A runner slows down after completing a race. Her deceleration is 0.25 m/s2. After 5 s she is travelling at 4 m/s, determine her initial velocity.​

Answer: Varies

Explanation:

Because moving his legs require force.

Answer:

He is also a low-level telekinetic

Explanation:

He is a telepath and doesn’t have telekinesis btw.

The required torque at the axle, is given by the difference between the

moments of the applied forces.

The torque required is 19.62 N·m counterclockwise

Reasons:

The given parameters are;

Mass of the disk, m = 5.0 kg

Location of the axle = Half the radius of the disk

Diameter of the disk, D = 40 cm = 0.4 m

Applied mass, 0.1 m from the axle = 15 kg

Applied mass, 0.3 m from the axle = 10 kg

Required:

Magnitude of torque at the axle that prevent the disk from rotating

Solution:

Torque needed = Clockwise moment - Counterclockwise moment

Clockwise moment = (10 kg × 0.3 m + 5 kg × 0.1 m) × 9.81 m/s² = 34.335 N·m

Counterclockwise moment = 15 kg × 0.1 m  × 9.81 m/s² = 14.715 N·m

τ + Counterclockwise moment = Clockwise moment

τ + 14.715 N·m = 34.335 N·m

Torque required, τ = 34.335 N·m - 14.715 N·m = 19.62 N·m

Torque required, τ = 19.62 N·m counterclockwise

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The probable question drawing obtained from a similar question online is attached

Hi there!

We know that:

Momentum (p) = mass (kg) × velocity (m/s)

Or:

P = mv

We can rearrange the equation to solve for speed:

P/m = v

Plug in the given values:

(3.75 × 10⁸)/75000 = 5000 m/s

Answer:

directly proportional

Explanation:

The galaxy is known to contain stars of different ages. The indicated features as it points  from left to right are;

Bottom row

The Milky Way Milky exist because  our Sun (a star) and all the planets close to it are part of a galaxy called the Milky Way Galaxy.

A galaxy is known to be a large group of stars, gas, and dust bound together by the force of gravity.

Our galaxy is called by the name the Milky Way because it is usually seen or it appears as a milky band of light in the sky when you view it in a really dark area.

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Answer:

6 newtons

Explanation:

If it's an equal force exerted on the student's hands, the object will not move.

If a student pushes on an object with a force of 6 newtons and the object does not move then the force exerted by the object on the student’s hands would be 6 Newtons because the applied force is equal to the static frictional force until the object does not move.

Friction is a type of force that resists or prevents the relative motion of two physical objects when their surfaces come in contact

As given in the problem If a student pushes on an object with a force of 6 newtons and the object does not move then we have to find out the force exerted by the object on the student’s hands,

Force applied by the student of the object = 6 Newtons

The force exerted by the object on the student's hand = 6 Newtons

Thus, the force exerted by the object on the student’s hands would be 6 Newtons

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The speed of light and the propagation of errors allows to find the results on the questions of the radiation emitted by the laser are:

    a) The frequency is: f = 3.7 10¹⁴ Hz

    b) The energy with its uncertainty is: E = (2.465 ± 0.004) 10⁻¹⁹ J

a) The speed of a wave is related to its wavelength and frequency.

           c = λ f

           [tex]f = \frac{c}{\lambda}[/tex]

Where c is the speed of light, λ the wavelength and f the frequency.

They indicate that the wavelength is λ = 800 nm = 800 10⁻⁹ m, the speed of light is a constant c = 2.99 10⁸ m/s.

         f = [tex]\frac{2.99 \ 10^8}{800 \ 10^{-9}}[/tex]  

         F = 3.7 10¹⁴ Hz

b) Planck's equation states that the energy is proportional to the frequency of the radiation.

         E = h f

Where E is the energy, h the Planck constant and f the frequency.

         E = 6.63 10⁻³⁴  3.7 10¹⁴

         E = 2.46467 10⁻¹⁹ J

The uncertainty or error is the fluctuation that a magnitude may have due to the precision in the measurements, when the magnitude is calculated by some formula, the propagation of these uncertainties must be carried out.

        Δm = ∑   [tex]\sum \frac{dm}{dx_i} | \Delta x_I|[/tex]  

the expression for energy is:

        E = [tex]\frac{hc}{\lambda }[/tex]  

        [tex]\Delta E = \frac{dE}{d \lambda} |D\lambda |[/tex]  

        [tex]\Delta E = \frac{h c }{\lambda^2 } |\Delta \lambda |[/tex]

When the error in the measured magnitude is not explicitly indicated, we assume that the error is in the last digit written, therefore

         Δλ = ± 1 nm = ± 1 10⁻⁹ m

We calculate.

        [tex]\Delta E = \frac{6.63 \ 10^{-34} \ 2.99 \ 10^8 }{(800 \ 10^{-9})^2} 1 \ 10^{-9}[/tex]  

        ΔE = 3.1 10⁻²² J

the error is given with a significant figure.

        ΔE = 3 10⁻²² J = 0.004 10⁻¹⁹ J

The result of the energy is:

        E = (2.465 ± 0.004) 10⁻¹⁹ J

In conclusion, using the speed of light and the propagation of errors, we can find the results on the questions of the radiation emitted by the laser are:

    a) The frequency is; f = 3.7 1014 Hz

    b) The energy with its uncertainty is: E = (2.465 ± 0.004) 10⁻¹⁹ J

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Answer:

Explanation:

BMI= weight/(height × height)          ; weight in kilogram and height in metter

     = 58kg / (1.61m  × 1.61m )

     = (58/ 2.5921) kg/[tex]m^{2}[/tex]

     = 22.375  kg/[tex]m^{2}[/tex]

     ≈ 22.4 kg/[tex]m^{2}[/tex]

Answer:

80kg

Explanation:

A = Fm

0.5 = 40m

m = 40/0.5

m = 80kg

Answer:

tidal heating and/or their composition  

Explanation:

Answer:

It is defined as an astronomical phenomenon which occurs when one spatial object comes within the shadow of another spatial object.

Answer:

Answer:

0.8 A

Explanation:

Given: Q = 240 C

t = 300 s

Required: I

Equation: I = Q / t

Solution: I = 240 C / 300 s

Answer: I = 0.8 A

Answer:

heat transfer? sorry if I'm wrong!

Answer:

a) Gradient = rise/run = mass/volume

since the graph is mass against volume we know mass is on the y-axis and volume is on the x-axis

in physics it’s best to use a larger part of the graph to find the gradient, so imma use the biggest values.

90/4.5 = 20

(additional note: sometimes you may get a different gradient. For example, when using 30 and 1.4 you get ≈21 this is an anomalous result since ita gradient differs; a mass against volume graph is supposed to be linear)

b) gradient represents density (p) since gradient is = mass/volume. And density also = mass/volume

For c and d just plot the points and you’ll be able to read from the graph to get the values.

I got this graph (the image)

but you’ll be able to interpret better when ‘you’ draw it (so try plotting it)

Answer:

40 to 80

Explanation:

A car's kinetic energy changes with the speed.  Cars going slower have less potential energy than cars going faster.

Answer:

C

Explanation:

fuses of same kind can be used for different things, and of different kinds could be used for different things as well.

Hi there!

(A) The force that the ball exerts on Earth is equal in magnitude to the force that Earth exerts on the ball.

Gravitational force is an example of an action-reaction pair:

[tex]F_{1,2} = -F_{2,1}[/tex]

Gravitational force is given by the equation:

[tex]F_g = \frac{Gm_1m_2}{r^2}[/tex]

Plugging in the masses of the Earth and ball, gravitational constant, and radius will result in the SAME GRAVITATIONAL FORCE exerted by both objects on each other.

Answer:

Explanation:

The kinetic energy of an object can be found by using the formula

[tex]k = \frac{1}{2} m {v}^{2} \\ [/tex]

m is the mass in kg

v is the velocity of the object in m/s

From the question

m = 100 kg

v = 10 m/s

We have

[tex]k = \frac{1}{2} \times 100 \times {10}^{2} \\ = 50 \times 100 \\ = 5000 \: \: \: \: \: \: \: \: [/tex]

We have the final answer as

Hope this helps you

Answer:

having a secure firewall

Explanation:

A firewall validates access by assessing this incoming traffic for any price malicious like hackers and malware that would infect your computer.

Answer:

no work done

Explanation:

unless you moved the object

When we apply a force on an object, but the object remains at rest when the force is applied, then we have zero work done on the object because the object does not move.

Work done by a force is defined as the product of the displacement and the component of the force exerted by the object in the direction of displacement. Work done is expressed as:

Work done= Force* Displacement

When an object is at rest, there is no external force on it except gravity acting on it, in which case work will be zero because the force acting on it is perpendicular. Thus displacement is zero and if displacement is zero then work done will be zero.

Suppose that displacement is zero then,

W=f×0

Work done is zero

Thus, the work done is zero.

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The models of the universe allow finding the result for how serious the universe in the distant future is:

The Big Bang model shows that the universe was created at a certain point and time where from which all matter is separating at a speed from these objects.

Based on these models and the measurements that the galaxies are moving away, in the distant future the galaxies must be very far from each other so that the universe would be composed of isolated entities without the possibility of interaction between them.

Within each galaxy the bodies are not separated because in each one there is a black body whose gravity holds the stars within its galaxy together.

In conclusion of the models of the universe we can find the result for how serious the universe in the distant future is:

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Hi there!

We can begin by converting "spinning once per second" to angular velocity:

[tex]\frac{1rev}{1s} * \frac{2\pi rad}{1rev} = 2\pi rad/sec[/tex]

(a)

As we are given the angular acceleration, we can calculate the time using the following equation:

ωf = ωi + αt

There is an initial angular velocity of 0 rad/sec, so:

ωf = αt

2π/1.2 = t

t = 5.236 sec

(b)

We can use the following rotational kinematic equation to first solve for the angular displacement:

θ = ωit + 1/2αt²

The initial velocity is 0 rad/sec, so plug in values:

θ = 1/2(1.2)(5.236²)

θ = 16.449 rad

Convert to linear distance using the following:

d = θr

d = 1.5m, so r = 1.5/2 = 0.75m

d = 16.449(0.75) = 12.337m

(c)

Find the amount of revolutions by converting radians to revolutions:

[tex]16.449 rad * \frac{1rev}{2\pi rad} = \large\boxed{2.618 rev}[/tex]

OR, 2.618 times.

Answer:

The variation of the wheel and axle is the pulley. In a pulley, a cord wraps around a wheel. It is a simple machine that is used to change the direction of the force. When the wheel rotates, the cord can move in either of the directions.

Explanation:

Answer:

PE=0

Explanation:

If the tank is on the ground, there is 0 height which means the equation of PE=mh will be PE=12543(0)=0, hope this helps!

Please find attached photographs for your answer.

Hope it helps.

Do comment if you have any query.