Answer:
0.0023 cm
Explanation:
The following data were obtained from the question:
Length (L) = 55 cm
Breadth (B) = 23.3 cm
Volume (V) = 2.9 cm³
Thickness (T) =?
Thus, we can obtain the thickness of the aluminum foil as illustrated below:
V = L × B × T
2.9 = 55 × 23.3 × T
2.9 = 1281.5 × T
Divide both side by 1281.5
T = 2.9/1281.5
T = 0.0023 cm
Therefore, the thickness of the aluminum foil is 0.0023 cm
What is the IUPAC name of this compound? ________ CH3-CHCl-CH2-CH2-Cl
Answer:
The prefixes are fluoro-, chloro-, bromo-, and iodo-. Thus CH 3CH 2Cl has the common name ethyl chloride and the IUPAC name chloroethane. Alkyl halides with simple alkyl groups (one to four carbon atoms) are often called by common names.05/06/2019
The IUPAC name of this compound is 2,3- dichlorobutane.
What is compound?Compound is defined as a chemical substance made up of identical molecules containing atoms from more than one type of chemical element.
Molecule consisting atoms of only one element is not called compound.It is transformed into new substances during chemical reactions. There are four major types of compounds depending on chemical bonding present in them.They are:
1)Molecular compounds where in atoms are joined by covalent bonds.
2) ionic compounds where atoms are joined by ionic bond.
3)Inter-metallic compounds where atoms are held by metallic bonds
4) co-ordination complexes where atoms are held by co-ordinate bonds.
They have a unique chemical structure held together by chemical bonds Compounds have different properties as those of elements because when a compound is formed the properties of the substance are totally altered.
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22. Metallic compounds
a. are poor conductors of electricity
b. dissolve in water
c. have low melting points
d. can be hammered into sheets
12oz of water initially at 75oF is mixed with 20oz of water intiially at 140oF. What is the final temperature?
Answer:
[tex]115.625^{\circ}\text{F}[/tex]
Explanation:
[tex]m_1[/tex] = First mass of water = 12 oz
[tex]m_2[/tex] = Second mass of water = 20 oz
[tex]\Delta T_1[/tex] = Temperature difference of the solution with respect to the first mass of water = [tex](T-75)^{\circ}\text{F}[/tex]
[tex]\Delta T_2[/tex] = Temperature difference of the solution with respect to the second mass of water = [tex](T-75)^{\circ}\text{F}[/tex]
c = Specific heat of water
As heat gain and loss in the system is equal we have
[tex]m_1c\Delta T_1=m_2c\Delta T_2\\\Rightarrow m_1\Delta T_1=m_2\Delta T_2\\\Rightarrow 12(T-75)=20(140-T)\\\Rightarrow 12T-900=2800-20T\\\Rightarrow 12T+20T=2800+900\\\Rightarrow 32T=3700\\\Rightarrow T=\dfrac{3700}{32}\\\Rightarrow T=115.625^{\circ}\text{F}[/tex]
The final temperature of the solution is [tex]115.625^{\circ}\text{F}[/tex].
Which separation technique is based on differences in the volatility of the substances to be separated?
a. filtration
b. solvent extraction
c. Distillation
d. paper chromatography
Answer:
The correct answer is c. Distillation
Explanation:
The volatility of a substance refers to the tendency to vaporize. The more volatility, more readily the substance vaporizes and passes from liquid state to gas state.
From the options, the only operation that separes substances by their tendency to vaporize is distillation. In distillation, evaporation and condensation processes at different temperatures are used to separe miscible liquid substances.
Therefore, the correct option is c. Distillation
Answer:
C. Distillation
Explanation:
EDGE2021
A gas at -20c occupies volume 140 ml calculate temperature at which the volume of the gas becomes 65 ml pressure constant
Answer:
–156 °C
Explanation:
The following data were obtained from the question:
Initial temperature (T1) = –20 °C
Initial volume (V1) = 140 mL
Final volume (V2) = 65 mL
Final temperature (T2) =?
Pressure = constant.
Next, we shall convert –20 °C to Kelvin temperature. This can be obtained as follow:
T(K) = T(°C) + 273
Initial temperature (T1) = –20 °C
Initial temperature (T1) = –20 °C + 273 = 253 K.
Next, we shall determine the new temperature of the gas as follow:
Initial temperature (T1) = 253 K
Initial volume (V1) = 140 mL
Final volume (V2) = 65 mL
Final temperature (T2) =?
V1/T1 = V2/T2
140/253 = 65/T2
Cross multiply
140 × T2 = 253 × 65
140 × T2 = 16445
Divide both side by 140
T2 = 16445 /140
T2 = 117 K
Finally, we shall convert 117 K to celcius temperature. This can be obtained as follow:
T(°C) = T(K) – 273
T2 = 117 K
T2 = 117 K – 273
T2 = –156 °C
Thus, the new temperature of the gas is –156 °C
which of the following is an example of violating aufbau principle in filling electronic orbitals
Answer:
[Ne] 3s² 3d³
Explanation:
According to aufbau's principle of filling electronic orbitals, the sublevels with lower energies are filled up before those with higher energies.
One important to know about this principle is that sublevels do not fill in numerical order.
The order of filling is;
1s 2s 2p 3s 3p 4s 3d 4p 5s 4d 5p 6s 4f 5d 6p 7s 5f e.tc
From the given choices the wrong one is;
[Ne] 3s² 3d³
3p fills up before 3d;
A cation is a _______ion
Positive b. Negative c. Neutral
Answer:
Positive
Explanation:
There are more protons than electrons making it positive
a polymer is made from 500 ethene molecule how many carbons will it contain
Explanation:
monomer
smaller molecules that are used to prepare a polymer.
may or may not be equivalent to the repeat unit.
oligomer
a molecule consisting of several repeat units of a monomer, but not large enough to be considered a polymer
polymers
arge, usually chainlike molecules that are built from small molecules called monomers. Polymers form the basis for synthetic fibers, rubbers, and plastics and have played a leading role in the revolution that has been brought about in daily life by chemistry.
first synthetic polymers were produced as
by-products of various organic reactions and were regarded as unwanted contaminants.
first completely synthetic plastic
Bakelite, a substance that when molded to a certain shape under high pressure and temperature cannot be softened again or dissolved. Bakelite is a thermoset polymer. In contrast, cellulose nitrate is a thermoplastic polymer; that is, it can be remelted after it has been molded.
ethylene
basic raw material in the production of polyethylene and other important compounds. Over 135 million tons of ethylene were produced worldwide in 2010 for use in the polymer, petrochemical, and plastic industries. Ethylene is produced industrially in a process called cracking, in which the long hydrocarbon chains in a petroleum mixture are broken into smaller molecules.
monomer ethylene (C2H4) is
a gas at room temperature, but when polymerized, using a transition metal catalyst, it is transformed into a solid material made up of long chains of -CH2- units called polyethylene. Polyethylene is a commodity plastic used primarily for packaging (bags and films).
nylon
the silky appearance and strength of this thread and realized that nylon could be drawn into useful fibers.
The reason for this behavior of nylon is now understood. When nylon is first formed, the individual polymer chains are oriented randomly, like cooked spaghetti, and the sub- stance is highly amorphous. However, when drawn out into a thread, the chains tend to line up (the nylon becomes more crystalline), which leads to increased hydrogen bonding between adjacent chains. This increase in crystallinity, along with the resulting increase in hydrogen-bonding interactions, leads to strong fibers and thus to a highly useful mate- rial. Commercially, nylon is produced by forcing the raw material through a spinneret, a plate containing small holes, which forces the polymer chains to line up.
polyethylene
simplest and one of the best-known polymers, constructed from ethylene monomers.
CH2=CH2
Polyethylene is a member of one subset of synthetic polymers classified as plastics.
properties of polyethylene
Polyethylene is a tough, flexible plastic used for piping, bottles, electrical insulation, packaging films, garbage bags, and many other purposes.
Its properties can be varied by using substituted ethylene monomers. For example, when tetrafluoroethylene is the monomer, the polymer Teflon.
Suppose you need to prepare 250.0 mL of a pH=3.60 buffer that has a total buffer concentration of formic acid + formate of 0.030 M. How many moles of formic acid will you need? The pKa of formic acid is 3.75.
Answer:
The number of moles of formic acid needed is 4.5x10⁻³ moles.
Explanation:
We can find the moles of formic acid using the Henderson-Hasselbalch equation:
[tex] pH = pKa + log(\frac{[CHOO^{-}]}{[CHOOH]}) [/tex]
We know:
pH = 3.60
pKa = 3.75
By solving the above equation for [CHOO⁻]/[CHOOH] we have:
[tex] \frac{[CHOO^{-}]}{[CHOOH]} = 10^{(pH - pKa)} = 10^{(3.60 - 3.75)} = 0.71 [/tex]
[tex] [CHOO^{-}] = 0.71[CHOOH] [/tex] (1)
Now, we have:
[tex] [CHOOH] + [CHOO^{-}] = 0.03 M [/tex] (2)
By entering equation (1) into (2) we have:
[tex] [CHOOH] + 0.71[CHOOH] = 0.03 M [/tex]
[tex] [CHOOH] = 0.018 M [/tex]
Hence, the concentration of formate is:
[tex] [CHOO^{-}] = (0.03 - 0.018)M = 0.012 M [/tex]
Finally, the number of moles of formic acid is:
[tex] n_{CHOOH} = [CHOOH]*V = 0.018 \frac{mol}{L}*0.250 L = 4.5 \cdot 10^{-3} moles [/tex]
Therefore, 4.5x10⁻³ moles of formic acid are needed.
I hope it helps you!
We have that for the Question "How many moles of formic acid will you need?"
It can be said that
[tex]4.39*10^{-3}[/tex] moles of formic acid will be needed
From the question we are told
to prepare 250.0 mL of a pH=3.60, total buffer concentration of formic acid + formate of 0.030 M, The pKa of formic acid is 3.75.
Let [tex]1+COO4 = X, 1+COON = (0.03-X)[/tex]
[tex]pH = pKa + log\frac{1+COON}{1+COO4}\\\\3.6 = 3.75 +log\frac{0.03-X}{X}\\\\log\frac{0.03-X}{X} = 3.6 - 3.75\\\\\frac{0.03-X}{X} = 0.708\\\\X = 0.0175M[/tex]
Therefore,
[tex]moles of formic acid = 0.0175*0.25mole\\\\= 4.39*10^{-3}mole[/tex]
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why francium has lowest atomic size(radius) ?
Answer:
helium is the smallest and francium is the largest
Find the pH of the equivalence point and the volume(ml) of 0.125M HCl needed to reach the point in titrations of: a) 65.5ml of 0.234M NH3.b) 21.8 mL of 1.11 M CH3NH2.
Answer:
a. 122.6 mL / pH = 4.03
b. 193.6 mL / pH = 5.73
Explanation:
In the equivalence point we know: mmoles acid = mmoles base- And the pH in a titration between a weak base and a strong base, is acid, at the equivalence point. For the volume, we can replace the equation with the data given.
a. 0.125M . volume of acid = 65.5 mL . 0.234M
Volume of acid = (65.5 . 0.234) / 0.125 = 122.6 mL
Total volume at the equivalence point = 188.1 mL
b. 0.125M . volume of acid = 21.8 mL . 1.11 M
Volume of acid = (21.8 . 1.11) / 0.125 = 193.6 mL
Let's calculate the pH. In the equilavence point we have a neutralization reaction.
a. NH₃ + HCl → NH₄Cl
All the mmoles of protons (65.5 mL . 0.234M) react to ammonia, to obtain ammonium.
New concentration is: 15.32 mmoles / 188.1 mL = 0.0814 M
This is the [NH₄⁺] to determine the pH in the acid base equilibrium.
NH₄⁺ + H₂O ⇄ NH₃ + H₃O⁺ Ka
Expression for Ka = [NH₃] . [H₃O⁺] / [NH₄⁺]
5.6×10⁻¹⁰ = x² / (15.32 - x)
(We can avoid the quadratic equation 'cause Ka is so small)
√(5.6×10⁻¹⁰ . 15.32) = x → [H₃O⁺] = 9.26×10⁻⁵
pH = - log [H₃O⁺] → 4.03
b. CH₃NH₂ + HCl → CH₃NH₃Cl
All the mmoles of protons (21.8 mL . 1.11M) react to methylamine, to obtain methylammonium.
New concentration is: 24.2 mmoles / 193.6 mL = 0.125 M
This is the [CH₃NH₃⁺] to determine the pH in the acid base equilibrium.
CH₃NH₃⁺ + H₂O ⇄ CH₃NH₂ + H₃O⁺ Ka
Expression for Ka = [CH₃NH₂] . [H₃O⁺] / [CH₃NH₃⁺]
2.7×10⁻¹¹ = x² / (0.125 - x)
(We can avoid the quadratic equation 'cause Ka is so small)
√(2.7×10⁻¹¹ . 0.125) = x → [H₃O⁺] = 1.84×10⁻⁶
pH = - log [H₃O⁺] → 5.73
The pH of the equivalence point of 0.125M HCl with NH₃ is 4.03 and with CH₃NH₂ is 5.73.
What is equivalence point?In the acid - base titration, at the equivalence point equal moles of acid as well as of base are present.
First we calculate the volume of HCl by using the below equation as:
M₁V₁ = M₂V₂, whereM₁ = molarity of NH₃ = 0.234 M
V₁ = volume of NH₃ = 65.5 mL
M₂ = molarity of HCl = 0.125 M
V₂ = volume of HCl = ?
V₂ = (65.5 . 0.234) / 0.125 = 122.6 mL
Total volume at the equivalence point = 188.1 mL
Chemical reacion will be written as:
NH₃ + HCl → NH₄Cl
All moles of protons react with moles of ammonia, so new moles (n) will be calculated as:
n = molarity × volume
n = 65.5 mL × 0.234M = 15.32 moles
Now, concentration in terms of molarity will be 15.32 mmoles / 188.1 mL = 0.0814 M
pH in the acid-base reaction due to [NH₄⁺], as:
NH₄⁺ + H₂O ⇄ NH₃ + H₃O⁺
Value of Ka for this reaction is = 5.6×10⁻¹⁰
According to the ICE table, Ka equation will be written as-
5.6×10⁻¹⁰ = x² / (15.32 - x)
x = [H₃O⁺] = 9.26 × 10⁻⁵
pH = - log [H₃O⁺] = 4.03
Again we calculate the volume of HCl with the CH₃NH₂ as:0.125M . volume of acid = 21.8 mL . 1.11 M
Volume of acid = (21.8 . 1.11) / 0.125 = 193.6 mL
Total volume at the equivalence point = 215.4 mL
Chemical reacion will be written as:
CH₃NH₂ + HCl → CH₃NH₃Cl
All moles of protons react with moles of ammonia, so new moles (n) will be calculated as:
n = 21.8 mL . 1.11M = 24.2 moles
Now, concentration in terms of molarity will be 24.2 moles / 215.4 mL = 0.11M
pH in the acid-base reaction due to [CH₃NH₃⁺], as:
CH₃NH₃⁺ + H₂O ⇄ CH₃NH₂ + H₃O⁺
Value of Ka = 2.7×10⁻¹¹
According to the ICE table, Ka equation will be written as-
2.7×10⁻¹¹ = x² / (0.11 - x)
x = [H₃O⁺] = 5.4×10⁻⁶
pH = - log [H₃O⁺] = 5.73
Hence the value of pH will be 4.03 and 5.73 respectively.
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Given the following balanced equation, determine the rate of reaction with respect to [Cl2]. If the rate of Cl2 loss is 4.64 × 10-2 M/s, what is the rate of formation of NOCl? 2 NO(g) + Cl2(g) → 2 NOCl(g)
Answer:
[tex]r_{NOCl}=9.28x10^{-2}M[/tex]
Explanation:
Hello!
In this case, given the balanced chemical reaction:
[tex]2 NO(g) + Cl_2(g) \rightarrow 2 NOCl(g)[/tex]
Since there is 1:2 mole ratio between chlorine and NOCl, based on the rate proportions, we can write:
[tex]\frac{1}{-1}r_{Cl_2} =\frac{1}{2}r_{NOCl}[/tex]
It means that for the formation of NOCl, we obtain:
[tex]r_{NOCl}=\frac{2}{-1}r_{Cl_2} \\\\r_{NOCl}=\frac{2}{-1}(-4.64x10^{-2}M)\\\\r_{NOCl}=9.28x10^{-2}M[/tex]
Notice that chlorine is disappearing, which means its rate is negate.
Best regards!
Calculate the pH of a solution that is 0.291 M acetic acid and 0.123 M sodium acetate. The Ka of acetic acid is 1.76×10^–5 at 25°C. What is the pH of this mixture at 0°C?
Answer:
The answer is "4.37."
Explanation:
at [tex]0^{\circ} C\ Ka = 1.76 \times 10^{-5}[/tex]
[tex]\to pKa = - \log \ Ka[/tex]
[tex]= - \log \ 1.76 \times 10^{-5}\\\\ = 4.75[/tex]
[tex]pH = pKa + \log \frac{[sodium \ acetate]}{[acetic \ acid]}[/tex]
[tex]= 4.75 + \log \frac{[0.123]}{[0.291]}\\\\= 4.75+ \lg(0.422680412)\\\\=4.75-0.373987878\\\\=4.37601212\\\\=4.37[/tex]
Calculate the slope of each line using the points given. (25.6cm³ , 28.16g), (17.3cm³, 19.03g)
Answer:
1.1
Explanation:
The slope of a line can be calculated using the values of the x and y corrdinates. The equation is given as;
M = ΔY / ΔX = Y2 - Y1 / X2 - X1
From the points;
(25.6cm³ , 28.16g) - (X1, Y1)
(17.3cm³, 19.03g) - (X2, Y2)
Inserting the values into the equation;
M = 19.03 - 28.16 / 17.3 - 25.6
M = -9.13 / -8.3 = 1.1
300cm³ of hydrogen diffuses through a porous pot in 50 seconds how long will it take 500 cm cube of oxygen diffuses through the same pot(h=1,o=16)
It takes 333.3 s for Oxygen to diffuses
Further explanationGraham's law: the rate of effusion of a gas is inversely proportional to the square root of its molar masses or
the effusion rates of two gases = the square root of the inverse of their molar masses:
[tex]\rm \dfrac{r_1}{r_2}=\sqrt{\dfrac{M_2}{M_1} }[/tex]
or
[tex]\rm M_1\times r_1^2=M_2\times r_2^2[/tex]
r₁ H₂ = 300 cm³/50 s=6 cm³/s
M₁ H₂ = 2 g/mol
M₂ O₂ = 32 g/mol
[tex]\tt 2\times 6^2=32\times r_2^2\\\\r_2^2=\dfrac{2\times 6^2}{32}=2.25\rightarrow r_2=1.5[/tex]
the diffusion time of Oxygen :
[tex]\tt r_2=\dfrac{V}{t}\\\\t=\dfrac{V}{r_2}=\dfrac{500~cm^3}{1.5~cm^3/s}=333.3~s[/tex]
at STP how many molecules of nitrogen gas are in 224 L?
a.6.022x10^22
b.6.022x10^23
c.6.022x10^24
d.6.022x10^25
Answer:
6.022×10²² molecules
Explanation:
Given data:
Volume of nitrogen = 224 L
Pressure = standard = 1 atm
Temperature = standard = 273 K
Number of molecules = ?
Solution:
PV = nRT
1 atm × 224 L = n × 0.0821 atm.L/mol.K × 273 K
224 atm.L = n ×22.41 atm.L/mol
n = 224 atm.L/22.41 atm.L/mol
n = 10 mol
1 mole contain 6.022×10²³ molecules
10 mol×6.022×10²³ molecules/ 1 mol
60.22×10²³ molecules
6.022×10²² molecules
Answer:
thank you! ladies... love the answer is A) 6.022 x 10 ^22
Explanation:
love this one!
have a good one everyone
what is the OH- in a solution that has a H+ = 2×10-5 M
Answer:
Explanation:
{H+}*[OH-] = 1 * 10^-14
[2*10^-5]* [OH^-] = 1*10^-14
[OH^-] = 1*10^-14/2*10^-5
[OH^-] = 5*10^-10
6.023*10^26 molecules of hydrogen gas into mass in gram
Answer:
Avogadro’s Number
Avogadro’s NumberIt certainly is easy to count bananas or to count elephants (as long as you stay out of their way). However, you would be counting grains of sugar from your sugar canister for a long, long time. Atoms and molecules are extremely small – far, far smaller than grains of sugar. Counting atoms or molecules is not only unwise, it is absolutely impossible. One drop of water contains about 10 22 molecules of water. If you counted 10 molecules every second for 50 years without stopping you would have counted only 1.6 × 10 10 molecules. Put another way, at that counting rate, it would take you over 30 trillion years to count the water molecules in one tiny drop.
Avogadro’s NumberIt certainly is easy to count bananas or to count elephants (as long as you stay out of their way). However, you would be counting grains of sugar from your sugar canister for a long, long time. Atoms and molecules are extremely small – far, far smaller than grains of sugar. Counting atoms or molecules is not only unwise, it is absolutely impossible. One drop of water contains about 10 22 molecules of water. If you counted 10 molecules every second for 50 years without stopping you would have counted only 1.6 × 10 10 molecules. Put another way, at that counting rate, it would take you over 30 trillion years to count the water molecules in one tiny drop.Chemists needed a name that can stand for a very large number of items. Amedeo Avogadro (1776 – 1856), an Italian scientist, provided just such a number. He is responsible for the counting unit of measure called the mole. A mole (mol) is the amount of a substance that contains 6.02 × 10 23 representative particles of that substance. The mole is the SI unit for amount of a substance. Just like the dozen and the gross, it is a name that stands for a number. There are therefore 6.02 × 10 23 water molecules in a mole of water molecules. There also would be 6.02 × 10 23 bananas in a mole of bananas, if such a huge number of bananas ever existed
Answer:
Mass = 2000 g
Explanation:
Given data:
Number of molecules of hydrogen = 6.023×10²⁶
Mass of hydrogen = ?
Solution:
1 mole of hydrogen contain 6.022×10²³ molecules
6.023×10²⁶ molecules× 1 mol/ 6.022×10²³ molecules
1.00 ×10³ mol
1000 mol
Mass of hydrogen:
Mass = number of moles × molar mass
Mass = 1000 mol × 2 g/mol
Mass = 2000 g
What are five minerals found on space rocks
Answer:
oxygen, silicon, iron, calcium, sodium
Explanation:
these are all found in space rocks known as meteorites. hope this helps :)
A small stream runs through a neighborhood. For many years, the shape of the streambed, the amount of water, and the species of wildlife remained stable. However, there has been an increase in construction in the area. New homes, new streets, and new storm drains have affected the area. What effect have the changes likely had on the local stream?
HELP FAST
Answer:
the water has been poulutid due to all of the construction and debris that might have flown into the water.
Explanation:
It is the combination of two or more substances that are physically combined and a new substance was formed. What do you mean by this?
A. It is Solid
B. It is Gas
C. It is Liquid
D. It is Mixture
Answer:
D. It is a Mixture
Explanation:
It tells us it is a combination of substances. We do not know the states of these substances or the state of the new substance. However, we do know that it was physically combined. Hence, this is a mixture. (FYI If it was combined chemically, it would be a compound)
Isotope Atomic Mass (amu) Percent Abundance
Silicon-28 27.98 92.21%
Silicon-29 28.98 4.70%
Silicon-30 29.97 3.09%
Look at the information given and predict whether the average atomic mass would be closer to Si-28, Si-29, or Si-30. Give reasons for your answer.
Answer:
The average atomic mass is closer to Si- 28 because this isotope is present in more percentage in the sample.
Explanation:
Given data:
Atomic mass of silicon= ?
Percent abundance of Si-28 = 92.21%
Atomic mass of Si-28 = 27.98 amu
Percent abundance of Si-29 = 4.70%
Atomic mass of Si-29 = 28.98 amu
Percent abundance of Si-30 = 3.09%
Atomic mass of Si-30 = 29.97 amu
Solution:
Average atomic mass = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass)+(abundance of 2nd isotope × its atomic mass) / 100
Average atomic mass = (92.21×27.98)+(4.70×28.98)+(3.09×29.97) /100
Average atomic mass = 2580.04 +136.21+92.61 / 100
Average atomic mass = 2808.86 / 100
Average atomic mass = 28.08amu.
The average atomic mass is closer to Si- 28 because this isotope is present in more percentage in the sample.
Answer:
The average atomic mass of silicon would be closer to Si-28 as it is the most abundant isotope.
Explanation:
From PLATO
If 0.0692 mol CaCl2 is dissolved in water to make a 0.810 M solution, what is the volume of the solution?
Answer:
Just ask google for help
Explanation:
I always do it and get it right
What color flame did lead nitrate produce?
yellow-red
blue
green
purple
Answer: it blue
Explanation:
How do the physical and chemical properties the halogens compare with those of the noble gases?
Explanation:
To form bonds with noble gases, a lot of energy is required to form those bonds. Halogens, on the other hand, are extremely reactive. ... The halogens tend to be very reactive, while the noble gases are in no way reactive and don't bond easily, if at all.
Metals have the ability to conduct electricity more effectively than other materials, such as ionic and covalent substances. This is because the way metals bond -
Answer:
See explanation
Explanation:
Substances are composed of bands. A band is a group of molecular orbitals, the energy differences between them are so small that the system behaves as if a continuous, non-quantization of energy within the barrier is possible.
Materials consists of a valence band and a conduction band separated by a band gap. A band gap occurs when the energy difference between two bands is significant.
The magnitude of band gap determines whether a material will be a metal, nonmetal or metalloid.
Metals have a very little band gap hence they are able to conduct electricity more effectively than other materials, such as ionic and covalent substances.
12. When the frequency of a wave increases, what happens to the wavelength?
A. The wavelength is not directly affected by the frequency of a wave
B. The wavelength increases
C. The wavelength decreases
D. More specific information is needed to form a conclusion
Answer:
C. The wavelength decreases
Explanation:
This is because frequency is how often the wave hits the top (peak) and the bottom (through). The more it hits the less wavelength it will have because it is moving faster and has more energy.
A molecule has sp3d2 hybridization with 1 lone pair. ... The electron pair geometry of this molecule is: octahedral ... The geometry of this molecule is: octahedral . ... This molecule will have approximate bond angles of (If more than one bond angle is possible, separate each with a space.):
Answer:
electron pair geometry - octahedral
molecular geometry - square pyramidal
bond angle - < 90 degrees
Explanation:
According to Valence Shell Electron Pair Repulsion Theory (VSEPR), The shapes of molecules depend on the number of electron pairs on the outermost shell of the central atom in the molecule. Recall that electron pairs are always positioned as far apart in space as possible to minimize repulsion.
For a molecule in sp3d2 hybridization, the expected electron domain geometry is octahedral. However, the presence of a lone pair in the molecule distorts the electron pair geometry away from the expected octahedral shape giving a molecular geometry of square pyramidal and decreases the bond angle less than the expected 90 degrees.
which group has two valence electrons A)Alkali metals B) Noble Gases C)Halogens D) Alkaline Earth Metals
Answer: The answer is A.
Explanation: Calcium is a group 2 element with two valence electrons. Therefore, it is very reactive and gives up electrons in chemical reactions. Calcium is also classified chemically as one of the alkaline earth elements (that is, in Group 2 of the periodic table. The metal is obviously reactive.
Answer:
D) Alkaline Earth Metals
Explanation:
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The formula for a lutetium carbonate compound is Lu2(CO3)3. What would be the formula for a lutetium nitrate compound given that the charge of lutetium is the same in both compounds?
a. LuNO3
b. Lu2NO3
c. Lu(NO3)2
d. Lu2(NO3)3
e. Lu(NO3)3
Answer:
E
Explanation:
From Lu2(CO3)3, we can determine the charge of the variable charge transition metal Lu has a charge of 3, as CO3 has a 2- charge (3*-2 = 6, 6/2 = 3). Then, we apply this to nitrate, which has a charge of 1-. Balance charges, reduce, and you get E.