What are the Laws of conservation of atoms?​

Explanation:

35 maybe hope it's right

Answer:

stop it get some help

:)

Explanation:

Answer:

My life be like oooh ahhh ooh ah

Explanation:

70N-40N=30N

Answer:

We want to have an acceleration of:

A = 1.5*g = 1.5*9.8m/s^2  = 14.7 m/s^2

When the rim is moving at 37m/s while spinning.

Now, in circular motion we have two accelerations.

Tangential acceleration, that is the one related to the change of speed, as we have a speed of 37m/s, we can assume that is constant, then the tangential acceleration is zero.

Centripetal acceleration, is the one related to the change in direction, is perpendicular to the velocity vector and is the one that allows the circular motion.

I suppose that in this problem we want to have a  centripetal acceleration of 14.7m/s^2

The equation for the centripetal acceleration is:

Ac = v^2/r

Where v = velocity and r = radius.

then we must solve:

14.7m/s^2 = (37m/s)^2/r

r = (37m/s)^2/14.7m/s^2 = 93.13 m

Answer:

Surface 1 is blacktop, Surface 2 is gravel, and Surface 3 is ice.

Explanation:

Hope this helps! :]

Answer:

C. Surface 1 is blacktop, Surface 2 is gravel, and

Surface 3 is ice.

Explanation:

The question is incomplete, the complete question is;

A student is measuring the volumes of nectar produced by a flowering plant for an experiment. He measures nectar from 50 flowers using a graduated cylinder that measures to the nearest millilitre (mL). Which statement describes a change that can help improve the results of his experiment?

A.) His measurements will be more precise if he takes measurements from an additional 100 flowers. B.) His measurements will be more accurate if he uses a graduated cylinder that measures to the nearest tenth of a mL. C.) His measurements will be more precise if he uses a graduated cylinder that measures to the nearest tenth of a mL. D.) His measurements will be more accurate if he takes measurements from an additional 100 flowers.

Answer:

His measurements will be more accurate if he uses a graduated cylinder that measures to the nearest tenth of a mL.

Explanation:

In the measurements of volume using most graduated cylinders, the cylinders are calibrated to the nearest tenth owing to the uncertainty in the measurement of volume.

Hence if a cylinder has measures to the nearest milliliter(mL), then he can improve his experiment by using a graduated cylinder that measures to the nearest tenth of a mL

Answer:

D is the correct answer

Answer:

1) The velocity of the ball return to the thrower's hand is -15 meters per second.

2) The resulting velocity of the boat is [tex]\vec v_{B} = 6\,\hat{i}+18\,\hat{j}\,\left[\frac{m}{s} \right][/tex].

Explanation:

1) Let suppose that ball experiments a free fall, that is an uniform accelerated motion, in which effects from gravity and Earth's rotation can be neglected. The velocity of the ball is represented by the following equations of motion:

Position

[tex]v_{o}\cdot t -\frac{1}{2}\cdot g\cdot t^{2} = 0[/tex]

[tex]t\cdot \left(v_{o}-\frac{1}{2}\cdot g\cdot t \right) = 0[/tex] (1)

Velocity

[tex]v = v_{o}-g\cdot t[/tex] (2)

Where:

[tex]t[/tex] - Time, measured in seconds.

[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.

[tex]v_{o}[/tex] - Initial velocity of the ball, measured in meters per second.

[tex]v[/tex] - Final velocity of the ball, measured in meters per second.

From (1), we get the time when the ball returns to the thrower's hand:

[tex]v_{o}-\frac{1}{2}\cdot g\cdot t = 0[/tex]

[tex]t = \frac{2\cdot v_{o}}{g}[/tex]

And then we apply this result in (2):

[tex]v = v_{o}-g\cdot \left(\frac{2\cdot v_{o}}{g} \right)[/tex]

[tex]v = -v_{o}[/tex] (3)

Then, the velocity of the ball return to the thrower's hand is -15 meters per second.

2) The resulting velocity of the boat ([tex]\vec v_{B}[/tex]) is represented by the vectorial sum of the velocity of the boat relative to the river ([tex]\vec v_{B/R}[/tex]) and the velocity of the river ([tex]\vec v_{R}[/tex]), both measured in meters per second, that is:

[tex]\vec v_{B} = \vec v_{R}+\vec {v}_{B/R}[/tex] (4)

If we know that [tex]\vec v_{R} = 6\,\hat{i}\,\left[\frac{m}{s} \right][/tex] and [tex]\vec v_{B/R} = 18\,\hat{j}\,\left[\frac{m}{s} \right][/tex], then the resulting velocity of the boat is:

[tex]\vec v_{B} = 6\,\hat{i}+18\,\hat{j}\,\left[\frac{m}{s} \right][/tex]

The resulting velocity of the boat is [tex]\vec v_{B} = 6\,\hat{i}+18\,\hat{j}\,\left[\frac{m}{s} \right][/tex].

Answer:

Mass is a measure of how much force it will take to change that path. Mass depends on how much matter – atoms and so on – there is in an object; more mass means more inertia, as there is more to get moving. ... Weight, on the other hand, is a measure of the amount of downwards force that gravity exerts on an object

The correct Answer: would be A B C E

Explanation:

Can i get brainlyest ?

Answer:

[tex]\boxed {\boxed {\sf 750 \ meters}}[/tex]

Explanation:

Distance can be found by multiplying the speed by the time.

[tex]d=s*t[/tex]

The speed is 25 meters per second. The time is 30 seconds.

[tex]s=25 \ m/s \\t= 30 \ s[/tex]

Substitute the values into the formula.

[tex]d=25 \ m/s * 30 \ s[/tex]

Multiply. Note the seconds, or "s" will cancel each other out.

[tex]d= 25 \ m * 30[/tex]

[tex]d= 750 \ m[/tex]

The football player ran 750 meters.

Answer:

3 kg

Explanation:

F = ma

(15) = m(5)

m = 3 kg

Answer:

I don't know the answer

Answer:

they are going to attract

Explanation:

Answer:

D) a Battery

Explanation:

The best real-life example of direct current is a battery. Batteries have positive and negative terminals on a battery, the electrons in the wires will begin to flow to produce a current.

Answer:

friction acts upon the ball when it is sliding down the slide and this action creates thermal energy

Answer:

true

Explanation:

Answer:

A) jupiter has orbiting moons

Explanation:

Btw I'm not sure abt it

Answer: It is important to use both QUALITATIVE and QUANTITATIVE data because the limitations of one type of data are counteracted by the advantages of the other.

Explanation:

QUALITATIVE data defined as type of data that centers on the measurement of the features of the subject under study. This is obtained through careful observations. It is a non numerical type of data. Some examples includes: sex(male or female), name, and colours. The limitations of using only qualitative data for a research includes:

--> it can not be statistically represented

--> the results can not be verified

--> it is time consuming and

--. It requires alot of labor.

QUANTITATIVE data is defined as the type of data that centers on the measurement of the amount and quantity of the subject under study. It can be used to conduct a large study than qualitative data. Examples include the heights and weights of students. The limitations of quantitative research includes:

--> poor representation of target population

--> inability to control the environment and

--> lack of resources for data collection.

Therefore, It is important to use both QUALITATIVE and QUANTITATIVE data analysis because the limitations of one type of data are counteracted by the advantages of the other. I hope this helps, thanks!

Answer:

Using a combination of qualitative and quantitative data can improve an evaluation by ensuring that the limitations of one type of data are balanced by the strengths of another. This will ensure that understanding is improved by integrating different ways of knowing.

Explanation:

Answer:

[tex] \boxed{(i).... 40cm}\\ \boxed{(ii).... 18cm}\\ \boxed{(iii).... 7.5N

}\\ [/tex]

Explanation:

[tex](i).... \\ the \: weight \: of \: the \: rod \: acts \: at \: the \: center \\ which \: is \: the \: half \: of \: 80cm = 40cm \\ (ii).... \\ let \: the \: distance \: be \: \boxed{d}...then \: 22 + d = 40 \\ d = 40 - 22 = 18cm \\ (iii).... \\let \: the \: weight \: of \: the \: metal \: rod \: be \: \boxed{ w} \\ taking \: the \: moment \: about \: the \: string \to \\ 15 \times (22 - 13) = 18w \\ 18w = (9)(15) \\ 2w = 15 \\ w = 7.5N[/tex]

♨Rage♨

Answer:

a) t = 14.2 s ,  v = -92 m / s , b) v = - 59.16 m / s ,   t = 0.916 s

c)  t = 7.75 s ,   x = 387.5 m

d) t = 10.64 s , x = 463.9 m ,   v = 92.2 m / s

Explanation:

This is an exercise in kinematics, suppose we take the upward direction as positive

a) is thrown up vertically.

Let's use the equation

          y = y₀ + v₀ t - ½ g t²

When reaching the ground y = 0, the initial height is y₀ = 300 m and the initial velocity is v₀ = + 50m / s, to simplify we use g = 10 m /s² as the value of the acceleration of gravity, for a more exact calculation we can must use 9.80 m /s²

         0 = y₀ + v₀t - ½ g t²

         ½ 10 t² - 50 t - 300 = 0

Let's solve the quadratic equation

         t² - 10 t - 60 = 0

         t = [10 ±√ (10² + 4 60)] / 2

         t = [10 ± 18.4] / 2

         t₁ = 14.2 s

         t₂ = -4.2 s

since time must be a positive quantity, the correctors result t = 14.2 s

the speed at this point is

         v = v₀ - g t

         v = 50 - 10 14.2

         v = -92 m / s

the sign indicates that the body is going down

b) in this case the initial velocity is vo = -50 m / s

let's calculate the velocity on the ground

    v² = v₀² - 2g (y-y₀)

    v² = 50 2 - 2 10 ((0- 300)

    v² = 3500

    v = + - 59.16 m / s

as the body is going down the correct sign is the negative

    v = - 59.16 m / s

the time it takes to arrive is

        v = v₀ - g t

        t = (v₀ - v) / g

        t = (-50 + 59.16) / 10

        t = 0.916 s

c) the velocity is horizontal (vox = 50 m / s), this implies that the vertical velocity is zero voy = 0

         y = y₀ + v₀ t - ½ g t²

         0 = 300 + 0 - ½ 10 t²

         t = √ (2 300/10)

         t = 7.75 s

the horizontal displacement at this time is

        x = v₀ₓ t

        x = 50 7.75

        x = 387.5 m

d) as it is thrown with an angle let's find each component of the velocities

      v₀ₓ = v₀ cos 30

      [tex]v_{oy}[/tex] = v₀ sin 30

       v₀ₓ = 50 cos 30 = 43.3 m / s

       v_{oy} = 50 sin 30 = 25 m / s

we look for the time of descent

     y = y₀ + v_{oy} t - ½ g t²

     0 = y₀ + v_{oy} t - ½ g t²

     0 = 300 + 25 t - ½ 10 t²

     t² - 5t - 60 = 0

   we solve the second degree equation

     t = [5 ±√ (5² + 4 60)] / 2

     t = [5 ± 16.28] / 2

     t₁ = 10.64 s

     t₂ = -5.64 s

since the time must be positive the result is t = 10.64 s

the range on the x axis is

       x = v₀ₓ t

       x = 43.6 10.64

       x = 463.9 m

the ground speed is

      v_{y} = [tex]v_{oy}[/tex] - g t

      v_{y} = 25 - 10 10.64

      v_{y} = -81.4 m / s

speed is

       v = √ (v₀ₓ² + v_{y}²)

       v = √ (43.3² + 81.4²)

       v = 92.2 m / s

Answer:

Action and reaction forces don't cancel each other out because they act on separate objects.

Explanation:

Action and reaction forces are always equal in magnitude, so it's not possible to exert more force on an object than it can exert back.

Answer: Potential energy would decrease, while total mechanical energy would remain constant.

Explanation: I did the test and this was right.

The graph should represent the third option.

The graph for the potential energy of the swimmer and the mechanical energy should be that there is a reduction of the potential energy and the mechanical energy should remain the same.

learn more about energy here; https://brainly.com/question/18640356

Answer:

Explanation:

The work done by an object can be found by using the formula

workdone = force × distance

From the question we have

workdone = 10 × 2

We have the final answer as

Hope this helps you

Answer:

20 i think

Explanation:

Answer:

?

Explanation:

Explanation:

Thats actually negative acceleration . It means a runner is running with the negative velocity of 1.35 m/s in every second .

In physics, the triangle symbol (∆) typically represents a change or difference in a particular quantity.



A triangle is often used to denote the difference between two values of a variable. For example, if we have two values of time, t1 and t2, the change or difference in time can be represented as Δt = t2 - t1, where Δt is the triangle symbol indicating the change in time. Similarly, it can be used to represent differences in other physical quantities such as displacement (∆x), velocity (∆v), or temperature (∆T). The triangle symbol (∆) is a shorthand notation commonly used in physics to indicate changes or differences.

In terms of change in displacement, the triangle symbol (∆) represents the difference between two positions or locations. It indicates the change in the object's position from an initial point to a final point.

For example, if an object initially starts at position x1 and then moves to position x2, the change in displacement (∆x) can be calculated as ∆x = x2 - x1. Here, ∆x represents the difference or change in the object's displacement.

The magnitude of ∆x gives the overall distance traveled by the object, and its sign indicates the direction of the displacement. A positive ∆x signifies a displacement in the positive direction (e.g., to the right or upward), while a negative ∆x represents a displacement in the negative direction (e.g., to the left or downward).

Therefore, The triangle symbol (∆) is commonly used in physics equations to denote changes or differences in various quantities, including displacement, velocity, time, and more. It helps us analyze and quantify the differences between two values of a physical quantity.

To learn more about the triangle symbol click:

https://brainly.com/question/30637056

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