a piping system consists of 100 ft of 2-inch pipe, a sudden expansion to 3-inch pipe, and then 50 ft of 3-inch pipe. Water is flowing at 100 gal/min through the system. What is the pressure difference from one end of the pipe to the other

Explanation:

the formula of speed is distance traveled by time it work

31.25 cm/sec

__________________________________________________________

We are given:

Distance travelled = 150 cm

Time taken = 4.8 seconds

Final Speed of the Marble:

Speed of the marble = Distance travelled / Time taken

Speed of the marble = 150 / 4.8

Speed of the marble = 31.25 cm/sec

One of the main uses of this device is to examine a beam of charged particles

The cathode ray tube is a device used to determine the charge flowing in a gas. When an electric field is set up with the help of metal electrodes, the cathode ray tends to bend towards the positive electrode.

Since the cathode ray bends towards the electrodes, it implies that it has a charge and the electrodes present help us determine the charge of the beam of charged particles and thus examine the beam of charged particles.

So, one of the main uses of this device is to examine a beam of charged particles.

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Answer:

B

Explanation:

Answer:

$4.00

Explanation:

The cost per pound is $4.00, $11 divided by 2.75 is 4.

Answer:

Th cost per pound is $4.00.

Explanation:

11/2.75= 4

Answer:

I AM SO SORRY

but here is the answer

Explanation:

20 j

Answer: • They have same change in velocity but different changes in kinetic energy

•They started at the same height.

Explanation:

First and foremost, we need to note that both balls have thesame acceleration due to gravity and due to this, even though they've different masses, they'll fall at same speed.

Also, since kinetic energy that's, the energy relating to motion of a mass, us dependent on mass and speed, their kinetic energy will be different.

Therefore, based in the explanation, the correct options are:

• They have same change in velocity but different changes in kinetic energy

•They started at the same height.

Answer:

A

Explanation:

Answer:

option c is correct

Explanation:

we know that

2as=vf^2-vi^2

vf=24 m/s

vi= 0 m/s

a=g= 9.8 m/s^2

s=vf^2-vi^2/2a

s=(24)²-(0)²/2*9.8

s=576/19.6

s=29.4 m

therefore option c is correct

Answer:

Explanation:

F=kx

x=F/k

F=2000 kg

x=100 cm=9*10^-3

effective spring constant=k=F/x

k=2000/9*10^-3=2.2*10^-5

now frequency

f=1/2π√k/m

f=1/2*3.14√2.2*10^-5/310

f=1/6.28√7.097*10^-8

f=1/6.28*2.7*10^-4

f=0.16*2.7*10^-4

f=4.32*10^-5

The effective spring constant of the springs is 33755.55 N/m.

The frequency of the car's vibration is 2.07 Hz.

The definition of force in physics is: The push or pull on a massed object changes its velocity. An external force is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude.

A spring balance can be used to calculate the Force. The Newton is the SI unit of force.

Weight of the four people: F = 310 × 9.80 N = 3038 Newton.

The additional compression of the spring: x = 0.90 cm = 0.90 × 10⁻² m.

Hence, the effective spring constant of the springs: k= force/compression

= 3038 N/0.90 × 10⁻² m

= 33755.55 N/m.

The frequency of the car's vibration is: f = 1/2π√(k/m)

=1/2π√(33755.55/2000)

= 2.07 Hz.

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Answer:

The time it takes the car to stop is 8.64 s.

Explanation:

Given;

initial velocity of the car, u = 37.3 m/s

final velocity of the car, v = 8.8 m/s

constant acceleration of the car, a = -3.3 m/s²

The time it takes the car to stop is given by;

[tex]t = \frac{v-u}{a}[/tex]

Substitute the givens;

[tex]t = \frac{v-u}{a}\\\\t = \frac{8.8-37.3}{-3.3}\\\\t = 8.64 \ s[/tex]

Therefore, the time it takes the car to stop is 8.64 s.

Answer:

[tex]{:}\longrightarrow[/tex][tex]\sf 1km=1000×100cm [/tex]

[tex]{:}\longrightarrow[/tex][tex]\sf 1km=100000cm [/tex]

Total distance

[tex]{:}\longrightarrow[/tex][tex]\sf 100000+560=1000560cm [/tex]

[tex]{:}\longrightarrow[/tex][tex]\sf 1000.56m[/tex]

[tex]{:}\longrightarrow[/tex][tex]\sf 1.560km [/tex]

Answer:

900

Explanation:

v = s / t = 9000m / 10 s = 900m/s

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Answer:

3240km/h. or, 900m/s.

Explanation:

plz mark mine as brainliest. i gave both.

Answer:

metals like iron or nickel

Explanation:

Answer:

320 paper clips

Explanation:

mass = volume × density = 20cm³ × 8g/cm³ = 160g

mass of 1 paper clip = 0.50g

mass of x paper clips = 160g

x = 160/0.50 = 320

Answer:

hi

Explanation:

how to convert gumbauan baboy to kung burger p

Answer:

False

Explanation:

Weather is the day-to day condition of an area including temperature, pressure, and precipitation. Climate is the usual pattern of temperature, pressure, and precipitation pf an area over time.

It is true that the climate is the day-to day condition of an area including temperature, pressure, and precipitation. Weather is the usual pattern of temperature, pressure, and precipitation pf an area over time.

The weather is the current state of the atmosphere for a particular place and at a definite or short period of time. The atmospheric conditions which are considered are temperature, cloudiness, dryness, humidity, rain, sunshine and wind.

The climate is the atmospheric conditions of a particular place over a long time period.

It is the condition of the Earth and the atmosphere which tells us about the extent at either it is hot or cold, wet or dry, or it can be calm or stormy type. Basically the weather changes and happened at the least level of the atmosphere and the layer is known to be the troposphere that is found just below the stratosphere. Troposphere is the layer present in the most lower level forming the Earth's atmosphere. In this layer of has 75% mass out of atmospheric mass and 99% of the total mass of water vapor.

So, the given statement is true.

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Answer:

The final velocity of the car is 26.65 m/s.

Explanation:

Given;

acceleration of the racecar, a = 6.5 m/s²

initial velocity of the car, u = 0

time of motion, t = 4.1 s

The final velocity of the car is given by;

v = u + at

where;

v is the final velocity of the car

suvstitute the givens

v = 0 + (6.5)(4.1)

v = 26.65 m/s.

Therefore, the final velocity of the car is 26.65 m/s.

Answer:

a. 18.375m/s²

b. 1.142s

Explanation:

A. Using v² = u² + 2as

Where;

V = final velocity (m/s)

u = initial velocity (m/s)

a = acceleration (m/s²)

s = distance (m)

In this question, v = 21m/s, u= Om/s, s = 12m

21² = 0² + 2 × a × 12

441 = 0 + 24a

441 = 24a

a = 18.375m/s²

B). Using V = u + at

21 = 0 + 18.375t

21 = 18.375t

t = 21/18.375

t = 1.142s

Answer:

ke = 1/2mv^2

    = 1/2 * 1200 * 22^2

    = 600 * 484

    = 290400 J

Hope it helped u,

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Answer:

The kinetic energy at this point 290,400

Answer:

oof ok

Explanation:

Thank you :)

As the pushing force x increases, it would be opposed by the static frictional force. As x passes a certain threshold and overcomes the maximum static friction, the block will start moving and will require a smaller magnitude x to maintain opposition to the kinetic friction and keep the block moving at a constant speed. If x stays at the magnitude required to overcome static friction, the net force applied to the block will cause it to accelerate in the same direction.

Let w denote the weight of the block, n the magnitude of the normal force, x the magnitude of the pushing force, and f the magnitude of the frictional force.

The block is initially at rest, so the net force on the box in the horizontal and vertical directions is 0:

n + (-w) = 0

n = w = m g = (5.3 kg) (9.80 m/s²) = 51.94 N

The frictional force is proportional to the normal force, so that f = µ n where µ is the coefficient of static or kinetic friction. Before the block starts moving, the maximum static frictional force will be

f = 0.67 (51.94 N) ≈ 35 N

so for 0 < x < 35 N, the block remains at rest and 0 < f < 35 N as well.

The block starts moving as soon as x = 35 N, at which point f = 35 N.

At any point after the block starts moving, we have

f = 0.48 (51.94 N) ≈ 25 N

so that x = 25 N is the required force to keep the block moving at a constant speed.

As x  is increasing it will be opposed by a static frictional force and for the object to start moving and maintain its acceleration, the magnitude of x must exceed the magnitude of the static frictional force and kinetic frictional force

Given data :

mass of block at rest ( m ) = 5.3 kg

Coefficient of static friction ( μ_s ) =0.67

Coefficient of kinetic friction is ( μ_k ) = 0.48

Horizontal force applied to block = x  

First step : magnitude of normal force ( n ) when object is at rest

n = w            where w = m*g

n - w = 0

n - ( 5.3 * 9.81 ) = 0     ∴  n = 51.94 N

Second step : Required magnitude of x before the movement of object

F =  μ_s * n

F = 0.67 * 51.94  = 34.79 N  ≈ 35 N

∴ The object will start moving once F and x = 35 N

Final step : Magnitude of x  after object start moving

F = μ_k  * n

  = 0.48 * 51.94 = 24.93 N  ≈ 25 N

∴ object will continue to accelerate at a constant speed once F and x = 25N

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Answer:

[tex]72.12\ \text{A/m}^2[/tex]

south

cross sectional area of the beam

Explanation:

v = Velocity of ions = [tex]4.6\times 10^5\ \text{m/s}[/tex]

Number of ions per [tex]\text{cm}^3[/tex] = [tex]4.9\times 10^8[/tex]

Charge density would be the product of number of ions per [tex]cm^3[/tex] and the charge of electrons multiplied by 2 as they are doubly charged.

[tex]\rho_q=4.9\times 10^8\times 10^6\times 2\times 1.6\times 10^{-19}\\\Rightarrow \rho_q=0.0001568\ \text{C/m}^3[/tex]

Current density is given by

[tex]J=\rho_qv\\\Rightarrow J=0.0001568\times 4.6\times 10^5\\\Rightarrow J=72.12\ \text{A/m}^2[/tex]

The current density is [tex]72.12\ \text{A/m}^2[/tex]

The direction of the current density is opposite to the movement of the charged particle. The particles are moving north so the direction of current density will be to the south.

Current is given by

[tex]I=JA[/tex]

where A is the cross sectional area of the beam .

So the cross sectional area of the beam is required to determine the total current in this ion beam.

Answer:

Explanation:

The mass of the object can be found by using the formula

[tex]m = \frac{f}{a} \\ [/tex]

f is the force

a is the acceleration

From the question we have

[tex]m = \frac{135}{25} = \frac{27}{5} \\ [/tex]

We have the final answer as

Hope this helps you

Answer:

k=320N/m

Explanation:

Step one:

given data

Let the initial/equilibrum position be x

mass m1= 0.2kg

F1= 0.2*10= 2N

elongation e= 9.5cm= 0.095m

mass m2=1kg

F2=1*10= 10N

elongation e= 12cm= 0.12m

Step two:

From Hooke's law, which states that provided the elastic limits of a material is not exceeded the extention e is proportional to applied Force F

F=ke

2=k(0.095-a)

2=0.095k-ka----------1

10=k(0.12-a)

10=0.12k-ka----------2

solving equation 1 and 2 simultaneously

   10=0.12k-ka----------2

-   2=0.095k-ka----------1

   8=0.025k-0

divide both side by 0.025

k=8/0.025

k=320N/m

The radial acceleration of a body a distance R from the center of a circular path and with period T has magnitude a such that

a = 4 π ² R / T ²

The given period is

T = 365.3 days ≈ 3.156 x 10⁷ s

(i.e. multiply the number of days by 24 hours/day and 3600 seconds/hour)

So the Earth's radial acceleration is

a = 4 π ² (1.5 x 10¹¹ m) / (3.156 x 10⁷ s)²

a ≈ 0.0059 m/s²