Answer:
a) τ = -518 lb-inch , b) d = 0 inch
Explanation:
a) The moment of a force is given by
τ = F x r
The bold letters indicate vectors, we can solve the magnitude of this expression with
τ = F r sin θ
and the angle by the right hand rule.
In general, the applied force is perpendicular to the rubber and in such a direction that the moment is opposite to the movement, therefore the angle is 270 = -90º and the sin 270 = -1
τ = -F r
To perform a complete calculation, the radius of the rubber is needed, for example for a small car the radius is about 14 inch = 1,167 feet
τ = -37 14
τ = -518 lb-inch
The point o is assumed to be the center of the wheel, the negative sign indicates that the moment is clockwise
b) As the rubber is a circle and the force is perpendicular, the vector product gives an emoticon perpendicular to the rubber, so that this value decreases to zero we must reduce the application point (distance), that is, the distance must be zero.
d = 0 inch
Which object has the most momentum?
A) a mass of 100, kg with a velocity of 2.0 m/sec
B) a mass of 100 kg with a velocity of 32.0 m/sec
C) a mass of 15 kg with a velocity of 200. m/ sec
Which statement is true for light passing into a medium that is less optically dense than the first medium through which it passed?
The index of refraction of the second medium is higher.
The index of reflection of the second medium is lower.
The index of reflection of the second medium is higher.
The index of refraction of the second medium is lower.
Answer:
The correct option is;
The index of refraction of the second medium is lower
Explanation:
The index of refraction of a material indicates the magnitude of the optical density of a material. The index of refraction or the refractive index, n, are indices (ratio) of the speed of light through an optically dense medium relative to the speed of light through a vacuum.
The definition of the refractive index is the number of times light travelling through a medium would be slower than light travelling through vacuum
Therefore, the index of refraction of a second medium that is less optically dense than a first medium from which light originates and travels through it would be lower than the index of refraction of the first medium
What is the kinetic energy of a 620.0 kg roller coaster moving with a velocity of 9.00 m/s? Round to 3 significant
figures
0 2.790 J
5,580 J
025,100 J
050,200 J
b) A shopkeeper sold a watch for Rs 810 at 10% loss. How much did he pay to
buy the watch?
indir
Answer:
rs 900
Explanation:
the process is given
Find the horizontal and vertical components of 75.0 N at 65 degrees
Horizontal component = 75 · cosine(65°) = 31.7 N
Vertical component = 75 · sine(65°) = 68.0 N
a car moving east with a velocity of 25mph.What is the acceleration?
Answer:
0
Explanation:
Moving east at constant velocity then a=0
cutting down forests change the populations of more than tress. lmagine the organisms that lived in this forest. After the trees have been cut, fewer animals can survive here. What are MOST LIKELY the limiting factors in this case?
A) Food and space
B) Food and water
C) Water and space
D) Food and shelter
Answer:
a
Explanation:
A stone is dropped from a high tower and 9.21 seconds later it hits the ground. How high is the tower?
Answer:
S = 415.64m
Explanation:
Given the following data;
Time, t = 9.21secs
Since it's a free fall, acceleration due to gravity = 9.8m/s²
Initial velocity, u = 0
To find the height of the tower, we would use the second equation of motion;
[tex] S = ut + \frac {1}{2}at^{2}[/tex]
Where;
S represents the displacement or height measured in meters. u represents the initial velocity measured in meters per seconds. t represents the time measured in seconds. a represents acceleration measured in meters per seconds square.Substituting into the equation, we have;
[tex] S = 0*9.21 + \frac {1}{2}*(9.8)*9.21^{2}[/tex]
[tex] S = 0 + 4.9*84.8241[/tex]
[tex] S = 4.9*84.8241 [/tex]
Height, S = 415.64m
Therefore, the tower is 415.64m in height.
Two asteroids with masses 5.34 x 103 kg and 2.06 x 104 kg are separated by a distance of 5,000 m. What is the gravitational force between the asteroids? Newton's law of gravitation is F gravity Gmim. The gravitational constant Gis 6.67 x 10-11 N-m²/kg2. A. 400N B. 1.24 x 1032 N C. 1.47 x 10-6 N D. 2.93 x 10-10 N
Answer:
[tex]F=2.93\cdot 10^{-10}~N[/tex]
Explanation:
Newton’s Law of Universal Gravitation
Objects attract each other with a force that is proportional to their masses and inversely proportional to the square of the distance.
[tex]\displaystyle F=G{\frac {m_{1}m_{2}}{r^{2}}}[/tex]
Where:
m1 = mass of object 1
m2 = mass of object 2
r = distance between the objects' center of masses
G = gravitational constant: [tex]6.67\cdot 10^{-11}~Nw*m^2/Kg^2[/tex]
The asteroids have masses of [tex]m1=5.34\cdot 10^{3}~Kg[/tex] and [tex]m2=2.06\cdot 10^{4}~Kg[/tex] and are separated by r=5,000 m.
Calculating the gravitational force:
[tex]\displaystyle F=6.67\cdot 10^{-11}~Nw*m^2/Kg^2~{\frac {5.34\cdot 10^{3}~Kg \cdot2.06\cdot 10^{4}~Kg}{5,000^{2}}}[/tex]
Calculating:
[tex]\mathbf{F=2.93\cdot 10^{-10}~N}[/tex]
Answer:
D. 2.93 x 10-10 N
Explanation:
Answer got deleted? Dont delete my answer 'katie'
btw got it right
brainliest please help
tell me if am right
if not correct me
please
Answer:
See the answers below
Explanation:
To solve this problem we must use the following equation of kinematics.
[tex]v_{f}=v_{o}+a*t[/tex]
where:
Vf = final velocity [m/s]
Vo = initial velocity [m/s]
a = acceleration [m/s²]
t = time [s]
First case
Vf = 6 [m/s]
Vo = 2 [m/s]
t = 2 [s]
[tex]6=2+a*2\\4=2*a\\a=2[m/s^{2} ][/tex]
Second case
Vf = 25 [m/s]
Vo = 5 [m/s]
a = 2 [m/s²]
[tex]25=5+2*t\\t = 10 [s][/tex]
Third case
Vo =4 [m/s]
a = 10 [m/s²]
t = 2 [s]
[tex]v_{f}=4+10*2\\v_{f}=24 [m/s][/tex]
Fourth Case
Vf = final velocity [m/s]
Vo = initial velocity [m/s]
a = acceleration [m/s²]
t = time [s]
[tex]v_{f}=5+8*10\\v_{f}=85 [m/s][/tex]
Fifth case
Vf = final velocity [m/s]
Vo = initial velocity [m/s]
a = acceleration [m/s²]
t = time [s]
[tex]8=v_{o}+4*2\\v_{0}=8-8\\v_{o}=0[/tex]
12.
A Pole 4m Long is laid along the principal axis of a convex mirror of
focal length 1m the end of the pole nearer the mirror is 2m from it.
Find the length of the image of the pole.
Ans: 0.19m
Answer:
The length of the image of the pole is 4/3 m
Explanation:
The given parameters are;
The length of the Pole = 4 m
The type of mirror = Convex mirror
The distance of the pole from the mirror = 2 m
The mirror formula for convex mirrors is presented here as follows;
[tex]\dfrac{1}{U} - \dfrac{1}{V} = - \dfrac{1}{F}[/tex]
Where;
U = The object (pole) distance from the mirror = 2 m
V = The image of the objects (pole) distance from the mirror
The focal length of the mirror
Therefore, by substitution, we have;
[tex]\dfrac{1}{2} - \dfrac{1}{V} = - \dfrac{1}{1}[/tex]
[tex]\dfrac{1}{2} + 1 = \dfrac{1}{V}[/tex]
[tex]\dfrac{1}{V} = \dfrac{1}{2} + 1 = \dfrac{3}{2}[/tex]
[tex]V = \dfrac{2}{3}[/tex]
We have;
[tex]Magnification = \dfrac{Image \ height}{Object \ height } = \dfrac{Length \ of \ the \ Image \ of \ the \ Pole}{Length \ of \ the \ of \ the \ Pole } =\dfrac{-V}{U}[/tex]
Which by substitution gives;
[tex]Magnification = \dfrac{Length \ of \ the \ Image \ of \ the \ Pole}{4} =\dfrac{-\dfrac{2}{3} }{2} = \dfrac{2}{6}[/tex]
[tex]{Length \ of \ the \ Image \ of \ the \ Pole}{} = 4 \times \dfrac{2}{6} = \dfrac{4}{3}[/tex]
The length of the image of the pole = 4/3 m
HELP ME!
Micah knows that a car had a change in velocity of 15 m/s. What does Micah need to determine acceleration.
distance
time
direction
speed
Micah knows that a car had a change in velocity of 15 m/s.To determine acceleration ,Micah also needs the TIME of the total trip in seconds.
Answer:
its b
Explanation:
1. Discuss how we use trial and error, algorithms, heuristics, and insight to solve problems. For each concept, define the term and then describe an incident (either from your own experience or that of a friend) in which the concept was used to determine a solution to a specific problem. You must use specific details of the incident and terms from our module to show me you understand the concept. (Total 64 points)
2., How can confirmation bias and fixation can interfere with effective problem solving. In this portion of your response, for each concept, define the term and then describe an incident (either from your own experience or that of a friend) in which the concept interfered with an appropriate solution being determined. You must use specific details of the incident and terms from our module to show me you understand the concept. (Total 32 pts).
Answer: used concepts to simplify and order the world around us, categories: objects, events, ideas, or people
hierarchies: subdivide categories into smaller more detailed units, prototypes: best example
algorithm: time-consuming but thorough set of rules or procedures
heuristics: simpler way of thinking, solve problems but maybe incorrect solutions
insight: flash of inspiration that solves problem
representativeness heuristic: judge likelihood of things in terms of how they represent our prototype
availability heuristic: judge likelihood of things based on how vivid they are or how readily they come to mind.
Explanation: i hope that helped!
If you walk 6mph how far would you get in 10 seconds?
Answer:
0.017
Explanation:
6÷3600×10=
6÷360=0.00166666666
=0.017(rounded)
Answer:
The answer is 1 mile in 10 minutes
Which of the following groups contain three elements with stable electron configurations?
A. xenon, neon, boron
B. helium, xenon, neon
C. argon, neon, barium
D. lithium, krypton, argon
Answer:
B. helium, xenon, neon
Explanation:
While the boys were playing baseball, one of the boys decides to kick his soccer ball high into the air. As the ball goes upward, which type of energy is increasing?
A.) Kinetic Energy
B.) Thermal Energy
C.) Potential Energy
D.) Mechanical Energy
What is the astronomical unit used to measure distances in the solar system?
Answer:
Astronomical unit
Explanation:
Short Answer: It's (au)
Long Answer:
The astronomical unit (au or AU) is defined as exactly 149,597,870,700 meters (about 93 million mi), which is roughly equal to the average distance between the Sun and Earth.
A tiger leaps horizontally from a 6.2 m high rock with a speed of 3.4 m/s. How far from the base of the rock will she land?
Answer:
u got the answer^^^^^^^^gngnnngggngng
A student wants to test if a bean plant will grow taller under green light than under sunlight. Select from the drop-down menu the correct step of the scientific method that each statement describes.
Two identical bean plants are grown next to each other. They receive the same amount of water and sunlight. One plant is covered with a green, light-filtering plastic cover, and the other with a clear plastic cover. Measurements of the bean plants’ heights are recorded every day for two weeks.
Answer:
Experiment
Record Results
Predict
Hypothesis
Analyze and Conclude
Observation and Questioning
Note: The question is incomplete. The complete question is given below:
A student wants to test if a bean plant will grow taller under green light than under sunlight. Select from the drop-down menu the correct step of the scientific method that each statement describes. Two identical bean plants are grown next to each other. They receive the same amount of water and sunlight. One plant is covered with a green, light-filtering plastic cover, and the other with a clear plastic cover. Measurements of the bean plants’ heights are recorded every day for two weeks. The student writes a lab report detailing the experimental procedure and results. The bean plant grown under the green filter will grow taller than the bean plant grown under unfiltered sunlight. Green light makes plants grow taller. The measurements show that the plant grown in natural sunlight grew taller than the green-filtered plant. So green light does not make plants grow taller. Plants are colored green, so maybe they grow more in green light.
Explanation:
1. An experiment is a procedure carried to test a hypothesis in order to support, reject or confirm the hypothesis. The steps below are for an experiment to whether bean plants grow taller under green light or sunlight.
Two identical bean plants are grown next to each other. They receive the same amount of water and sunlight. One plant is covered with a green, light-filtering plastic cover, and the other with a clear plastic cover. Measurements of the bean plants’ heights are recorded every day for two weeks.
2. Results of the experiment are recorded. The statement below indicates that results were recorded.
The student writes a lab report detailing the experimental procedure and results.
3. Predictions are expected results based on an initial hypothesis. The statement below is a prediction.
The bean plant grown under the green filter will grow taller than the bean plant grown under unfiltered sunlight.
4. A hypothesis is a statement that seeks to explain an observed phenomena. The statement below is a hypothesis:
Green light makes plants grow taller.
5. Analysis and conclusion: the results of the experiment are analysed and conclusions are then drawn. The statement below shows analysis and conclusion based on results of the experiment:
The measurements show that the plant grown in natural sunlight grew taller than the green-filtered plant. So green light does not make plants grow taller.
6. Observations and Questions are necessary parts of the scientific method. Observing phenomena around and asking questions about our observations helps in the process of making a hypothesis. The statement below is illustrates observation and questioning:
Plants are colored green, so maybe they grow more in green light.
Answer: D,F,C,B,E,A
Explanation:
i took the test
A ball weighing 2.0 N falls through a distance of 4 m.
Answer:
This question is incomplete, a possible question would be to calculate the work done by the ball.
Work done = 8J
Explanation:
Work done by an object is calculated my multiplying the force by the distance.
The weight of this ball is 2.0N, which also represents the force exerted by the ball. The ball travels through a distance of 4m
Hence, work done = F × d
Work done = 2N × 4m
Work done = 8Nm or 8J
I need help plz
Help meh
Answer:
6. False
7. a
8.kinetic
9. ek/n
10.True
Explanation:
Answer:
1. kinetic
2. d
3. b
4. true?
5. true
6. True
7. a
8. kinetic
9. Thermal
10. true
Refinery EM can produce 22 gallons of gasoline or 18 gallons of flight fuel per barrel of crude oil. Refinery CG can produce 18 gallons of gasoline or 16 gallons of flight fuel per barrel of crude oil. Does OUTPUT vary or does INPUT vary in this problem?
Answer:
Output varies
Explanation:
Here the outputs of gallons of gasoline and flight fuel is mentioned of two refineries namely Refinery EM and Refinery CG. The output has been mentioned with respect to one barrel of crude oil. So, one barrel of crude is used by both the refineries.
So, here the output (gallons of gasoline and flight fuel) varies while the input (one barrel of crude oil) remains constant.
What are the Laws of conservation of atoms?
Answer:
Both the initial and final substances are composed of atoms because all matter is composed of atoms. According to the law of conservation of matter, matter is neither created nor destroyed, so we must have the same number and kind of atoms after the chemical change as were present before the chemical change.
Explanation:
Answer:
The law of conservation of atoms is simple but it has a great affect. An atom cannot be destroyed by such a force. Matter/atoms can't be created by any means. An atom exits only by nature and not by force.
Hope this helped! Please mark brainliest! Have a great day!
how are atoms in a molecule held together?
A.through shared protons
B.through shared electrons
C.through shared neutrons
D.through shared energy
Atoms held together through shared electrons.
A molecule is composed of atoms. Atoms are the smallest particles of a substance which can take part in a chemical reaction. Atoms are composed of electrons and the electrons in the outermost shell of atoms help bond atoms together in a molecule.
Hence, atoms are held together in molecules by electrons so they are held together through shared electrons.
Learn more about molecules: https://brainly.com/question/19922822
A child throws a baseball straight up into the air and it takes 4.5 seconds to reach maximum height. What is the total time of flight for the baseball after being thrown and the baseball player catching it? What are the known and unknown variables? And what equation must be used?
Answer:
9 s.
Explanation:
The following data were obtained from the question:
Time (t) taken to reach the maximum height = 4.5 s
Time of flight (T) =?
The time of flight (T) is simply defined as the total time spent by the ball in the air. Mathematically, it defined as twice the time taken (t) to reach the maximum height i.e
T = 2t
With the above formula, we can obtain the time of flight as follow:
Time (t) taken to reach the maximum height = 4.5 s
Time of flight (T) =?
T = 2t
T = 2 × 4.5
T = 9 s
Thus, the time of flight of the ball is 9 s.
I need help with this please
Answer:
i know
Explanation:
2. Two people, one on Earth and the other on the Moon, try and lift 200 kg blocks. Which person
will have to exert more force to lift their block or will they need to exert the same amount of
force? Explain your reasoning(4 pts)
Answer:
The person on Earth will have to exert more force to lift their block
Explanation:
The mass of the blocks to be lifted = 200 kg
The location of the first person = On Earth
The location of the second person = On the Moon
The force a person will have to exert to lift the block = The weight of the block = The gravitational force, F, on the block which is given as follows;
[tex]F = \dfrac{G \times M_1}{R^2} \times m_2[/tex]
Where;
[tex]\dfrac{G \times M_1}{R^2}[/tex]= The acceleration due to gravity on the Earth or the Moon, depending on the location of the block
m₂ = The mass of the block
Therefore, given that the acceleration due to gravity on the Earth is larger than the acceleration due to gravity on the Moon, the weight of the block on the Earth is larger than the weight of the block on the Moon, and the person on Earth have to exert more force to lift the heavier weight of the block on Earth than the person on the Moon will have to exert to lift the same block as the block has a lower weight on the Moon due to lower acceleration due to gravity on the Moon.
A tortoise can run with a speed of 0.10 m/s, and a hare can run 20 times as fast. In a race, they both start at the same time, but the hare stops to rest for 2.0 minutes. The tortoise wins by a shell (20 cm)!How long does the race take?What is the length of the race?
Answer: a. 126.21secs
b. 12.621 meters.
Explanation:
Given data:
Speed of tortoise = 0.1m/s.
Speed of hare = 2m/s.
Solution:
a. Distance traveled = Speed* Time
Speed of tortoise = 0.1 m/s
Speed of hare = 20*0.1 m/s = 2 m/s
2 minutes = 2* 60 s = 120 s
Let the time taken for the race be t seconds.
• Distance moved by tortoise
= (0.1 /s)* (t s)
= 0.1*t meter
•Hare has run for a time of (t - 120)s.
distance moved by hare
= Speed * Time
= (2 m/s)*(t- 120)s
= (2t - 240) meter.
Since hare is 20 cm (0.2 m) behind the tortoise, therefore
(0.1*t - 0.2) meter
= (2t - 240) meter
0.1*t - 0.2 = 2t - 240
Collect like terms
239.8 = 1.9t
Divide both sides by 1.9
t = 126.21secs
The race lasted for 126.21secs
b. Length of race
= Distance moved by tortoise
= 0.1*126.21 meter
= 12.621 meter
The length of the race is 12.621 meters.
Find the acceleration of a car with the mass of 1,200 kg and a
force of 11 x 103 N.
The acceleration of the car with the mass of 1200kg and a force of 11 × 10³N is 9.17m/s²
HOW TO CALCULATE ACCELERATION:
The acceleration of a moving body can be calculated by dividing the force applied by the mass. That is;Acceleration (m/s²) = Force (N) ÷ mass (kg)According to this question, a car has a mass of 1,200 kg and a force of 11 x 10³ N. The acceleration can be calculated as follows:Acceleration = 11000N ÷ 1200kgAcceleration = 9.17m/s²Therefore, the acceleration of the car with the mass of 1200kg and a force of 11 × 10³N is 9.17m/s²Learn more at: https://brainly.com/question/17289046?referrer=searchResults
Lindsay is planning a flight from St. Catharines to Hamilton, which lies due west of St. Catharines. Her aircraft flies at a speed of 200 km/h in still air.A wind of 50.0 km/h is blowing from [W 608 N]. In what direction must sheaim the airplane to fly directly to Hamilton?
Answer:
Lindsay is planning a flight from St. Catherines to Hamilton, which lies due west of St. Catharines. Her aircraft flies at a speed of 200 km/h in still air. A wind of 50.0 km/h is blowing from [W 60.0� N]. In what direction must she aim the airplane to fly directly to Hamilton?
------------
It's a triangle problem.
The long side is the 200 km/hr, at an angle to be determined.
-----
1 side is 50 km/hr at an angle of -60 degs or 300 degs.
The 3rd side's length is not known, but it's at an angle of 180 degs (along the x-axis).
Lindsay has to fly this plane towards this direction [W 12.5° S] to get to Hamilton.
From this question, the plane is still up in the air.
We have wind blowing in [W 60° N ]
To solve the problem we have to make use of the sine rule
[tex]\frac{SinA}{a}=\frac{SinB}{b} =\frac{SinC}{c}[/tex]
We put the values in the equation, we have:
50/Sinθ = 200/sin60°
The next step is to cross multiply
50 x sin60° = 200Sinθ
50 x 0.8660 = 200sinθ
We make Sin θ the subject
Sine θ = 43.30/200
sine θ = 0.2165
we find the value of θ
θ = sine⁻¹(0.2165)
θ = 12.50
So Lindsay has to fly this plane towards this direction
[W 12.5° S]
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