A plane is flying due west at 34 m/s. It encounters a wind blowing at 19 m/s south. Find the resultant veloci

Answers

Answer 1

Answer:

The resultant velocity has a magnitude of 38.95 m/s

Explanation:

Vector Addition

Given two vectors defined as:

[tex]\vec v_1=(x_1,y_1)[/tex]

[tex]\vec v_2=(x_2,y_2)[/tex]

The sum of the vectors is:

[tex]\vec v=(x_1+x_2,y_1+y_2)[/tex]

The magnitude of a vector can be calculated by

[tex]d=\sqrt{x^2+y^2}[/tex]

Where x and y are the rectangular components of the vector.

We have a plane flying due west at 34 m/s. Its velocity vector is:

[tex]\vec v_1=(-34,0)[/tex]

The wind blows at 19 m/s south, thus:

[tex]\vec v_2=(0,-19)[/tex]

The sum of both velocities gives the resultant velocity:

[tex]\vec v =(-34,-19)[/tex]

The magnitude of this velocity is:

[tex]d=\sqrt{(-34)^2+(-19)^2}[/tex]

[tex]d=\sqrt{1156+361}=\sqrt{1517}[/tex]

d = 38.95 m/s

The resultant velocity has a magnitude of 38.95 m/s


Related Questions

A current-carrying wire passes through a region of space that has a uniform magnetic field of 0.96 T. If the wire has a length of 2.7 m and a mass of 0.79 kg, determine the minimum current needed to levitate the wire.

Answers

Answer:

I = 2.99 A

Explanation:

magnetic field, B = 0.96 T, length of wire, l = 2.7 m, mass of wire, m = 0.79 kg.

Since it is expected that the wire would vibrate or move in the magnetic field, from Newton's second law of motion;

F = mg

where F is the force on the wire, m is the mass of the wire and g is the acceleration due to gravity.

But,

F = BIL

⇒ BIL = mg

0.96 x I x 2.7 = 0.79 x 9.8

2.592I = 7.742

I = [tex]\frac{7.742}{2.592}[/tex]

 = 2.9869

I = 2.99 A

The required minimum current is 2.99 A.

The electron dot diagram shows the arrangement of dots without identifying the element.

? with 2 dots above and 1 dot each right, below, left.

Which element’s symbol could replace the question mark in the diagram?

boron (B)
neon (Ne)
rubidium (Rb)
arsenic (As)

Answers

Answer:

Arsenic (As)

Explanation:

Arsenic is the only answer choice that has five valence electrons like the electron dot structure shows.

Answer:

Arsenic (As)

Explanation:

An oscilloscope is set on a TIME/DIV setting of 50 ms. There are 10 divisions on the time scale. A sinewave on the oscilloscope display has exactly three full cycles of the sine wave that fit on the 10 divisions. What is the frequency of the wave?

Answers

Answer:

f= 6 Hz

Explanation:

Since the TIME/DIV setting is set to 50 ms, and there 10 divisions on the time scale, that means that full scale display is 500 msec.If a sinewave has exactly three full cycles of the sine wave that fit on the 10 div, this means that one cycle is just one-third of the 10 div value, as follows:

       [tex]T = \frac{500 msec}{3} = 166.7 msec (1)[/tex]

Since the frequency of a wave is just the number of cycles per unit time, can be written as follows:F = 1/T = 1/(166.7 msec) = 6 Hz

A rollercoaster moves from the bottom of a hill and approaches the top of the hill. If friction between the wheels and the track is ignored, which statement describes the components of the total energy?

*answer choices pic attached*

{If anyone has the answers to the Energy Flows Quick Check or others please let me know}.

Answers

Answer:

The kinetic energy remains same and gravitational potential energy increases.

Explanation:

KINETIC ENERGY:

As, we know that the kinetic energy depends upon the speed of the object. Hence, the kinetic energy is given as:

K.E = (1/2)mv²

where,

m = mass

v = speed

K.E = Kinetic Energy

Since, the friction is ignored, therefore the speed of roller coaster will remain same.

Therefore, its Kinetic Energy will also remain same.

POTENTIAL ENERGY:

The potetial energy od a body depends upon its height, as follows:

P.E = mgh

where,

P.E = potential Energy

m = mass

g = acceleration due to gravity

h = height

As, the roller coaster moves up hill its height increases.

Therefore, its potential energy will also increase.

hence, the correct option is:

The kinetic energy remains same and gravitational potential energy increases.

Consider a block sliding down a ramp whose motion is opposed by frictional forces. The total energy of this system is modeled by the equation:
Etotal = 1/2mv^2 + mgh + Ff(f is underscore)d

Which part of the equation represents the amount of energy converted to thermal energy?

A. mg
B. Ffd
C. mgh
D. 1/2 mv^2

Answers

Answer:

Energy Flows Quick check answers:

1. Ffd.

2. The kinetic energy decreases, and gravitational potential energy increases.

3. The internal energy of the system increases.

4. KEbox= Etotal-mgh

5. Etotal = 1/2m1(v1)^2+1/2m^2(v2)^2+U

The part of the equation that represents the amount of energy converted to thermal energy is [tex]F_f d[/tex].

The given equation for the total energy of a system;

[tex]E_{total} = \frac{1}{2} mv^2 \ +\ mgh\ + \ \ F_fd[/tex]

The definition of the various terms in the energy equation is given as;

[tex]E_{total}[/tex]: this is the total mechanical energy of the system[tex]\frac{1}{2} mv^2[/tex]: this is the kinetic energy of the system[tex]mgh[/tex]:  this is the potential energy of the system[tex]F_f d[/tex]:  this is the energy lost due to friction.

The energy lost due to friction is equal to the energy converted to thermal energy.

Thus, the part of the equation that represents the amount of energy converted to thermal energy is [tex]F_f d[/tex].

Learn more here:https://brainly.com/question/17858145

1) 1000 kg car takes travels on a circular track having radius 100 m with speed 10 m/s. What is the magnitude of the centripetal force acting on the car? *

1 point

1 N

100 N

1000 N

10000 N


2) 1000 kg car takes travels on a circular track having radius 100 m with speed 10 m/s. What is the magnitude of the acceleration of the car? *

1 point

0.1 m/s^2

1 m/s^2

10 m/s^2

100 m/s^2

Answers

Answer:

(1) 1000 N (2) 1 m/s²

Explanation:

(1) Given that,

The mass of a car, m = 1000 kg

Radius of a circular track, r = 100 m

Speed of the car, v = 10 m/s

We need to find the magnitude of the centripetal force acting on the car. The magnitude of the centripetal force is given by :

[tex]F=\dfrac{mv^2}{r}\\\\F=\dfrac{1000\times (10)^2}{100}\\\\F=1000\ N[/tex]

So, the correct option is (c) i.e. 1000 N

(2).The mass of a car, m = 1000 kg

Radius of a circular track, r = 100 m

Speed of the car, v = 10 m/s

We need to find the magnitude of the centripetal acceleration of the car. The magnitude of the centripetal acceleration is given by :

[tex]a=\dfrac{v^2}{r}\\\\a=\dfrac{(10)^2}{100}\\\\a=1\ m/s^2[/tex]

So, the correct option is (b) i.e. [tex]1\ m/s^2[/tex]

Sitting in a parked bu s, you suddenly look up at a bus moving alongside and it appears that you are moving. Why is this? How about with both buses moving in opposite directions?

Answers

Answer:

Explained below

Explanation:

When one sits in a parked bus, and another bus is moving alongside, it means the other bus is moving relative to you. However, this makes the brain register in such a way that it's feels the bus you are in is the one moving.

In the second case where both buses are moving in opposite directions, the brain will register it in such a way that it seems the bus in which you are at is moving at a far higher speed than the speed in which it is actually moving.

This is because the relative velocity of the other vehicle is higher and it is therefore what makes your brain think your bus is moving at a faster speed.

Temporary Wind Turbines-

Answers

Answer:

lol what

Explanation:

Please answer my question

Answers

Answer:

Answer is (b) Mercury, venus and Mars.

Explanation:

i think b is correct!!

;-) :-) :-) :-)

The sun is 150,000,000 km from earth; its diameter is 1,400,000 km. A student uses a 4.6-cm-diameter lens with f = 10 cm to cast an image of the sun on a piece of paper. What is the diameter of the image on the paper?

Answers

Answer:

Explanation:

the image distance can be calculated using below formula of lens

1/v=1/- 1/u

Where

u= Object distance = 15×10^7km

Diameter = 1400000 km

Diameter of lens = 4.6 cm

f= Focal length ( 10 cm)= 1×10^-4

We can substitute to the above formula we have

1/15×10^7km+1/1×10^-4

V=0.001km

Therefore, paper stayed on the focus, hence the sharp image

Explain what it means when we say a substance is magnetic.


Discuss the relationship between electric and magnetic fields.


Which types of wires (cooper, aluminum, or string) are ferromagnetic metals?​

Answers

Answer: See the explanation.

Explanation:

When we say a substance is magnetic it means the atoms are lined in a way that created a magnetic field that goes from one side to the other

These are essentially two aspects of the same thing, because a changing electric field creates a magnetic field, and a changing magnetic field creates an electric field. This is the relationship.

Answer: Copper isn't ferromagnetic,

Aluminum isn't ferromagnetic,

String does have a ferromagnetic property

someone help please


waves disturb ____, but do not transmit it.

a. energy
b. matter
c. sound
d. none of the above

Answers

Answer:

b. matter

Explanation:

Waves disturb matter but do not transmit it.

Waves are disturbances that transmit energy from one point to another. Although they cause disturbances, they do not transfer the matters in the medium.

Energy is propagated by a wave. When for example, sound waves are produced, the disturbance is propagated via particle - particle interaction But after the wave train moves, the particles remain.

A projectile is shot straight up from the earth's surface at a speed of 11,000 km/hr. How high does it go? ________km?

Taken from "Physics for Scientists and Engineers by Randall D. Knight 2nd Edition. Chapter 13 #34. There is an answer in the database already, but I do not understand it.

Answers

Answer:

476.35 km

Explanation:

The following data were obtained from the question:

Initial velocity (u) = 11000 km/hr

Final velocity (v) = 0 km/hr (at maximum height)

Acceleration due to gravity (g) = 9.8 m/s²

Maximum height (h) = ?

Next, we shall convert 9.8 m/s² to km/hr². This is illustrated below:

1 m/s² = 12960 km/hr²

Therefore,

9.8 m/s² = 9.8 m/s² × 12960 km/hr² / 1 m/s²

9.8 m/s² = 127008 km/hr²

Thus, 9.8 m/s² is equivalent to 127008 km/h²

Finally, we shall determine the maximum height reached by the projectile.

This is illustrated below:

Initial velocity (u) = 11000 km/hr

Final velocity (v) = 0 km/hr (at maximum height)

Acceleration due to gravity (g) = 127008 km/hr²

Maximum height (h) = ?

v² = u² – 2gh (since the projectile is going against gravity)

0² = 11000² – (2 × 127008 × h)

0 = 121×10⁶ – 254016h

Collect like terms

0 – 121×10⁶ = – 254016h

– 121×10⁶ = – 254016h

Divide both side by – 254016

h = – 121×10⁶ / – 254016

h = 476.35 km

Thus, the maximum height reached by the projectile is 476.35 km

Light from two lasers is incident on an opaque barrier with a single slit of width 4.0 x 10-5 m. One laser emits light of wavelength 4.0 x 10-7 m and the other is 6.0 x 10-7 m. A screen to view the light intensity pattern is 2.0 m behind the barrier. What is the distance from the center of the pattern to the nearest completely dark spot (dark for both colors)?

Answers

Answer:

y = 6 10⁻² m

Explanation:

This is a diffraction exercise which is described by the expression

          a sin θ = m λ

we can use trigonometry to find the distance from the inside of the screen to the dark point (y)

          tan θ = y / L

angles are very small in diffraction experiments, so we can approximate

          tan θ = sin θ /cos θ = sin θ

          sin θ = y / L

substituting

         a (y / L) = m λ

Let's find the points where the intensity becomes zero

         y = m L λ / a

λ₁ = 4.0 10⁻⁷ m

m = 1

          y = 1 2.0 4.0 10⁻⁷/ 4.0 10⁻⁵

          y = 2 10⁻² m

m = 2

          y = 4 10⁻² m

λ₂ = 6.0 10⁻⁷ m

m = 1

          y = 1 2.0 6.0 10⁻⁷ / 4.0 10⁻⁵

          y = 3 10⁻² m

m = 2

          y = 6 10⁻² m

if we want a point where the two colors are dark, we set the two expressions equal

          y₁ = y₂

          m₁ L  λ₁ / a = m₂ L  λ₂ / a

          m₁/m₂ =  λ₂/λ₁

          m₁ / m₂ = 6 10⁻⁷ / 4 10⁻⁷

          m₁ / m₂ = 1.5

since the quantities m must be integers, the smallest relation that the relation fulfills is

            m₁ = 3

            m₂ = 2

the distance for this destructive interference is

           y = 3 2 4.0 10⁻⁷ / 4.0 10⁻⁵

           y = 6 10⁻² m

this is the first point where the minimum of the two wavelengths coincide

A baseball player exerts a force of 100 N on a ball for a distance of 0.5 mas he throws it. If the ball has a mass of 0.15 kg, what is its velocity as it leaves his hand?

Answers

Answer:

25.82 m/s

Explanation:

We are given;

Force exerted by baseball player; F = 100 N

Distance covered by ball; d = 0.5 m

Mass of ball; m = 0.15 kg

Now, to get the velocity at which the ball leaves his hand, we will equate the work done to the kinetic energy.

We should note that work done is a measure of the energy exerted by the baseball player.

Thus;

F × d = ½mv²

100 × 0.5 = ½ × 0.15 × v²

v² = (2 × 100 × 0.5)/0.15

v² = 666.67

v = √666.67

v = 25.82 m/s

This question involves the concepts of the law of conservation of energy and kinetic energy.

The baseball leaves the hand with a velocity of "25.82 m/s".

From the law of conservation of energy the work done on the ball must be equal to the kinetic energy of the ball:

[tex]W=K.E\\\\Fd=\frac{1}{2}mv^2\\\\v=\sqrt{\frac{2Fd}{m}}\\\\v=\sqrt{\frac{2(100\ N)(0.5\ m)}{0.15\ kg}}[/tex]

where,

F = force applied = 100 N

d = displacement of ball = 0.5 m

m = mass of ball = 0.15 kg

v = 25.82 m/s

Learn more about the law of conservation of energy here:

brainly.com/question/20971995?referrer=searchResults

The attached picture explains the law of conservation of energy.

If the total mechanical energy of the block spring system is 512 J, what is the amplitude for this oscillation?

Answers

Answer:

A = 2.26 m

Explanation:

Given that,

The total mechanical energy of the block spring system is 512 J

Let the spring constant, k = 200 N/m

We need to find the amplitude for this oscillation. The mechanical energy of the spring mass system is given by :

[tex]E=\dfrac{1}{2}kA^2[/tex]

k is spring constant

[tex]A=\sqrt{\dfrac{2E}{k}} \\\\A=\sqrt{\dfrac{2\times 512}{200}} \\A=2.26\ m[/tex]

So, the amplitude of the oscillation is 2.26 m

it is the question 12 part okay​

Answers

Answer:

Yeah it's ok I think. Also, I can't see the answer you gave so maybe updating the question would be nice.

So if you fall into icy water your gonna freeze that’s a given but you can stop it if you get out fast and get in a real hot bath and then get a towel on and you get Hypothermia because your body physically can’t take the cold so it decides to freeze your insides until your heart eventually just stops because it’s frozen.

Can I pls have brainliest :)

Why is the metric system used globally, but we use the US customary units?

Answers

Answer:

The biggest reasons the U.S. hasn't adopted the metric system are simply time and money. When the Industrial Revolution began in the country, expensive manufacturing plants became a main source of American jobs and consumer products.

Explanation:

You are designing a flywheel. It is to start from rest and then rotate with a constant angular acceleration of 0.200 rev/s^2. The design specifications call for it to have a rotational kinetic energy of 330 J after it has turned through 30.0 revolutions.

What should be the moment of inertia of the flywheel about its rotation axis?
Express your answer with the appropriate units.

Answers

Answer: 1.14 kg*m/s

Explanation:

The first person explained everything right, they just forgot to convert the angular acceleration to rads/sec^2 from revs/sec^2. Once that is converted, your answer should come out right.

Another small thing, the answer there has an extra unnecessary step. It tells you to find the square root of w^2 to find w but that is unnecessary since the final equation asked for w^2. Hope this helps! :)

The moment of inertia I of the flywheel about its rotation axis is

[tex]1.39Kgm^2[/tex]

Given

Angular displacement,

[tex]\theta = 30rev \\\\\theta = (30) * 2\pi rad \\\\\theta = 188.495rad[/tex]

Therefore, Final angular velocity (w) will be:

[tex]w^2 = 2\alpha\theta\\\\w^2 = 2 * (0.200 * 2\pi) * (188.49)\\\\w^2 = 473.73\\\\w = 21.76 rad/s[/tex]

Therefore,

moment of inertia

[tex]I = 2 * K / w^2[/tex]

[tex]I = 2 * 330 / 473.73[/tex]

[tex]I = 1.39kgm^2[/tex]

For more information on moment of inertia

https://brainly.com/question/19557854?referrer=searchResults

Erma built the simple motor shown below with a battery, a permanent magnet, a copper coil of wire, and an iron bar. When the motor is turned on, the iron bar and coil spin in a circle The motor transforms _______ energy into _______ energy. Question 27 options: mechanical; chemical electrical; mechanical mechanical; electrical thermal; electrical

Answers

Answer:

electrical to mechanical

Explanation:

The current theory of the structure of the Earth, called plate tectonics, tells us that the continents are in constant motion.
Assume that the North American continent can be represented by a slab of rock 4450 km on a side and 31 km deep and that the rock has an average mass density of 2620 kg/m3.
The continent is moving at the rate of about 1 cm/year.
What is the mass of the continent? Answer in units of kg.
(part 2 of 3)
What is the kinetic energy of the continent? Answer in units of J.
(part 3 of 3)
A jogger (of mass 77 kg) has the same kinetic energy as that of the continent.
What would his speed be? Answer in units of m/s.

Answers

Answer:

1) The mass of the continent is approximately [tex]1.608\times 10^{21}[/tex] kilograms.

2) The kinetic energy of the continent is approximately [tex]8.04\times 10^{16}[/tex] joules.

3) The speed of the 77 kg-jogger would be approximately [tex]45.698\times 10^{6}[/tex] meters per second.

Explanation:

1) The mass of the North American continent can be estimated by using the following formula under the assumption that rock has an uniform density:

[tex]m = \rho \cdot L^{2}\cdot h[/tex] (1)

Where:

[tex]m[/tex] - Mass of the continent, measured in kilograms.

[tex]\rho[/tex] - Average density of the rock, measured in kilograms per cubic meter.

[tex]L[/tex] - Side of the continent, measured in meters.

[tex]h[/tex] - Depth of the continent, measured in meters.

If we know that [tex]\rho = 2620\,\frac{kg}{m^{3}}[/tex], [tex]L = 4.450\times 10^{6}\,m[/tex] and [tex]h = 31\times 10^{3}\,m[/tex], then the mass of the continent is:

[tex]m = \left(2620\,\frac{kg}{m^{3}} \right)\cdot (4.450\times 10^{6}\,m)^{2}\cdot (31\times 10^{3}\,m)[/tex]

[tex]m = 1.608\times 10^{21}\,kg[/tex]

The mass of the continent is approximately [tex]1.608\times 10^{21}[/tex] kilograms.

2) By assuming that continent can be represented as a particle, we define its kinetic energy as:

[tex]K = \frac{1}{2}\cdot m \cdot v^{2}[/tex] (2)

Where:

[tex]K[/tex] - Translational kinetic energy, measured in joules.

[tex]v[/tex] - Motion rate of the continent, measured in meters per second.

If we know that [tex]m = 1.608\times 10^{21}\,kg[/tex] and [tex]v = 1\times 10^{-2}\,\frac{m}{s}[/tex], then the kinetic energy of the continent is:

[tex]K = \frac{1}{2}\cdot (1.608\times 10^{21}\,kg)\cdot \left(1\times 10^{-2}\,\frac{m}{s} \right)^{2}[/tex]

[tex]K = 8.04\times 10^{16}\,J[/tex]

The kinetic energy of the continent is approximately [tex]8.04\times 10^{16}[/tex] joules.

3) The speed of the jogger is derived from the definition of translational kinetic energy:

[tex]v = \sqrt{\frac{2\cdot K}{m} }[/tex]

If we know that [tex]K = 8.04\times 10^{16}\,J[/tex] and [tex]m = 77\,kg[/tex], then the expected speed of the jogger is:

[tex]v = \sqrt{\frac{2\cdot (8.04\times 10^{16}\,J)}{77\,kg} }[/tex]

[tex]v\approx 45.698\times 10^{6}\,\frac{m}{s}[/tex]

The speed of the 77 kg-jogger would be approximately [tex]45.698\times 10^{6}[/tex] meters per second.

PLEASE HELP!!
Which statement accurately describes a balanced force?


A 2-N force presses down on the marble at the same time as a 1.5-N force presses up on the marble.

A marble rolling downhill suddenly comes to rest at a garden wall.

A 25-N force acts on the left side of the marble at the same time as a 25-N force acts on the right side of the marble.

A marble resting on the sidewalk suddenly begins to roll downhill without being touched.

Answers

Answer:

A 25-N force acts on the left side of the marble at the same time as a 25-N force acts on the right side of the marble.

Explanation:

just took test

A 25-N force acts on the left side of the marble at the same time as a 25-N force acts on the right side of the marble.

What is force?

A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.

Balanced force is when the net force applied on the object is zero than said to be balanced.

A 25-N force acts on the left side of the marble at the same time as a 25-N force acts on the right side of the marble.

To learn more about force refer to the link:

brainly.com/question/13191643

#SPJ2

An object moves in along the x-axis with an acceleration given by: a = 5t (m/s2). The position of the object at t=0.0 is 6 m, and its velocity at t=0.0 s is 4 m/s. Calculate the position at t=5 s.​

Answers

Answer:

The position of the object at [tex]t = 5\,s[/tex] is 130.167 meters.

Explanation:

Let [tex]a(t) = 5\cdot t\,\left[\frac{m}{s^{2}} \right][/tex] the acceleration experimented by the object along the x-axis. We obtain the equation for the position of the object by integrating in acceleration formula twice:

Velocity

[tex]v(t) = \int {a(t)} \, dt[/tex] (1)

[tex]v(t) = 5\int {t} \, dt[/tex]

[tex]v(t) = \frac{5}{2}\cdot t^{2}+v_{o}[/tex] (2)

Where [tex]v_{o}[/tex] is the initial velocity of the object, measured in meters per second.

Position

[tex]s(t) = \int {v(t)} \, dt[/tex] (3)

[tex]s(t) = \frac{5}{2}\int {t^{2}} \, dt+v_{o}\int \, dt[/tex]

[tex]s(t) = \frac{5}{6}\cdot t^{3}+v_{o}\cdot t + s_{o}[/tex] (4)

Where [tex]s_{o}[/tex] is the initial position of the object, measured in meters per second.

If we know that [tex]s_{o} = 6\,m[/tex], [tex]v_{o} = 4\,\frac{m}{s}[/tex] and [tex]t = 5\,s[/tex], then the position of the object is:

[tex]s(5) = \frac{5}{6}\cdot (5)^{3}+\left(4\right)\cdot (5)+6[/tex]

[tex]s(5) = 130.167\,m[/tex]

The position of the object at [tex]t = 5\,s[/tex] is 130.167 meters.

HELP THIS IS DUE IN 5 MINUTES!!!!!!!!!!!! WILL GIVE BRAINLIEST

what is the definition of total velocity?

Answers

Answer:

Image result for total velocity definition

The average speed of an object is defined as the distance traveled divided by the time elapsed.

Explanation:

You are explaining to friends why astronauts feel weightless orbiting in the space shuttle, and they respond that they thought gravity was just a lot weaker up there. Convince them and yourself that it isn't so by calculating how much weaker gravity is 200 above the Earth's surface.
Delta G/G = ? %

Answers

Answer:

The gravity is 87.4% as strong as at the Earth’s surface.

Explanation:

Hope this helped!

what happens to the strength of an electromagnet when the voltage in the coils of the solenoid is decreased

Answers

Answer:

Make sure you look at the wording!

Explanation:

if the last word is increased, the answer is increased

if the last word is decreased, the answer is it decreases!

A ball is launched from a 300m cliff and lands 380m away from the cliff in 9 seconds. Calculate the initual speed and the angle of the ball when it was launched.​

Answers

Answer:

Explanation:

Given

Maximum height H = 300m

Range (horizontal distance) = 380m

Required

Initial speed U and the angle of the ball when it was launched.​

Range = U√2H/g

380 = U√2(300)/9.8

380 = U√600/9.8

380 = 7.8246U

U = 380/7.8246

U = 48.57m/s

The initial speed is 48.57m/s

b) Using the formula for calculating time of flight;

T = 2Usin theta/g

9 = 2(48.57)sin theta/9.8

9*9.8 = 97.14sin theta

88.2 = 97.14sin theta

88.2/97.14 = sin theta

sin theta = 0.9079

theta = sin^-1(0.9079)

theta = 65.23°

hence the angle when the ball was launched is 65.23°

A cyclist is riding his bike up a mountain trail. When he starts up the trail, he is going 8 m/s. As the trail gets steeper, he slows to 3 m/s in 1 minute. What is the cyclist’s acceleration?

Answers

Answer:

[tex]\boxed {\boxed {\sf a\approx -0.08 \ m/s^2}}[/tex]

Explanation:

Acceleration can be found by dividing the change in velocity by the time.

[tex]a=\frac{v_f-v_i}{t}[/tex]

The final velocity is 3 meters per second. The initial velocity is 8 meters per second.

We need to convert the time to seconds.

t= 1 minute 60 seconds = 1 minute t=60 seconds

So, we know that:

[tex]v_f=3 \ m/s \\v_i= 8 \ m/s\\t= 60 \ s[/tex]

Substitute the values into the formula.

[tex]a=\frac{3 \ m/s - 8 \ m/s}{60 \ s}[/tex]

Solve the numerator.

3 m/s - 8 m/s = -5 m/s

[tex]a=\frac{-5 \ m/s}{60 \ s}[/tex]

Divide.

[tex]a=-0.0833333333 \ m/s/s[/tex]

Let's round to the nearest hundredth.

The 3 in the thousandth place tells us to leave the 8 in the hundredth place.

[tex]a\approx -0.08 \ m/s^2[/tex]

The cyclist's acceleration is about [tex]\boxed {-0.08 m/s^2}[/tex]

200. Un automóvil se desplaza

hacia la izquierda con

velocidad constante v,

en el momento en que se

deja caer un saco de lastre

desde un globo en reposo.

El vector que representa

la velocidad del saco vista

desde el automóvil en ese

instante en que se suelta es

Answers

Skajwopwpoe eueusjjeww

When the palmaris longus muscle in the forearm is flexed, the wrist moves back and forth. If the muscle generates a force of 39.5 N39.5 N and it is acting with an effective lever arm of 2.75 cm2.75 cm, what is the torque that the muscle produces on the wrist?

Answers

Answer:

Explanation:

Torque is expressed according to the formula;

Torque = Force × radius

Given

Force = 39.5N

Radius = 2.75cm

Convert radius to metres

100cm ,= 1m

2.75cm = (2.75/100)

2.75cm = 0.0275m

Find the torque

Torque = 39.5×0.0275

Torque = 1.08625Nm

Hence the torque is 1.08625Nm

Other Questions
What are the alkaline earth metals?A. Group 2 elementsO B. Group 18 elementsC. The transition metalsD.up 1 elements An annual fur rendezvous can best be described as acasual meeting where furs were traded for guns.formal meeting that was attended by fur trappers and explorers.formal meeting where trappers traded furs for goods.casual meeting where trapping zones were agreed to. Opportunity cost and provide an example [Choose ]Yo soy Carla; yo tengo el pelo castao.Yo soy Juan y soy rubio.Me llamo Susan y soy baja.Arthur, t tienes el pelo castao. How would you describe Elie Wiesel as a child based on the details you were given as a reader in Chapter One A bicycle rider rode her bike 8 1/4 miles on Monday. Yesterday, she rode 6 3/8 miles. The difference in length between the two rides is what fraction of the longer ride? Part B. What distance did she ride if she biked 2 2/11 times her distance on Monday? Explain your response. In the first sentence of paragraph 2, the speaker utilizes which of the following devices? (Gettysburg address)I. asyndetonII. anaphoraIII. parallelismA.I onlyB.III onlyC.I and IIID.II and III E.I, II, and III lupita and kevin walk to school.lupita walks 3/5 mi.kevin walks 0.65 mi.who walks a greater distance to school?how much greater? Si la probabilidad de que un recin nacido sea nio es de 1 de dos opciones, representado en fraccin 1/2, Cul es la probabilidad de que un recin nacido sea nia? If your friend asks you which color sign can also frequently be finger-spelled, what would you say?Group of answer choices"black""white""brown""gray" Solve the inequality 4x-7 What is the controversy that surrounds the phrase he shall take care that the laws be faithfully executed? How pandemic affects your studies ? our community and to the world? Chemistry, please help Describe where most people live in Russia and explain why.???? Find the slope of the line y = -5/4x - 2 Imagine you were George Latham. Explain how you would feel upon reading this letter. Which answer shows 8.45x 104 written in standard form?.00008458,450 84,500 8,450,000 which statement best sums up the relationship between poverty and the need for tribal funding? 1. most tribes are wealthy and can pay for their needs themselves.2. most tribes have high poverty levels and may require outside funding3. American Indians have about the same funding needs as other Americans4. American Indians have high poverty levels but do not except outside funds How was Joseph Stalin different from other totalitarian rulers of his time?O A. He did not kill civilians who opposed him.O B. He allowed his citizens to vote.O C. He fully controlled the Soviet economy.O D. He was extremely nationalistic.