At liftoff, the space shuttle Discovery has a constant acceleration of 16.4 ft/s/s with an initial velocity of 1,341 ft/s due to the rotation of the Earth. How long does it take to travel 100,000 ft?

Answers

Answer 1

From orbital speed formula which is the ratio of the circumference of the earth and the period of time, it will take 6097.6 seconds to travel 100,000 ft

Given that the space shuttle Discovery has a constant acceleration of 16.4 ft/s with an initial velocity of 1,341 ft/s due to the rotation of the Earth.

The period of time T it will require to travel round the a distance 100,000 ft can be calculated by using the formula below.

V = 2πr / T

Where 2πr = 100,000 ft

V = 16.4 ft/s

Substitute both in the formula above.

16.4 = 100000 / T

T = 100000 / 16.4

T = 6097.6 seconds

Therefore, it will take 6097.6 seconds to travel 100,000 ft

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Related Questions


2. Where do hyperbolic comets originate?
A.the Oort cloud
B.the asteroid belt
B.the Kuiper belt
C.interstellar space

Answers

Answer:

Hyperbolic comets originate from the Kuiper Belt.

What happens to the gravitational force between two objects if the distance between them triples?

A. The force increases by a factor of 9

B. The force decreases by a factor of 9

C. The force decreases by a factor of 3

D. The force increases by a factor of 3

Answers

So as two objects are separated from each other, the force of gravitational attraction between them also decreases. ... If the separation distance between any two objects is tripled (increased by a factor of 3), then the force of gravitational attraction is decreased by a factor of 9 (3 raised to the second power).

So the answer you are looking for is B.
The answer will be B.

Gravity obeys something called the inverse square law.

This means if distance increases by a factor of x, the force of gravity will decrease by a factor of x^2

For example, if distance increases by 2, the force would be 4 times weaker

If Distance increases by a factor of 3, the force will be 9 times weaker

Water pumps use electrical energy to create mechanical energy needed to move water.
A 1875 W water pump is plugged into a 110 V electrical outlet.

Answers

Answer:

n/a

Explanation:

this question is not feasible

which alkali metal is most reactive

Answers

Francium is the most reactive alkali metal

A wheel has a radius of r = 2.0 m and it rolls down a smooth incline. The height of the incline is h = 8.0 m . What is the angular velocity ω of the wheel at the bottom of the incline?
Express your answer in radians per second.

Answers

The angular velocity of the wheel at the bottom of the incline is 4.429 rad/sec

The angular velocity (ω) of an object is the rate at which the object's angle position is changing in relation to time.

For a wheel attached to an incline angle, the angular velocity can be computed by considering the conservation of energy theorem.

As such the total kinetic energy (K.E) and rotational kinetic energy (R.K.E) at a point is equal to the total potential energy (P.E) at the other point.

i.e.

P.E = K.E + R.K.E

[tex]\mathbf{mgh = \dfrac{1}{2}m(r \times \omega)^2 + \dfrac{1}{2}\times I \times \omega^2}[/tex]

[tex]\mathbf{gh = \dfrac{1}{2}(r \times \omega)^2 + \dfrac{1}{2}\times r^2 \times \omega^2}[/tex]

[tex]\mathbf{2 \times \dfrac{gh}{r^2} =\omega^2 + \omega^2}[/tex]

[tex]\mathbf{2 \omega^2=2 \times \dfrac{9.81 \times 8 m }{2.0 ^2} }[/tex]

[tex]\mathbf{\omega^2=\dfrac{39.24 }{2}}[/tex]

[tex]\mathbf{\omega=\sqrt{19.62 } \ rad/sec}[/tex]

[tex]\mathbf{\omega=4.429 \ rad/sec}[/tex]

Therefore, we can conclude that the angular velocity of the wheel at the bottom of the incline is 4.429 rad/sec

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The angular velocity of the wheel depends on the mass, radius and the

mode of rotation of the wheel (with or without slipping).

The angle velocity at the bottom of the incline, ω ≈ 4.43 rad/sec

Reasons:

The given parameters are;

Radius of the wheel, r = 2.0 m

Height of the incline, h = 8.0 m

Required:

Angular velocity of the wheel at the bottom of the incline.

Solution:

The potential energy of the wheel at the top of the hill, P.E. = m·g·h

[tex]Sum \ of \ the \ kinetic \ energy \ of \ the \ wheel, \ K.E. = \mathbf{\displaystyle \frac{1}{2} \cdot m \cdot v^2 + \frac{1}{2} \cdot I \cdot \omega ^2}[/tex]

Where;

v = The translational velocity of the wheel = ω·r

I = The moment of inertia of the wheel = m·r²

Therefore'

[tex]Sum \ of \ K.E. = \displaystyle \frac{1}{2} \cdot m \cdot (\omega \cdot r)^2 + \frac{1}{2} \cdot m \cdot r^2 \cdot \omega ^2 = \mathbf{m \cdot r^2 \cdot \omega^2}[/tex]

At the bottom of the hill, the potential energy is converted to kinetic energy

Therefore;

P.E. = Sum of K.E.

m·g·h = m·r²·ω²

g·h = r²·ω²

[tex]\displaystyle \omega = \sqrt{ \frac{g \cdot h}{r^2} } = \mathbf{ \frac{\sqrt{g \cdot h} }{r}}[/tex]

Where;

g = Acceleration due to gravity ≈ 9.81 m/s²

Therefore;

[tex]\displaystyle \omega = \frac{\sqrt{9.81 \times 8} }{2} \approx \mathbf{ 4.43}[/tex]

The angular velocity of the of the wheel at the bottom of the incline, ω ≈ 4.43 rad/sec

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E
D
С
B
A
Column
Column
1.
Electron Cloud
B
2
Nucleus
b. A
3.
Electron
CD
4.
Neutron
d.
5.
Proton
ec

Answers

Answer:

1. D electron cloud

2. A nucleus

3. E electron

4. B neutron

5. C proton

Explanation:

electrons are located outside the nucleus. The nucleus holds the protons and neutrons. Protons have a positive symbol (+). electron cloud holds the electrons.

Explanation:

Electron cloud : D

Nucleus : A

Electron : E

Neutron : B

Proton : C

hope this helps you.

find the total volume of the material used to making the cylinder​

Answers

Answer:

Hey mate

Explanation:

Whereas the basic formula for the area of a rectangular shape is length × width, the basic formula for volume is length × width × height.

pls mark me as brainliest!!

If a rocket experiences an acceleration generated by the gravity force between the earth and itself, what is this acceleration if the rocket flies 1000 km above the ground and the Earth's radius is 6.378 * 10 ^ 6 * r m. We know the Earth has a mass of 5.97*10^ 24 kg(in m/s^ 2 , G=6.67*10^ -11 N(m/kg)^ 2 ) ?
a 8.97
b 7.32
c 9.81
d 5.5
e 11.45

Answers

This question involves the concepts of Gravitational Force and Weight force.

The value of acceleration is "b. 7.32 m/s²".

At the given height the weight of the rocket must be equal to the gravitational force between rocket and the Earth:

[tex]W=F_G\\mg=\frac{GmM}{R^2}\\\\g=\frac{GM}{R^2}[/tex]

where,

g = acceleration = ?

G = universal gravitational constant = 6.67 x 10⁻¹¹ N.m²/kg²

M = mass of earth = 5.97 x 10²⁴ kg

R = Radius of Earth + Height = 6.378 x 10⁶ m + 1 x 10⁶ m = 7.378 x 10⁶ m

Therefore,

[tex]g=\frac{(6.67\ x\ 10^{-11}\ N.m^2/kg^2)(5.97\ x\ 10^{24}\ kg)}{(7.378\ x\ 10^6\ m)^2}[/tex]

g = 7.32 m/s²

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8/10
A person stands on a square pedestal whose side lengths are
1.20 m. The person and pedestal together weigh 1.84 x 103 N.
What is the pressure the person and and pedestal exert on the
floor in Pa?

Answers

Answer:

Explanation:

P = 1.84 x 10³ N / 1.20² m² = 1,277.77777... N/m²

P = 1.28 x 10³ Pa

A ball has the energy to move 30 m/s with the mass of 5. What is the energy

Answers

If an object is moving and has velocity it has kinetic energy. the kinetic energy of an object is the energy that it possesses due to its motion.

In my work I used the formula for kinetic energy to answer your question. Hope this helps.

The following is an example of what type of reaction?

Answers

Answer:

Single Displacement Reaction

Explanation:

Here, only one element is getting replaced during the reaction, that is, silver gets replaced by copper, hence, single displacement reaction.

Hope it helps :)

Convert the decimal number 61078 to binary by using sum-of-weights method​

Answers

Answer:

1110111010010110

Explanation:

I am not able to upload the working out using the sum of weights method sorry

A cylinder with a radius of 1.8 cm is floating in water as shown below. The mass of the cylinder is 1.80 kg. Calculate the depth of the bottom end of the cylinder

Answers

Answer:

Explanation:

I will ASSUME that the cylinder floats with the axis through the center of its flat ends is perpendicular to the water surface.

The cylinder will displace it's mass in water.

water density has a value of 1000 kg/m³

if the depth of the bottom is "h" in meters

1.80 kg = π(0.018² m²)(h m)(1000) kg/m³

h = 1.768388256...

or about 1.77 m

A 4.0 kilogram projectile is fired horizontally from a 500 kilogram cannon initially at rest. The momentum of the projectile after being fired is 600 kilogram-meters per second to the north
(neglecting friction).
What is the speed of the cannon after firing?
0.83 m/s
1.2 m/s
o
3.3 m/s
150 m/s

Answers

The speed of the cannon after firing is 1.2 m/s

This can be solved using the law of conservation of momentum.

From the law of conservation of momentum,

⇒ The momentum of the projectile is equal to the momentum of the cannon.

MV = P................ Equation 1

⇒ Where :

M = mass of the cannon,V = velocity of the cannonP = momentum of the projectile.

⇒ make V the subject of the equation

V = P/M.................. Equation 2

From the question,

⇒ Given:

P = 600 kgm/sM = 500 kg

⇒ Substitute these values into equation 2

V = 600/500V = 1.2 m/s

Hence, The speed of the cannon after firing is 1.2 m/s

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What effect does the time taken to lift the mass have on power output?

Answers

The longer the time taken, the lower the power output.

This is since power is calculated through

Energy transferred / time

Increasing the denominator will lead to a lower value overall

if a current of 2.0 A is flowing from point a to point b, the potential difference between Vb- Va (in V) is:


a. 6
b. 8
c. -6
d. -8
e. 22

Answers

Answer:

[tex]\huge\color{skyblue}\boxed{\colorbox{black}{Answer ☘}}[/tex]

[tex]total \: resistance \: ( R_{t} ) = (3 + 1)ohm \\ (since \: the \: resistors \: are \: connected \\ in \: series)[/tex]

[tex]current \: flowing \: through \: circuit(I) = 2A \\ \\ now... \: by \: ohms \: law \\ V = IR\\ V = (2)(4) \\ = > 8v[/tex]

therefore , option (b) is correct!!

hope helpful~

Which of the following statements is NOT true of a hypoosmotic solution?
A. It is also known as a hypotonic solution.
B. There are more dissolved solids within the cell than outside the
cell.
C. It may cause water to move into the cell, which will cause it to
swell.
D. It may cause the cell to shrink or crenate.

Answers

There are more dissolved solids within the cell than outside thecell.

Answer:

Good luck on the test, you donuts.

Explanation:

Two steel guitar strings have the same length. String A has a diameter of 0.489 mm and is under 410 N of tension. String B has a diameter of 1.27 mm and is under a tension of 809 N. Calculate the ratio of the wave speeds, vA/vB, in these two strings.

Answers

Answer:

Explanation:

vA / vB = √(TA/(m/L)) / √(TB/(m/L))

The lengths are the same, so the L divides out to 1

The material is identical so the mass will be directly proportional to the cross sectional area of the string

vA / vB = √(TA/(πdA²/4)) / √(TB/(πdB²/4))

π/4 is common so divides out to 1

vA / vB = √(TA/dA²) / √(TB/dB²)

vA / vB = √(410/0.489²) / √(809/1.27²)

vA / vB = 41.407 / 23.396

vA / vB = 1.8488961...

vA / vB = 1.85

You are pulling a sled with a constant velocity using a rope held horizontally in
the snow. Using a spring scale attached to the rope, you measure the tension
to be 0.96 N. The sled's mass is 0.58 kg. Write the surface force the ground
exerts on the sled in component form, and determine its magnitude.

Answers

Answer:

Explanation:

if you are pulling in the positive direction and Upward is also positive.

F = -0.96i + 0.58(9.8)j

F = -0.96i + 5.7j

F = √(-0.96² + 5.7²) = 5.8 N

You are pulling a sled with constant velocity by using a rope then the surface force the ground exerts on the sled will be 5.8 N.

What is tension?

The pulling force conveyed axially by a string, cable, chain, or another analogous object, or by either end of a rod, truss member, or another such three-dimensional object, is referred to as tension in physics. Another way to think of tension is as the action-reaction pair of forces acting at each end of the previous elements. Perhaps tension is the polar opposite of compression.

A restoring force may cause what is also referred to as tension when atoms or molecules are torn apart from one another at the atomic level and build up potential energy.

If you are moving upward and pushing in a positive way,

F = -0.96 i + 0.58(9.8) j

F = -0.96 i + 5.7 j

F = [tex]\sqrt{(-0.96^2 + 5.7^2)}[/tex]

F= 5.8 N

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Hello I am absolutely stumped on these six physics problems. Please help me on them.

Answers

Answer:

Explanation:

20° from the normal = 110° from parallel

1a) τ = (200sin90)[6] + (75sin110)[3] - (100sin110)[3]

     τ = 1,129.52305... = 1100 N•m CCW

1b) τ =  200(6)(sin90) + 75(-3)(sin(360-110)) + 100(3)(sin(270 + 20)

     τ = 1,129.52305... = 1100 N•m CCW

1c) My directions agree, both are positive z by right hand rule.

1d) Moment of inertia for a thin rod about an axis perpendicular to its center is

I = (1/12)mL²

τ = Iα

α = τ/I = 1129.523 / ((1/12)(200)(12²)) = 0.4706 rad/s²

θ = ½αt²

θ = ½(0.4706)(2•60)² = 3,388.56916... radians

θ = 3400 radians

at which time is is spinning about 9 revolutions per second

The diagram shows the tropic levels in a lake in a farm. Suppose the farmer sprays a field with a chemical fertilizer. Based on the flow of energy in the lake, which organisms would contain the highest concentration of the chemical fertilizer?

Answers

Based on the flow of energy that's in the lake, it can be deduced that the diatoms and algae will have the highest concentration.

Energy flow refers to the flow of energy through living organisms that are within an ecosystem. Energy is passed from one trophic level to the next trophic level.

If the farmer sprays a field with chemical fertilizer, the organism that would contain the highest concentration of the chemical fertilizer are diatoms and algae since they're at the bottom of the ecosystem.

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HELP ME the mean free path λ and the mean collision time τ of the molecules of a diatomic gas of molecular mass 6.00 × 10⁻²⁵ kg and radius r = 1.0 x 10⁻¹⁰ m are measured. From these microscopic data can we obtain macroscopic properties such as temperature T and pressure P? If so, consider λ = 4.32 x 10⁻⁸ m and τ = 3.00 x 10⁻¹⁰ s and calculate T and P.

Answers

The temperature of the diatomic gas is 300.5 K and the pressure is 5.33 atm.

The given parameters;

Mass of the gas molecules, m = 6 x 10⁻²⁵ kgRadius of the gas, r = 1 x 10⁻¹⁰ mMean free path, [tex]\lambda_{rms}[/tex] = 4.32 x 10⁻⁸ mMean collision time, [tex]\tau = 3 \times 10^{-10} \ s[/tex]

The mean velocity of the gas molecules is calculated as follows;

[tex]\tau = \frac{\lambda _{rms}}{V_{rms}} \\\\V_{rms} = \frac{\lambda _{rms}}{\tau} \\\\V_{rms} = \frac{4.32 \times 10^{-8} }{3 \times 10^{-10}} \\\\V_{rms} = 144 \ m/s[/tex]

The temperature  of the gas molecules is calculated as follows;

[tex]V_{rms} = \sqrt{\frac{3kT}{M} } \\\\V_{rms}^2 = \frac{3kT}{M} \\\\T = \frac{V_{rms} ^2 M}{3k}[/tex]

where;

k is Boltzmann constant

[tex]T = \frac{V_{rms} ^2 M}{3k} \\\\T = \frac{(144)^2 \times (6.0 \times 10^{-25})}{3 \times 1.38 \times 10^{-23}} \\\\T = 300.5 \ K[/tex]

The number of gas molecules per unit volume is calculated as follows;

[tex]\lambda = \frac{1}{4\pi \sqrt{2} \ r^2 n} \\\\n = \frac{1}{\lambda 4\pi \sqrt{2} \ r^2} \\\\n = \frac{1}{(4.32 \times 10^{-8}) \times 4 \pi \times \sqrt{2} \ \times (1\times 10^{-10})^2} \\\\n = 1.303 \times 10^{26} \ molcules/m^3[/tex]

The pressure of the gas molecule is calculated as follows;

[tex]n = \frac{P}{kT} \\\\P = nkT\\\\P = (1.303 \times 10^{26} ) \times (1.38 \times 10^{-23}) \times (300.5)\\\\P = 540,341.07 \ Pa\\\\P = 5.33 \ atm[/tex]

Thus, the temperature of the diatomic gas is 300.5 K and the pressure is 5.33 atm.

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a 2000kg car initially traveling at a speed of 15 m/s is accelerated by a constant force of 10000 n for 3 seconds. the new speed of the car is

Answers

Mass of the car (m) = 2000 KgInitial velocity (u) = 15 m/sForce (F) = 10000 NTime (t) = 3 sLet the acceleration be a.By using the formula, F = ma, we get,10000 N = 2000 Kg × aor, a = 10000 N ÷ 2000 Kgor, a = 5 m/s^2Let the final velocity be v.By using the formula, v = u + at, we get,v = 15 m/s + 5 m/s^2 × 3 sor, v = 15 m/s + 15 m/sor, v = 30 m/s

Answer:

The new speed of the car is 30 m/s.

Hope you could get an idea from here.

Doubt clarification - use comment section.

In the following free body diagram, what is the net force on the object?
A.10n
B.5 N to the right
C.20 N to the right
D.7 N to the right

Answers

Answer:

B

Explanation:

Simply take all forces pointing to the right of the box as positive and all of the forces pointing to the left of the box as negative and add all values.

ΣF = 7 + 18 + (-20) = 5N to the right

A person is drinking a glass of soda with ice.
which option describes the relative kinetic energy of molecules in and above the soda in the glass?

A. in : least energy
above : intermediate and greatest energy

B. in : greatest energy
above : least energy

C. in : least energy
above : greatest energy

D. in least and intermediate energy
above : greatest energy ​

Answers

The relative kinetic energy of molecules in the soda is least energy and above the soda in the glass is greatest energy.

The relative kinetic energy of gas molecules increases with increase in the mean distance between the gas molecules.

Also, relative kinetic energy of gas molecules increases with in the temperature of the gas molecules and decreases with a decrease in the temperature of the of the gas molecules;

ΔK.E ∝ T

The ice in the soda lowers the temperature of the gas molecules, thereby reducing their average speed which in turn reduces the average kinetic energy of the gas molecules in the soda.

Above the soda in the glass, the concentration of the gas molecules is less and their mean distance is greatest when compared to inside the soda. This results to an increase in the speed of the gas molecules which increases their average kinetic energy.

Thus,  the relative kinetic energy of molecules in the soda is least energy and above the soda in the glass is greatest energy.

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When a 1 is on the input of an inverter, what is the output?​

Answers

Answer:

When the input to an inverter is high (1) the output is low (0); and when the input is low, the output is high.

(c) It is suggested that one side of the copper sheet cools to a lower temperature than the
other side.
Explain why this does not happen.
[2]

Answers

Answer:

Explanation:

The word "sheet" implies that the copper is quite thin.

Copper is also a very good conductor of heat.

Therefore, with a very short heat flow distance to cover and a high rate of heat transmission, temperature differences on either side of the sheet are almost instantaneously eliminated by heat flow.



Raghu studies in grade 6th. He wants a cricket bat to be made by a carpenter. He tells the
that the length of the bat should be 7 hand spans. The tall carpenter tells Raghu that it
will be ready by tomorrow. When Raghu went to collect the bat the next day, he was very
disappointed. Why? Was the bat longer or shorter than what Raghu expected? Give reason.
carpenter

Answers

Based on the information given, it can be noted that the bat was either shorter or longer than what he expected.

From the information given, it was stated that Raghu wants a cricket bat to be made by a carpenter and he tells the carpenter that the length of the bat should be 7 hand spans.

Since he got disappointed when he collected the bat, the reason for this will be because the bat was either shorter or longer than what he requested.

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is xenon a pure substance​

Answers

[tex]\large\huge\green{\sf{Yes}}[/tex]

a car moving at 5 m/s accelerates at a rate of 10 m/s2 for 25 seconds. How far does it move during this time?

Answers

Answer:

t is time in s For example, a car accelerates in 5 s from 25 m/s to 3 5m/s. Its velocity changes by 35 - 25 = 10 m/s. Therefore its acceleration is 10 ÷ 5 = 2 m/s2

Explanation:

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Determine if the sequence below is arithmetic or geometric and determine the common difference/ ratio in simplest form 15, 11 ,7, ToolScientists are searching for planets that orbit stars outside Earth's solar system by collecting data from different technology tools. A student lists a few tools and their cases that would provide clientswith information about these planets in a table, as shownUsespectroscopegathers information about theplanets in any weather conditionsspace probecollects data from the planets thatwould otherwise not be availableidentifies different elements presentreflector telescopearound the planetsradio telescope produces images of the planetsWhich tool is paired correctly with its intended use?space probeOpectroscoperadio telescopereflector telescope III. The following paragraph contrasts the writers two cousins. Three major differences are identified, andeach of these is illustrated with several specific examples. Read the paragraph and circle anytransitions. Then write the transitions in the appropriate blanks below.OppositesMy cousins Joanne and Mary couldnt be more different. First, Joanne is a total nonconformist. For one thing, Joannes appearance is bizarre. For example, her hair is partially shaved and dyed pink, and shes covered in tattoos. In addition, her favorite clothes are ripped and have pictures on them of things like skulls. Furthermore, Joanne has a wild personality. For instance, shell do outrageous things, like the time she got her nose pierced. Another time, she hitchhiked to San Francisco at 2:00 a.m. Finally, when it comes to interests, Joanne is really into music. She plays the guitar in a punk rock band, and she loves to go to clubs and concerts to check out other bands. In contrast, Mary is the total opposite of Joanne. For one thing, Marys appearance is very conservative. For instance, her naturally blond hair is usually in a ponytail, and her favorite clothes are sweats or a soccer uniform. 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What transition is used to signal the conclusion? ____________________________