(PLEASE HELP 50 POINTS) At a dog show, the entries included Welsh corgis and cocker spaniels. The table compares the weights within this sample of dogs.
Answer the questions to compare the weights of the dog breeds and determine which breed of dog had the heaviest entry.
1. What is the median weight of the Welsh corgis? What does the median tell you about their weights?
Write your answer in the space below.
2. Which type of dog has the greater variation in weights? Justify your answer.
Write your answer in the space below.
3. Do you think the heaviest dog in the show was a Welsh corgi or a cocker spaniel? Explain how you made your choice.
Write your answer in the space below.
Answers
Answer:
1. 27
Im not sure about 2 but i think its welsh corgis
3. (Im also not sure about this one, so dont take my word for it if my answer doesnt seem right) I think the heaviest dog is the welsh corgi bc i added all the weights together for the welsh corgis.
Step-by-step explanation:
According to the table the median of Welsh Corgi is 27.3kg whereas the Welsh Corgi has the maximum variation in weights.
What is the median?The median is the center most value of the data.
What is mean absolute deviation?It is the distance of value from the average mean.
How to answer?1) When we see table we can easily find that the median of Welsh Corgi is 27.3 kg and median tells us about the center level of all the weights.
2)Welsh Corgi has the greater variation in weights because its range is higher than Cocker Spaniel.
3) No, because average weight of both the type of dogs is equal.
Learn more about statistics at https://brainly.com/question/15525560
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Answer:
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Step-by-step explanation:
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I hope this helps:
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Step-by-step explanation:
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Answer:
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Step-by-step explanation:
Step one:
given data
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the online store will cost
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Answer:
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Step-by-step explanation:
I hope this helps!!!
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Step-by-step explanation:
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Step-by-step explanation:
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yo yo yo hi hi hi hi hi
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Step-by-step explanation:
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Step-by-step explanation:
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Answer:
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Step-by-step explanation:
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Step-by-step explanation:
Given KW is perpendicular to JO, JP is perpendicular to KO, KN intersects with JP=Q. Prove that triangle OKW ~ triangle OJP
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Answer:
Proved
Step-by-step explanation:
m∠JPO = 90 = m∠OWK, and angle O is common between both triangles [reflexive property]. Therefore by Rule AA, ΔOKW~ΔOJP
Triangle OKW similar to triangle OJP by angle-angle or AA or ΔOKW ~ ΔOJP by AA.
What is the similarity law for triangles?It is defined as the law to prove that the two triangles have the same shape, but it is not compulsory to have the same size. The ratio of the corresponding sides is in the same proportions and the corresponding angles are congruent.
Please refer to the attached picture for the diagram.
We have:
KW is perpendicular to JO, JP is perpendicular to KO.
KN intersects with JP=Q.
From the figure:
Angle JPO =Angle OWK = 90 degrees
By using the reflexive property:
Angle O = Angle O
Thus, triangle OKW similar to triangle OJP by angle-angle or AA or ΔOKW ~ ΔOJP by AA.
Learn more about the similarity of triangles here:
brainly.com/question/8045819
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