Given that the expression "p dollars for every q items" describes a unit price, which statement must be true? p=1 p=9 q=1 pg= 1​

Answer:

f(4)= -10

If g(x) =2, then x=0

Step-by-step explanation:

Answer:

The input of the function

Step-by-step explanation:

Answer:

Step-by-step explanation:

The above two expressions can be used to find the percentage of mark-up for the phone.

The first expression for instance will give;

[tex]= \frac{100 * (281.20 - 152)}{152}\\\\= \frac{12,920}{152}\\\\= 85[/tex]

= 85%

The second expression will give;

[tex]= (\frac{281.20}{152}-1 ) * 100\\\\= 0.85 * 100\\\\= 85[/tex]

= 85%

Both of them will show that an 85% mark-up has been added to the cost of the phone.

Answer:

2/3 = 8/12

1/6 = 2/12

11/12 = 11/12

Answer:

radical sign of -233

Step-by-step explanation:

Answer:

Step-by-step explanation:

We have to find the value of the expression i^{233}i

233

We know that the below values.

i

2

=−1

i

4

=1

​

Hence, in order to find the value of the given expression, we can first rewrite it in terms of i^4i

4

i^{233}=(i^4)^{58}

233

=(i

4

)

58

⋅i

Now, we know that i^4=1i

4

=1

Hence, we have

i^{233}=(1)^{58}

233

=(1)

58

⋅i

i^{233}=

233

=1⋅i

i^{233}=ii

233

=i

Answer:

First table's unit rate is -1.6

Second table's unit rate is  3.5

Step-by-step explanation:

First table:

[tex]\Delta y/\Delta x =(-16--8)/(10-5)= -8/5[/tex]

and this is constant for any pair of (x, y) values of the table.

So the unit rate is: -8/5 = -1.6

Second table:

[tex]\Delta y/\Delta x =(21-7)/(6-2)=14/4=7/2[/tex]

and the rate is constant for any pair of (x, y) values of the table.

So the unit rate is: 7/2 = 3.5

Answer:

140 ft.

Step-by-step explanation:

first find the area of the rectangle

16 x 8 = 128

Area: 128

then find the area of the triangle

Base: 4

Height: 6

Area: 12

Then all u need to do is add

12 + 128 = 140

Answer:

237ft²

63.5ft

Step-by-step explanation:

Given parameters:

  Length  = 19[tex]\frac{3}{4}[/tex] ft

   Width  = 12ft

Unknown:

Area of rectangle  = ?

Perimeter of rectangle  = ?

Solution:

Area of rectangle  = length x width

                              = 19[tex]\frac{3}{4}[/tex] x 12

                               = [tex]\frac{79}{4}[/tex] x 12

                               = 79 x 3

                              = 237ft²

Perimeter of rectangle  = 2(length + width)

                                      = 2 (19.75 + 12 )

                                     = 63.5ft

Answer:

rvefncoqjefadsNofvewnvfeeljjnfvqe

Step-by-step explanation:

fdcopjsfddcaxjefwpojdsjandipewhhqdaspcixpjewfs;odkcnewoasjjncikkjasn;kcjnnsixjfiasxhcjnsdaxo[okckiefihihehabficphbkjckd khksdk a help me

Answer:

lol im confused aswell

Step-by-step explanation:

Answer:

That would be y = 2x.

Answer:

1 rupee=100 paisa

so, 20 paisa:2000 rupees

=>20 paisa:2000×100

=>1:10000.

Answer:

90 minutes

Step-by-step explanation:

Since 15 divided by 2 is 7.5, it takes 7.5 minutes to paint 1 section. 7.5 times 12 is 90, meaning that is takes 90 minutes for her to paint 12 sections.

Answer:a car

Step-by-step explanation:

Answer:

(-4)^3 * y^2

Step-by-step explanation:

hope it helps.

Answer:

X=6 3/4

Step-by-step explanation:

IF X=9-9/4(X=9-2 1/4) THEN X=6 3/4. HOPE THIS HELPS

Area of a complete circle is area = pi x r ^2

Area = 3.14 x 4^2

Area = 3.14 x 16

Area = 50.24 square units.

1/4 of the circle is missing, so multiply the area of the full circle by 3/4:

50.24 x 0.75 = 37.68 cubic units.

Answer:

1+8i

Step-by-step explanation:

Given, complex numbers z = 9 – 2i and zw = 25 + 70i. w = 1 + 8i.

In mathematics, a complex number is an element of a number system that contains the real numbers and a specific element denoted i, called the imaginary unit, and satisfying the equation i² = −1.

= (9 - 2i)(1 + 8i)

= 9 + 72i - 2i -16i^2

= 9 + 70i + 16  (i^2 = -1)

= 25 + 70i

Learn more about complex numbers here

https://brainly.com/question/10251853

#SPJ2

Answer:

3.25

Step-by-step explanation:

I plugged in 5 for x and got 3.25 when I solved

Answer:

adjacent

Step-by-step explanation:

this just means they are next to each other, like they share a ray

Answer:

they are adjacent

Step-by-step explanation:

Adjacent means they are next to each other; and both these angles are right beside each other

Answer:

Step-by-step explanation:

The graph is proportional because

it is in a straight line in the graph.

Hope this helps! <3

Answer:

44 ft/hr

Step-by-step explanation:

First, we convert miles to feet.

6 mi*5280 = 31680 feet

Now we convert a month to hours. For this question, lets say that a month is equal to 30 days.

30*24 hrs = 720 hrs

Now we have this speed -

31680 ft/720 hrs

Now we simplify this to -

44 ft/hr

So in conclusion, the speed of 6 miles per month is equivalent to the speed of 44 feet per hour.

Here,

g (x) = -3x + 1

then ,

g(10) = -3 (10) + 1

= -30 +1

= - 29

Again,

g(-6) = -3 (-6) + 1

= 18 + 1

= 19

Complected *******

Thank me later.

Answer:

Step-by-step explanation:

n = 9c - 80

n = 19

19 = 9c - 80

-9c = -80 - 19

-9c = -99

c = 99 / 9

c = 11

Hope this helps

plz mark as brainliest!!!!!!

Answer:

18 weeks

Step-by-step explanation:im gay

Answer:

2a⁷

Step-by-step explanation:

you have to add 3 to 4

Answer:

[tex]\mathbf{\int \int _R \ 4xy e^{x^2 \ y} \ dA = 2 (e^7 -8)}[/tex]

Step-by-step explanation:

Given that:

[tex]\int \int _R 4xye^{x^2 \ y} \ dA, R = [0,1]\times [0,7][/tex]

The rectangle R = [0,1] × [0,7]

R = { (x,y): x ∈ [0,1] and y ∈ [0,7] }

R = { (x,y): 0 ≤ x ≤ 1 and 0 ≤ x ≤ 7 }

[tex]\int \int _R \ 4xy e^{x^2 \ y} \ dA = \int^{7}_{0}\int^{1}_{0} 4xye^{x^2 \ y} \ dx dy[/tex]

[tex]\int \int _R \ 4xy e^{x^2 \ y} \ dA = \int^{7}_{0} \begin {bmatrix} ye^{yx^2} \dfrac{4}{2y} \end {bmatrix}^1 _ 0 \ dy[/tex]

[tex]\int \int _R \ 4xy e^{x^2 \ y} \ dA = \int^{7}_{0} \begin {bmatrix} ye^{y1^2} \dfrac{4}{2y} - ye^{y0^2} \dfrac{4}{2y} \end {bmatrix}\ dy[/tex]

[tex]\int \int _R \ 4xy e^{x^2 \ y} \ dA = \int^{7}_{0} \dfrac{4}{2}(e^y -1) \ dy[/tex]

[tex]\int \int _R \ 4xy e^{x^2 \ y} \ dA = \dfrac{4}{2}[e^y -1]^7_0 \ dy[/tex]

[tex]\int \int _R \ 4xy e^{x^2 \ y} \ dA = 2 [(e^7 -7)-(e^0 -0)][/tex]

[tex]\int \int _R \ 4xy e^{x^2 \ y} \ dA = 2 [(e^7 -7)-1][/tex]

[tex]\mathbf{\int \int _R \ 4xy e^{x^2 \ y} \ dA = 2 (e^7 -8)}[/tex]