From 1997 - 2001 the number n (in millions) of black-and-white TV S sold in the U.S. Can be modeled by n = 26.8 * (0.85) ^ t where t is the number of years since 1997.

Answers

Answer 1

Question

a) What is the decay factor?

b) What is the percent decrease?

c) Estimate the number of black and white TV's  sold in 1999.

Answer:

a. Decay factor = 0.85

b. Percent decrease = 15%

c. 19.363  million TVs were sold

Step-by-step explanation:

Given

[tex]n = 26.8(0.85)^t[/tex]

Solving (a): The decay factor

An exponential function has the form

[tex]y = ab^x[/tex]

Where b is:

[tex]b = decay\ factor\ or\ growth\ factor[/tex]

By comparison:

[tex]b = 0.85[/tex]

Solving (b): Percentage decrease:

Percentage decrease P is calculated as follows:

[tex]P = 1 - b[/tex]

Substitute 0.85 for b

[tex]P = 1 - 0.85[/tex]

[tex]P = 0.15[/tex]

Convert to percentage

[tex]P = 0.15*100\%[/tex]

[tex]P = 15\%[/tex]

Solving (c): TVs sold in 1999

First, we need to determine the value of t for 1999

In 1997, t= 0

In 1998, t= 1

In 1999, t= 2

So, we substitute 2 for t in: [tex]n = 26.8(0.85)^t[/tex]

[tex]n = 26.8(0.85)^2[/tex]

[tex]n = 26.8*0.7225[/tex]

[tex]n = 19.363[/tex]


Related Questions

Leo ordered shirts for 12 members of the social work team. He had each person's
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12x3=36

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Answer:

[tex]\Large\boxed{\text{Perpendicular Equation:} \ y = -\frac{2}{7}x + \frac{22}{7}}[/tex]

[tex]\Large\boxed{\text{Parallel Equation:} \ y = \frac{7}{2}x -12}[/tex]

Step-by-step explanation:

In order to find the equations that are parallel/perpendicular to the line [tex]y = \frac{7}{2}x - 4[/tex], we need to note a couple things about the relationships between lines and their parallel/perpendicular lines.

A) If a line is perpendicular to another, the slopes will be opposite reciprocals (for instance [tex]-2[/tex] and [tex]\frac{1}{2}[/tex] - multiplied, they equal -1.)B) If a line is parallel to another, they will have the exact same slope.

Perpendicular:

We know that the slope of a perpendicular line will be the the opposite reciprocal of the line we're comparing it to.

Since the slope of our base line is [tex]\frac{7}{2}[/tex], we can find the reciprocal, then the opposite of that.

Reciprocal of [tex]\frac{7}{2} = \frac{2}{7}[/tex] Opposite of [tex]\frac{2}{7} = -\frac{2}{7}[/tex]

So the slope of this line will be [tex]-\frac{2}{7}[/tex], making our equation [tex]y = -\frac{2}{7}x+ b[/tex]

However, y-intercepts will not stay the same. In order to find this, we can substitute the point (4, 2) into our equation to solve for b.

[tex]2 = -\frac{2}{7} \cdot 4 + b[/tex] [tex]2 = -\frac{8}{7} + b[/tex] [tex]b = 2+\frac{8}{7}[/tex] [tex]b = 2 \frac{8}{7}[/tex] [tex]b=\frac{22}{7}[/tex]

Now we know the y-intercept of this equation is [tex]\frac{22}{7}[/tex]. We can now finish off our equation of the line by substituting that in to what we already have,  [tex]y = -\frac{2}{7}x+ b[/tex].

[tex]y = -\frac{2}{7}x+ \frac{22}{7}[/tex]

Parallel:

As mentioned earlier, parallel lines will have the exact same slope but not the same y-intercept. Since the slope of our original equation is [tex]\frac{7}{2}[/tex], the slope for this one will also be [tex]\frac{7}{2}[/tex].

So we now know the equation looks something like [tex]y = \frac{7}{2}x + b[/tex].

In order to solve for b, we apply the same logic we did in the perpendicular line and substitute in the point (4, 2) into the equation.

[tex]2 = \frac{7}{2} \cdot 4 + b[/tex] [tex]2 = \frac{28}{2}+b[/tex] [tex]2 = 14+b[/tex] [tex]b = 2-14[/tex] [tex]b =-12[/tex]

Now that we know the slope and the y-intercept, we can finish off our equation as [tex]y = \frac{7}{2}x -12[/tex].

Hope this helped!

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Answers

Answer:

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Answers

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Answers

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Answers

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Answers

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Answers

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