step explanation:

The two base angles in each triangle are equal. (The triangle is isoceles and the property used is angles opposite equal sides are equal).

Now the tricky part. The peak angles are also equal. That's because both peak angles are made equal by Peak angle + 2*base angle = 180

Peak angle = 180 - 2*base angle

Therefore the triangles are congruent by SAS.  

I suppose you could get them equal by taking one of the base angles (all 4 are equal to each other) and the peak angles and claim equality by ASA, but it seems a little bit tortuous to me.

Use substitution to determine which system is represented by the graph.

Answers

Answer:

2x + 4y = 28

-2y = x + 28

Step-by-step explanation:

Looking at the graph, we can see that the lines do not intersect. Therefore, they do not have a shared solution. We need to find the system of equations that does not have a solution.

1) Let's try to solve the third system given (counting from the top). To solve with the substitution method, we need to isolate one variable in one of the equations. I chose to isolate y in -2y = x + 28:

[tex]-2y = x + 28\\y = \frac{-1}{2}x -14[/tex]

2) Now that we've isolated the y in that equation, substitute what y equals in that equation for the y in the other equation. So, substitute [tex]\frac{-1}{2}x-14[/tex] for y in 2x + 4y = 28 and simplify:

[tex]2x + 4(\frac{-1}{2}x - 14) = 28\\2x - 2x- 64 = 28\\-64 = 28[/tex]

In a normal situation, the x's would not cancel out, and we would be able to isolate x to get the x-value of the solution. However, in this case, they have, and we ended up with a false statement, as -64 does not equal 28. Whenever this happens, it means the system does not have a solution. Therefore, the third option would represent the system in the graph.

The given graph shows the simultaneous relationship of equations 2x + 4y = 28 and  -2y = x + 28. Option C is correct.

What are simultaneous linear equations?

Simultaneous linear equations are two- or three-variable linear equations that can be solved together to arrive at a common solution.

Here,
From the graph, the two lines represents the simultaneous relationship,
Where,

The slope of the both lines is,
m = -1/2

And y-intercept of both lines is,
C₁ = 7 and C₂ = - 14

Now,
equations  of the lines are,
y = -x/2 + 7 and y = -x/2 - 14
x + 2y = 14  and x + 2y = -28
or
2x + 4y = 28  - - - - -  -(1) and  -2y = x + 28 - - - - - - -(2)

Now,
From equation 2 substitute y in equation 1
2x + 4[-x - 28]/2= 28
2x - 2x - 56 = 28
-56 = 28
So the lines are parallel and has no solution.

Thus, the given graph shows the simultaneous relationship of equations 2x + 4y = 28 and  -2y = x + 28. Option C is correct.

Learn more about simultaneous equations here:

https://brainly.com/question/16763389

#SPJ2

Learning Task 1: Find the percentage. Write your answer in your notebook.
1) What is 20% of 160?
2) 25% of 96 is
3) 15% of 80 is
4) What is 50% of 70?
5) What is 30% of 20
6) 75% of 40 is
7) 65% of 100 is
8) 200% of 100 is
9) What is 125% of 100?
10) What is 300% of 100?
--​

Answers

Answer:

1.32%

2.24%

3. 12%

4.35%

5. 6%

6. 30%

7. 65%

8. 200%

9. 125%

10. 300%

Help full?

Which is the hidden question in this problem?
Jason bought 6 season tickets to the theatre. Each ticket cost $120.
A season parking pass cost $30. How much did Jason spend for the tickets and the parking pass?
A Will the tickets cost more than $1,500?
B. How much more is the cost of the tickets than the cost of the parking pass?
How much do six season tickets cost?
D
How much will two parking passes cost?

Answers

Answer

how much more is the cost of tickets than the cost of parking pass

Step-by-step explanation:\

i think, sorry if im wrong but its kinda hard to understand what you typed.

Answer:

A: No the tickets won't cost more than $1500.

B: 90 more dollars.

6 season tickets cost $720

D: 2 parking tickets will cost $60

Help plz:)))I’ll mark u Brainliest

Answers

6/2 or 3/0 I dont know if this is right I'm really not sure but the sums look right except for the fact that you can simplify down to 3/0 overall I think its ok

Step-by-step explanation:

39+24+33 = 96

11+13+8 = 32

96/32 simplified down = 6/2 = 3/0

Answer this question
(Factors of 36)

1,36


_,_

_,_

4,9

_,_

*please answer asap!*

Answers

Answer:

1,36  2,18  3,12  4,9 and 6,6

Step-by-step explanation:

If you multiply them, they equal 36

Given that the following is a Rhombus, find the missing angles.

Answers

Answer:

1. 90

2. 61

3. 29

4. 61

Step-by-step explanation:

1 is a 90 degree angle. Triangles = 180 degrees

Amy purchased a brand–new mountain bike, which she's riding through the winding trails. The bike's displacement is given by
s(t) = t3 − 2t2 + 3. What is the bike's acceleration after three minutes?

Answers

Answer:

a = 14 m/min²

Step-by-step explanation:

The displacement of bike is given by :

[tex]s(t)=t^3-2t^2+3[/tex]

Velocity, [tex]v=\dfrac{ds(t)}{dt}[/tex]

Finding velocity of the bike.

[tex]v=\dfrac{d}{dt}(t^3-2t^2+3)\\\\=3t^2-4t[/tex]

Acceleration, [tex]a=\dfrac{dv(t)}{dt}[/tex]

[tex]a=\dfrac{d}{dt}(3t^2-4t)\\\\=6t-4[/tex]

At t = 3 minutes,

a = 6(3) - 4

= 18-4

= 14 m/min²

So, the bike's acceleration after 3 minutes is 14 m/min².

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