describe and justify the methods you used to solve the quadratic equations in parts a and B

I also submitted two pictures of questions, A and B

The yearly appreciation of the value of Mike's coin collection over the 5-year period is $510 per year.

The given problem involves finding the yearly appreciation of value of Mike's coin collection over a period of 5 years, based on the values of the collection in 2000 and 2005.

To calculate the yearly appreciation of the value of the collection, we need to first find the total increase in value over the 5-year period. This can be calculated by subtracting the initial value of the collection in 2000 from its final value in 2005:

Total increase in value = 7675 - 5125 = 2550

Next, we can calculate the average annual increase in value by dividing the total increase by the number of years:

Average annual increase = Total increase in value / Number of years

Average annual increase = 2550 / 5 = 510

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The answer is (a) 0.50.

To find the percent of observations that fall between 1 and 4, we need to find the area under the curve between 1 and 4 and divide by the total area under the curve.

The total area under the curve is equal to 1, since this is a probability density function.

The area under the curve between 1 and 4 can be found by calculating the integral of the density function from x = 1 to x = 4:

∫1^4 (1/6) dx = (1/6)(4-1) = 1/2

So the area between 1 and 4 is 1/2, and the percent of observations that fall in this range is:

(1/2) * 100% = 50%

Therefore, the answer is (a) 0.50.

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a) The probability that daily sales will fall between 2,500 and 3,000 gallons is 0.2.

b) The probability that the service station will sell at least 4,000 gallons is 0.3.

c) The probability that the station will sell exactly 2,500 gallons is 0.1.

Gasoline sold daily is uniformly distributed between 2,000 and 5,000 gallons.

a) To find the probability that daily sales will fall between 2,500 and 3,000 gallons, we need to find the area under the uniform distribution curve between 2,500 and 3,000.

Since the distribution is uniform, the probability density function (PDF) is a constant:

f(x) = 1 / (5000 - 2000) = 1 / 3000, for 2000 <= x <= 5000.

The probability of the daily sales being between 2,500 and 3,000 gallons is equal to the area under the PDF curve between 2,500 and 3,000:

Therefore, the probability that daily sales will fall between 2,500 and 3,000 gallons is 0.1667 or 16.67%.

b) To find the probability that the service station will sell at least 4,000 gallons,

we need to find the area under the uniform distribution curve from 4,000 to 5,000 gallons:

Therefore, the probability that the service station will sell at least 4,000 gallons is 0.3333 or 33.33%.

c) To find the probability that the station will sell exactly 2,500 gallons, we need to find the area under the uniform distribution curve at 2,500 gallons:

P(X = 2500) = 0 (since the probability of a single point is zero for a continuous distribution)

Therefore, the probability that the station will sell exactly 2,500 gallons is zero.

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The difference between the area of box and the pizza is 21.46 square inches .

First find the area of the square box to be :

= Length x Width

= 10 x 10

= 100 square inches

Then, find the area of the pizza inside the pizza box to be :

= π x radius x radius

= π x 5 x 5

= 78. 54 square inches

The difference between the areas of the box and pizza is :

=  100 - 78.54 = 21.46 square inches

In conclusion, the difference would be 21.46 square inches.

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The possible rational zeros of the polynomial are of the form:

±1, ±3, ±7, ±21, ±1/3, ±7/3.

The Rational Root Theorem proclaims that if any polynomial is composed of integer coefficients, then its potential rational zeros will have a numerator which is a divisor of the constant term and a denominator that can be factored into the leading coefficient.

Considering the case at hand, with the leading coefficient as 3 and the constant term being -21, the reasonable zeros conceived are in this format:

±1, ±3, ±7, ±21, ± 1/3, ± 7/3.

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The chances of winning a rare item at least once in 20 attempts is approximately 33.3%.

If you have a 2% chance of winning a rare item, and you want to know the chances after being multiplied by 20

To calculate the probability of winning the rare item at least once in 20 attempts, you can use the complement probability method.

First, find the probability of not winning the item in a single attempt, which is 1 - 0.02 = 0.98.

Then, find the probability of not winning the item in all 20 attempts by multiplying the probability of not winning in a single attempt (0.98) by itself 20 times, which is[tex]0.98^20.[/tex]

Finally, subtract that result from 1 to find the probability of winning at least once in the 20 attempts.

Calculate the probability of not winning in a single attempt.

1 - 0.02 = 0.98

Calculate the probability of not winning in all 20 attempts.

[tex]0.98^20.[/tex] ≈ 0.667

Calculate the probability of winning at least once in 20 attempts.

1 - 0.667 ≈ 0.333

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The solutions of the equation sec² x - 4 = 0 are x = π/3 + 2kπ, 2π/3 + 2kπ, 4π/3 + 2kπ, 5π/3 + 2kπ. Therefore, option d. is correct.

We start by solving for x in the equation sec² x - 4 = 0:

sec² x - 4 = 0
sec² x = 4
sec x = ±2

Recall that sec x = 1/cos x, so we can rewrite the equation as:

1/cos² x = 4
cos² x = 1/4
cos x = ±1/2

Now we need to find all values of x that satisfy cos x = ±1/2. These values are:

x = π/3 + 2kπ or x = 5π/3 + 2kπ (for cos x = 1/2)
x = 2π/3 + 2kπ or x = 4π/3 + 2kπ (for cos x = -1/2)

Combining these solutions, we get:
x = π/3 + 2kπ, 2π/3 + 2kπ, 4π/3 + 2kπ, 5π/3 + 2kπ

Therefore, the correct answer is d. pi/3 + 2k pi, 2pi/3 + 2k pi, 4pi/3 + 2k pi, 5pi/3 + 2k pi.

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The derivative of u(t) x v(t) is (0, -t cos(9t) + 72 sin(9t), 81 cos(9t) - 9t sin(9t)).

The formula 5 of the theorem states:

d/dt (u(t) x v(t)) = (d/dt u(t)) x v(t) + u(t) x (d/dt v(t))

where x denotes the cross product.

First, we need to find the derivatives of u(t) and v(t):

d/dt u(t) = (9 cos(9t), -9 sin(9t), 1)

d/dt v(t) = (1, -9 sin(9t), 9 cos(9t))

Now we can substitute into the formula:

d/dt (u(t) x v(t)) = (9 cos(9t), -9 sin(9t), 1) x (t, cos(9t), sin(9t)) + (sin(9t), cos(9t), t) x (1, -9 sin(9t), 9 cos(9t))

Expanding the cross products, we get:

d/dt (u(t) x v(t)) = (-9 sin(9t), -9t cos(9t), 81 cos(9t)) + (9 cos(9t), -t sin(9t), -9 sin(9t))

Simplifying, we get:

d/dt (u(t) x v(t)) = (0, -t cos(9t) + 72 sin(9t), 81 cos(9t) - 9t sin(9t))

Therefore, the derivative of u(t) x v(t) is (0, -t cos(9t) + 72 sin(9t), 81 cos(9t) - 9t sin(9t)).

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The area of the triangle from the vertices of the triangle is B. 32 square units

From the question, we have the following parameters that can be used in our computation:

The vertices of a triangle are

L(2, 2), M(6, -2), N(2, -6)

The area of the triangle is calculated using

Area = 1/2 * |Lx * (My - Ny) + Mx * (Lx - Ny) + Nx * (Lx - My)|

Substitute the known values in the above equation, so, we have the following representation

Area = 1/2 * |2 * (-2 + 6) + 6 * (2 + 6) + 2 * (2 + 2)|

Evaluate

Area = 32

Hence, the area is B. 32 square units

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a) The first negative term of the sequence is given as follows: -1.

b) -30 is not a term on the sequence, as it has a difference of 29 from -1, and 29 is not divisible from the common difference of -4.

An arithmetic sequence is a sequence of values in which the difference between consecutive terms is constant and is called common difference d.

The common difference for this problem is defined as follows:

d = 27 - 31

d = -4.

Hence the next terms on the sequence are given as follows:

15, 11, 7, 3, -1.

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The probability of getting a sum of 7 is 6/36, which simplifies to 1/6 or approximately 16.67%.

Here's a step-by-step explanation using the terms die, sum, spots, and drawing:

1. Die: A standard die has 6 faces with spots numbered 1 to 6.
2. Rolling the die 2 times: You roll the die once, record the number of spots, then roll it again.
3. Sum of the spots: Add the number of spots from the first roll to the number of spots from the second roll.
4. Drawing: A drawing can be a table or a chart to represent the possible outcomes and their corresponding sums.

To visualize this, you can create a 6x6 drawing (table) with rows and columns representing the spots on each roll:

```
  1  2  3  4  5  6
1  2  3  4  5  6  7
2  3  4  5  6  7  8
3  4  5  6  7  8  9
4  5  6  7  8  9 10
5  6  7  8  9 10 11
6  7  8  9 10 11 12
```

This drawing shows all possible sums (from 2 to 12) when rolling a die two times. To find the probability of a specific sum, count the number of times that sum appears in the table, and divide it by the total number of outcomes (6 x 6 = 36).

For example, the probability of getting a sum of 7 is 6/36, which simplifies to 1/6 or approximately 16.67%.

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a. The total number of possible passwords is 45,697,014,176.

b. The total number of possible passwords is 44,146,368,000

(a) If digits and letters can be repeated, then there are 10 possible choices for each of the 3 digits as well as 26 possible choices for each of the 4 letter. Therefore, the total number of possible passwords is:

10^3 * 26^4 = 45,697,014,176

(b) If digits and letters cannot be repeated, then there are 10 choices for the first digit, 9 choices for the second digit (since one digit has already been used), 8. Therefore, the total number of possible passwords is:

10 * 9 * 8 * 26 * 25 * 24 * 23 = 44,146,368,000

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a. The total number of possible passwords is 45,697,014,176.

b. The total number of possible passwords is 44,146,368,000

(a) If digits and letters can be repeated, then there are 10 possible choices for each of the 3 digits as well as 26 possible choices for each of the 4 letter. Therefore, the total number of possible passwords is:

10^3 * 26^4 = 45,697,014,176

(b) If digits and letters cannot be repeated, then there are 10 choices for the first digit, 9 choices for the second digit (since one digit has already been used), 8. Therefore, the total number of possible passwords is:

10 * 9 * 8 * 26 * 25 * 24 * 23 = 44,146,368,000

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The general term formula for the given sequence is an = (2n + 1)(n²), where n represents the position of the term in the sequence.

Let's analyze the given sequence:

a1 = 3 × 16 = 48

a2 = 5 × 25 = 125

a3 = 7 × 36 = 252

a4 = 9 × 49 = 441

We can observe that each term in the sequence is obtained by multiplying (2n + 1) with n², where n is the position of the term in the sequence. This pattern continues for all the terms in the sequence.

So, the general term formula for the given sequence is an = (2n + 1)(n²), where n represents the position of the term in the sequence.

Therefore, the formula for the general term of the sequence is an = (2n + 1)(n²).

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To determine where g has a local maximum, we need to find the critical points of g'(x) and analyze the sign changes around those points.

Here's a step-by-step explanation:
1. Identify the critical points of g'(x) by setting it equal to 0:
g'(x) = x(x - 5)(x + 1)^4 = 0
The critical points are x = -1, x = 0, and x = 5.

2. Determine the sign of g'(x) around the critical points:
For x < -1, g'(x) > 0 (since there are three negative factors)
For -1 < x < 0, g'(x) > 0 (since there are two negative factors)
For 0 < x < 5, g'(x) < 0 (since there is one negative factor)
For x > 5, g'(x) > 0 (since all factors are positive)

3. Analyze the sign changes and apply the First Derivative Test:
- At x = -1, there is no sign change, so it is not a local maximum.
- At x = 0, g'(x) changes from positive to negative, indicating a local maximum.
- At x = 5, there is no sign change, so it is not a local maximum.

So, g has a local maximum at x = 0 only. The correct answer is (c).

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Answer:.40 or .4 would be the correct answer

Answer:

0.4

Step-by-step explanation:

40% can be written as 0.4. Recall that to get a decimal to a percent or vice versa, you can move the decimal place 2 places to the right or left to get the desired outcome. In this case, the decimal needs to move 2 places to the left leaving you with the decimal 0.4 or 4 parts out of 10 (40 parts out of 100= 40%)

Step-by-step explanation:

Let's represent the cost of one peach as "x" and the cost of one nectarine as "y". We can set up a system of equations using the given information:

4x + 12y = 2.28

2x + 14y = 2.10

We can write this system in matrix form as AX = B, where

A = |4 12|

|2 14|

X = |x|

|y|

B = |2.28|

|2.10|

To solve for X, we can use the formula X = A^(-1)B, where A^(-1) is the inverse of matrix A.

First, we need to find the inverse of matrix A:

|4 12| |7/30 -2/15|

|2 14| = |-1/30 2/15|

Now we can use the formula X = A^(-1)B:

|x| |7/30 -2/15||2.28| |0.24|

|y| = |-1/30 2/15||2.10| = |0.12|

Therefore, the cost for a peach is $0.24 (rounded to two decimal places) and the cost for a nectarine is $0.12 (rounded to two decimal places).

The expected gestation period of this species with a 17-year life expectancy is approximately 430.2 days, rounded to one decimal place as needed.

A certain mammal has a life expectancy of about 17 years. To estimate the expected gestation period of this species, we can use the scatterplot provided, which shows Gestation Period (in days) vs. Life Expectancy (in years) for 18 species of mammals.

To determine if there is any evidence that an animal's gestation period is related to the animal's lifespan, we can look at the R-squared value provided, which is 86.5%. This indicates a strong positive correlation between gestation period and life expectancy.

To estimate the gestation period for the species with a 17-year life expectancy, we can use the provided linear regression equation:

Gestation = Constant + Coefficient * Life Expectancy

The given constant is 90.1808 and the coefficient is 20.

Gestation = 90.1808 + (20 * 17)

Gestation = 90.1808 + 340

Gestation ≈ 430.2 days

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the set of points at which the function G(x, y) = ln(1+x−y) is continuous is the set of all (x, y) such that y < x+1.

To determine the set of points at which the function G(x, y) = ln(1+x−y) is continuous, we need to check for continuity in both x and y directions.

First, we consider the x-direction. The function ln(1+x−y) is continuous for all x and y such that 1+x−y > 0, i.e., x−y > −1. Therefore, the set of points at which the function is continuous in the x-direction is the set of all (x, y) such that x−y > −1.

Next, we consider the y-direction. The function ln(1+x−y) is continuous for all x and y such that 1+x−y > 0, i.e., x > y−1. Therefore, the set of points at which the function is continuous in the y-direction is the set of all (x, y) such that x > y−1.

To determine the overall set of points at which the function is continuous, we need to find the intersection of the sets of points where the function is continuous in the x and y directions.

The set of all (x, y) such that x−y > −1 is equivalent to the set of all (x, y) such that y < x+1.

The set of all (x, y) such that x > y−1 is equivalent to the set of all (x, y) such that y < x+1.

Therefore, the set of points at which the function G(x, y) = ln(1+x−y) is continuous is the set of all (x, y) such that y < x+1.

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The missing values of the polynomial are listed as below

The Polynomial x² - 8x + 15 is factored to (x - 3)(x - 5)

comparing with (ax + b)(cx + d)

a = 1, b  = -3, c = 1 d = -5.

the Polynomial 2x² - 24x is factored to 2x(ax + b)(cx + d)

2x² - 24x = 2x(x + 0)(2x - 6) = 2x(x)(2x - 6)

comparing with 2x(ax + b)(cx + d)

a = 1, b  = 0, c = 2 d = -6.

2x² - 24x = 2x(x)(2x - 6)

the Polynomial 6x² + 14x + 4 is factored to (2x + 2) (3x + 2)

comparing with  (ax + b)(cx + d)

a = 2, b = 2, c = 3, and d = 2.

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The missing values of the polynomial are listed as below

The Polynomial x² - 8x + 15 is factored to (x - 3)(x - 5)

comparing with (ax + b)(cx + d)

a = 1, b  = -3, c = 1 d = -5.

the Polynomial 2x² - 24x is factored to 2x(ax + b)(cx + d)

2x² - 24x = 2x(x + 0)(2x - 6) = 2x(x)(2x - 6)

comparing with 2x(ax + b)(cx + d)

a = 1, b  = 0, c = 2 d = -6.

2x² - 24x = 2x(x)(2x - 6)

the Polynomial 6x² + 14x + 4 is factored to (2x + 2) (3x + 2)

comparing with  (ax + b)(cx + d)

a = 2, b = 2, c = 3, and d = 2.

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The two solutions for the system of equations y=2x+4 and y=10(1.07)ˣ are (6.02, 16.04) and (-3.07, 0.289).

What is meant by solutions?

Solutions refer to the values that satisfy an equation or inequality. Equations are mathematical expressions that represent the relationship between variables or quantities and are used to solve problems or describe mathematical concepts.

What is meant by equations?

An equation is a statement that shows the equality between two mathematical expressions. It consists of variables, constants, and mathematical operators and is used to represent relationships between different quantities or variables. Equations are fundamental in mathematical modelling and problem-solving.

According to the given information

To find the solutions for the system of equations y=2x+4 and y=10(1.07)ˣ, we can set them equal to each other:

2x + 4 = 10(1.07)ˣ

We can then solve for x:

2x = 10(1.07)ˣ - 4

x = log(10(1.07)ˣ - 4)/log(2)

Using a calculator, we find that x ≈ 6.02 or x ≈ -3.07.

To find the corresponding values of y, we can substitute these values of x into either equation:

For x ≈ 6.02, y = 2(6.02) + 4 ≈ 16.04

So, one solution is (6.02, 16.04).

For x ≈ -3.07, y  ≈ 0.289

So, another solution is (-3.07, 0.289).

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a= 1

h= 1

k= 0

The graph moves to the right 1 unit.

The approximate probability of obtaining an a-to-(1-a) split in the partition using the median-of-three method in Quicksort is about 0.6667 or 66.67%.

We'll first need to understand the median-of-three method in Quicksort and then approximate the probability of obtaining an a-to-(1-a) split in the partition.

1. Median-of-three method: This method involves selecting three random elements from the array, finding their median, and using it as the pivot. This helps improve the efficiency of Quicksort by reducing the chances of choosing a bad pivot.

2. Calculate the probability: Let's assume that a is a real number in the range 0 < a < 1. We want to find the probability of obtaining an a-to-(1-a) split in the partition. To get an a-to-(1-a) split, the pivot must be in the a-th percentile (or 1-a percentile, which is equivalent) of the sorted list.

Since there are three randomly selected elements, there are a total of 3! = 6 permutations for the order of these elements. The cases that result in an a-to-(1-a) split are when the median of the three elements is in the a-th percentile. There are two possible cases:

a) The first element is in the a-th percentile and the other two are larger.

b) The first element is larger, and the second element is in the a-th percentile.

Each of these two cases has 2! = 2 permutations (as the other two elements can be switched), giving us a total of 4 favorable permutations.

Now we can calculate the probability:

Probability = (Number of favorable permutations) / (Total permutations)

= 4/6 = 2/3 ≈ 0.6667

So, the approximate probability of obtaining an a-to-(1-a) split in the partition using the median-of-three method in Quicksort is about 0.6667 or 66.67%.

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The series Σ^[infinity]_n=1 (3 / (4^n + 5)) converges.

To determine whether the series converges or diverges, consider the series Σ^[infinity]_n=1 (3 / (4^n + 5)).

Step 1: Apply the Comparison Test. We will compare our given series with a known convergent or divergent series. In this case, let's compare it to the geometric series Σ^[infinity]_n=1 (3 / 4^n).

Step 2: Since 4^n + 5 > 4^n, we have (3 / (4^n + 5)) < (3 / 4^n). Now we need to determine if the geometric series converges.

Step 3: Check the geometric series. A geometric series converges if the absolute value of the common ratio is less than 1. The common ratio in our case is 1/4 (since each term is multiplied by 1/4 to get the next term). The absolute value of the common ratio |1/4| = 1/4, which is less than 1.

Step 4: Conclude the convergence of the geometric series. Since the geometric series Σ^[infinity]_n=1 (3 / 4^n) converges, and our given series is term-by-term smaller, it also converges by the Comparison Test.

Thus, the series Σ^[infinity]_n=1 (3 / (4^n + 5)) converges.

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To the left of z₁ = -1.74 and to the right of z₂ = 1.74, the total area under the standard normal curve is roughly 0.0818.

The standard normal distribution table calculates the probability that a regularly distributed random variable Z, with a mean of 0 and a difference of 1, is not exactly or equal to z. A persistent probability distribution is the normal distribution. It is also known as the Gaussian distribution. It only applies to positive z estimations.

The total area under the standard normal curve to the left of z₁ and to the right of z₂ is the sum of the area to the left of z₁ and the area to the right of z₂.

Using a standard normal distribution table or calculator, we can find:

Therefore, the total area under the standard normal curve to the left of z₁ and to the right of z₂ is:

0.0409 + 0.0409 = 0.0818

Rounding this answer to four decimal places, we get:

0.0818

Therefore, the total area under the standard normal curve to the left of z₁ = -1.74 and to the right of z₂ = 1.74 is approximately 0.0818.

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The bias of mu1 is 0, the variance of mu1 is 1/2, and the mean squared error of mu1 is 1/2.

We need to find the bias, variance, and mean squared error of mu1, given that x1 and x2 are independent with an unknown mean (mu) and a known variance (sigma^2 = 1), and mu1 = (x1 + x2)/2.

Step 1: Compute the expected value of mu1.
E(mu1) = E((x1 + x2)/2) = (E(x1) + E(x2))/2 = (mu + mu)/2 = mu

Step 2: Calculate the bias of mu1.
Bias (mu1) = E (mu1) - mu = mu - mu = 0

Step 3: Calculate the variance of mu1.
Var(mu1) = Var((x1 + x2)/2) = (1/4) * (Var(x1) + Var(x2)) = (1/4) * (1 + 1) = 1/2

Step 4: Calculate the mean squared error of mu1.
MSE(mu1) = Bias(mu1)^2 + Var(mu1) = 0^2 + 1/2 = 1/2

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The statement that alone is enough to prove that a parallelogram is a rectangle is Opposite sides of the quadrilateral must be congruent and one angle must be 90 degrees

Option A is the correct answer.

We have,

A rectangle is a type of parallelogram with four right angles.

So, if a quadrilateral has opposite sides that are congruent and one angle is 90 degrees, then it must be a parallelogram with four right angles, i.e., a rectangle.

Statement 2 describes the properties of a rhombus, which is a special type of parallelogram with all sides congruent, not a rectangle.

Statement 3 describes the properties of a parallelogram, but it does not guarantee that the angles are right angles.

Therefore, it does not prove that the parallelogram is a rectangle.

Statement 4 describes the properties of a square, which is a special type of rectangle with all sides congruent, not a general rectangle.

Thus,

Opposite sides of the quadrilateral must be congruent and one angle must be 90 degrees is enough to prove that a parallelogram is a rectangle.

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(a) For 10 kWh, we use the first function because 0 ≤ 10. So, C(10) = 7.52 + 0.1079(10) = $8.60.
(b) For 27 kWh, we use the second function because 10 < 27 ≤ 750. So, C(27) = 19.22 + 0.1079(27) = $22.45.
(c) For 9000 kWh, we use the fourth function because 9000 > 1500. So, C(9000) = 131.345 + 0.0321(9000) = $425.25.

In mathematics, a function from the set X to the set Y assigns each element of X to one of Y. The set X is called the function of the function, and the set Y is called the common area of ​​the function.

A function is basically a measure of how one variable depends on another variable. For example, the earth's position is a function of time. Historically, the concept was explained using infinitesimal calculus in the late 17th century, and until the 19th century, functions were determined differently (i.e. they had a higher regularity).

(a) For 10 kWh usage, we use the first formula since 0 ≤ x ≤ 10:
C(10) = 7.52 + 0.1079(10) = 7.52 + 1.079 = $8.60 (rounded to the nearest cent)

(b) For 27 kWh usage, we use the second formula since 10 < x ≤ 750:
C(27) = 19.22 + 0.1079(27) = 19.22 + 2.9133 = $22.13 (rounded to the nearest cent)

(c) For 9000 kWh usage, we use the fourth formula since x > 1500:
C(9000) = 131.345 + 0.0321(9000) = 131.345 + 288.9 = $420.24 (rounded to the nearest cent)

So, the monthly charges for the given usages are:
(a) 10 kWh: $8.60
(b) 27 kWh: $22.13
(c) 9000 kWh: $420.24

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The distribution of (M,N) is a bivariate Poisson distribution with parameters λ_1 = 9 (rate of local calls) and λ_2 = 3 (rate of long distance calls) since the rates of the two processes are independent Poisson processes.  and the number of people on line are 60.

The joint probability mass function of (M,N) is given by:

[tex]P(M=m, N=n) = e^{-(\lambda_1 +\lambda_2) (lambda_1^m/ m!) (\lambda_2^n/ n!)[/tex]

The number of people on the line is the expected value of the total number of minutes of all calls, which can be calculated as E[10M + 5N] = 10E[M] + 5E[N].

Since M and N are independent Poisson random variables, we have E[M] = λ_1/(1-p_1) and E[N] = λ_2/(1-p_2), where p_1 and p_2 are the probabilities of a call being local or long distance, respectively.

Substituting in the given values, we get:

E[10M + 5N] = 10(9/3) + 5(3/1) = 45 + 15 = 60

Therefore, the expected number of people on the line is 60.

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For 2 sec the snowboarder in the air.

We have,

The height (in feet) of a snowboarder above the bottom of the half-pipe can be modeled by h=-16t²+24t + 16.4

So, 3.2 = -16t² + 24t + 16.4

-16t² + 24t + 12.4 = 0

Now, solving the above quadratic equation we get

t = -0.40650, 1.90650

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Answer: 720 miles

Step-by-step explanation:

180/3= 60 which means she drove 60 miles in 1 hour. so 60 x 12 = 720 miles