Let X, denote the weight of a randomly selected prepackaged one-pound bag of carrots. Of course, one pound bags of carrots won't weigh exactly one pound. In fact, history suggests that Xi is normally distributed with a mean of 1.18 pounds and a standard deviation of 0.07 pound. Now, let W denote the weight of randomly selected prepackaged three-pound bag of carrots. Three pound bags of carrots won't weigh exactly three pounds either. In fact, history suggests that Wis normally distributed with a mean of 3.22 pounds and a standard deviation of 0.09 pound. Selecting bags at random, what is the probability that the sum of three one-pound bags exceeds the weight of one three-pound bag?

Answer:

Mean y = 19 ; SD y = 10

Step-by-step explanation:

Given that:

No of customers : __ 0 ____ 1 _____ 2 ___ 3

P(x) : ___________0.10 __ 0.20 __0.30 _0.40

Fuel cost =$1 (constant)

Amount paid per customer =$10

Number of customers = x

σx = 1 ; μx = 2

σ^2 = 1^2 = 1

Mean of Y

μy = E(Y)

= E(10x - 1)

= 10(Ex) - 1

E(x) = 2

= 10(2) - 1

= 20 - 1

= 19

σY = SD(y)

SD(10x - 1)

10*SD(x) - 1

SD(x) = 1

10(1) - 0

Note : SD of a constant = 0

10 - 0

= 10

The mean of Y is 19 and the standard deviation of Y is 10 and this can be determined by using the given data.

Given :

The mean of Y can be calculated as given below:

[tex]\rm \mu(Y)=E(Y)[/tex]

[tex]\rm \mu(Y)=E(10x - 1)[/tex]

[tex]\rm \mu(Y) = 10E(x) - 1[/tex]

According to the given data, the value of E(x) is 2. Substitute the value of E(x) in the above expression.

[tex]\rm \mu(Y) = 10(2) - 1[/tex]

[tex]\rm \mu(Y) = 19[/tex]

Now, the standard deviation of Y can be calculated as:

[tex]\rm \sigma_Y=SD(Y)[/tex]

[tex]\rm \sigma_Y=SD(10x-1)[/tex]

[tex]\rm \sigma_Y=10SD(x)-SD(1)[/tex]

The value of SD for a constant is zero.

[tex]\rm \sigma_Y=10(1)-0[/tex]

[tex]\rm \sigma_Y = 10[/tex]

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Answer:

someone game me that same question but sadly i wasn't able to get the answer sorry for the inconvience

Step-by-step explanation:

Answer:

3. 2nd degree. Leading term:

[tex] {3x}^{2} [/tex]

Leading coefficient: 3x

Part 1:

[tex] {2x}^{2} + 11x + 15[/tex]

Part 2:

[tex] {3x}^{2} - x - 2[/tex]

Part 3:

[tex] - {x}^{2} + 12x + 17[/tex]

(Part 3 should be correct, double check it, I think it cancels out the minuses in the part 2 equation?)

P.S. I forgot to solve the equations on this and the first page, don't forget that and I can leave another answer for those if you need!

Answer:

I think its true but im not sure

Step-by-step explanation:

Answer

how much more is the cost of tickets than the cost of parking pass

Step-by-step explanation:\

i think, sorry if im wrong but its kinda hard to understand what you typed.

Answer:

A: No the tickets won't cost more than $1500.

B: 90 more dollars.

6 season tickets cost $720

D: 2 parking tickets will cost $60

Answer:

You can make infinite 3-digit number using the digits 6,7 and 8. Hope it helps :)

Answer:

$455 for seven nights

Step-by-step explanation:

260/4= 65

65 is the cost for 1 night

65*7=455

Answer:

$455

Step-by-step explanation:

260 divided by 4 will give you how much for one night so then multiply that answer by 7 and you have your answer.

Answer:

4

Step-by-step explanation:

25÷2= 12.50

So it would be 4 because you are trying to find the price (p) for the boots (b)

Answer:

c is correct answer is yes then please

Answer:

34 lies in between 5 and 6

5^2=25, 6^2=36, so sqrt(34) lies between 5 and 6

Answer:

171.38 - 15% plus tax= 171.23

Hope this helped!

Answer:

Step-by-step explanation:

(a) [tex]\int x^n e^{5x^4+1} \ dx[/tex]

Suppose [tex]5x^4 + 1 = f[/tex]

by differentiation;

[tex]\implies \ 20 x^3 dx = df --- (1)[/tex]

Suppose n = 3

Then, the integral

[tex]I = \int x^ 3 e^{5x^4 + 1} \ dx[/tex]

[tex]= \int e^f \ \dfrac{df}{20}[/tex]

[tex]= \dfrac{1}{20} \int e^f \ dt[/tex]

[tex]= \dfrac{1}{20} e^f + C[/tex]

recall that [tex]f = 5x^4 + 1[/tex]

Then;

[tex]\mathbf{ I = \dfrac{1}{20}e^{5x^4+1}+C}[/tex]

(b) [tex]\int \dfrac{cos (\dfrac{1}{x^3})}{x^n } \ dx[/tex]

suppose; [tex]\dfrac{1}{x^3} = f[/tex]

[tex]x^3 = f[/tex]

[tex]\implies -3x^{-4} \ dx = df[/tex]

[tex]\implies \dfrac{1}{x^4} \ dx =-\dfrac{1}{3} df[/tex]

If n = u, then the integration is:

[tex]I = \int \dfrac{1}{x^4} \ cos (\dfrac{1}{x^4}) \ dx[/tex]

[tex]= \int -\dfrac{1}{3} \ cos \ f \ df[/tex]

[tex]= -\dfrac{1}{3} \int \ cos \ f \ df[/tex]

[tex]= -\dfrac{1}{3} \ sin \ f + C[/tex]

Since;  [tex]x^3 = f[/tex]

Then;

[tex]\mathbf {I = -\dfrac{1}{3} \ sin \ \Big( \dfrac{1}{x^3}\Big) + C}[/tex]

(c) [tex]\int \dfrac{x+n}{x^2 + 8x -4} \ dx[/tex]

Suppose  [tex]x^2 + 8x - 4 = f[/tex]

Then, by differentiation of both sides

[tex](2x + 8) \ dx = df[/tex]

[tex](x + 4) \ dx = \dfrac{1}{2} \ df[/tex]

Suppose n = 4 in integration, then:

[tex]I = \int \dfrac{(x + 4) }{x^2 +8x -4} \ dx[/tex]

By substitution;

[tex]I = \int \dfrac{1}{2}\dfrac{1}{f} \ df[/tex]

[tex]= \dfrac{1}{2} \ \ { In |f|} + C[/tex]

[tex]\mathbf{= \dfrac{1}{2} \ \ { In |x^2+8x -4|} + C}[/tex]

The suitable substitutions of n are 3,4,4 respectively.

The process of finding integrals is called integration.

a)[tex]f(x)=\int\limits {x^3e^{5x^4+1} } \, dx[/tex]

Suppose

[tex]5x^4+1 =t\\20x^3 dx =dt[/tex]

So, we need n=3 for easy integration.

[tex]f(x)=\int\limits {x^3e^{5x^4+1} } \, dx[/tex]

[tex]I = \frac{1}{20} \int\limits {e^{t} } \, dt[/tex]

[tex]I=\frac{e^{t} }{20}[/tex]

[tex]I = e^{5x^{4}+1 }/20 +c[/tex]

b)Similarly for [tex]f(x) = \int\limits\frac{cos(\frac{1}{x^3} )}{x^n} \, dx[/tex]

n=4 is needed for easy integration.

I = [tex]\frac{-1}{3} sin(\frac{1}{x^3} ) +c[/tex]

c)For [tex]f(x) = \int\limits \frac{x+n}{x^{2} +8x-4} \, dx[/tex]

n=4 is needed for easy integration.

[tex]I = \frac{1}{2} log(x^{2} +8x-4)[/tex]

Hence, the suitable substitutions of n are 3,4,4 respectively.

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Answer:

it's easier if you use the scan & solve. that brainly provided for you

Step-by-step explanation:

Ryan's garden=1.3 yards wides

We know that,

1 yard=0.914 meters

so,

1.3 yards=0.914×1.3=1.1882=1.9

So,

Ryan's garden is 1.9 meters wide.

Answer:

Step-by-step explanation:

We are given a circle with a partially shaded region. First, we need to determine the area of the whole circle. To do this, we need the measurement of the radius of the circle:

Use the Pythagorean theorem to solve for the other leg of the right triangle inside the circle:

5^2 = 3^2 + x^2

x = 4

The radius is 4 + 1 cm = 5 cm

So the area of the circle is A = pi*r^2

A = 3.14 * (5)^2  

A = 25pi cm^2

To solve for the area of the shaded region:

Ashaded = Acircle - Atriangles

we need to solve for the area of the triangles:

A = 1/2 *b*h

A = 1/2 *6 * 5

A = 15 cm^2

Atriangles = 2 * 15  

Atriangles = 30 cm^2

Ashaded = 25pi - 30

Answer:

Step-by-step explanation:

The two base angles in each triangle are equal. (The triangle is isoceles and the property used is angles opposite equal sides are equal).

Now the tricky part. The peak angles are also equal. That's because both peak angles are made equal by Peak angle + 2*base angle = 180

Peak angle = 180 - 2*base angle

Therefore the triangles are congruent by SAS.  

I suppose you could get them equal by taking one of the base angles (all 4 are equal to each other) and the peak angles and claim equality by ASA, but it seems a little bit tortuous to me.

Answer:

The answer to that question is c. y = x

Answer:

x≤24

Step-by-step explanation:

4(x+5)≤116

x+5≤29

x≤29-5

x≤24

Answer:

n=5, m = 4

Step-by-step explanation:

It is a parallelogram so m+8 = 3m and 2n-1 = 9

Answer:

x=-3

Step-by-step explanation:

rearrange terms

distribute

subtract the numbers

subtract 1 from both sides of the equation

simplify

Answer:

Step-by-step explanation:

Here you go mate

Step 1

7(1-8x)-6=169  Equation/Question

Step 2

7(1-8x)-6=169  Simplify

-56x+1=169

Step 3

-56x+1=169  Subtract 1

-56x=168

Step 4

-56x=168  Divide both sides

Answer

x=-3

Answer:

um well i can do part A

Step-by-step explanation:

its 6/24 which equals 1/4 yards

Step-by-step explanation:

Sum of interior angles in a polygon

= 180°(n - 2), where n is the number of sides.

Hence a convex polygon with 6 sides

=> 180°(6 - 2) = 720°.

Answer:

2x + 4y = 28

-2y = x + 28

Step-by-step explanation:

Looking at the graph, we can see that the lines do not intersect. Therefore, they do not have a shared solution. We need to find the system of equations that does not have a solution.

1) Let's try to solve the third system given (counting from the top). To solve with the substitution method, we need to isolate one variable in one of the equations. I chose to isolate y in -2y = x + 28:

[tex]-2y = x + 28\\y = \frac{-1}{2}x -14[/tex]

2) Now that we've isolated the y in that equation, substitute what y equals in that equation for the y in the other equation. So, substitute [tex]\frac{-1}{2}x-14[/tex] for y in 2x + 4y = 28 and simplify:

[tex]2x + 4(\frac{-1}{2}x - 14) = 28\\2x - 2x- 64 = 28\\-64 = 28[/tex]

In a normal situation, the x's would not cancel out, and we would be able to isolate x to get the x-value of the solution. However, in this case, they have, and we ended up with a false statement, as -64 does not equal 28. Whenever this happens, it means the system does not have a solution. Therefore, the third option would represent the system in the graph.

The given graph shows the simultaneous relationship of equations 2x + 4y = 28 and  -2y = x + 28. Option C is correct.

Simultaneous linear equations are two- or three-variable linear equations that can be solved together to arrive at a common solution.

Here,
From the graph, the two lines represents the simultaneous relationship,
Where,

The slope of the both lines is,
m = -1/2

And y-intercept of both lines is,
C₁ = 7 and C₂ = - 14

Now,
equations  of the lines are,
y = -x/2 + 7 and y = -x/2 - 14
x + 2y = 14  and x + 2y = -28
or
2x + 4y = 28  - - - - -  -(1) and  -2y = x + 28 - - - - - - -(2)

Now,
From equation 2 substitute y in equation 1
2x + 4[-x - 28]/2= 28
2x - 2x - 56 = 28
-56 = 28
So the lines are parallel and has no solution.

Thus, the given graph shows the simultaneous relationship of equations 2x + 4y = 28 and  -2y = x + 28. Option C is correct.

Learn more about simultaneous equations here:

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Step-by-step explanation:

parallel

8g - 3 = 25

8g = 25 + 3

8g = 28

g = 28/8

g = 14/4

f + 30 + 72 = 180 (straight angle = 180°)

f = 180 - 30 - 72

= 78

Answer:

59.58333

Step-by-step explanation:

715/12

write in long division format ( which u did )

divide 71 by 12 to get 5

multiply 71 by 12 = 5

subtract 60 by 71

bring down the next number

115/12 =9

multiply 12 by 9

subtract 180 by 115

add a decimal on the top and bring down zero

divide 70 by 12 = 5

multiply 5 by 12

subtract 60 - 70

bring down a zero

divide 100 by 12 = 8

multiply 12 by 8

subtract 96 by 100

bring down zero

divide 40 by 12 = 3

anddd u get the point

sorry it took so long

Answer:

the anser is 22.10

Step-by-step explanation:

you have to round to the nearest ten. here is a tip 4 or down round down 5 or up round up now you are good to go! and also to find me if you need help

Answer:

154.8 is you answer

Step-by-step explanation:

9514 1404 393

Answer:

  it is less expensive to purchase a new car

Step-by-step explanation:

The expected cost of gas, insurance, and repairs for the old car are ...

  Total miles in 5 years = (325 mi/wk)(52 wk/yr)(5 yr) = 84,500 mi

Old car

  Gas cost in 5 years = (84,500 mi)/(14 mi/gal)($3.50/gal) = $21,125

  Insurance cost in 5 years = (5 yr)($600/yr) = $3,000

  Repair cost in 5 years = ($1500/yr)(5 yr) = $7,500

  Total operating cost in 5 years = $21125 +3000 +7500 = $31,625

__

New Car

  Gas cost in 5 years = (84,500 mi)/(47 mi/gal)($3.50/gal) ≈ $6,293

  Insurance cost in 5 years = (5 yr)($1000/yr) = $5,000

  Repair cost in 5 years = (0)(5 yr) = 0

  Total operating cost in 5 years = $6293 +5000 = 11,293

__

Difference in operating costs is $31,625 -11,293 = $20,332.

It is less expensive to purchase a new car for any price less than $20,300. If the new car costs only $16,000, it is the less-expensive option.

Purchase of a new car is the least-expensive option.

__

Additional comments

The cost of financing, annual license fees, and resale value of the new car may also come into play. In addition, the relative non-economic values of consumption of new materials, adding old materials to the scrap heap, and environmental pollution may figure in the decision. While the car dealer may pay for maintenance costs of a new car, it seems likely that at least one set of tires will be required in 5 years (85000 miles). (Assuming wheel alignment is not an issue for tire wear, that cost may balance out for the two cars.)

Answer:

1,36  2,18  3,12  4,9 and 6,6

Step-by-step explanation:

If you multiply them, they equal 36

Answer:

i really dont know

Step-by-step explanation:

i just dont