Use the graph to determine the object's average velocity
What is the average velocity of the object?
m/s
Position vs Time
Position (m)
N A 0 0
0
10
20
30
40
50
Time (s)

Answer:

The displacement of the car after 6s is 43.2 m

Explanation:

Given;

velocity of the car, v = 12 m/s

acceleration of the car, a = -1.6 m/s² (backward acceleration)

time of motion, t = 6 s

The displacement of the car after 6s is given by the following kinematic equation;

d = ut + ¹/₂at²

d = (12 x 6) + ¹/₂(-1.6)(6)²

d = 72 - 28.8

d = 43.2 m

Therefore, the displacement of the car after 6s is 43.2 m

Answer:

B, which is why ice skaters often keep their arms close to their body when doing spins and jumps to minimize resistance.

Answer:

distance i think

Explanation:

Answer:

a) The perimeter of the rectangle is 29.4 centimeters.

b) The uncertainty in its perimeter is 0.8 centimeters.

Explanation:

a) From Geometry we remember that the perimeter of the rectangle ([tex]p[/tex]), measured in centimeters, is represented by the following formula:

[tex]p = 2\cdot (w+l)[/tex] (1)

Where:

[tex]w[/tex] - Width, measured in centimeters.

[tex]l[/tex] - Length, measured in centimeters.

If we know that [tex]w = 6.4\,cm[/tex] and [tex]l = 8.3\,cm[/tex], then the perimeter of the rectangle is:

[tex]p = 2\cdot (6.4\,cm+8.3\,cm)[/tex]

[tex]p = 29.4\,cm[/tex]

The perimeter of the rectangle is 29.4 centimeters.

b) The uncertainty of the perimeter ([tex]\Delta p[/tex]), measured in centimeters, is estimated by differences. That is:

[tex]\Delta p = 2\cdot (\Delta w + \Delta l)[/tex]  (2)

Where:

[tex]\Delta w[/tex] - Uncertainty in width, measured in centimeters.

[tex]\Delta l[/tex] - Uncertainty in length, measured in centimeters.

If we know that [tex]\Delta w = 0.2\,cm[/tex] and [tex]\Delta l = 0.2\,cm[/tex], then the uncertainty in perimeter is:

[tex]\Delta p = 2\cdot (0.2\,cm+0.2\,cm)[/tex]

[tex]\Delta p = 0.8\,cm[/tex]

The uncertainty in its perimeter is 0.8 centimeters.

Answer:

a

Explanation:

wind energy results from solar radiation

Answer:

♡ madeline here ♡

goodmorning!

it's a, have a great day! ☆

- madeline/madi

✧･ﾟ: *✧･ﾟ:･ﾟ✧*:･ﾟ✧･ﾟ

Explanation:

Type of meter would be connected on both sides of a resistor in a circuit is a a voltmeter , which measures potential difference .

A voltmeter is an instrument used for measuring the potential difference , or voltage between two points in an electrical circuit .

A voltmeter is always attached in a series combination and an ammeter (which measures current in a circuit ) always attached in parallel combination with the circuit.

Since , in question it is given that a meter would be connected on both sides of a resistor in a circuit that means it must be a series combination

hence , correct answer is B) a voltmeter , which measures potential difference .

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Answer:

Brown dwarf or main sequence star

Answer:

104.57

Explanation:

V = πr^2h

-3.14, 1.045^2, and 30.48=104.567666431

Answer:

The time constant is [tex]\tau = 17.5 \ s[/tex]    

Explanation:

From the question we are told that

   The spring constant is  [tex]k = 11.5 \ N/m[/tex]

   The mass  of the ball is  [tex]m_b = 490 \ g = 0.49 \ kg[/tex]

   The amplitude of the  oscillation t the beginning is [tex]x = 6.70 cm = 0.067 \ m[/tex]

    The amplitude after time t is  [tex]x_t = 2.20 cm = 0.022 \ m[/tex]

    The number of oscillation is [tex]N = 30[/tex]

Generally the time taken to attain the second amplitude is mathematically represented as

       [tex]t = N * T[/tex]                                            Here  T is the period of oscillation

         [tex]t = N * 2\pi \sqrt{\frac{m}{k} }[/tex]

=>     [tex]t = 30 * 2 * 3.142 * \sqrt{\frac{ 0.490}{11.5} }[/tex]

=>     [tex]t = 38.88 \ s[/tex]

Generally the amplitude at time t is mathematically represented as

         [tex]x(t) = x e^{-\frac{at}{2m} }[/tex]

Here a is the damping  constant so

 at  [tex]t = 38.88 \ s[/tex] ,  [tex]x_t = 2.20 cm = 0.022 \ m[/tex]

So  

     [tex]0.022 = 0.067 e^{-\frac{a * 38.88}{2 * 0.490} }[/tex]

=>  [tex]0.3284 = e^{-\frac{a * 38.88}{2 * 0.490} }[/tex]

taking natural log of both sides

=>  [tex]ln(0.3284 ) = -\frac{a * 38.88}{2 * 0.490} }[/tex]    

=>   [tex]a = 0.028[/tex]

Generally the time constant is mathematically represented as

    [tex]\tau = \frac{m}{a}[/tex]      

=> [tex]\tau = \frac{0.490}{ 0.028}[/tex]    

=> [tex]\tau = 17.5 \ s[/tex]    

Answer:

1.  Energy

2. All of the above

3. Store and use

4.  Kinetic

5. mass and velocity

6. Potential

7. mass, height, and gravity

8. Chemical Potential

9. Elastic Potential

10.  (`⌒*)O-(`⌒´Q)

Explanation:

Answer: The rate at which an object moves towards a target is Speed

Explanation:

Rate is something that tells us amount of solmething that changes in one unit of time.

Speed is defined as the measure of the rate of movement of a body expressed either as the distance travelled divided by the time taken.

Arc is defined as the apparent path described above and below the horizon taken up by a celestial body.

Force is defined as a push or pull upon an object resulting from the object's interaction with another object.

Trajectory is defined as the path followed by an object moving under the action of given force.

Answer:

Car A would have a better average speed

Explanation:

added weight to a object that is self propelled will be slower than a identical object with no added weight

Answer:

B porque tiene energía n..

Explanation:

Given

Velocity v = 23.0m/s

Distance S = 3.45m

Required

Time it will take the skier to reach the ground;

Using the equation of motion;

S = ut + 1/2gt²

3.45 = 23t + 1/2(9.8)t²

3.45 = 23t + 4.9t²

4.9t²+23t-3.45 = 0

Factorize;

t = -23 ±√23²-4(4.9)(-3.45)/2(4.9)

t = -23 ±√529+67.62/9.8

t = -23±√596.62/9.8

t = -23±24.43/9.8

t = 1.43/9.8

t = 0.146 secs

Hence take the skier 0.146 secs to reach the ground.

b) Horizontal distance covered is the range;

Range = U√2H/g

Range = 23√2(3.45)/9.8

Range = 23√6.9/9.8

Range = 23√0.7041

Range = 23(0.8391)

Range = 19.29m

Hence the horizontal distance travelled in air is 19.29m

(a).The time taken by the skier to reach the ground is 0.145 second.

(b).The skier travel in the air before landing is 19.29 meter.

a. Given that A skier leaves the end of a horizontal ski jump at 23.0 m/s and falls through a vertical distance of 3.45 m before landing.

Using equation of motion.

       [tex]S=ut+\frac{1}{2}gt^{2}[/tex]

Where S is vertical distance , u is initial velocity and g is gravitational acceleration.

Substitute S = 3.45 m, u = 23m/s  and g = 9.8 in above equation.

        [tex]3.45=23t+\frac{1}{2} (9.8)t^{2}\\\\4.9x^{2} +23t-3.45=0\\\\t=0.145,-4.83[/tex]

Since, time can not be negative.

So that,  [tex]t=0.145s[/tex]

b. The horizontal distance travel before landing is known as Range.

           Horizontal distance  ,

                                             [tex]=v*\sqrt{\frac{2S}{g} }[/tex]

Substitute v = 23m/s , S = 3.45 and g = 9.8 meter per second square.

                         [tex]Distance=23*\sqrt{\frac{2*3.45}{9.8} } \\\\Distance=23*\sqrt{0.7041} \\\\Distance=23*0.8391=19.29m[/tex]

Thus, The skier travel in the air before landing is 19.29 meter.

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Answer:

The value is  [tex]F_{net} = 4444 lb[/tex]

The force will be  outward

Explanation:

From the question we are told that

   The diameter of the disk is  [tex]d = 50.0 \ cm = \frac{50}{100} = 0.5 \ m[/tex]

   The external pressure on Mars  is [tex]P = 650 \ N/m^2[/tex]

From the question we are told that  

   Internal pressure  =  External pressure

Generally the external Force on earth is

      [tex]F_E = P_{atm} * A[/tex]

Here [tex]P_{atm}[/tex] is the atmospheric pressure with value  [tex]P_{atm} = 1.013*10^{5}\ Pa[/tex]

So

      [tex]F_E = 1.013 *10^{5} * \pi * \frac{d^2}{4}[/tex]

=>   [tex]F_E = 1.013 *10^{5} *3.142 * \frac{0.50 ^2}{4}[/tex]

=>   [tex]F_E = 19893 \ N[/tex]

Generally the external Force on Mars is  

       [tex]F= P * A[/tex]

      [tex]F = 650 * \pi * \frac{d^2}{4}[/tex]

=>   [tex]F = 650 *3.142 * \frac{0.5^2}{4}[/tex]

=>   [tex]F = 127.6 \ N[/tex]    

Net force is mathematically represented as

      [tex]F_{net} = F_E -F[/tex]

=>    [tex]F_{net} = 19893 -127.6[/tex]

=>    [tex]F_{net} = 19765.6 \ N[/tex]converting to  pounds

    [tex]F_{net} = \frac{19765.6}{4.448}[/tex]

=> [tex]F_{net} = 4444 lb[/tex]

Given that that the value is positive then the force will be  outward

Answer:

The algorithm

Step 1: Start

Step 2: Input Radius

Step 3: While Radius < = 0

                 Input Radius

Step 4: Pi = 3.14

Step 5: Perimeter = 2 * Pi * Radius

Step 6: Area = Pi * r^2

Step 7: Print Area, Perimeter

Step 8: Stop

Explanation:

This indicates the start of the algorithm

Step 1: Start

This inputs the radius

Step 2: Input Radius

The following loop is repeated until user input for radius is greater than 0

Step 3: While Radius < = 0

                 Input Radius

This initializes Pi to 3.14

Step 4: Pi = 3.14

This calculates the Perimeter or Circumference

Step 5: Perimeter = 2 * Pi * Radius

This calculates the Area

Step 6: Area = Pi * r^2

This prints the calculated Perimeter ad Area

Step 7: Print Area, Perimeter

This indicates the end of the algorithm

Step 8: Stop

I've added the flowchart as an attachment

Answer:

horizontal velocity vh = 6*cos(30°) = 6*(√3)/2 = 3√3 m/s

initial vertical velocity vv = 6*sin(30°) = 6/2 = 3m/s

Using s = ut + at2/2 for change in vertical distance in time t, with acceleration a (-9.8m/s2) and initial velocity u (vv = 3m/s) we have

0 = 3*t - 9.8*t2/2 or t = 6/9.8 s (ignoring the t = 0 solution, which just represents staying still!).

The horizontal distance in time t is vh*t or 3√3*6/9.8 m

Explanation:

Answer:

2

Explanation:

there are 2 significant figures in there

Answer:

5×10^4Pa

Explanation:

Given force of 108 lb is required to pull the lid off the box,

To convert "Ib"to Newton ,we use conversation rate below

1 pounds = 4.4482216282509 newtons

Then 108 lb=x Newton

Cross multiply we have

X= 480.41Newton

The force that is needed to open the lid is F and pressure P.

We know that Pressure= Force/Area

Area is given as 80.0 cm^2, we can convert to m^2 for unit consistency since 1cm^2= 0.001m^2 then

80.0 cm^2 = 80×10^-4m^2

Substitute to the equation of the pressure we have

P= 480.41Newton/(80×10^4m^2)

P=6×10^4 Pa

The pressure in the box will be difference between the initial pressure and final pressure

=( 1.01 ×10^5 Pa)-(6×10^4 Pa)

= 50100Pa

= 5×10^4Pa

Therefore, The pressure in the box was

5×10^4Pa

Since we are sitting in the bus, our current system is the bus

If any object outside our current system moves, we might think that our system has started moving

We are given the choices:

Passenger moving to the back of the bus: This passenger is moving in our current system. So, his movement will not make us think that the bus is moving

The bus driver turns to look through the windshield: The driver is part of our system and is moving moving within the system. So, we wont think that the bus is moving

A car in the next lane: This car is outside our current system and if it moves, we might think that our current system (the bus) has started moving

Therefore, the movement of a car in the next lane will make us think that the bus is moving

Answer:

45 kg is the mass of a table that weights 441 newton.

Answer:

45 kg

__________________________________________________________

Explanation:

We are given:

weight of the object = 441 N

Solving for the mass of the object:

We know that the weight of an object is the force applied by gravity to pull it towards the ground. So, we can say that:

Weight = Mg

[where M is the mass of the object and g is the gravitational constant]

replacing the variables with given values

441 = M(9.8)                                                     [since g = 9.8 m/s²]

Dividing both sides by 9.8

M = 441 / 9.8

M = 45 kg

Hence, the object has a mass of 45 kg

Answer:Final volume after pressure is applied=4,292cm3

Explanation:

Using the bulk modulus formulae

We have that The bulk modulus of waTer is given as  

K =-V dP/dV

Where  K, the bulk modulus of water = 2.15 x 10^9N/m^2

2.15 x 10^9N/m^2= - 4,300 x  4 × 106N/m2 / dV

dV = - 4,300 x  4 × 10^6N/m^2/ 2.15 x 10^9N/m^2

dV (change in volume)= -8.000cm^3

Final volume after pressure is applied,

V= V+ dV

V= 4300cm3 + (-8.000cm3)

=4300cm3 - 8.000cm3

Final Volume, V =4,292cm3

Answer:

* If we increase the distance traveled before stopping, the forces decrease significantly,

* If we decrease the height of the fall by grabbing the net to slow down.

* Creating a process of absorption of force in the shoes, through the deformation of the elastic soles.

Explanation:

When basketball players jump to place the ball in the net they see from a good height, when they hit the ground, strong tensions are produced in the bones and bonds.

Applying science to this case of fall, we can suggest several processes to decrease the forces on impact.

* If we increase the distance traveled before stopping, the forces decrease significantly,

* If we decrease the height of the fall by grabbing the net to slow down.

* Creating a process of absorption of force in the shoes, through the deformation of the elastic soles.

By designing shoes that have some degree of force absorption, it is possible to significantly reduce the stress on the player.

Well it seems that you did not give answer choices, but that its fine since we can use newtons law of universal gravitational, Fg = GM1M2/r^2. So G is the gravitational constant, which is 6.67*10^-11, we can plug in 6*1024 for M1, and 7*1022 for M2, and 3.8*108 for r. Which then we get 1.74 * 10^8 N as the force of attraction between the Earth and the moon.

The magnitude of the gravitational force between the earth and the moon is equal to 20 ×10¹⁹ N.

Gravitational force can be described as a force that attracts a body toward the center of the earth or any physical system that has mass. Every particle with mass exerts a gravitational pull on every other object with mass.

Mathematically gravitational force can be written as:

[tex]{\displaystyle F = G\frac{mM}{r^2}[/tex]

Where F is the force between objects, m and M are their masses, r is the distance between them, and G is the universal gravitational constant.

Given, the mass of the moon, M = 7 ×10²² Kg

The mass of earth, M =  6 ×10²⁴ Kg

The distance between the earth and the moon, r = 3.8 ×10⁸ m

The value of G = 6.7  ×10⁻¹¹ Nm²/Kg

The magnitude of the gravitational force can be calculated as:

[tex]{\displaystyle F = 6.7\times 10^{-11}\frac{6\times 10^{24}\times 7\times 10^{22}}{(3.8 \times 10^8)^2}[/tex]

F = 20 ×10¹⁹ N

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Answer:

9.55m

Explanation:

From T = 2π√L/g ........ 1

Where T is the period

L is the length of the string and g is the acceleration due to gravity = 9.8m/s^2

Given that,

Mass of ball = 227g

The ball makes 5 oscillations in 31 s.

T = 31/5

T = 6.2s

Solving for L from equation 1

T = 2π√L/g

Square both sides

T^2 = 4π^2×L/g

T^2×g = 4π^2×L

Make L the subject

L = T^2*g/4π^2 ......... 2

Now, substitute the values into equation 2

L = 6.2^2 × 9.8/4×3.14^2

L = 38.44*9.8/39.4384

L = 376.712/39.4384

L = 9.55m

Hence, the length of the string is 9.55m

Answer:

Evaporation from oceans = 460,000 km³

Explanation:

Given:

Precipitation on oceans = 420,000 km³

Precipitation on land = 130,000 km³

Evaporation from land = 90,000 km³

Find:

Evaporation from oceans

Computation:

Evaporation from oceans = Precipitation on oceans + Precipitation on land - Evaporation from land

Evaporation from oceans = 420,000 km³ + 130,000 km³ - 90,000 km³

Evaporation from oceans = 460,000 km³

Answer:ccccccC

Explanation:okay

Answer:

d = 105 m

Explanation:

Speed of a car, v = 21 m/s

We need to find the distance traveled by the dar during those 5 s before it stops. Let the distance is d. It can be calculated as :

d = v × t

d = 21 m/s × 5 s

d = 105 m

So, it will cover 105 m before it stops.

Answer:

A radar gun is a device for measuring the speed of moving objects. ... The radar gun is a Doppler radar unit that can be static, vehicle-mounted or hand-held. It measures the

Explanation: