[tex]{\underline{\pink{\textsf{\textbf{ Answer : }}}}}[/tex]
➡ 150hrs.
[tex]{\underline{\pink{\textsf{\textbf{Explanation : }}}}}[/tex]
➡ Time = distance × speed
➡ Time = 15*10
➡ Time = 150hrs ans.
7. Answer each of the following questions if the student applied a 550N force to a 100kg box on the same surface. What would be the magnitude of the box's acceleration?
Acceleration of an object is the force divided by its mass. Hence, acceleration of the 100 Kg box with an applied force of 550 N is 5.5 m/s².
What is acceleration?Acceleration is a physical quantity having both magnitude and direction. This vector measures the rate of change of velocity of a moving body. Thus, acceleration has the unit of m/s².
According to Newton's second law of motion, force acting on a body is the product of its mass and acceleration. Thus, force is directly proportional to the mass and acceleration of the body.
Given the mass of the box = 100 Kg
Force applied on it = 550 N.
Acceleration = 550 N / 100 Kg
= 5.5 m/s² ( 1 N = 1 Kg m/s²)
Therefore, the acceleration of the box is 5.5 m/s².
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A radio wave transmits 38.5 W/m2 of power per unit area. A flat surface of area A is perpendicular to the direction of propagation of the wave. Assuming the surface is a perfect absorber, calculate the radiation pressure on it.
Answer:
[tex]P=2.57\times 10^{-7}\ N/m^2[/tex]
Explanation:
Given that,
A radio wave transmits 38.5 W/m² of power per unit area.
A flat surface of area A is perpendicular to the direction of propagation of the wave.
We need to find the radiation pressure on it. It is given by the formula as follows :
[tex]P=\dfrac{2I}{c}[/tex]
Where
c is speed of light
Putting all the values, we get :
[tex]P=\dfrac{2\times 38.5}{3\times 10^8}\\\\=2.57\times 10^{-7}\ N/m^2[/tex]
So, the radiation pressure is [tex]2.57\times 10^{-7}\ N/m^2[/tex].
A woman standing before a cliff claps her hands, and 2.8s later she hears the echo. How far away is the cliff? The speed of sound in air a ordinary temperature is 343 m/s.
Answer:
480.2 m
Explanation:
The following data were obtained from the question:
Speed of sound (v) = 343 m/s.
Time (t) = 2.8 s
Distance (x) of the cliff =?
The distance of the cliff from the woman can be obtained as follow:
v = 2x /t
343 = 2x /2.8
Cross multiply
2x = 343 × 2.8
2x = 960.4
Divide both side by the coefficient of x i.e 2
x = 960.4/2
x = 480.2 m
Therefore, the cliff is 480.2 m away from the woman.
The distance should be 480.2 m
The calculation is as follows:Since A woman standing before a cliff claps her hands, and 2.8s later she hears the echo. And, there is the velocity of 343 m/s
[tex]v = 2x \div t\\\\343 = 2x \div 2.8\\\\2x = 343 \times 2.8[/tex]
2x = 960.4
x = 480.2 m
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The x and y coordinates of a particle at any time t are x = 5t - 3t2 and y = 5t respectively, where x and y are in meter and t in second. The speed of the particle at t = 1 second is
Answer:
[tex]v=\sqrt{26}~m/s[/tex]
Explanation:
Parametric Equation of the Velocity
Given the position of the particle at any time t as
[tex]r(t) = (x(t),y(t))[/tex]
The instantaneous velocity is the first derivative of the position:
[tex]v(t)=(v_x(t),v_y(t))=(x'(t),y'(t))[/tex]
The speed can be calculated as the magnitude of the velocity:
[tex]v=\sqrt{v_x^2+v_y^2}[/tex]
We are given the coordinates of the position of a particle as:
[tex]x=5t-3t^2[/tex]
[tex]y=5t[/tex]
The coordinates of the velocity are:
[tex]v_x(t)=(5t-3t^2)'=5-6t[/tex]
[tex]v_y(t)=(5t)'=5[/tex]
Evaluating at t=1 s:
[tex]v_x(1)=5-6(1)=-1[/tex]
[tex]v_y(1)=5[/tex]
The velocity is:
[tex]v=\sqrt{(-1)^2+5^2}[/tex]
[tex]v=\sqrt{1+25}[/tex]
[tex]\mathbf{v=\sqrt{26}~m/s}[/tex]
At what speed do a bicycle and its rider, with a combined mass of 100 kg, have the same momentum as a 1500 kg car traveling at 1.0 m/s?
Answer:
15m/sExplanation:
Step one:
given data
mass of bicycle m=100kg
the velocity of bicyle v=?
mass of car M=1500kg
the velocity of car V=1.0m/s
Step two:
we know that the momentum is expressed as
P=mv
since the momentum of the bicycle must be equal to car then
mv=MV---------1
100*v=1500*1
divide both sides by 100
v=1500/100
v=15m/s
The velocity of the bicycle should be 15m/s
As the skiers travel down the slope a portion of their total energy is lost. This means that when they perform their tricks, they will never go as high as they were when they first pushed off from the gate. Describe how this energy is lost.
Answer:
Explained below
Explanation:
In skying down a hill, usually the skiers start at an elevated position and this means that they possess a large quantity of potential energy since they are in vertical position.
Now, as the skiers start to descend down the hill, they will lose potential energy while they gain kinetic energy since they are in motion. This is because there is reduction in height which results in a loss of potential energy and there is an increase in their speed which results in an increase in kinetic energy.
Now, immediately the skiers reaches the bottom of the hill, it means they are now at zero level height which means potential energy is now zero and it implies they have completely depleted the potential they had at the beginning at the top of the hill.
In contrast, at this zero level height, their speed and kinetic energy would have reached a maximum and this kinetic energy state will be maintained until they encounter a section of unpacked snow where they have to skid to a stop under force of friction. This friction force will carry out work on the skiers which will make their total mechanical energy to decrease. This means that as the force of friction keeps acting over an increasing distance, the quantity of work will therefore increase while the mechanical energy of the skiers will gradually be dissipated.
Eventually, the skiers will run out of energy and comes to a rest position and therefore they wouldn't be able to go as high as they first were before pushing off from the gate.
A block is attached to one end of a spring so that it can bounce back and forth on a horizontal frictionless surface. The block is pulled a distance of 0.150 m away from equilibrium and released. When the block is 9.00 cm away from equilibrium, it is traveling with a speed of 0.800 m/s. If the spring constant of the spring is 60.0 N/m, what is the mass of the block?
Answer:
m = 1.35 kg
Explanation:
In absence of friction, total mechanical energy must be conserved, so the sum of the initial elastic potential energy plus the initial kinetic energy, must be equal to the sum of the final kinetic energy plus the final elastic potential energy, as follows:[tex]U_{i} + K_{i} = U_{f} + K_{f} (1)[/tex]
As the block starts from rest, this means that Ki =0.We can express the elastic potential energy at any point , as follows:[tex]U = \frac{1}{2} * k * \Delta x^{2} (2)[/tex]
where k is the spring constant = 60.0 N/m, and Δx is the distance from
the equilibrium position.
Replacing Ui, Uf and Kf in (1), we have:[tex]\frac{1}{2} * k *\Delta x_{i} ^{2} =\frac{1}{2} * k *\Delta x_{f} ^{2} +\frac{1}{2} * m *v ^{2} (3)[/tex]
Replacing by the givens, and solving for m, we get:m =1.35 kg
Tornadoes are accompanied by spinning downdrafts and updrafts that form a funnel cloud. True or False
Answer: True
Explanation: I took the quiz and got it right! have a great day.
True, tornadoes are accompanied by spinning downdrafts and updrafts that form a funnel cloud.
What is a Tornado?
A tornado can be defined as a spinning air column, usually violet resulting from a thunderstorm in the cloud and extends to the ground.
These tornadoes are accompanied by spinning downdrafts and updrafts that form a funnel cloud.
The major constituent of tornadoes are:
Air, which are invisibleWater droplets DustDebrisThus, we can conclude that the given statement about tornadoes is true.
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In contact forces, _____.
A.) objects do not touch each other
B.) objects must touch each other
C.) more work is done than in other forces
Answer:
B is the best answer for this
How does Hydroelectric Energy impact the environment? Use in your own words.
Explanation:
ok sooooooooooo Hydropower is fueled by water so it's a clean fuel source, meaning it won't pollute the air like power plants that burn fossil fuels.
During takeoff, an airplane goes from 0 to 42 m/s is 5 s.
How far is it going after 4 s. Calculate answer to one decimal
Answer:
33.6 m
Explanation:
In order to solve the distance of the airplane traveled, we have to write each statement in the question:
1. The distance covered by the plane after 5s: 42 m ( This was calculated by getting the difference of the first and second speed recorded)(42 - 0 = 42)
2. Time taken for the plane to reach this speed: 5s
The question asks for:
Distance of the plane after 4s.
We then solve this by saying:
If 42 m are covered in 5s, how many are covered in 4s? or:
42 m = 5s
x m = 4s
We then cross multiply:
42 × 4 = 168 and 5 × (x) = 5x
After that we divide the "x" side on both sides:
168÷5 and 5x ÷ 5
= 33.6 m = x
Since its already rounded to one decimal place already, it remains unchanged.
A plane starts from rest accelerates to 40 m/s in 10 seconds. How far did the plane travel during this time?
200 m
Explanation:We are given:
Initial velocity of the plane (u) = 0 m/s
Final velocity of the plane (v) = 40 m/s
Time interval (t) = 10 seconds
Displacement of the plane (s) = x m
Solving for x:
Acceleration of the plane
v = u + at [First equation of motion]
40 = 0 + a(10) [replacing known variables]
a = 4 m/s² [dividing both sides by 10]
Displacement of the Plane:
s = ut + 1/2 (at²) [Second equation of motion]
s = (0)(10) + 1/2(4)(10)² [replacing known variables]
s = 200 m
Hence, the Plane covers a distance of 200 m in the given time interval
A horse trots away from its trainer in a straight line, moving away 8m away in 8.0s it then turns abruptly gallops halfway back in 2.0’s what is the magnitude of the horses average velocity for the entire trip
Answer:
v = 0.4 m/s
Explanation:
By definition, the average velocity is the rate of change of the position with respect to time, as follows:[tex]v_{avg} = \frac{x_{f}-x_{o}}{t_{f} -t_{o}} (1)[/tex]
Choosing arbitrarily x₀ = 0 and t₀ = 0, (1) reduces to:[tex]v_{avg} = \frac{x_{f}}{t_{f} }} (2)[/tex]
During the first part of the trip, the horse moves 8m away from its trainer, and during the the second part, gallops halfway back, which means that it finishes 4m away from its trainer.Since total time is 8.0 s + 2.0 s = 10s, replacing xf = 4m and tif = 10,0 s in (2) we get:[tex]v_{avg} =\frac{x_{f}}{t_{f} } = \frac{4.0m}{10s} = 0.4 m/s (3)[/tex]
Big Bubba has a mass of 80 kg. What are his mass and weight on the moon respectively, if the acceleration due to gravity on the moon is 1.67 m/s2?
80 kg, 134 N
120 kg, 134 N
80 kg, 1180 N
120 kg, 704 N
Answer:
A
Explanation:
m = 80 kg
a = 1.67 m/s^2
The mass is the same anywhere in the universe. So Bubba will be 80 kg anywhere. That makes A and C the only possible answers.
F = Weight = m * a
F = 80 * 1.67
F = 134 N
The answer is A
An object moves along the x-axis with its position x given as a function of time t by x(t)= Ht^2 - Ft + G
What is the object's velocity
Answer:
v(t) = 2Ht - F
Explanation:
Since, the position of the object is given in terms of time (t) as follows:
x(t) = Ht² - Ft + G
where,
H, F, G are constants.
Therefore, the velocity of the object can also be found in terms of the time (t), by simply taking the derivative of the given position equation with respect to time. So, the velocity can be found as follows:
(d/dt) x(t) = (d/dt)(Ht² - Ft + G)
v(t) = (d/dt)(Ht²) - (d/dt)(Ft) + (d/dt)(G)
v(t) = H (d/dt)(t²) - F (d/dt)(t) + (d/dt)(G)
v(t) = H(2t) - F(1) + 0
v(t) = 2Ht - F
Please help me out, I need someone helpful enough.
How many sig figs are in 0.00357
How many sig figs are in 0.0009239
How many sig figs are in 0.0037930
How many sig figs are in 0.93938900
Answers:
Question 1: 3 sig figs
Question 2: 4 sig figs
Question 3: 5 sig figs
Question 4: 8 sig figs
The rule for sig figs:
Any number after a zero in a decimal is one sig fig.
Example: 0.00359, it has three sig figs.
Also, remember if there are zeros after a number greater than zero, it is also a sig fig as well.
Hope this helps you!
Answer:
1) 3 sf 2) 3 sf 3) 5 sf 4) 6 sf
Explanation:
00s at the start dont count towards the sig figs and 00s at the end dont either but 00s in the middle do
your welcome :)
You just tested the hypothesis a proposed model for the position of bright fringes produced by two slits. Explain what the model says and what you found in your investigations with the simulation.
Answer:
two-slit interference model was proposed by Young d sin θ = m λ
Explanation:
The two-slit interference model was proposed by Young, it establishes that if a coherent source of light passes through two slits, the shape of the given pattern is a consequence of the relative phase difference between the two rays; mathematically it can be expressed by
d sin θ = m λ
m= 0, 1, 2, 3, ...
for constructive interference, that is, the two rays arrive with a number between wavelengths.
D is the distance between the slits, tea the angle between the two rays, m an integer and m the wavelength used.
In a simulation a pattern of slits of equal intensity and equally spaced is observed.
What is the value of the normal force of the coefficient of kinetic friction friction is 0.22 and kinetic friction force is 40 N
Answer: 1.8x10 sqaured newtons for all plato users
Explanation:
The value of the normal force of reaction is 181.8 N
Friction is defined as the resistance to motion caused by the contact between a surface and the object moving against it.
The normal reaction force is the weight of the body experiencing friction and normally acts vertically downwards.
The frictional force, the coefficient of kinetic friction and the normal force are related by the formula:
coefficient of friction = frictional force / normal reaction
Therefore, normal reaction = frictional force / coefficient of friction
Frictional force = 40 N; coefficient of kinetic friction friction is 0.22
Normal reaction = 40 N/ 0.22 = 181.8 N
Therefore, the value of the normal force of reaction is 181.8 N
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Calculate how long
in years it will take your radiation to reach Earth from Alpha Centauri (research this).
( MY RADIATION IS INFARED )
Alpha Centauri is 4.4 lightyears away. Traveling at 1/10 speed of light it would take you 44 years.
What is the answer to the question ?
0.11m/s
Explanation:
avg. velocity = total displacement/ total time
total displacement = 2.55 - 1.09
= 1.46
total time taken = 12.8s
avg velocity = 1.46/12.8
=0.11
How should the magnetic field lines be drawn for the magnets shown below?
Answer:
Magnetic field lines can be drawn by moving a small compass from point to point around a magnet. At each point, draw a short line in the direction of the compass needle.When opposite poles of two magnets are brought together, the magnetic field lines join together and become denser between the poles.
Explanation:
Calculate the gauge pressure at a depth of 295 m in seawater
Answer:
P = 2893.95 [kPa]
Explanation:
The manometric pressure can be calculated by means of the following equation.
[tex]P=Ro*g*h[/tex]
where:
Ro = density of the water = 1000 [kg/m³]
g = gravity acceleration = 9.81 [m/s²]
h = deep = 295 [m]
Now replacing:
[tex]P = 1000*9.81*295\\P = 2893950 [Pa]\\P = 2893.95 [kPa][/tex]
According to the textbook, which indicator should Andrea use? Hint: Neutral substances have a pH of 7. Acids have a pH that is less than 7, and bases have a pH that is greater than 7. OA, phenol Red OB thymol Blue OC. phenolphthalein D. trinitrobenzoic acid Raclet Submit
Answer:
Thymol blue
Explanation:
Answer: c
Explanation:
An object is allowed to fall freely near the surface of an unknown planet. The object falls 80 meters from rest in 5.0 seconds. The acceleration due to gravity on that planet is
Answer:
a=5 m/s^2
Explanation:
just took a quiz about it and got it right
At its maximum speed, a typical snail moves about 4.0 m in 5.0 min.
What is the average speed of the snail?
Answer:
Explanation:
Given
Distance = 4.0m
Time = 5.0 mins = 300secs
Required
Average speed
Average speed = Distance/Time
Average speed = 4.0/300
Average speed = 0.01333m/secs
Hence the average speed of the snail is 0.01333m/s
Answer as soon as possible
Answer:
the velocity of the acorn
Explanation:
just do in in real life and see
Answer:
it is probably the velocity of the acorn
Glycerin at 30°C has a density of 1,260 kg/m3 and a viscosity of 0.630 Pa s. In a laboratory experiment, some glycerin is forced through a horizontal tube that is 10.0 cm long and 1.00 cm in diameter. The high-pressure end of the tube is held at a gauge pressure of 618 Pa, while the other end is open to the atmosphere. What is the flow rate of the glycerin through the tube?
Answer:
Explanation:
Rate of flow of liquid through a tube can be expressed by the following expression
V = π P r⁴ / 8ηl
P is pressure difference between end of tube = 618 Pa
r , radius of tube = .5 x 10⁻²
η is viscosity of liquid flowing = .63
l is length of tube = .10 m
V = 3.14 x 618 x ( .5 x 10⁻² )⁴ / (8 x .63 x .10 )
= 240.64 x 10⁻⁸ m³ /s
mass = 240.64 x 1260 x 10⁻⁸ kg / s
= 3.03 x 10⁻³ kg /s
= 3.03 gram /s .
Which of the following is an example of a mixture? A. calcium B. water C. carbon dioxide D. the atmosphere
Answer:
D
Explanation:
The atmosphere is made up of constituents not chemically combined unlike the rest of the options...
The atmosphere is made up of O2, N2, etc. and they are not chemically combined, hence the atmosphere is a mixture
what is the advantage of increasing the length of the handles of a wheelbarrow?
A student kicks a soccer ball upward at a 30º angle with an initial speed of 20 m∕s. What expression should the student use to calculate the magnitude of the ball’s initial velocity in the horizontal direction?
Answer:
[tex]\displaystyle x=10\sqrt{3}\ m/s[/tex]
[tex]y=10\ m/s[/tex]
Explanation:
Rectangular coordinates of vectors in 2D
Given a vector with a magnitude v and angle θ with respect to the positive horizontal direction, the x and y components of the vector are given by:
[tex]x=v\cos\theta[/tex]
[tex]y=v\sin\theta[/tex]
The soccer ball is kicked upward at an angle θ = 30° and at a speed v=20 m/s.
The rectangular components of the vector are:
[tex]x=20\cos 30^\circ[/tex]
[tex]\displaystyle x=20\cdot \frac{\sqrt{3}}{2}[/tex]
Operating:
[tex]\mathbf{\displaystyle x=10\sqrt{3}\ m/s}[/tex]
[tex]y=20\sin 30^\circ[/tex]
[tex]\displaystyle y=20\cdot \frac{1}{2}[/tex]
Operating:
[tex]\mathbf{y=10\ m/s}[/tex]