Adrian gets a loan for $500 to go on a trip. He borrows the money at 5% interest for 1 year. Find the interest Adrian will pay on the loan.

Answer:

the second one(20)

Step-by-step explanation:

If you pretend 20 is x, you solve the equation by pluging in x (20) into the equation and it gives you 70, 70 is what the big part is and 70+20 is 90, which is the size of a 90degree side.

4(20)-10

80-10

70

70+20=90

Answer: The answer to this question is 20 degrees

Step-by-step explanation:

So, you know that it's a straight line, which is 180 degrees. The angle on the very left is 90 degrees because it's a right angle.

So that means (x + 10) + x = 90 degrees because 180 - 90 = 90

Solve that equation for x:

x + 4x - 10 = 90

5x = 100

x = 20

So, your final answer is 20 degrees

Answer:

Step-by-step explanation:

SOH - CAH - TOA

Since the opposite side is given and we need to find the length of the adjacent side, we can use tangent to solve for x.

[tex]tan 21=\frac{opposite}{adjacent} \\tan 21 =\frac{8}{x} \\0.384 =\frac{8}{x} \\0.384x =8 \\x=\frac{8}{0.384} \\x=20.84[/tex]

Since the opposite side is given and we need to find the length of the hypotenuse, we can use sine to solve for y.

[tex]sin 21=\frac{opposite}{hypotenuse} \\sin21 =\frac{8}{y} \\0.358 =\frac{8}{y} \\0.358y=8 \\y=\frac{8}{0.358} \\y=22.32[/tex]

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To find the inverse first we need to solve the equation for x ,

Then put x instead of y .

_________________________________

[tex]f(x) = 8x + 2[/tex]

[tex]y = 8x + 2[/tex]

[tex]8x + 2 = y[/tex]

Subtract sides 2

[tex]8x + 2 - 2 = y - 2[/tex]

[tex]8x = y - 2[/tex]

Divide sides by 8

[tex] \frac{8x}{8} = \frac{y - 2}{8} \\ [/tex]

[tex]x = \frac{y - 2}{8} \\ [/tex]

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Thus ;

[tex] {f}^{ - 1} (x) = \frac{x - 2}{8} \\ [/tex]

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Answer:

KL =9cm

Step-by-step explanation:

IL = KL {being corresponding side of congruent triangle}

or, 3x = x+6

or, 3x-x = 6

or, 2x = 6

or, x = 6/2

or, x = 3cm

Now,

KL = x+6

= 3+6

=9cm

Answer:

Hey bro

Step-by-step explanation:

Answer:

The ramp should be 32.9 feet longer.

Step-by-step explanation:

When the ramp is at [tex]6^{o}[/tex] to the ground, its length can be determined by applying the appropriate trigonometric function. Let the length be represented by l, so that;

Sin θ = [tex]\frac{opposite}{hypotenuse}[/tex]

Sin [tex]6^{o}[/tex] = [tex]\frac{3.45}{l}[/tex]

l = [tex]\frac{3.45}{Sin 6^{o} }[/tex]

 = [tex]\frac{3.45}{0.10453}[/tex]

 = 33.0048

l = 33.0 feet

When the angle is reduced to [tex]3^{o}[/tex], the length of the ramp would be;

Sin θ = [tex]\frac{opposite}{hypotenuse}[/tex]

Sin [tex]3^{o}[/tex] = [tex]\frac{3.45}{l}[/tex]

l = [tex]\frac{3.45}{Sin 3^{o} }[/tex]

 = [tex]\frac{3.45}{0.05234}[/tex]

= 65.9152

l = 65.9 feet

Change in length of ramp = 65.9 - 33.0

                            = 32.9

The ramp should be 32.9 feet longer.

Answer:

x=5

Step-by-step explanation:

1. Distribute

2. Subtract  8 from both sides of the equation.

3. Simplify

4. Divide both sides of the equation by the same term

5. Simplify

6. Solution : = 5

Answer:

For any equation X€R But here is Nothing like it.

Step-by-step explanation:

0 = -x^-4 is wrong to say.

Answer:

x = 19.8

Step-by-step explanation:

5x - 9 = 90

5x = 90 + 9

5x = 99

x = 19.8

Hope this helped!

Answer:

19.8

Step-by-step explanation:

5x-9=90

Cancel the 9 on both sides, so you get:

5x=90+9

5x=99

x= 19.8

Answer:

Hello! What are the questions? You can type them in Comments and I will edit my answer :)

Step-by-step explanation:

Answer:

what are the questions I don't see any?

Step-by-step explanation:

Answer:

11000 meters

Step-by-step explanation:

1km=1000m

5km=5000m

5000+6000=11000m

Answer:

Step-by-step explanation:

there are a couple ways to find slope

1. Rise over Run Method:

for this method, you use basic counting

to do this, you count the number of x spaces it takes the line to get from one y space to the next

for your line, the run is 3 because it takes 3 x spaces to get from one whole number to the next on the y spaces

you would say the rise is -1 because the line is going down, and it takes 3 x spaces to get the next pot that is on a y-axis increment

so we know the rise is -1 and the run is 3

if you put this into rise/run format, you get 1/-3

so -1/3 is you slope

2. Using the Coordinates

in this line, you see two points

the points are 1. (-1, -1), and 2. (2, -2)

using the coordinates means that you use a formula: [tex]\frac{y_{2}-y_{1} }{x_{2} -x_{1} }[/tex]

the y2 is the y value of the second coordinate (-2), the y1 is the y value of the first coordinate (-1)

the x2 is the x value of the second coordinate (2), the x1 is the x value of the  first coordinate (-1)

if you plug these it you get: -2 - (-1) / 2 - (-1)

this can be simplified to -2 + 1 / 2 + 1

and simplified again to -1/3

Qhat ever method you use, you should get the same answer. Using both methods is a good way to check your work.

Note: Your exponential expression seems a little unclear. Because 27 is not an exponential expression.

But, I am assuming that your exponential expression is:

The reason is that my solution would still clear your concept about this topic, no matter what the question is.

Answer:

The simplified value of the exponential expression is:

[tex]27^{\frac{1}{3}}=3[/tex]

Step-by-step explanation:

Assuming the exponential expression

[tex]\:27^{\frac{1}{3}}[/tex]

[tex]\mathrm{Factor\:the\:number:\:}\:27=3^3[/tex]

[tex]=\left(3^3\right)^{\frac{1}{3}}[/tex]

[tex]\mathrm{Apply\:exponent\:rule}:\quad \left(a^b\right)^c=a^{bc},\:\quad \:a\ge 0[/tex]

[tex]\left(3^3\right)^{\frac{1}{3}}=3^{3\cdot \frac{1}{3}}[/tex]

[tex]=3^{3\cdot \frac{1}{3}}[/tex]

[tex]=3^1[/tex]

[tex]\mathrm{Apply\:exponent\:rule}:\quad \:a^1=a[/tex]

[tex]=3[/tex]

Therefore, the simplified value of the exponential expression is:

[tex]27^{\frac{1}{3}}=3[/tex]

k-6:5 + 4-k:6= 6k-36+20-5k:30 =

k-16:30

Answer:

I think that there should be 320 tagged deer in the population

A ratio shows us the number of times a number contains another number. The total population of the deer after a month was 1320.

A ratio shows us the number of times a number contains another number.

When the deer were recaptured 10 out of the 40 deers were tagged therefore, the ratio of the tagged deers to the total population of the deers is 10/40. Thus, we can write the total population of the deer as,

[tex]\dfrac{\text{Tagged Population}}{\text{Total Population}} = \dfrac{10}{40}\\\\\\\dfrac{330}{\text{Total Population}} = \dfrac{10}{40}\\\\\\\text{Total Population} = \dfrac{330 \times 40}{10} = 1320[/tex]

Thus, the total population of the deer after a month was 1320.

Learn more about Ratios:

https://brainly.com/question/1504221

Answer:

-125

Step-by-step explanation:

Answer:

2⁵

Step-by-step explanation:

Given:

Number 96

Computation:

96 = 2 x 2 x 2 x 2 x 2 x 3

96 = 2⁵ x 3  

So, Number 2 repeat 5 times

Answer:

Answer would be (n) = x(x+y)(x-2y) and the (d) = y^2

Step-by-step explanation:

Hope it helps

Answer:

The average speed of the car is 90 km/h

Step-by-step explanation:

The rule of the distance id D = v × t, where

∵ A car can travel 450 km in the same time it takes a train to travel

   350 km

→ That means the time of them are equals

∴ Time of the car = Time of the train

→ From the rule above t = [tex]\frac{D}{v}[/tex]

∵ D(car) = 450 km and D(train) = 350 km

∵ The car's average speed is 20 km/h faster than the average speed

   of the train

→ Assume that the average speed of the train is x km/h

∴ v(train) = x km/h and v(car) = (x + 20) km/h

→ Use the rule of the time above to find the time of each one

∵ t(car) = [tex]\frac{450}{(x+20)}[/tex]

∵ t(train) = [tex]\frac{350}{x}[/tex]

∵ t(car) = t(train)

∴ [tex]\frac{450}{(x+20)}[/tex] =  [tex]\frac{350}{x}[/tex]

→ By using cross multiplication

∵ 450 × x = 350 × (x + 20)

∴ 450x = 350(x) + 350(20)

∴ 450x = 350x + 7000

→ Subtract 350x from both sides

∴ 100x = 7000

→ Divide both sides by 100 to find x

∴ x = 70

∵ x represents the average speed of the train

∴ The average speed of the train = 70 km/h

∵ The average speed of the car = x + 20

∴ The average speed of the car = 70 + 20

∴ The average speed of the car = 90 km/h

Answer:

10 kits

Step-by-step explanation:

Because the price of one kit is $3.45 (pencil, pen, eraser, and a notebook). You can get 10 kits for $34.50. 11 kits would be over the amount she would be willing to pay for the kits.

Hope this is helpful, to you have a gret day! Brainliest would be awesome.

Answer:

[tex]\displaystyle T_6=\frac{448}{729} f^2t^6[/tex]

Step-by-step explanation:

Binomial Theorem

Any power of x + y can be expanded into a sum of the form:

[tex]\displaystyle (x+y)^{n}={n \choose 0}x^{n}y^{0}+{n \choose 1}x^{n-1}y^{1}+{n \choose 2}x^{n-2}y^{2}+\cdots +{n \choose n-1}x^{1}y^{n-1}+{n \choose n}x^{0}y^{n}[/tex]

For any given term k, counted from 0 to n:

[tex]\displaystyle T_k={n \choose k}x^{n-k}y^{k}[/tex]

Note if we have to find the 7th term, we have to use k=6. The expression is:

[tex]\displaystyle \left(4f+\frac{t}{3}\right)^8[/tex]

For n=8, x=4f, y=t/3, k=6:

[tex]\displaystyle T_6={8 \choose 6}(4f)^{8-6}\left (\frac{t}{3} \right )^{6}[/tex]

[tex]\displaystyle T_6={8 \choose 6}(4f)^{2}\left (\frac{t}{3} \right )^{6}[/tex]

[tex]\displaystyle T_6={8 \choose 6}16f^2\frac{t^6}{3^6}[/tex]

Calculate:

[tex]\displaystyle {8 \choose 6}=\frac{8!}{2!\cdot 6!}=28[/tex]

Thus:

[tex]\displaystyle T_6=28\cdot 16f^2\frac{t^6}{729}[/tex]

Simplifying, the 7th term is:

[tex]\mathbf{\displaystyle T_6=\frac{448}{729} f^2t^6}[/tex]

Answer:

15/2

Step-by-step explanation:

Answer:

3=15

4=20

5=25

Step-by-step explanation:

bold are the answers

Answer:

(1,1)

Step-by-step explanation:

Answer:

9y+7=2y+98

7y+7=98

7y = 91

y = 13

m<PDV = 2y+98

             = 2(13)+98

             = 26+98

             = 124

Answer:

x=72

Step-by-step explanation:

1.2x−2.4=84

Step 1: Add 2.4 to both sides.

1.2x−2.4+2.4=84+2.4

1.2x=86.4

Step 2: Divide both sides by 1.2.

x=72

Answer: x=72

Step-by-step explanation:

Answer:

a) +-12-6

b) 70.5 * 18 = 1,269 + 120 = 1389 - 4 = 1385

c) 18

Step-by-step explanation: