Substitute x=3y+1 into the expression-x -7 and simplify

Answer:

100% = 14

75% = 10.5

25% = 3.5

Answer:

Step-by-step explanation:

50% if a number is also 1/2 of that number. So, we multiply 7 by 2 to get 14.

Now we know that we need to solve for 25%, 75%, and 100% of 14.

100% of a number is just that number, so 100% of 14 is 14.

To solve for 75% of 14, we multiply 3/4 by 14.

3/4 x 14/1 = 42/4 = 10 1/2

The final number to solve for is 25% of 14.

1/4 x 14/1 = 14/4 = 3 1/2

Answer:

Step-by-step explanation:

(2/3)/4=(2/3)*(4/1)=8/3=2 2/3

The algebraic expression is 0.3G+25F

An algebraic expression is a sentence with a minimum of two numbers or variables and at least one mathematical operation.  

First, we can use G to represent green house flowers and F to represent ferns.

Then thirty percent of the green house flower can be represented by 0.3G.

25 ferns can be written as 25F.

The algebraic expression for the given verbal description is 0.3G+25F.

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Answer:

yes???

Step-by-step explanation:

16 celsius is warmer than 0 celsius by 16 degrees.0 is colder by 16 degrees.

T o T hope that helped...

Answer:

b

Step-by-step explanation:

Answer:

A.

Step-by-step explanation:

Pa follow po na log out kasi ang isa kong brainly

Answer:35

Step-by-step explanation:

35x93/100=32.55

32.55x107/100=35

Answer:

reduction

Step-by-step explanation:

the orange is a reduction of the black shape because it is the same shape just smaller

Answer:

it's a reduction because the new shape is smaller than the original shape

Step-by-step explanation:

We have that Linda's net and expression incorrect

With the Expression of the surface area of attic

[tex]45(40+25+25)+1/2(40*15)[/tex]

Surface area is

[tex]X=4050+600\\\\X=4650ft^2[/tex]

So for the Question is Are Linda's net and  expression correct?

The answer is No Because

Her expression for the triangles are incorrect

[tex]1/2(40*15)[/tex]

Instead of

[tex]1/2*40*(15)[/tex]

Hence

Linda's net and expression incorrect

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Answer:is 5/4/37/2

Step-by-step explanation:

Answer:

Step-by-step explanation:

didn't distribute the 3 into the six

16z+72z-18-7-31z

57z-25

Answer:

number 2 is 20 percent so j

Step-by-step explanation:

Answer:

y=-0.215x^2+35

Step by Step:

Let, [tex]h=0[/tex],  [tex]k=35[/tex], [tex]x=8[/tex], [tex]y=21[/tex]

We know that, the general equation of the parabola.

   [tex]y-k = a(x-h)^2[/tex]

[tex]\Rightarrow y=a(x-h)^2+k .........(i)[/tex]

Substitute the  value of [tex]h, k, x, y[/tex] in equation [tex](i)[/tex] and find the value of [tex]a.[/tex]

  [tex]21=a(8-0)^2+35[/tex]

[tex]\Rightarrow 21=a\times 8^2+35[/tex]

[tex]\Rightarrow 21=64a+35[/tex]

[tex]\Rightarrow 64a=21-35[/tex]

[tex]\Rightarrow 64a=-14[/tex]

[tex]\Rightarrow a=\frac{-14}{65}[/tex]

[tex]\Rightarrow a=-0.215[/tex]

Hence, the equation of the parabola is:

[tex]y=-0.215x^2+35[/tex]

Answer: b there are 12flasses

Step-by-step explanation:

Answer:

I think the answer would be r=-9

Step-by-step explanation:

12+r=3

-12     -12

-------------

r=-9

Answer:

It Is >

Step-by-step explanation: Try Using Your Calculator It Help's.

I Also Took The Quiz And I Got This Question Correct.

Answer:

C. 2a

Step-by-step explanation:

edge, mark me brainliest

Answer:

i think it 0.4%

Step-by-step explanation:

Answer:

35 = x +4 (subtract 4 from both sides to isolate x)

x = 31

Step-by-step explanation:

I hope this helps :)

Answer:

Step-by-step explanation:

Answer:

52.94

Step-by-step explanation:

Answer:  It's 52.9411765

Answer:

x=4

Step-by-step explanation:

The value of x from the given similar triangles is 7 units.

Two triangles are similar if the angles are the same size or the corresponding sides are in the same ratio. Either of these conditions will prove two triangles are similar.

The given triangles ABC and DEF are similar triangles.

Here, AB/DE =AC/DF =BC/EF

4/12 =8/3(x+1)

8/3(x+1) =1/3

24=3x+3

3x=24-3

3x=21

x=7

Therefore, the value of x is 7 units.

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Answer:

do you still need help

Step-by-step explanation:

Answer:

40.20cm approx

Step-by-step explanation:

Step one

given data

We are told that the dimension of a computer screen

diagonal= 52 cm

height= 33cm

Length = ?

Required

The length of the base of the screen

Step two

Let us use Pythagoras theorem to find the length of the base

Hyp^2= Opp^2+ Adj^2

52^2= 33^2+ L^2

2704= 1089+L^2

L^2= 2704-1089

L^2= 1615

L=√1615

L= 40.20cm approx

The length is 40.20cm approx.

Answer:

(-4, 3)

General Formulas and Concepts:

Algebra I

Step-by-step explanation:

Where the 2 lines intersect would be the solution set to the systems of equations.

Answer:

-2x^2 + x^2 +11x +2

Step-by-step explanation:

f(x) = 2x^2-5x -3

g(x) = x^2 + 6x -1

h(x) = g(x) - f(x)

x^2 + 6x -1 - 2x^2 +5x +3

-2x^2 + x^2 +11x +2

Answer:

[tex]T(ln2)[/tex][tex]= <\sqrt{145} , \frac{6\sqrt{2} }{\sqrt{145} } , \frac{6\sqrt{2} }{\sqrt{145} } >[/tex]

Step-by-step explanation:

Given : [tex]r(t)=<7-\sqrt{e^t}, 3e^t,3e^t > .........(i)[/tex]

We first have to differentiate of equation [tex](i)[/tex]

[tex]r'(t) = < \frac{\sqrt{e^t} }{2} , 3e^t,3e^t> ..........(ii)[/tex]

Now to get a unit tangent vector at the given value of [tex]t[/tex], we put [tex]t = ln2[/tex] in equation [tex](ii)[/tex]

[tex]r'(ln2) = < \frac{\sqrt{e^{ln2}} }{2} , 3e^{ln2},3e^{ln2}>[/tex]

            [tex]= <\frac{1}{\sqrt{2} } ,6,6>[/tex]        [∵[tex]e^{lna}=a[/tex]]

Now to get a unit tangent vector , we will divide our vector [tex]r'(ln2)[/tex] by its magnitude. So let's first find the magnitude.

[tex]|r'(ln2)|=\sqrt{(\frac{1}{\sqrt{2} } )^2 +6^2+6^2}[/tex]

             [tex]= \sqrt{\frac{1}{2}+36+36 }[/tex]

             [tex]= \sqrt{\frac{145}{2} }[/tex]

Now we can find the our unit tangents vector.

      [tex]T(ln2)=\frac{r'(ln2)}{|r'(ln2)|}[/tex]

                  [tex]= \frac{<\frac{1}{\sqrt{2}} ,6,6> }{\sqrt{\frac{145}{2}} }[/tex]

                  [tex]= <\frac{\frac{1}{\sqrt{2} } }{\sqrt{\frac{145}{2}} } ,\frac{6}{{\sqrt{\frac{145}{2}} }}, \frac{6}{{\sqrt{\frac{145}{2}} }} >[/tex]

                   [tex]= <\sqrt{145} , \frac{6\sqrt{2} }{\sqrt{145} } , \frac{6\sqrt{2} }{\sqrt{145} } >[/tex]

Hence, [tex]T(ln2)[/tex] [tex]= <\sqrt{145} , \frac{6\sqrt{2} }{\sqrt{145} } , \frac{6\sqrt{2} }{\sqrt{145} } >[/tex]