Cecily is inflating her bicycle tyre with the pump below. When she pushes the plunger down, it is doing work against the gas. This means that the plunger is transferring what to the gas particles?

Answer:

3.85s

Explanation:

Given parameters:

Wavelength = 25m

Velocity  = 6.5m/s

Frequency  = 0.26Hz

Unknown:

Period of the wave = ?

Solution:

The period of a wave is the inverse of the frequency of the wave.

    Period  = [tex]\frac{1}{frequency}[/tex]  

  Period = [tex]\frac{1}{0.26}[/tex]   = 3.85s

Answer:

08 and 09 with be 67

Explanation:

i know this because it was the vase major

Answer:

the selected configuration is PARALLEL

Explanation:

There are two ways to connect electrical circuits.

In series in this type of circuit the equipment is connected to the same line, in this case the current of the circuit circulates through all the inputs is the same, but the voltage in each one is a part of the total voltage, this circuit has the problem that if an appliance is disconnected or damages the power and the entire circuit is interrupted

              V_total = ∑ V_i

In a parallel circuit the equipment is connected in two two cables, for which the current is divided in each branch, the voltage in all the branches is the same, this type of circuit has the advantage that if one equipment is damaged or disconnects the others they can continue working

            V_total = V

Therefore, in consequence of the above, the selected configuration is PARALLEL

Answer:

(a) 34.4°

(b) 49.4 N

Explanation:

(a) From the diagram,

Amgle between the x axis can be calculated as,

cosΘ = adjacent/hypoteneous

cosΘ = 72.1/87.4

cosΘ = 0.8249

Θ = cos⁻¹(0.8249)

Θ = 34.4°.

Hence the angle between the x axis is 34.4°

(b) To find the component along the y axis we make use of pythagoras theorem.

a² = b²+c²................... Equation 1

Where a = 87.4 N, b = 72.1 N, c = y.

Substitute  these values into equation 1

87.4² = 72.1² + y²

y² = 87.4²-72.1²

y² = 2440.35

y = √(2440.35)

y = 49.4 N

Answer:

.

Explanation:

F = kx so k = 800/((10-5)/100) = 16000 N/m

W = 1/2 kx^2 = 1/2 * 16000 * .05^2 = 20 J.

(sorry if it's wrong)

Answer:

b. 10 meters

Explanation:

In a single pulley , which is a lever , velocity ratio is one . In other words , velocity of load is equal to velocity of effort . The load shifts by the same distance as the force or effort moves . The only advantage of this pulley is that direction of force is reversed .

Hence to raise  a flag by 10 m , rope would have to move by 10 m .

Answer:

3 maybe since protons=atomic

The correct answer is 5 km/h

Explanation:

The speed at which the duck travels can be found by using the equation that is given (speed= distance/ time). The first step to do this is to replace distance and time using the values given. Here is the process:

speed = distance / time

speed = 10 km / 2 hours

Now, solve this equation

speed = 10 km/ 2 hours

10 / 2 or 10 divided 2 = 5

Finally, use the units, in this case, the correct units are km/h

Answer:

Let Vx = 35 m/s     speed of swimmer across river

     Vy = 22 m/s     speed of river dowstream

V = (Vx^2 + Vy^2)^1/2 = 41.3 m/s      net speed of swimmer

tan theta = Vy / Vx = .629    theta = 32.2 deg

(Theta would be zero if speed of river was zero)\

Answer:

  v = 1.4 m / s

Explanation:

To solve this problem we use the law of conservation of momentum, for this we define a system formed by the two blocks in such a way that the force during the collision have been internal

initial instant. Just before the crash

           p₀ = M v₁ - m v₂

final instant. Right after the crash

          p_f = (M + m) v

the moment is preserved

          p₀ = p_f

          M v₁ - m v₂ = (M + m) v

           v = [tex]\frac{1}{M+m}[/tex]  (M v₁ - mv₂)

let's calculate

           v = [tex]\frac{1}{4+1}[/tex]  (4 2 - 1 1)

           v = 1.4 m / s

in the same direction as the largest block (M)

The approximate speed of block X after the collision is 1.4 m/s.

Given information:

Block X and block Y travel toward each other along a horizontal surface with block X traveling in the positive direction.

Block X has a mass of [tex]m_1=[/tex] 4 kg and a speed of [tex]u_1=[/tex] 2 m/s.

Block Y has a mass of [tex]m_2=[/tex] 1 kg and a speed of [tex]u_2=[/tex] -1 m/s.

The collision between them is perfectly inelastic. So, the final velocity of both the objects will be the same.

The momentum of the system will be conserved. Let v be the final velocity of both the blocks.

The final velocity v can be calculated as,

[tex]m_1u_1+m_2u_2=(m_1+m_2)v\\4\times 2-1\times1=(4+1)v\\5v=7\\v=1.4\rm\;m/s[/tex]

Therefore, the approximate speed of block X after the collision is 1.4 m/s.

For more details about collision, refer to the link:

https://brainly.com/question/12941951

Answer:

Explanation:

For an incline projection made at angle of θ , expression of horizontal range R can be given by the following equation .

R = u² sin 2θ / g

u is initial velocity of throw .

For range R to be maximum , the value of sin 2θ must be maximum . The maximum value of sin of an angle is 1 , so

For maximum R ,

sin2θ = 1 = sin90

2θ = 90 .

θ = 45⁰ .

So for projection made at 45⁰ , horizontal range is maximum .

Answer:

most likely be included in the analysis section of a lab report

Explanation:

Answer:

1.31×10¯⁶ N

Explanation:

From the question given above, the following data were obtained:

Mass of John (M₁) = 81 Kg

Mass of Mike (M₂) = 93 Kg

Distance apart (r) = 0.620 m

Gravitational constant (G) = 6.67×10¯¹¹ Nm²/Kg²

Force (F) =?

The gravitational force between the two students, John and Mike, can be obtained as follow:

F = GM₁M₂ / r²

F = 6.67×10¯¹¹ × 81 × 93 / 0.62²

F = 6.67×10¯¹¹ × 7533 / 0.3844

F = 1.31×10¯⁶ N

Therefore, the gravitational force between the two students, John and Mike, is 1.31×10¯⁶ N

Answer:

Uh, I could be wrong but doesn’t it mean that the wave and particle are reacting together to make light? I think it’s something like that... I hope this helps!

Answer: A forest fire could affect the geosphere by ash and the heat from the fire, but the fire would affect the biosphere by less oxygen in the air and would make it hard for human to breath affecting climate change. Also many homes to wildlife that live in the forest would lose their homes. This would result in lose of money from no hunting and that affect the economy.

Answer:

The models are larger versions of atoms/molecules. It is a visualization so we can understand the super small particles.

Explanation:

Atoms and molecules are very, very, small. They average 100 picometers across.

They definitely cannot be seen with the naked human eye. We can only see them with special microscopes (electron, optical, etc).  that magnify hundreds of thousands of times.

So, we use models of atoms and molecules. It allows us to study, visualize, understand,  and "see" the particles on a much larger scale.

Answer:

The answer is A) all components of health

Explanation:

Got it right on edge

Answer:

7

Explanation:

We are given:

    w(x) = 3x   -   7

     w(x)  = 14

The problem here entails us to solve for x;

To solve for x; equate the two expressions:

          3x  - 7  = 14

           3x  = 14 + 7

           3x  = 21  

             x = 7

So the value of x  = 7

Answer:

112.63km/hr

Explanation:

The given dimension is :

         70mph

We are to convert this to km/hr

         1 mile  = 1.609km

so;

     70mph x 1.609    = 112.63km/hr

So,

  The solution is 112.63km/hr

What will happen to the magnitude of the field energy between them is that

Whenever there is a stored energy in an object at rest, the object will move in the direction that causes the energy stored to decrease, which will be replaced by movement energy.

Therefore, if two magnets with like poles are pointing together, then the energy stored will decrease as they move apart. Hence, as the distance between poles decreases, field energy increases.

Magnetic pole are region at each end of a magnet where the external magnetic field is strongest.

For more information on magnetic poles, visit

https://brainly.com/question/19542022

Answer:

Given:

W=104J

t=8sec

Solve:

P=?

Equation:

P=W/t or Fd/t

P= 104J'8sec

P=13W

Answer:

The solution to this question can be defined as follows:

Explanation:

In point (a):

[tex]v_i= 100 \ mV\\\\ i_I = 100 \mu \ A\\\\ v_O = 10 \ V\\\\ R_L = 100 \ \Omega \\\\i_L = \frac{V_0}{R_L} = \frac{10}{100} = 100 \ MA \\\\A_v = \frac{V_0}{V_i} = \frac{10}{100 \times 10^{-3}} =100 \\\\A_v(db) = 20 \lag (100) =40 \ db \\\\ A_i= \frac{i_L}{i_i} = \frac{100 \times 10^{-3}}{100 \times 10^{-6}} =1000 \\\\A_i(db) = 20 \lag (100) =60 \ db \\\\[/tex]

[tex]A_p= \frac{P_0}{p_i} =\frac{v_0 i_L}{v_i i_i} = \frac{ 10(100 \times 10^{-3})}{100 \times 10^{-6} \times 100 \times 10^{-3}} =100000\\\\ A_p(db) =10 \log (100000) =50 \ db \\\\[/tex]

In point (b):

[tex]v_i = 10 \mu V\\\\ i_i = 100 \ nA \\\\ v_O =1 \ V \\\\ R_L= 10 \ k \Omega \\\\i_0 = \frac{V_0}{R_L} = \frac{1}{10 \ K} = 100 \ \muA \\\\A_v = \frac{V_0}{V_i} = \frac{10}{10 \times 10^{-6}} =100000 \\\\A_v(db) = 20 \lag (100000) =100 \ db \\\\ A_i= \frac{i_0}{i_i} = \frac{100 \times 10^{-6}}{100 \times 10^{-9}} =1000 \\\\A_i(db) = 20 \lag (1000) =60 \ db \\\\[/tex]

[tex]A_p= \frac{P_0}{p_i} =\frac{v_0 i_0}{v_i i_i} = \frac{ 1 \times 100 \times 10^{-6})}{10 \times 10^{-6} \times 100 \times 10^{-9}} =100000000\\\\A_p(db) =10 \log (100000000) =80 \ db \\\\[/tex]

In point (C):

[tex]v_i =1\ V\\\\ i_I = 1 \ mA\\\\ v_O =5\ V \\\\ R_L = 10 \ \Omega \\\\i_0 = \frac{V_0}{R_L} = \frac{5}{10 } = 0.5 \ A \\\\A_v = \frac{V_0}{V_i} = \frac{5}{1} =5 \\\\A_v(db) = 20 \log 5 =13.97 \ db = 14 \db \\\\ A_i= \frac{i_0}{i_i} = \frac{0.5}{1\times 10^{-3}} =500 \\\\A_i(db) = 20 \log (500) =53.97 \ db = 54 \db \\\\[/tex]

[tex]A_p= \frac{P_0}{p_i} =\frac{v_0 i_0}{v_i i_i} = \frac{ 5 \times 0.5 }{1 \times 1 \times 10^{-3}} =2500\\\\A_p(db) =10 \log (2500) = 33.97 \ db = 34 \db\\\\[/tex]

Answer:

a) v = 1.01 m/s

b) a = 5.6 m/s²

Explanation:

a)

       [tex]\tau = I * \alpha (1)[/tex]

       [tex]\alpha = \frac{2*F}{m*r} = \frac{2*34.5N}{35.2kg*0.2m} = 9.8 rad/s2 (4)[/tex]

        [tex]\omega_{f}^{2} - \omega_{o}^{2} = 2*\Delta \theta * \alpha (5)[/tex]

       [tex]0.2 rev*\frac{2*\pi rad}{1 rev} = 1.3 rad (6)[/tex]

       [tex]\omega_{f} = \sqrt{2*\alpha *\Delta\theta} = \sqrt{2*1.3rad*9.8rad/s2} = 5.1 rad/sec (7)[/tex]

        [tex]v = \omega * r (8)[/tex]

       [tex]v= 5.1 rad/sec* 0.2 m = 1.01 m/s (9)[/tex]

b)    

       [tex]a_{t} = \alpha * r (9)[/tex]

       [tex]a_{t} = 9.8 rad/s2 * 0.200 m = 1.96 m/s2 (10)[/tex]

       [tex]a_{c} = \omega^{2} * r (11)[/tex]

       [tex]a_{c} = \omega^{2} * r = (5.1 rad/sec)^{2} * 0.200 m = 5.2 m/s2 (12)[/tex]

       [tex]a = \sqrt{a_{t} ^{2} + a_{c} ^{2} } = \sqrt{(1.96m/s2)^{2} +(5.2m/s2)^{2} } = 5.6 m/s2 (13)[/tex]

Answer:

14.6m/s

Explanation:

Given parameters:

Mass of the student  = 62kg

Initial velocity  = 0m/s

Height of slide = 10.6m

g  = 10m/s²

Unknown:

Speed at the bottom of the slide = ?

Solution:

The speed at the bottom of the slide is the final velocity;

             v ² = u²  + 2gh

v is the final velocity

u is the initial velocity

g is the acceleration due to gravity

h is the height

             v² = 0²  +  2x 10 x 10.6

             v²  = 212

              v  =  14.6m/s

Answer:

I think you are trying to ask 'what happens to the average speed (of humans or animals.) if the distance decreased and time stayed the same (the time such as what hour it is or what second?)' If that is the case then the average speed will be more since the distance decreased. And the time staying the same might affect it I am not fully sure so I will not say anything about that. I hope this helps!