solve for b d=3a+3b​

Answer:

a. m∠1 = 75°

b. m∠2 = 46°

c. m∠3 = 59°

d. m∠4 = 59°

e. m∠5 = 46°

f. m∠7 = 121°

g. m∠8 = 59°

h. m∠9 = 62°

i. m∠10 = 118°

j. m∠11 = 59°

k. m∠13 = 118°

i. m∠14 = 62°5

Example 5

m∠1 =78°

m∠2 = 102°

m∠3 = 59°

m∠4 = 102°

m∠5 =  38

m∠6 = 142°

m∠7 = 38°

m∠8 = 142°

m∠9 = 78°

m∠11 = 78°

m∠12 =  102°

m∠13 = 38°

m∠14 =  142°

Step-by-step explanation:

a. m∠1 ≅ m∠6 (Alternate angle theorem)

m∠1 = m∠6 = 75° (Definition of congruency)

m∠1 = 75°

b. m∠12 = m∠5 + m∠6 (Angle addition postulate/Corresponding angles)

m∠5 = 121° - 75° = 46°

m∠5 = 46°

m∠2 ≅ m∠5 (Alternate angle theorem)

m∠2 = m∠5 = 46° (Definition of congruency)

m∠2 = 46°

c. m∠3 = 180 - (m∠1 + m∠2) (Angle subtraction and sum of angles on a straight line)

m∠3 = 180 - (75 + 46) = 59°

m∠3 = 59°

d. m∠4 = 180 - (m∠1 + m∠5)

m∠4 = 180 - (75 + 46) = 59°

m∠4 = 59°

e. m∠12 = m∠5 + m∠6 (Angle addition postulate/Corresponding angles)

m∠5 = 121° - 75° = 46°

m∠5 = 46°

f. m∠7 = m∠12 = 121° (Alternate angle theorem)

m∠7 = 121°

g. m∠8 = 180 - m∠7 = 180 - 121 = 59°

m∠8 = 59°

h. m∠9 + m∠5 + m∠8 = 180 (The sum of the interior angles of a triangle)

m∠9 = 180 - (59 + 59) = 62°

m∠9 = 62°

i. m∠10 = 180 - m∠9 = 180 - 62 = 118°

m∠10 = 118°

j. m∠11 = m∠8 = 59°

m∠11 = 59°

k. m∠13 = m∠10 = 118°

m∠13 = 118°

i. m∠14 = m∠9 = 62°

m∠14 = 62°

Example 5

m∠5 = m∠7 = 38

m∠5 =  38°

m∠6 = 180 - 38 = 142°

m∠6 = 142°

m∠8 = m∠6 = 142°

m∠8 = 142°

m∠12 = m∠10 = 102°

m∠12 =  102°

m∠11 = 180 - m∠12 = 180 - 102 = 78°

m∠11 = 78°

m∠9 = m∠11 = 78°

m∠9 = 78°

m∠1 = m∠9 = 78°

m∠1 =78°

m∠3 = 78°

m∠2 = m∠4 = m∠10 = 102°

m∠13 = 360 - (m∠3 + m∠6 + m∠12) = 360 - (78 + 142 + 102) = 38°

m∠13 = 38°

m∠15 = 38°

m∠14 = m∠16 = 180 - m∠15 = 180 - 38° = 142°

m∠14 =  142°

m∠16 = 142°

Answer: -1/2

Step-by-step explanation:

Slope=rise/run

Up 1 and to the left 2 which makes it a negative

Answer:

2.5

Step-by-step explanation:

because you can tell by the numbers and how close they are then u have to divide

Answer:

x_>0,_>3000

Step-by-step explanation:

I saw the answer key :)

The domain of a function is the set of input values the function can take.

The reasonable domain of the function is [0,16]

From the question, we understand that x represents the number of years after 2000 until 2016.

Hence, the reasonable domain of the function is [0,16]

Read more about domain at:

https://brainly.com/question/10197594

9,2.5,-4,-10.5,-17

Let's find the difference between two consecutive terms

2.5 - 9 = -6.5

-4 - 2.5 = -6.5

-10.5 - (-4) = -6.5

-17 -(-10.5) = -6.5

We can see that the common difference is -6.5

-6.5 is the common difference between successive terms in the sequence 9,2.5,-4,-10.5,-17

the common difference is negative because we subtract 6.5 to get the next term.

Answer:

The common difference between 9, 2.5, –4, –10.5, –17, ...

Is –6.5

Step-by-step explanation:

Because,

2.5 - 9 = -6.5

-4 - 2.5 = -6.5

-10.5 - (-4) = -6.5

-17 -(-10.5) = -6.5

We can see that the common difference is -6.5

-6.5 is the common difference between successive terms in the sequence 9,2.5,-4,-10.5,-17

the common difference is negative because we subtract 6.5 to get the next term.

Answer:

im going to say 4 hope it helps

Step-by-step explanation:

Answer:

Step-by-step explanation:

let the number of dimes=x

and number of quarters=y

x=2y

0.10 x+0.25 y=2.25

or 10x+25y=225

divide by 5

2x+5y=45

2 ×2y+5y=45

4y+5y=45

9y=45

y=45/9=5

x=2y=2×5=10

Hence dimes=10

quarters=5

Answer:

y = - 12(x + 3)² + 7

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

Here (h, k ) = (- 3, 7 ), thus

y = a(x - (- 3))² + 7 , that is

y = a(x + 3)² + 7

To find a substitute (- 2, - 5) into the equation

- 5 = a(- 2 + 3)² + 7 ( subtract 7 from both sides )

- 12 = a(1)² = a

y = - 12(x + 3)² + 7 ← equation in vertex form

Answer:

a) Maria has d+f

b) Ivan has 3d+ (f-7)

c) 5d+20f

Step-by-step explanation:

Answer:

The question is not complete, fortunately, I found a match:

Tran planned a rectangular pool and made a scale drawing using centimeters as the unit of measurement. he originally planned for the length of the pool to be 40 m but decided to change it to 32 m. if the length of the pool in his scale drawing is 8 cm, which statement about the change of scale is true?

one cm represented 5 m in the first scale, but now 1 cm represents 4 m in the second scale.

one cm represented 40 m in the first scale, but now 1 cm represents 32 m in the second scale.

one cm represented 1 m in the first scale, but now 1 cm represents 5 ft in the second scale.

one cm represented 4 m in the first scale, but now 1 cm represents 5 m in the second scale.

answer:

one cm represented 5 m in the first scale, but now 1 cm represents 4 m in the second scale.

Step-by-step explanation:

To calculate the scaling factor, we will divide the actual figure by the figure in the scale.

Before the change: 8cm in the drawing represents 40m

8cm ≡ 40m

∴ 1cm ≡ 40 ÷ 8 = 5m

∴ 1 cm represents 5m

After the change: 8cm in the drawing represents 32m

8cm ≡ 32m

∴ 1cm ≡ 32 ÷ 8 = 4

∴ 1cm represents 4m

Therefore, one cm represented 5 m in the first scale, but now 1 cm represents 4 m in the second scale.

Answer:

It’s the first choice

Step-by-step explanation:

Answer:

-5

Step-by-step explanation:

h(-2)=3(-2)+1

= -6+1

= -5

hope this help you!! :))))))

I just need to fill 20 characters, the answer is right there on the sheet

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

[tex](6x + 13) + (3x - 4) = 180[/tex]

[tex]9x + 9 = 180[/tex]

Subtract sides 9

[tex]9x + 9 - 9 = 180 - 9[/tex]

[tex]9x = 171[/tex]

Divide sides by 9

[tex] \frac{9}{9} x = \frac{171}{9} \\ [/tex]

[tex]x = 19[/tex]

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

Answer:

See below

Step-by-step explanation:

[tex] \huge {4}^{3}. (3 \sqrt{16} )^{ - 2} \\ \\ = \huge 64. (3 .4 )^{ - 2}\\ \\ = \huge 64. (12)^{ - 2} \\ \\ = \huge \frac{64}{(12)^{ 2}} \\ \\ = \huge \frac{64}{144} \\ \\\huge = \frac{4}{9} \\ \\ \\ \huge( {a}^{5} . {a}^{ - 2} )^{3} \\ \\ = \huge( {a}^{5 - 2} )^{3} \\ \\ = \huge( {a}^{3} )^{3} \\ \\ = \huge{a}^{3 \times 3} \\ \\ = \huge{a}^{9} [/tex]

Arithmetic Sequence

'nth' term of each

i)n^2+2n

ii) n^2- 2n​

1) Sum of first n terms = n² + 2n

We know that,

Sum of first n terms = n/2 * [ a + l ]

Where,

a is first term

l is nth or last term.

Substitute n = 1 to find the sum of first 1 terms i.e., first term (a) of the AP.

→ S₁ = a = (1)² + 2(1)

→ a = 1 + 2

→ a = 3

Hence,

→ n/2 * [ a + l ] = n² + 2n

→ a + l = n(n + 2) * 2/n

→ a + l = 2n + 4

→ l = 2n + 4 - a

→ l = 2n + 4 - 3

→ l = 2n + 1

Hence, the nth term is 2n + 1.

2)S(n) = n² - 2n

→ S₁ = a = (1)² - 2(1)

→ a = - 1

Hence,

→ n/2 * [ - 1 + l ] = n² - 2n

→ l - 1 = n(n - 2) * 2/n

→ l - 1 = 2n - 4

→ l = 2n - 4 + 1

→ l = 2n - 3

Hence, the nth term is 2n - 3.

I hope it will help you.

Regards.

Step-by-step explanation:

Series

The series of a sequence is the sum of the sequence to a certain number of terms. It is often written as Sn. So if the sequence is 2, 4, 6, 8, 10, ... , the sum to 3 terms = S3 = 2 + 4 + 6 = 12.

The Sigma Notation

The Greek capital sigma, written S, is usually used to represent the sum of a sequence. This is best explained using an example:

This means replace the r in the expression by 1 and write down what you get. Then replace r by 2 and write down what you get. Keep doing this until you get to 4, since this is the number above the S. Now add up all of the term that you have written down.

This sum is therefore equal to 3×1 + 3×2 + 3×3 + 3×4 = 3 + 6 + 9 + 12 = 30.

3

S 3r + 2

r = 1

This is equal to:

(3×1 + 2) + (3×2 + 2) + (3×3 + 2) = 24 .

The General Case

n

S Ur

r = 1

This is the general case. For the sequence Ur, this means the sum of the terms obtained by substituting in 1, 2, 3,... up to and including n in turn for r in Ur. In the above example, Ur = 3r + 2 and n = 3.

Arithmetic Progressions

An arithmetic progression is a sequence where each term is a certain number larger than the previous term. The terms in the sequence are said to increase by a common difference, d.

For example: 3, 5, 7, 9, 11, is an arithmetic progression where d = 2. The nth term of this sequence is 2n + 1 .

In general, the nth term of an arithmetic progression, with first term a and common difference d, is: a + (n - 1)d . So for the sequence 3, 5, 7, 9, ... Un = 3 + 2(n - 1) = 2n + 1, which we already knew.

The sum to n terms of an arithmetic progression

This is given by:

Sn = ½ n [ 2a + (n - 1)d ]

You may need to be able to prove this formula. It is derived as follows:

The sum to n terms is given by:

Sn = a + (a + d) + (a + 2d) + … + (a + (n – 1)d) (1)

If we write this out backwards, we get:

Sn = (a + (n – 1)d) + (a + (n – 2)d) + … + a (2)

Now let’s add (1) and (2):

2Sn = [2a + (n – 1)d] + [2a + (n – 1)d] + … + [2a + (n – 1)d]

So Sn = ½ n [2a + (n – 1)d]

Example

Sum the first 20 terms of the sequence: 1, 3, 5, 7, 9, ... (i.e. the first 20 odd numbers).

S20 = ½ (20) [ 2 × 1 + (20 - 1)×2 ]

= 10[ 2 + 19 × 2]

= 10[ 40 ]

= 400

Geometric Progressions

A geometric progression is a sequence where each term is r times larger than the previous term. r is known as the common ratio of the sequence. The nth term of a geometric progression, where a is the first term and r is the common ratio, is:

arn-1

For example, in the following geometric progression, the first term is 1, and the common ratio is 2:

1, 2, 4, 8, 16, ...

The nth term is therefore 2n-1

The sum of a geometric progression

The sum of the first n terms of a geometric progression is:

a(1 - rn )

1 – r

We can prove this as follows:

Sn = a + ar + ar2 + … + arn-1 (1)

Multiplying by r:

rSn = ar + ar2 + … + arn (2)

(1) – (2) gives us:

Sn(1 – r) = a – arn (since all the other terms cancel)

And so we get the formula above if we divide through by 1 – r .

Example

What is the sum of the first 5 terms of the following geometric progression: 2, 4, 8, 16, 32 ?

S5 = 2( 1 - 25)

1 - 2

= 2( 1 - 32)

-1

= 62

The sum to infinity of a geometric progression

In geometric progressions where |r| < 1 (in other words where r is less than 1 and greater than –1), the sum of the sequence as n tends to infinity approaches a value. In other words, if you keep adding together the terms of the sequence forever, you will get a finite value. This value is equal to:

a

1 – r

Example

Find the sum to infinity of the following sequence:

1 , 1 , 1 ,

1

,

1

,

1

, ...

2 4 8 16 32 64

Here, a = 1/2 and r = 1/2

Therefore, the sum to infinity is 0.5/0.5 = 1 .

So every time you add another term to the above sequence, the result gets closer and closer to 1.

Harder Example

The first, second and fifth terms of an arithmetic progression are the first three terms of a geometric progression. The third term of the arithmetic progression is 5. Find the 2 possible values for the fourth term of the geometric progression.

The first term of the arithmetic progression is: a

The second term is: a + d

The fifth term is: a + 4d

So the first three terms of the geometric progression are a, a + d and a + 4d .

In a geometric progression, there is a common ratio. So the ratio of the second term to the first term is equal to the ratio of the third term to the second term. So:

a + d = a + 4d

a a + d

(a + d)(a + d) = a(a + 4d)

a² + 2ad + d² = a² + 4ad

d² - 2ad = 0

d(d - 2a) = 0

therefore d = 0 or d = 2a

The common ratio of the geometric progression, r, is equal to (a + d)/a

Therefore, if d = 0, r = 1

If d = 2a, r = 3a/a = 3

So the common ratio of the geometric progression is either 1 or 3 .

Answer:

I sorry can't help I'm doing Geometry

Answer:

Step-by-step explanation:

Sorry but please give detailed question

Answer:

an+9n-11

Step-by-step explanation:

the answer is

C. neither

Answer:

Scenario 1/129 veggie rolls/Scenario 2/59 Shrimpy BOis

Step-by-step explanation:

1/

129x .75 = 96.75=97

.95 x 56 = 53.2=53

2/

59 x .95 = 56.05=56

.75 x 38 = 28.5=28

Answer:

[tex](-∞,1) , (0,\frac{7}{4})[/tex]

Step-by-step explanation:

Factor:

x(4x³-3x-7)<0

Answer:

DNE

Step-by-step explanation:

If x and y may be any real number, there is no minimum value for C. It can approach negative infinity.

If C is a constant, and the domain of x is all real numbers, there is no minimum for y. It can approach negative infinity.

We're not sure what you want or what restrictions may exist. The given relation does not suggest any minimum. We'd have to say it Does Not Exist

Hello there,

Use the first constraint to isolate y :

[tex]9x+2y\geq 35[/tex]

[tex]y \geq \frac{35-9x}{2}[/tex]

Now use the second one to isolate x :

[tex]x+3y\geq 14[/tex]

[tex]x\geq 14-3y[/tex]

You know that [tex]x\geq 0[/tex] and [tex]y\geq 0[/tex]

So what's the minimum value of x it's 0 ! Same for y !

So substitute x by 0 and y by 0

[tex]y\geq \frac{35}{2} =17.5[/tex]

[tex]x\geq 14[/tex]

So the minimum value of C is :

[tex]C=14+3*17.5[/tex]

[tex]\boxed{C=66.5}[/tex]

Hope it helps !

Photon

Answer:

0

Step-by-step explanation:

Say the number was x.

3(x+5)-5=10

3(x+5)=15

x+5=5

x=0

Answer:

(-5,-4)

Step-by-step explanation:

reflection over y-axis makes (x,y) become (-x,y)

Answer:

That is Cool

Step-by-step explanation:

Because it just is.

Answer:

first one: liters seconds one: milliliters third one: liters

Liters

Milliliters

Liters

Liters are larger are milliliters