Ned is learning about cells in science class. He drew a picture to model a cell. What can he show with his cell drawing?
A)
how big a cell is
B)
how fast cells grow
c)
what cells do to move
D)
what the cell parts are

Ned Is Learning About Cells In Science Class. He Drew A Picture To Model A Cell. What Can He Show With

Answers

Answer 1

Answer:I need the answer pls

Explanation:

I don't have one

Answer 2

Answer:

The answer is D, what the cell parts are.

Explanation:


Related Questions

Explain how the net impact forces can be reduced for basketball players through the
application of scientific and engineering concepts in sneaker design.

Answers

Answer:

* If we increase the distance traveled before stopping, the forces decrease significantly,

* If we decrease the height of the fall by grabbing the net to slow down.

* Creating a process of absorption of force in the shoes, through the deformation of the elastic soles.

Explanation:

When basketball players jump to place the ball in the net they see from a good height, when they hit the ground, strong tensions are produced in the bones and bonds.

Applying science to this case of fall, we can suggest several processes to decrease the forces on impact.

* If we increase the distance traveled before stopping, the forces decrease significantly,

* If we decrease the height of the fall by grabbing the net to slow down.

* Creating a process of absorption of force in the shoes, through the deformation of the elastic soles.

By designing shoes that have some degree of force absorption, it is possible to significantly reduce the stress on the player.

"2.40 A pressure of 4 × 106N/m2 is applied to a body of water that initially filled a 4300 cm3 volume. Estimate its volume after the pressure is applied."

Answers

Answer:Final volume after pressure is applied=4,292cm3

Explanation:

Using the bulk modulus formulae

We have that The bulk modulus of waTer is given as  

K =-V dP/dV

Where  K, the bulk modulus of water = 2.15 x 10^9N/m^2

2.15 x 10^9N/m^2= - 4,300 x  4 × 106N/m2 / dV

dV = - 4,300 x  4 × 10^6N/m^2/ 2.15 x 10^9N/m^2

dV (change in volume)= -8.000cm^3

Final volume after pressure is applied,

V= V+ dV

V= 4300cm3 + (-8.000cm3)

=4300cm3 - 8.000cm3

Final Volume, V =4,292cm3

A Long Jumber leaves the ground at on
a bouche horizontal al speed ilms.
How far does he jume in the horizontal direction ?​

Answers

Answer:

horizontal velocity vh = 6*cos(30°) = 6*(√3)/2 = 3√3 m/s

initial vertical velocity vv = 6*sin(30°) = 6/2 = 3m/s

Using s = ut + at2/2 for change in vertical distance in time t, with acceleration a (-9.8m/s2) and initial velocity u (vv = 3m/s) we have

0 = 3*t - 9.8*t2/2 or t = 6/9.8 s (ignoring the t = 0 solution, which just represents staying still!).

The horizontal distance in time t is vh*t or 3√3*6/9.8 m

Explanation:

An object with a mass of 3.0 kg has a
force of 9.0 newtons applied to it. What
is the resulting acceleration of the
object?

Answers

[tex] \LARGE{ \underline{ \tt{Required \: answer:}}}[/tex]

We have:

Mass of the object = 3 kgForce on the object = 9 N

We need to find:

Resulting accleration of the object?

Solution:

According to Newton's 2nd law of motion, or quantitative measure of Force:

Force = Mass × Accleration

Using this,

➝ F = ma

➝ 9N = 3 kg × a

➝ a = 9/3 m/s²

➝ a = 3 m/s²

Hence,

The resulting accleration of the object is 3 m/s². And we are done! :D

⛱️ [tex] \large{ \blue{ \bf{FadedElla}}}[/tex]

If mass (3.0 kg) multiplying (*) acceleration gives you force (newtons), force dividing mass gives you acceleration; 9/3 =


3 m/s^2

An explanation of the relationships among particular phenomena.

Answers

Answer:

Theory

Explanation:

Theory is a term that is used often in academic work or scientific research to explain certain things or conditions established on universal principles or laws.

It is used to describe the "why and how" or the reason behind the occurrence of a situation.

Hence, it is correct to conclude that THEORY is "an explanation of the relationships among particular phenomena."

Answer:

E) Theory

Explanation:

Edge 2020

Brainliest?

Dolphins rely on echolocation to be able to survive in the ocean. In a 20 °C ocean, a dolphin produces an ultrasonic sound with a frequency of 125 kHz. What is the wavelength of this sound, in meters?While remaining stationary, the dolphin emits a sound pulse and receives an echo after 0.220 s. How far away, in meters, is the reflecting object from the dolphin?

Answers

Answer:

wavelength =  0.01 m

distance = 162.8 m

Explanation:

Given that;

Speed of sound in water = 1,480 meters per second

Frequency of ultrasound = 125KHZ

From=

v=λf

v= speed of sound

λ= wavelength of sound

f= frequency of sound

λ= 1,480 ms-1/125 * 10^3 Hz

λ= 0.01 m

From

v = 2x/t

where;

v= velocity of sound in water

x= distance traveled

t = time taken

x = vt/2

x = 1,480 ms-1 *  0.220 s/2

x= 162.8 m

A pulley is in the form of a uniform solid cylinder of radius 7cm and mass 2kg. One end of a very light rope is fixed to wind the pulley and the other end is
free. When we pull the free end of the rope the pulley starts rotating from rest and accelerates uniformly. If the angular acceleration is 100rad/s2 so the
constant force that we exert on the pulley through the rope is:
Chọn một:
a.
200 N
b.
7N
C
0.49 N
d.
49 N

Answers

Answer:

correct is b  7N

Explanation:

The torque is

         Στ = I α

      

torque

      τ = F x R

bold, indicate vectors. The magnitude of torque is

    τ = F R sin θ

in this case the angle is 90º so sin 90 = 1

     τ = F R

The moment of inertia of a cylinder

    I = ½ M R²

substitute

      F R = ½ M R² α

      F = ½ M R α

reduce to the SI system

     R = 7 cm (1m / 100cm) = 0.07 m

calculate

      F = ½ 2 0.07 100

      F = 7 N

A 227 g ball is tied to a string. It is pulled to an angle of 9.62° and released to swing as a pendulum. A student with a stopwatch finds that 5 oscillations take 31 s. How long is the string?

Answers

Answer:

9.55m

Explanation:

From T = 2π√L/g ........ 1

Where T is the period

L is the length of the string and g is the acceleration due to gravity = 9.8m/s^2

Given that,

Mass of ball = 227g

The ball makes 5 oscillations in 31 s.

T = 31/5

T = 6.2s

Solving for L from equation 1

T = 2π√L/g

Square both sides

T^2 = 4π^2×L/g

T^2×g = 4π^2×L

Make L the subject

L = T^2*g/4π^2 ......... 2

Now, substitute the values into equation 2

L = 6.2^2 × 9.8/4×3.14^2

L = 38.44*9.8/39.4384

L = 376.712/39.4384

L = 9.55m

Hence, the length of the string is 9.55m

Write an algorithm and draw the flowchart of finding the area and perimeter of a circle. The
radius (float) need to be entered by the user and if the user enters negative radius or zero radius,
the algorithm will ask the user to be entered again. (The algorithm will ask the user to enter the
radius until it is entered as positive.) At the end, the algorithm will find and print area and
perimeter of the circle as output.

Answers

Answer:

The algorithm

Step 1: Start

Step 2: Input Radius

Step 3: While Radius < = 0

                 Input Radius

Step 4: Pi = 3.14

Step 5: Perimeter = 2 * Pi * Radius

Step 6: Area = Pi * r^2

Step 7: Print Area, Perimeter

Step 8: Stop

Explanation:

This indicates the start of the algorithm

Step 1: Start

This inputs the radius

Step 2: Input Radius

The following loop is repeated until user input for radius is greater than 0

Step 3: While Radius < = 0

                 Input Radius

This initializes Pi to 3.14

Step 4: Pi = 3.14

This calculates the Perimeter or Circumference

Step 5: Perimeter = 2 * Pi * Radius

This calculates the Area

Step 6: Area = Pi * r^2

This prints the calculated Perimeter ad Area

Step 7: Print Area, Perimeter

This indicates the end of the algorithm

Step 8: Stop

I've added the flowchart as an attachment

When the palmaris longus muscle in the forearm is flexed, the wrist moves back and forth. If the muscle generates a force of 39.5 N39.5 N and it is acting with an effective lever arm of 2.75 cm2.75 cm, what is the torque that the muscle produces on the wrist?

Answers

Answer:

Explanation:

Torque is expressed according to the formula;

Torque = Force × radius

Given

Force = 39.5N

Radius = 2.75cm

Convert radius to metres

100cm ,= 1m

2.75cm = (2.75/100)

2.75cm = 0.0275m

Find the torque

Torque = 39.5×0.0275

Torque = 1.08625Nm

Hence the torque is 1.08625Nm

What is energy ? Use in your own words.

Answers

Answer:

the potential for causing changes

Explanation:

Write Radar gun summary

Answers

Answer:

A radar gun is a device for measuring the speed of moving objects. ... The radar gun is a Doppler radar unit that can be static, vehicle-mounted or hand-held. It measures the

Explanation:

1.045cm and a height of 30.48cm what is the volume of the cylinder

Answers

Answer:

104.57

Explanation:

V = πr^2h

-3.14, 1.045^2, and 30.48=104.567666431

A projectile is shot straight up from the earth's surface at a speed of 11,000 km/hr. How high does it go? ________km?

Taken from "Physics for Scientists and Engineers by Randall D. Knight 2nd Edition. Chapter 13 #34. There is an answer in the database already, but I do not understand it.

Answers

Answer:

476.35 km

Explanation:

The following data were obtained from the question:

Initial velocity (u) = 11000 km/hr

Final velocity (v) = 0 km/hr (at maximum height)

Acceleration due to gravity (g) = 9.8 m/s²

Maximum height (h) = ?

Next, we shall convert 9.8 m/s² to km/hr². This is illustrated below:

1 m/s² = 12960 km/hr²

Therefore,

9.8 m/s² = 9.8 m/s² × 12960 km/hr² / 1 m/s²

9.8 m/s² = 127008 km/hr²

Thus, 9.8 m/s² is equivalent to 127008 km/h²

Finally, we shall determine the maximum height reached by the projectile.

This is illustrated below:

Initial velocity (u) = 11000 km/hr

Final velocity (v) = 0 km/hr (at maximum height)

Acceleration due to gravity (g) = 127008 km/hr²

Maximum height (h) = ?

v² = u² – 2gh (since the projectile is going against gravity)

0² = 11000² – (2 × 127008 × h)

0 = 121×10⁶ – 254016h

Collect like terms

0 – 121×10⁶ = – 254016h

– 121×10⁶ = – 254016h

Divide both side by – 254016

h = – 121×10⁶ / – 254016

h = 476.35 km

Thus, the maximum height reached by the projectile is 476.35 km

A man walks south at a speed of 2.00 m/s for 60.0 minutes. He then turns around and walks north a distance 3000 m in 25.0 minutes. What is the average velocity of the man during his entire motion?

Answers

Answer:

v = 0.823 m/s

Explanation:

A man walks south at a speed of 2.00 m/s for 60.0 minutes.

The distance covered in South = 60 × 60 × 2 = 7200 m

He then turns around and walks north a distance 3000 m in 25.0 minutes.

As they moved in opposite direction, net displacement will be : 7200 - 3000 = 4200 m

Average velocity of the man = net displacement/time

[tex]v=\dfrac{4200\ m}{(60+25)\times 60}\\\\=0.823\ m/s[/tex]

So, the average velocity of the man is 0.823 m/s.

Solar radiation makes several other energy sources possible, including ________

a. wind energy
b. tidal energy
c. geothermal energy
d. hydrothermal energy
e. nuclear energy

Answers

Answer:

a

Explanation:

wind energy results from solar radiation

Answer:

♡ madeline here ♡

goodmorning!

it's a, have a great day! ☆

- madeline/madi

✧・゚: *✧・゚:・゚✧*:・゚✧・゚

Explanation:

Position c
Position B
Position D
Position A
Position E
Position
Kinetic Energy
Potential Energy
A
B
С
D

Answers

Answer:

B porque tiene energía n..

The ability to do work or cause a change is the definition for

energy

motion

inertia

force


What is the SI unit for energy?

Newton meter

Joule

all of the above



What are the only two things you can do with energy?

use and waste

store and transfer

store and use

transfer and waste




Energy stored as motion is also known as

chemical potential

elastic potential

kinetic

gravitational potential


Kinetic energy depends upon

mass and velocity

mass and gravity

mass and displacement

mass and height


Energy stored in position is also known as

chemical

potential

kinetic

elastic


Potential energy depends upon

mass and velocity

mass and gravity

mass, height and gravity

mass and displacement


Energy stored in chemical bonds is known as

kinetic

chemical potential

gravitational potential

elastic potential



Energy stored in a rubber band is known as

kinetic

gravitational potential

chemical potential

elastic potential



What is the force of gravity for a 12 kg turkey?

Answers

Answer:

1.  Energy

2. All of the above

3. Store and use

4.  Kinetic

5. mass and velocity

6. Potential

7. mass, height, and gravity

8. Chemical Potential

9. Elastic Potential

10.  (`⌒*)O-(`⌒´Q)

Explanation:

An airtight box, having a lid of area 80.0 cm^2, is partially evacuated. Atmospheric pressure is 1.01 Times 10^5 Pa. A force of 108 lb is required to pull the lid off the box. The pressure in the box was:_________.

Answers

Answer:

5×10^4Pa

Explanation:

Given force of 108 lb is required to pull the lid off the box,

To convert "Ib"to Newton ,we use conversation rate below

1 pounds = 4.4482216282509 newtons

Then 108 lb=x Newton

Cross multiply we have

X= 480.41Newton

The force that is needed to open the lid is F and pressure P.

We know that Pressure= Force/Area

Area is given as 80.0 cm^2, we can convert to m^2 for unit consistency since 1cm^2= 0.001m^2 then

80.0 cm^2 = 80×10^-4m^2

Substitute to the equation of the pressure we have

P= 480.41Newton/(80×10^4m^2)

P=6×10^4 Pa

The pressure in the box will be difference between the initial pressure and final pressure

=( 1.01 ×10^5 Pa)-(6×10^4 Pa)

= 50100Pa

= 5×10^4Pa

Therefore, The pressure in the box was

5×10^4Pa

A spring with spring constant 11.5 N/m hangs from the ceiling. A 490 g ball is attached to the spring and allowed to come to rest. It is then pulled down 6.70 cm and released.
What is the time constant if the ball's amplitude has decreased to 2.20 cm after 30.0 oscillations?

Answers

Answer:

The time constant is [tex]\tau = 17.5 \ s[/tex]    

Explanation:

From the question we are told that

   The spring constant is  [tex]k = 11.5 \ N/m[/tex]

   The mass  of the ball is  [tex]m_b = 490 \ g = 0.49 \ kg[/tex]

   The amplitude of the  oscillation t the beginning is [tex]x = 6.70 cm = 0.067 \ m[/tex]

    The amplitude after time t is  [tex]x_t = 2.20 cm = 0.022 \ m[/tex]

    The number of oscillation is [tex]N = 30[/tex]

Generally the time taken to attain the second amplitude is mathematically represented as

       [tex]t = N * T[/tex]                                            Here  T is the period of oscillation

         [tex]t = N * 2\pi \sqrt{\frac{m}{k} }[/tex]

=>     [tex]t = 30 * 2 * 3.142 * \sqrt{\frac{ 0.490}{11.5} }[/tex]

=>     [tex]t = 38.88 \ s[/tex]

Generally the amplitude at time t is mathematically represented as

         [tex]x(t) = x e^{-\frac{at}{2m} }[/tex]

Here a is the damping  constant so

 at  [tex]t = 38.88 \ s[/tex] ,  [tex]x_t = 2.20 cm = 0.022 \ m[/tex]

So  

     [tex]0.022 = 0.067 e^{-\frac{a * 38.88}{2 * 0.490} }[/tex]

=>  [tex]0.3284 = e^{-\frac{a * 38.88}{2 * 0.490} }[/tex]

taking natural log of both sides

=>  [tex]ln(0.3284 ) = -\frac{a * 38.88}{2 * 0.490} }[/tex]    

=>   [tex]a = 0.028[/tex]

Generally the time constant is mathematically represented as

    [tex]\tau = \frac{m}{a}[/tex]      

=> [tex]\tau = \frac{0.490}{ 0.028}[/tex]    

=> [tex]\tau = 17.5 \ s[/tex]    

A skier leaves the end of a horizontal ski jump at 23.0 m/s and falls through a vertical distance of 3.45 m before landing.

(a) Neglecting air resistance, how long does it take the skier to reach the ground?

(b) How far horizontally does the skier travel in the air before landing?

m

Answers

Explanation:

Given

Velocity v = 23.0m/s

Distance S = 3.45m

Required

Time it will take the skier to reach the ground;

Using the equation of motion;

S = ut + 1/2gt²

3.45 = 23t + 1/2(9.8)t²

3.45 = 23t + 4.9t²

4.9t²+23t-3.45 = 0

Factorize;

t = -23 ±√23²-4(4.9)(-3.45)/2(4.9)

t = -23 ±√529+67.62/9.8

t = -23±√596.62/9.8

t = -23±24.43/9.8

t = 1.43/9.8

t = 0.146 secs

Hence take the skier 0.146 secs to reach the ground.

b) Horizontal distance covered is the range;

Range = U√2H/g

Range = 23√2(3.45)/9.8

Range = 23√6.9/9.8

Range = 23√0.7041

Range = 23(0.8391)

Range = 19.29m

Hence the horizontal distance travelled in air is 19.29m

(a).The time taken by the skier to reach the ground is 0.145 second.

(b).The skier travel in the air before landing is 19.29 meter.

a. Given that A skier leaves the end of a horizontal ski jump at 23.0 m/s and falls through a vertical distance of 3.45 m before landing.

Using equation of motion.

       [tex]S=ut+\frac{1}{2}gt^{2}[/tex]

Where S is vertical distance , u is initial velocity and g is gravitational acceleration.

Substitute S = 3.45 m, u = 23m/s  and g = 9.8 in above equation.

        [tex]3.45=23t+\frac{1}{2} (9.8)t^{2}\\\\4.9x^{2} +23t-3.45=0\\\\t=0.145,-4.83[/tex]

Since, time can not be negative.

So that,  [tex]t=0.145s[/tex]

b. The horizontal distance travel before landing is known as Range.

           Horizontal distance  ,

                                             [tex]=v*\sqrt{\frac{2S}{g} }[/tex]

Substitute v = 23m/s , S = 3.45 and g = 9.8 meter per second square.

                         [tex]Distance=23*\sqrt{\frac{2*3.45}{9.8} } \\\\Distance=23*\sqrt{0.7041} \\\\Distance=23*0.8391=19.29m[/tex]

Thus, The skier travel in the air before landing is 19.29 meter.

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Consider a block sliding down a ramp whose motion is opposed by frictional forces. The total energy of this system is modeled by the equation:
Etotal = 1/2mv^2 + mgh + Ff(f is underscore)d

Which part of the equation represents the amount of energy converted to thermal energy?

A. mg
B. Ffd
C. mgh
D. 1/2 mv^2

Answers

Answer:

Energy Flows Quick check answers:

1. Ffd.

2. The kinetic energy decreases, and gravitational potential energy increases.

3. The internal energy of the system increases.

4. KEbox= Etotal-mgh

5. Etotal = 1/2m1(v1)^2+1/2m^2(v2)^2+U

The part of the equation that represents the amount of energy converted to thermal energy is [tex]F_f d[/tex].

The given equation for the total energy of a system;

[tex]E_{total} = \frac{1}{2} mv^2 \ +\ mgh\ + \ \ F_fd[/tex]

The definition of the various terms in the energy equation is given as;

[tex]E_{total}[/tex]: this is the total mechanical energy of the system[tex]\frac{1}{2} mv^2[/tex]: this is the kinetic energy of the system[tex]mgh[/tex]:  this is the potential energy of the system[tex]F_f d[/tex]:  this is the energy lost due to friction.

The energy lost due to friction is equal to the energy converted to thermal energy.

Thus, the part of the equation that represents the amount of energy converted to thermal energy is [tex]F_f d[/tex].

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The sun is 150,000,000 km from earth; its diameter is 1,400,000 km. A student uses a 4.6-cm-diameter lens with f = 10 cm to cast an image of the sun on a piece of paper. What is the diameter of the image on the paper?

Answers

Answer:

Explanation:

the image distance can be calculated using below formula of lens

1/v=1/- 1/u

Where

u= Object distance = 15×10^7km

Diameter = 1400000 km

Diameter of lens = 4.6 cm

f= Focal length ( 10 cm)= 1×10^-4

We can substitute to the above formula we have

1/15×10^7km+1/1×10^-4

V=0.001km

Therefore, paper stayed on the focus, hence the sharp image

Two identical wind-up cars A and B are released. Car B has a 2 kilogram weight strapped to the back of the car. Which will have the greatest average speed towards the end of the motion?

A)Car A

B)They will both have an average speed of zero.

C)They will have the same average speed.

D)Car B

E)There is not enough information to answer.

Answers

Answer:

Car A would have a better average speed

Explanation:

added weight to a object that is self propelled will be slower than a identical object with no added weight

An ant crawled from a hole to the food. For the first 6 minutes,it travelled at an average speed of 15m/min. For The next 9 minutes it travelles at an average speed of 10m/min what was the average speed of the whole journey?

Answers

Answer:

v = 12 m/min

Explanation:

By definition, the average velocity is the rate of change of the position with respect to time, as follows:

        [tex]v_{avg} =\frac{x_{f} -x_{o} }{t_{f}-t_{o} } (1)[/tex]

Choosing x₀ = 0 and t₀ =0, (1) reduces to :

        [tex]v_{avg} = \frac{x_{f} }{t_{f} } (2)[/tex]

From the givens, we have:

       tif = 6 min + 9 min = 15 min

In order to get xf, we know that during the first part, vavg = 15 m/min, so solving for xf:

        [tex]x_{f1} = v_{avg1}* t_{1} = 15 m/min * 6 min = 90 m (3)[/tex]

For the following 9 min, we know that the average speed was 10m/min, so the distance traveled during the second part of the trip was simply:

       [tex]x_{f2} = v_{avg2} *t_{2} = 10m/min * 9 min = 90 m (4)[/tex]

Adding (3) and (4):

       [tex]x_{f} = 90 m + 90 m = 180 m (5)[/tex]

Replacing xf and tif in (2), we finally get:

       [tex]v_{avg} =\frac{x_{f} }{t_{f}} =\frac{180m}{15 min} = 12 m/min (6)[/tex]

PLEASE HELP!!
Which statement accurately describes a balanced force?


A 2-N force presses down on the marble at the same time as a 1.5-N force presses up on the marble.

A marble rolling downhill suddenly comes to rest at a garden wall.

A 25-N force acts on the left side of the marble at the same time as a 25-N force acts on the right side of the marble.

A marble resting on the sidewalk suddenly begins to roll downhill without being touched.

Answers

Answer:

A 25-N force acts on the left side of the marble at the same time as a 25-N force acts on the right side of the marble.

Explanation:

just took test

A 25-N force acts on the left side of the marble at the same time as a 25-N force acts on the right side of the marble.

What is force?

A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.

Balanced force is when the net force applied on the object is zero than said to be balanced.

A 25-N force acts on the left side of the marble at the same time as a 25-N force acts on the right side of the marble.

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what are the two outcomes for a proto star?
Brown dwarf or main sequence star
Brown dwarf or red dwarf
Red giant or red dwarf
Black hole or main sequence star​

Answers

Answer:

Brown dwarf or main sequence star

What type of meter would be connected on both sides of a resistor in a circuit?

Answers

Type of meter would be connected on both sides of a resistor in a circuit is a a voltmeter , which measures potential difference .

What is a voltmeter ?

A voltmeter is an instrument used for measuring the potential difference , or voltage between two points in an electrical circuit .

A voltmeter is always attached in a series combination and an ammeter (which measures current in a circuit ) always attached in parallel combination with the circuit.

Since , in question it is given that a meter would be connected on both sides of a resistor in a circuit that means it must be a series combination

hence , correct answer is B) a voltmeter , which measures potential difference .

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When is a magnetic force produced in a copper wire?
O A. Whenever the wire is connected to a magnet
B. Whenever the wire is wrapped around an iron bar
C. Whenever there is current in the wire
D. Whenever the wire is coiled

Answers

Answer:

ur answer is d

Explanation:

it has to be coiled to give off magnetic energy

Yes the answer is d the person is right

A coconut is thrown straight downward and explodes into two pieces. One piece moves directly to the right. What direction does the other piece go?
A. left
B. right
C. down
D. up
E. it stays at rest

Answers

I would GUESS left, I really don’t know how you would learn something like this though because everything would probably move differently
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