I don't have time to calculate I have to go somewhere. HELP ASAP! What is x+300=500

Answer:

x=+30

Step-by-step explanation:

1200-5(3x+30)=600

We move all terms to the left:

1200-5(3x+30)-(600)=0

We add all the numbers together, and all the variables

-5(3x+30)+600=0

We multiply parentheses

-15x-150+600=0

We add all the numbers together, and all the variables

-15x+450=0

We move all terms containing x to the left, all other terms to the right

-15x=-450

x=-450/-15

x=+30

Answer:

[tex] \boxed{ \bold{ \huge{ \boxed{ \sf{x = 30}}}}}[/tex]

Step-by-step explanation:

[tex] \sf{1200 - 5(3x + 30) = 600}[/tex]

Distribute 5 through the parentheses

[tex] \dashrightarrow{ \sf{1200 - 15x - 150 = 600}}[/tex]

Subtract the numbers: 150 from 1200

[tex] \dashrightarrow{ \sf{ - 15x + 1050 = 600}}[/tex]

Move 1050 to right hand side and change it's sign

[tex] \dashrightarrow{ \sf{ - 15x = 600 - 1050}}[/tex]

Subtract 1050 from 600

[tex] \dashrightarrow{ \sf{ - 15x = 450}}[/tex]

Divide both sides of the equation by -15

[tex] \dashrightarrow{ \sf{ \frac{ - 15x}{ - 15} = \frac{ - 450}{ - 15} }}[/tex]

Calculate

[tex] \dashrightarrow{ \sf{x = 30}}[/tex]

Hope I helped!

Best regards! :D

Answer:

3y-2

Step-by-step explanation:

y+y+y-2

3y-2

The perimeter of the isosceles triangle with base length y - 2 and length of legs y is 3y - 2. legs.

Here,

Base length of triangle is y - 2.

Length of legs of triangle is y.

What is Perimeter of triangle?

Perimeter of triangle is sum of all three sides of a triangle.

Now,

Base length of triangle is y - 2.

Length of legs of triangle is y.

Perimeter = y - 2 + y + y

               = 3y - 2

Hence, The perimeter of the isosceles triangle with base length y - 2 and legs of length y is 3y - 2.

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Answer:

C. .024

Step-by-step explanation:

You multiply 25 by 4 to get 100 and then you multiply 6 by 4 to get twenty four. After that you divide both numbers by one hundred and you get C

Answer:

47.53

Step-by-step explanation:

First you add all of the numbers together.

66.9+5.6+70.1=142.6

Then you divide the sum of numbers by how many number there are.

142.6/3=47.53

Answer:

Step-by-step explanation:

3x^2 - 4x^2 - 6mn + 5mn

-x^2 - mn

Answer:

i believe it's 39

Step-by-step explanation:

29 -39 = -10

Answer:

Step-by-step explanation:

10x - 15 + 4x + 4

14x - 11

Answer:

The surface area of the larger prism is 4 times the surface area of the smaller one.

(which agrees with answer B in your list)

Step-by-step explanation:

Notice that the lateral surface area of prisms always consists of parallelograms, whose areas are given by the product base times height. = B x H

Therefore if the dimensions of the prism double, then the base and height of the parallelograms will double as well, making such individual ares of the lateral faces go from:

B x H  to -->  2 B x 2 H = 4 (B x H)

that is 4 times the original lateral face's area.

with the faces for the top and bottom bases of the prism, something similar happens, so we conclude that the surface area of the larger prism is 4 times the surface area of the smaller one.

Answer:

c

Step-by-step explanation:

edge 2021

Answer:

AB = 4.5

Step-by-step explanation:

Distance between A(-1, 2) and B(1, -2):

[tex] AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} [/tex]

Let,

[tex] A(-1, 2) = (x_1, y_1) [/tex]

[tex] B(1, -2) = (x_2, y_2) [/tex]

[tex] AB = \sqrt{(1 - (-1))^2 + (-2 - 2)^2} [/tex]

[tex] AB = \sqrt{(2)^2 + (-4)^2} [/tex]

[tex] AB = \sqrt{4 + 16} = \sqrt{20} [/tex]

[tex] AB = 4.5 [/tex] (nearest tenth)

Answer:

your pics a little blurry but if i am reading it right

the first one

f(x)=log x+5

w²+7w>293 is the inequality which we use to determine what lengths would make the area of the base of the tree house greater than 293 square Inches

The area of Rectangle is length times of width.

Given that Adam built a tree house with a rectangular base.

The length of the base is 7 inches more than its width.

Length=W+7

W is the width

The area of the base of the tree house greater than 293

We need to find the inequality to represent the area of the base of tree

Area of rectangle=Length×width

293=(w+7)w

293=w²+7w

As area is greater we have

w²+7w>293

Hence, w²+7w>293 is the inequality which we use to determine what lengths would make the area of the base of the tree house greater than 293 square Inches

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Answer:

[tex]\frac{x}{5} + 6y[/tex]

Step-by-step explanation:

Answer:

B) -2

Step-by-step explanation:

[tex]\frac{25-(-15)}{-12-8} =\frac{40}{-20} =-2[/tex]

Answer:

12, 12 and 12 so 36

Step-by-step explanation:

Answer:

Step-by-step explanation:

Answer:

18

Step-by-step explanation:

The integral is the area between f(x) and the x-axis.  Remember that area below the x-axis is negative.

The area between x=0 and x=6 is a trapezoid.

The area between x=6 and x=9 is a rectangle.

The area between x=9 and x=15 is a triangle.

The area between x=15 and x=21 is a triangle.

The area between x=21 and x=27 is a trapezoid.

A = ½ (3+9) (6) + (3)(9) + ½ (6)(9) + ½ (6)(-9) + ½ (-9+-6) (6)

A = 36 + 27 + 27 − 27 − 45

A = 18

Answer:

the answer is 2.16

Step-by-step explanation:

just use a calculator and it will tell you the answer

Answer:

32 degrees is the missing angle

Step-by-step explanation:

I subtracted 40 and 112 from 180.

Answer:

40+112+x=180

x=180-152

=28 degree.

ans is 25

Step-by-step explanation:

12(10-5)-40+(4+1)

=12 of 5 - 40 + 5

= 60 - 40 +5

=60 +5 - 40

=65-40

=25

Answer:

-25

Step-by-step explanation:

We start off by using PEMDAS. 10-5 then 4+1.

12(5)-40+5

we multiply, then add and subtract giving us -25

Answer:

a.  y= e raise to power y

c. y = e^ky

Step-by-step explanation:

The first derivative is obtained by making the exponent the coefficient and decreasing the exponent by 1 . In simple form the first derivative of

x³ would be 2x³-² or 2x².

But when we take the first derivative of  y= e raise to power y

we get y= e raise to power y. This is because the derivative of e raise to power is equal to e raise to power y.

On simplification

y= e^y

Applying ln to both sides

lny= ln (e^y)

lny= 1

Now we can apply chain rule to solve ln of y

lny = 1

1/y y~= 1

y`= y

therefore

derivative of e^y = e^y

The chain rule states that when we have a function having one variable and one exponent then we first take the derivative w.r.t to the exponent and then with respect to the function.

Similarly when we take the first derivative of  y= e raise to power ky

we get y=k multiplied with e raise to power ky. This is because the derivative of e raise to a  constant and power is equal to constant multiplied  with e raise to power y.

On simplification

y= k e^ky

Applying ln to both sides

lny=k ln (e^y)

lny=ln k

Now we can apply chain rule to solve ln of y ( ln of constant would give a constant)

lny = ln k

1/y y~= k

y`=k y

therefore

derivative of e^ky = ke^ky

Answer:

8n=55

Step-by-step explanation:

The product(multiplication) of 8 AND a number(meaning the multiplication of 8 and a number which is said to be n)  is(equal to) 55.

I hope I explained it well enough. lol

Answer:

B - the second answer .... 8n =55

Step-by-step explanation:

Answer:

Here Ratio=1:2:4

total money =$70

Step-by-step explanation:

let the ratio number be 1x,2x and4x

Now,

1x+2x+4x =$70

or, 7x. =$70

or, x. =$70÷7=$10

again,

1x=1×$10=$10,

2x=2×$10=$20 and

4x=4×$10=$40

Answer:

The saying money breeds money means that with money, you have the possibility to create more money. Simple interest is the idea that you have something, and you obtain a percentage of that every designated time period. That being said, simple interest = money breeds money

Answer:

Step-by-step explanation:

If the distance marked on a centimeter scale is from 2.5 to 4.5, then the final destination is 4.5cm and the initial point = 2.5.

Distance between the two points will give us the length of the line segment.

Distance between the two points = final point - initial point

Distance between the two points  = 4.5 - 2.5

Distance between the two points = 2.0 cm

Hence the line segment is 2.0cm long

Answer:

(a) 0.16759

(b)  0.9649

Step-by-step explanation:

Given that:

n = 10 , p = 0.3 and  [tex]\hat p = 0.4[/tex]

[tex]P(|\hat p - p| > 0.2 ) = 1 - P ( |\hat p -p| \leq 0.2)[/tex]

= [tex]1 - P(-0.2 \leq \hat p-p \leq 0.2)[/tex]

= [tex]1 - P \begin {pmatrix} \dfrac{-0.2}{\sqrt{\dfrac{pq}{n}}} \leq \dfrac{\hat p -p}{\sqrt{\dfrac{pq}{n}}} \leq \dfrac{0.2}{\sqrt{\dfrac{pq}{n}}} \end {pmatrix}[/tex]

[tex]=1 - P \begin {pmatrix} \dfrac{-0.2}{\sqrt{\dfrac{(0.3)(1-0.3)}{10}}} \leq Z \leq \dfrac{0.2}{\sqrt{\dfrac{(0.3)(1-0.3)}{10}}} \end {pmatrix}[/tex]

[tex]=1 - P \begin {pmatrix} \dfrac{-0.2}{\sqrt{\dfrac{(0.3)(0.7)}{10}}} \leq Z \leq \dfrac{0.2}{\sqrt{\dfrac{(0.3)(0.7)}{10}}} \end {pmatrix}[/tex]

[tex]=1 - P \begin {pmatrix} \dfrac{-0.2}{\sqrt{0.021}} \leq Z \leq \dfrac{0.2}{\sqrt{0.021}} \end {pmatrix}[/tex]

[tex]=1 - P \begin {pmatrix} -1.380 \leq Z \leq 1.380 \end {pmatrix}[/tex]

= 1 - P( Z ≤ 1.380) - P(-1.380)

= 1 - ( 0.91620 - 0.08379 )

= 1 - 0.83241

= 0.16759

b) when n = 400; p =0.3 , q = 1 - p = 1 - 0.3 = 0.7

[tex]P( |\hat p - p | > 0.001) = 1- P ( |\hat p - p | < 0.001 )[/tex]

[tex]= 1- P ( -0.001 < \hat p - p < 0.001 )[/tex]

[tex]= 1- P ( \dfrac{-0.001}{\sqrt{\dfrac{pq}{n}}} < \dfrac{ \hat p - p}{\dfrac{pq}{n}} < \dfrac{0.001}{\sqrt{\dfrac{pq}{n}}} )[/tex]

[tex]= 1- P ( \dfrac{-0.001}{\sqrt{\dfrac{0.3\times 0.7}{400}}} < Z < \dfrac{0.001}{\sqrt{\dfrac{0.3 \times 0.7}{400}}} )[/tex]

[tex]= 1- P ( \dfrac{-0.001}{\sqrt{5.25 \times 10^{-4}}} < Z < \dfrac{0.001}{\sqrt{5.25 \times 10^{-4}}} )[/tex]

[tex]= 1- P ( -0.0436< Z < 0.0436)[/tex]

= 1 - P ( Z < 0.0436) - P ( -0.0436)

= 1 - (0.5176 - 0.4825)

= 1 -  0.0351

= 0.9649