Physics High School

An electric heater is rated 300W 110V. The safety fuse in the circuit can withstand 15 A of current. How many heaters can be safely operated in the circuit

Answers

Answer 1

The number of heaters that can safely be operated in the circuit is 5 heaters.

From the question given above, the following data were obtained:

Power of heater = 300 W

Voltage (V) = 110 V

Current (I) = 15 A

Number of heaters = ?

Next, we shall determine the power that can be drawn from the circuit. This can be obtained as follow:

Voltage (V) = 110 V

Current (I) = 15 A

Power (P)= ?

P = IV

P = 15 × 110

P = 1650 W

Thus, the power that can be drawn from the circuit is 1650 W

Finally, we shall determine the number of heaters that can be operated in the circuit. This can be obtained as follow:

Power of heater = 300 W

Power of Circuit = 1650 W

Number of heaters = ?

[tex]Number \: of \: heaters \: = \frac{power \: of \: circuit}{power \: of \: heater} \\ \\ = \frac{1650}{300} \\ \\ = 5.5[/tex]

From the calculation made above, the number of heaters that can be operated safely in the circuit is 5 heaters.

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Related Questions



Use the graph of velocity versus time for an object to answer the question.

Which statement fairly compares segment 2 and segment 3?
(1 point)
O These represent equal periods of time, but the force during segment 2 is different than the force during segment 3.
These represent different periods of time, but the force acting on the object is the same during each period of time.
O These represent different periods of time, and the force during segment 2 is different than the force during segment 3.
O These represent equal periods of time, and the force acting on the object is the same during each period of time.​

Answers

The statement which fairly compares segment 2 and segment 3 is These represent equal periods of time, but the force during segment 2 is different than the force during segment 3.

Since segment 2 starts at t = 60 s and ends at t = 150 s, the time interval is Δt = 150 - 60 = 90 s.

Also, segment 3 starts at t = 150 s and ends at t = 240 s, the time interval is Δt = 240 - 150 = 90 s.

So, their time periods are the equal.

We notice that segment 2 is less steep than segment 3 this implies that the acceleration in each segment is different, since the acceleration is the slope of the graph.

Since force is determined by acceleration, this implies that the force on segment 2 is different form the force acting in segment 3.

So, we have equal time periods but different forces.

So, the statement which fairly compares segment 2 and segment 3 is These represent equal periods of time, but the force during segment 2 is different than the force during segment 3.

Learn more about velocity-time graph here:

https://brainly.com/question/24788847

Answer:

Segments 2 and 3 have equal periods of time but the force during segment 2 is different than the force during segment 3 !! :)

Explanation:

The weight of a cart with a mass of 150 kg is ___ N. (Use 9.8
m/s2 for the acceleration due to gravity.)

Answers

Answer:

1470 N

Explanation:

Weight = m*g

So 150 kg * 9.8 m/s^2 = 1470 N

What net force would be necessary to cause a block of wood with a mass of 2.5 kg to accelerate at a rate of 3.0 m/s2

Answers

Answer:

7.5 N

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question

mass = 2.5 kg

acceleration = 3.0 m/s²

We have

force = 2.5 × 3.0 = 7.5

We have the final answer as

7.5 N

Hope this helps you

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