A. praised
B. scolded
C. rewarded
14. Reicon's parents admonished him for breaking their antique collection,
D. silenced
15. I am an advocate of anti-corruption movement in the country.
D. supporter
C. enemy
DirectioRead the statements below. Using context clues, identify the meaning
A. opponent
B. primer
highlighted words.
16. The hotel abolishes its rice-all-you-can policy to avoid wastage of food.
b. removes
d. proposes
A. continues
17. The country has a very tropical climate where it only has dry and wet
seasons similar to other countries in Southeast Asia
a. humid
b. cold
d. normal
-
c. comfortable
d. collected
a. new
c. outdated
18. The obsolete books and other references in the library resulted to the
removal in the shelves and inventory.
b. old
19. Beverages, such as juices, milk, beers and sodas, have increased in
,
due to low supply and importation issues.
a. drinks b. food
d. pastas
20. The luxurious life of my cousin in an exclusive subdivision in Ta
makes me inspired to dream and work hard for me to escape this unp
d.
a. ordinary b. fantastic
c. uncomfortable
c. bread








Help help me plis po summative test ko po ito plis help me

Explanation:

Fgravity = G*(mass1*mass2)/D²

G is the gravitational constant throughout the universe.

D is the distance between the 2 objects.

the distance is now quadrupled.

Fgravitynew = G*(mass1*mass2)/(4D)² =

= G*(mass1*mass2)/(16D²) =

= (G*(mass1*mass2)/D²) / 16 = Fgravity/16

the new gravitational force will be 179/16 = 11.1875 units

Answer:

90m/h N

Explanation:

we consider janes velocity to the positive X axis so Vj=280km/s

and the final position a dot in on the graph r=294km, we find the x and y components:

294*cos(17.8)=280 X+ confirming our theory

294*sin(17.8)=90 Y+ or N and that's the winds' velocity.

Answer:

Mark me as brainlist please.

Answer:

Explanation:

The work of the brakes will equal the initial kinetic energy of the car

Fd = ½mv²

F = mv²/2d

F = 2457(18²) / (2(62))

F = 6,419.903...

F = 6.4 kN

This question involves the concepts of work done and the frictional force.

a. Work done by the person is "692.82 N".

b. Work done by the frictional force is "490.5 N".

a.

Work done by the person can be given by the following formula:

[tex]W=FdCos\theta[/tex]

where,

W = work done by the person = ?

F = Force applied by the person = 80 N

d = distance traveled = 10 m

θ = angle between force and motion = 30°

Therefore,

[tex]W=(80\ N)(10\ m)Cos30^o[/tex]

W = 692.82 N

b.

Work done by the frictional force is given by the following formula:

[tex]W_f=fd\\W_f=\mu mgd[/tex]

where,

[tex]W_f[/tex] = work done by the frictional force = ?

μ = coefficient of friction = 0.5

g = acceleration due to gravity = 9.81 m/s²

Therefore,

[tex]W_f=(0.5)(10\ kg)(9.81\ m/s^2)(10\ m)[/tex]

[tex]W_f=490.5\ N[/tex]

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Answer:

A) -31.2 rad/s

B) 28.1 rad/s^2

Explanation:

Answer:

Explanation:

s = s₀ + v₀t + ½at²

assuming that the acceleration is in the direction of initial velocity.

(it would not have to be so)

s = 0 + 10(8) + ½(3.5)(8²)

s = 192 m

Answer:

The importance of signal processing science as has been made clear. Since we now know that it help to convert discrete signal from time domain to frequency domain. Moreover, we are now aware of the difference in DF5 and FFT algorithms as well as the implementation in Matlab.

Explanation:

Fgravity = G*(mass1*mass2)/D².

G is the gravitational constant, which has the same value throughout our universe.

D is the distance between the objects.

so, if you triple one of the masses, what does that do to our equation ?

Fgravitynew = G*(3*mass1*mass2)/D²

due to the commutative property of multiplication

Fgravitynew = 3* G*(mass1*mass2)/D² = 3* Fgravity

so, the right answer is 3×12 = 36 units.

Answer:

Explanation:

s = s₀ + v₀t + ½at²

if the throw point is origin and UP the positive direction and ignoring air resistance.

s = 0 + (-5)(7) + ½(-10)(7²)

s = 0 - 35 - 245

s = - 280 m

Answer:

0.80 kN

Explanation:

Hope you understood it

Answer:

3

Explanation:

state of matter are solid

liquid and

gases

Answer:

Explanation:

At the top of the arc, 3/4 of the acceleration of gravity is use to supply the necessary centripetal acceleration.

0.75g = ω²R

R = 0.75g/ω²

R = 0.75(9.81) / (0.15 rev/s)(2π rad/rev)²

R = 8.283006...

R = 8.28 m

22.5 J

Explanation:

Given:

x = 3 m

[tex]k = 5\:\text{N/m}[/tex]

The spring potential energy [tex]PE_s[/tex] is

[tex]PE_s = \frac{1}{2}kx^2 = \frac{1}{2}(5\:\text{N/m})(3\:\text{m})^2[/tex]

[tex]\:\:\:\:\:\:\:=22.5\:\text{J}[/tex]

The reason why a tiny 1.5 V cell can operate a calculator for a year, but would burn out in a few hours in a tiny robot is because the power demands of the calculator are way less than that of the tiny robot.

Cell capacity is measured by the amount of Amps and Amp Hour (A.H.) capacity for how long a battery can endure.

On the label or in the user's manual, batteries mention their reserve capability, which specifies the approximate amount of time they can operate between charges. You might notice a shorter or longer battery life if your circuit uses more or less power than this hypothetical circuit. Calculate the battery's entire capacity and divide it by the power of your circuit to see how long it can survive.

Load current, which is influenced by the power of the linked item, influences how quickly the battery's electrical capacity will be used up.

The reason the 1.5 V cell would operate the calculator for a year and yet die in a few hours with the robot is that the robot has a much higher load current than the calculator.

Find out more on cell life at https://brainly.com/question/4503865

#SPJ1

Answer:

Enrol in our 50 studyscore masterclass. Click here! Fuel cells are a type of primary cell in that they are not recharged, However, they are unique because they never run out, if the reactants are constantly supplied.

Answer:

a = 25 m/s2

Explanation:

A = f/m

A = Speed/Acceleration

F =‘Force

M = Mass

If the load is in the equilibrium, the magnitude of the tension in the cable is equal to 1,414.5 Newton.

Given the following data:

Scientific data:

To calculate the magnitude of the tension in the cable, if the load is in the equilibrium:

First of all, we would determine the tension caused by the horizontal component of the force:

[tex]\sum F_y ; Tcos\theta - mg=0\\\\Tcos\theta = mg\\\\T=\frac{mg}{cos\theta} \\\\T=\frac{250 \times 9.8}{cos30} \\\\T= \frac{2450}{0.8660}[/tex]

T = 2,829.1 Newton

The magnitude of the tension in the cable is given by:

[tex]\sum F_x ; F - Tsin\theta = 0\\\\F = Tsin\theta\\\\F = 2829.1sin30\\\\F = 2829.1 \times 0.5[/tex]

F = 1,414.5 Newton.

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Answer:

5m

Explanation:

x=?

[tex]sin30^{0} =\frac{x}{10}[/tex]

[tex]x=10sin30^{0} =10(0.5)=5[/tex]

Hope this helps

Answer: Contagion theory states that crowds cause people to act in a certain way; convergence theory says the opposite, claiming that people who wish to act in a certain way come together to form crowds.

Explanation: Its C

Answer:

200 feet

Explanation:

Answer:

A saturated vapour is one that is in balance with its own liquid. Space is considered to be unsaturated if it contains fewer vapours than the maximum amount it can retain at a given temperature. Saturated vapour pressure is unaffected by volume, although it rises as temperature rises.

Explanation:

The equation of the progressive wave is y = 12 cos(40t - 4x)

The general wave equation is given by:

y = A sin(ωt - kx)

Where A is the amplitude, ω is the angular frequency = 2πf, f is the frequency, k is the wave number and y, x is the displacement.

Given the equation for a progressive wave is y=6 cos⁡(20t-4x). Hence:

The amplitude A = 6,

ω = 20 = 2πf

f = 20/2π = 3.183 Hz

Twice the amplitude = 2 * 6 = 12, twice the frequency = 2 * 3.183.

ω = 2π(3.183*2) = 40

Therefore the other progressive wave has an equation of:

y = 12 cos(40t - 4x)

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Answer:

A

Explanation:

Down the hill, the net force increases if she pushes more forward.

Answer:

its a im just did the test

Explanation:

Answer:

The acceleration of the car is 8.10 m/s²

Explanation:

d = 110 m

t = 5.21 s

vi = 0 m/s

a = ?

d = Vᵢ × t + 0.5 × a × t²

110 m = (0 m/s) × (5.21 s) + 0.5 × (a) × (5.21 s)²

110 m = (13.57 s²) × a

a = (110 m)/(13.57 s²)

a = 8.10 m/s²

Thus, The acceleration of the car is 8.10 m/s²

-TheUnknownScientist 72

Hi there!

We can begin by calculating the acceleration of the block and the wheel using the following equation:

d = vit + 1/2at², where initial velocity = 0 m/s

d = 1/2at²

2d/t² = a

2(1.5)/2² = 0.75 m/s²

Now, we can do a summation of torques:

∑τ =  rT

Rewrite using Newton's 2nd Law for rotation:

Iα = rT

Convert α to a using the relationship α = a/r:

I(a/r) = rT

Ia = r²T

I = r²T/a

Plug in the values:

I = (0.40²)(20)/(0.75) = 4.267 kgm²

At the highest attitude, the  velocity of  the ball is 0 m/s, so the kinetic energy is 0 as well.

Hence the answer is potential energy because it doesn't depend on velocity .

We have that for the Question "" it can be said that Calculate the moment which must be applied to the handle of the screw to raise the block is

From the question we are told

The vertical position of the 100-kg block is adjusted by the screw activated wedge. Calculate the moment which must be applied to the handle of the screw to raise the block. The single thread screw has square threads with a mean diameter of 30 mm and advances 10 mm each complete turn. The coefficient of friction for the screw threads is 0.24, and the coefficient of friction for all the mating surfaces of the block and the wedge is 0.40. Neglect friction at the ball joint A

Generally the equation for the Block is mathematically given as

[tex]\sum Fy=0[/tex]

[tex]981cos21.80 = R_2cos53.6\\\\R_2=1535N[/tex]

the equation for the Wedge is mathematically given as

[tex]\sum Fx=0\\\\1535cos36.4=Pcos21.8\\\\P=1331N[/tex]

the equation for the Screw is mathematically given as

[tex]\beta = tan^{-1}*\frac{L}{2*\pi*r} \\\\\beta = tan^{-1}*\frac{10}{2*\pi*(15)} \\\\\\beta = 6.06\\\\\theta = tan^{-1}*0.25 \\\\\theta = 14.04\\\\\\Therefore\\\\\theta + \beta = 20.1\\\\[/tex]

Therefore

[tex]M = Pr tan (\theta + \beta)\\\\M = 1331(0.015) tan20.09\\\\M = 7.30 N.m[/tex]

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