Answer:
A formula car is a single seat, open cockpit, open wheel racing car with substantial front and rear wings and an engine positioned behind the driver intended to be used in competition.
A music performance takes place in an enclosed arena. A person sitting a distance of 20.0 m from the speaker experiences a sound intensity of 0.32 W/m2. What is the power of the speaker? (Assume that the area over which the speaker transmits sound is given by A = 4πd2, where d is the distance from the speaker.)
A.
100 W
B.
550 W
C.
1,200 W
D.
1,600 W
You have two pure substance that you cannot identify. Each sample is solid at room temperature. Describe at least five steps in the appropriate sequence that you would take to be able to identify the substance.
Answer:
pue like ad
Explanation:
For the two pure substance that you cannot identified , The steps taken in the right sequence are:
When two pure substance are places before you. you have to visually anaylse the sample, note the various colors that they have. It can tell you if it's an anions or cations.You can use reactants to precipitate the cations of the sample you have We then add a reactant to the sample and you did not see any precipitate, it corresponds to any of the elements or compound. If you do not see a precipitate, you can add other reactant.You then observe the color of this precipitate. example if the color changes to green, it will tell you that the substance is Ni(OH)₂ etc. One can also find out through the melting and boiling point of the two substances.Pure substance are regarded as substance that does not have impurities. one common way of finding out the purity of a substance is by its melting and boiling point determination.
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A 2kg metal cylinder is supplied with 1600J of energy to heat it from 5*C to 13*C. What is the SHC of the metal?
Answer:
100Jkg/°C
Explanation:
Given parameters:
Mass of metal = 2kg
Amount of heat energy = 1600J
Initial temperature = 5°C
Final temperature = 13°C
Unknown:
Specific heat capacity of the metal = ?
Solution:
Specific heat capacity of a body is the amount of heat needed to raise the temperature of unit mass of a body by 1°C.
H = m x C x (T₂ - T₁ )
H is the amount of heat
m is the mass
C is the unknown specific heat capacity
T is the temperature
Insert the parameters and solve;
1600 = 2 x C x (13 - 5)
1600 = 16C
C = 100Jkg/°C
What might happen if you mixed a strong acid with an equally strong base? Question 2 options:
A.You'd wind up with a pH-neutral salt and water.
B.You would see an explosive chemical reaction.
C.The base would destroy the acid.
D.The acid would destroy the base.
Answer:
b
Explanation:
How do her cells use these molecules to release energy for her body to run?
Her cells use oxygen, in the oxidation of sugar(glucose) to provide energy in the body's admissible form (i.e ATP).
Her cells, like that of every animal depend on the oxidation of sugars particularly glucose by Oxygen, O2 to provide energy in a process termed Cellular respiration.
The process of cellular respiration in her cell occurs in the mitochondria although the first part of cellular respiration occurs in the cytoplasm.
Essentially, the process of cellular respiration is made of 3 metabolic pathways as follows;
GlycolysisKreb's cycleThe Electron Transport ChainUltimately, the admissible form of energy, the Adenosine Tri Phosphate-ATP is the end result of this glucose metabolism.
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Suppose the current flowing from a battery is used to electroplate an object with silver. Calculate the mass of silver that would be deposited by a battery that delivers 1.65 A·hr of charge.
Answer:
m = 0.00659 kg = 6.59 g
Explanation:
From Faraday's Law of Electrolysis, we know that:
m = ZQ
where,
m = mass of silver deposited = ?
Q = charge supplied = (1.65 A-hr)(3600 s/1 hr) = 5940 C
Z = electrochemical equivalent of silver = 1.18 x 10⁻⁶ kg/C
Therefore,
m = (1.11 x 10⁻⁶ kg/C)(5940 C)
m = 0.00659 kg = 6.59 g
The mass of silver that would be deposited by a battery is 6.65 grams
The precipitation of Ag requires the removal of one electron. The reduction process for silver electrode at the cathode is as follows:
[tex]\mathbf{Ag^+ + e^- \to Ag(s)}[/tex]
The current flowing in the battery = 1.65 A = 1.65 C/sThe time at which the current is flowing = 1 hr = 3600sec∴
The charge Q = Current (I) × time (t)Charge Q = 1.65 C/s × 3600 sCharge (Q) = 5940 CIn one mole of an electron, the charge carried = 96500 C
Recall that:
The atomic mass of silver (Ag) = 108 g
∴
The mass of silver that would be deposited in a 5940 C can be computed as:
[tex]\mathbf{=5940\ C \times \dfrac{108 \ g }{96500 \ C}}[/tex]
= 6.65 grams
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what is aluminum’s nuclear charge?
Answer:All six of the ions contain 10 electrons in the 1s, 2s, and 2p orbitals, but the nuclear charge varies from +7 (N) to +13 (Al)
Explanation:
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to make a solute dissolve more quikly in a solvent wich whould you do? a. stir it in cold water b.stir it in warm water c.solvent d.lets the solute settle down d. nothing to do with the solute?
Answer:
b.stir it in warm water
Explanation:
the slobility will be faster in the high temperture
The phase of the moon you see depends on
Answer:
The phases of the Moon depend on the moon's position compared to the Earth and the Sun. Remember that the moon revolves around the Earth. As the moon goes around the Earth, half of the moon is always illuminated by the Sun.
The atomic of nitrogen is 7. The number of electrons a neutral atom has is_, and its atomic mass is approximately_amu.
Electrons - 7
Atomic mass - 14
For future reference, you can find the number of Electrons by subtracting the number of protons (7) from the element's mass number (14
We know, Atomic Number = Number of Electrons (In a neutral atom).
& Atomic mass = Number of protons + Number of Neutrons
The atomic number of nitrogen is 7. The number of electrons a neutral nitrogen atom has is "Seven (7)", and its atomic mass is approximately "Fourteen(14)" amu
Hope this helps!
A student has a balloon with a volume of 2.5 liters that contains 4.0 moles of air. The ballon has a small leak, allowing one mole to escape, leaving just 3.0 moles of air inside the balloon. What is the balloon's new volume after the air has escaped?
Answer:
1.9 L
Explanation:
Step 1: Given data
Initial number of moles of air (n₁): 4.0 molInitial volume of the balloon (V₁): 2.5 LFinal number of moles of air (n₂): 3.0 molFinal volume of the balloon (V₂): ?Step 2: Calculate the final volume of the balloon
According to Avogadro's law, the volume of an ideal gas is directly proportional to the number of moles. We can calculate the final volume of the balloon using the following expression.
V₁ / n₁ = V₂ / n₂
V₂ = V₁ × n₂ / n₁
V₂ = 2.5 L × 3.0 mol / 4.0 mol
V₂ = 1.9 L
Which statement describes an example of a chemical property of a metal statue?
O It is metal.
O It can tarnish.
OIt is solid.
OIt is shiny.
Answer:
The answer is "it can tarnish"
Explanation:
The statement describes an example of a chemical property of a metal statue is that it can tarnish.
Chemical properties are defined as those properties which become evident during or after a chemical reaction has taken place.
These properties cannot be determined externally just by viewing the substance ,these change immensely after a substance undergoes a chemical change.These are used for identification of unknown substances and used for building up chemical classifications.
The major chemical properties include flammability,toxicity,reactivity,acidity and heat of combustion.For a chemical property to be apparent , it is necessary that the structure of the substance is altered.
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Which isomer of 1-bromo-4-tert-butylcyclohexane reacts faster when refluxed with potassium tert-butoxide?
Answer:
See explanation.
Explanation:
Since potassium tert-butoxide is a strong bulky base, we expect that an elimination reaction predominates.
This reaction is expected to occur by E2 mechanism. The cis isomer of 1-bromo-4-tert-butylcyclohexane is known to react faster by E2 mechanism because it fulfills the anticoplanar arrangement required for for E2 mechanism, where the leaving group and adjacent proton must be anti to each other and in the same plane. The trans isomer can not fulfill this requirement.
Can you answer these two questions right please and thank you
Answer:
B. LZAQD
A. Younger than A but older than Q
Explanation:
To solve this problem, we simply apply the stratigraphic laws which are the law of superposition and principle of cross cutting.
According to the law of superposition, in an undeformed sequence of strata, the oldest layer is always at the bottom and the youngest on top. In this case, we have a little disturbance but it did not affect much of the original bedding. So, the rock ages from L to Z to A to Q and D. L is the oldest and D is the youngest.According to the principle of cross-cutting "features that cuts through a rock are younger than the layers they cut through". In this problem, the fault cuts through layers LZ and A which suggests that these layers are older than the faulting event. Layer Q is unaffected by the faulting so, the fault is older than the layer.
A 75 mL solid is estimated by a student to be 81 mL. Calculate the percent error.
Answer:
8 %Explanation:
The percentage error of a certain measurement can be found by using the formula
[tex]P(\%) = \frac{error}{actual \: \: number} \times 100\% \\ [/tex]
From the question
error = 81 - 75 = 6 mL
actual volume = 75 ml
We have
[tex]p(\%) = \frac{6}{75} \times 100 \\ = \frac{2}{25} \times 100 \\ = 2 \times 4 \\ = 8 \: \: \: \: \: \: \: \: [/tex]
We have the final answer as
8 %Hope this helps you
A tank contains 7.0 moles of a mixture of nitrogen gas and oxygen gas. The total
pressure exerted by the gas mixture is 530 kPa. The partial pressure exerted by the
oxygen is 140 kPa. How many moles of NITROGEN gas are present in the tank?
Answer:
5.2 mol
Explanation:
Step 1: Given data
Total number of moles (n): 7.0 molTotal pressure (P): 530 kPaPartial pressure of oxygen (pO₂): 140 kPaStep 2: Calculate the mole fraction of oxygen
We will use the following expression.
pO₂ = P × X(O₂)
X(O₂) = pO₂ / P
X(O₂) = 140 kPa / 530 kPa
X(O₂) = 0.264
Step 3: Calculate the moles of oxygen
We will use the definition of mole fraction of oxygen.
X(O₂) = n(O₂) / n
n(O₂) = X(O₂) × n
n(O₂) = 0.264 × 7.0 mol
n(O₂) = 1.8 mol
Step 4: Calculate the moles of nitrogen
The total number of moles is equal to the sum of moles of the individual gases.
n(O₂) + n(N₂) = n
n(N₂) = n - n(O₂)
n(N₂) = 7.0 mol - 1.8 mol
n(N₂) = 5.2 mol
A reaction vessel is charged with 0.50 atm of A and 0.030 atm of B. Once the reaction reaches equilibrium, what is the equilibrium partial pressure of B? Kp for this reaction is 67.2A (g) ⇌ 2 B (g)
Answer:
1.000 atm
Explanation:
Step 1: Write the reversible reaction
A(g) ⇌ 2 B(g)
Step 2: Calculate the reaction quotient
Q = [B]²/[A]
Q = 0.030²/0.50
Q = 0.0018
since Q < Kp, the reaction will proceed to the right
Step 3: Make an ICE chart
A(g) ⇌ 2 B(g)
I 0.50 0.030
C -x +2x
E 0.50-x 0.030+2x
Step 4: Find the value of "x"
We will use the definition of the pressure equilibrium constant.
Kp = 67.2 = [B]²/[A] = (0.030+2x)²/0.50-x
33.6 - 67.2x = 0.0009 + 0.12x + 4x²
4x² + 67.32x -33.5991 = 0
We solve this quadratic equation and we get x=0.485112 and x=−17.3151 (neglected).
Step 5: Find the partial pressure of B at equilibrium
pB = 0.030+2x = 0.030+2(0.485112) = 1.000 atm
The equilibrium partial pressure of B would be:
[tex]1.000 atm[/tex]
Reversible Reaction
Given that,
Reaction
[tex]A(g)[/tex] ⇄ [tex]2 B(g)[/tex]
Charge on the reaction vessel [tex]= 0.50 atm[/tex] of A
[tex]0.030 atm[/tex] of B
To find,
Reaction quotient first
[tex]= B^2/A\\= (0.030)^2/0.50\\= 0.0018[/tex]
This shows that the reaction quotient is greater than Kp.
Through the reaction [tex]A(g)[/tex] ⇄ [tex]2 B(g)[/tex], ICE can be drawn
I [tex]0.50[/tex] [tex]0.030[/tex]
C [tex]-x[/tex] [tex]+2x[/tex]
E [tex]0.50-x[/tex] [tex]0.030+2x[/tex]
Now,
We will determine the value of [tex]x[/tex],
Kp [tex]= 67.2[/tex]
[tex]= [B]^2/[A][/tex]
[tex]= (0.030+2x)^2/0.50-x[/tex]
⇒ [tex]33.6 - 67.2x[/tex] [tex]= 0.0009 + 0.12x + 4x^2[/tex]
⇒ [tex]4x^2 + 67.32x -33.5991 = 0[/tex]
∵ [tex]x = -17.3151[/tex]
Therefore, Equilibrium Partial Pressure
[tex]= 0.030+2x[/tex]
[tex]= 0.030+2(0.485112)[/tex]
= [tex]1.000[/tex] atm
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Draw the product or products that are obtained from the reaction of HCl with 1-butene and with 2-butene. Show the relative stereochemistry if the product has two or more stereocenters.
Delete me please!!!!!!
Which periodic group has the smallest atomic radius ?
-alkali metals
- halogens
- Nobel gases
- transition metals
The Nobel gases, Group 8 elements have the smallest atomic radIi in the periodic table.
Atomic radius decreases as you move across a period. This is because Within a period, a new electron is being added to the same shell , and at the same time a new proton is added , This causes an attraction and causes the electron to pull nearer to the nucleus causing the radius to shrink and reduce in size.
In decreasing order of atomic radius, we have alkali metals>halogens> transition metal > Nobel gases
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3. Theoretically how many grams of magnesium is required to produce to 5.0 g of
Magnesium oxide?
Answer:
3grams
Explanation:
The reaction for the production of Magnesium dioxide will be
Mg + O2 → MgO
we have 5g of MgO (molar mass 40g)
no of moles of MgO = 5/40 = 0.125
Using unitary method we have
1 mole of Mg require 1 mole of MgO
0.125 Mole of MgO = 0.125mole of Mg
n = given mass /molar mass
0.125 = mass / molar mass
mass = 0.125* 24 = 3grams
Scenario Three: Carbon dioxide emissions increase
• Set the carbon dioxide emissions rate to 9.8 gigatons.
• Set the time step size to 10 years.
• Select the step forward button once.
• Increase the carbon dioxide emissions by 0.2 and press step forward.
• Continue stepping forward once, increasing the carbon emissions each time, until you reach 2110.
• Record the data in the table below.
Maintain carbon dioxide emissions at 9.8 for the rest of scenario one.
2020 9.8 58
2030 9.8 58.5
2040 9.8 58.9
2050 9.8 59.1
2060 9.8 59.5
2070 9.8 59.8
2080 9.8 60
2090 9.8 60.1
2100 9.8 60.5
2110 9.8 60.9
why does 3-methylcyclohexene elute before
1-methylcyclohexene in gas chromatography?
Answer: The mole percent of 1-methylcyclohexene was 80.21% and the mole percent of 3-methylcyclohexene was 19.79%. This is because 1-methylcyclohexene is the major product with the more stable carbocation intermediate and 3-methylcyclohexene is the minor product with the less stable carbocation intermediate.
Explanation: The mole percent of 1-methylcyclohexene was 80.21% and the mole percent of 3-methylcyclohexene was 19.79%
Calculate how many grams of sodium hypochlorite can be theoretically formed when 1.23 mol of sodium hydroxide is combined with 1.36 mol of chlorine.
Answer:
45.78 g NaClO
Explanation:
The reaction that takes place is:
2NaOH + Cl₂ → NaCl + NaClO + H₂OIn order to react completely, 1.36 moles of chlorine would require (2*1.36) 2.72 moles of NaOH. There are more moles than that, so NaOH is the limiting reactant.
We calculate the moles of NaClO formed, from the limiting reactant:
1.23 mol NaOH * [tex]\frac{1molNaClO}{2molNaOH}[/tex] = 0.615 mol NaClOFinally we convert NaClO moles to grams, using its molecular weight:
0.615 mol NaClO * 74.44 g/mol = 45.78 g NaClOA scientist wants to make a solution of tribasic sodium phosphate, Na3PO4, for a laboratory experiment. How many grams of Na3PO4 will be needed to produce 725 mL of a solution that has a concentration of Na ions of 1.30 M
Answer:
51.53 grams .
Explanation:
Na₃PO₄ ⇄ 3Na⁺¹ + PO₄⁻³ .
1 mole 3 mole
725 mL of 1.3 M Na⁺ ions
= .725 x 1.3 moles of Na⁺ ions
= .9425 moles
3 mole of Na⁺ is formed by 1 mole of Na₃PO₄
.9425 mole of Na⁺ is formed by .9425/3 mole of Na₃PO₄
Na₃PO₄ needed = .9425/3 moles = .3142 moles
Molecular weight of Na₃PO₄ = 164
grams of Na₃PO₄ needed = .3142 x 164 = 51.53 grams .
Calculate molecules in 1dm^3 of oxygen
Number of molecules in 1 dm³ Oxygen = 2.71 x 10²²
Further explanationConditions at T 0 ° C and P 1 atm are stated by STP (Standard Temperature and Pressure). At STP, Vm is 22.4 liters/mol.
The mole is the number of particles contained in a substance
1 mol = 6.02.10²³
1 dm³ of oxygen = 1 L Oxygen
mol Oxygen :[tex]\tt \dfrac{1}{22.4}=0.045`mol[/tex]
molecules of Oxygen :n=mol=0.045
No = 6.02.10²³
[tex]\tt N=n\times No\\\\N=0.045\times 6.02\times 10^{23}\\\\N=2.71\times 10^{22}[/tex]
How many moles of KCI would be dissolved in 4 L of water to make a 2 M
solution?
1
A.
mole
B. 2 moles
C. 8 moles
D. 4 moles
Answer:
C. 8 Moles
Explanation:
why do we need air? If you know please answer this
Answer:
I found this on the internet People need to breathe, and so do lots of other animals—and plants! Breathing is part of a process called respiration. During respiration, a living thing takes in oxygen from the air and gives out carbon dioxide.
Explanation:
10 Interesting Things About Air | NASA Climate Kidsclimatekids.nasa.gov › 10-things-air
Your welcome!
to breath
with out air we can't live here
Balance the following equation.
C3H8(g) + O2(g) → CO2(g) + H2O(l)
Explanation:
C3H8+5O2----->3CO2+4H2O
Answer:
C3H8+5O2----->3CO2+4H2O
Explanation:
Stoichiometric coefficients indicate the ratio between ________of given substances in a chemical reaction
a) moles
b) molecules
c) molar masses
d) masses
both a) and b)
any of the a), b), c) and d)
both a) and c)
only b)
only a)
Answer:
b
Explanation:
In the metallurgic industry one of the processes to get pure iron takes tree steps.
a) CaCO3→CaO + CO2
b) CO2 + C → CO
c) Fe2O3 + CO → Fe + CO2
Calculate the kilograms of iron that would be produced from 1340 g of calcium carbonate.
Mass of Iron produced : 1.5 kg
Further explanationReaction
a) CaCO3→CaO + CO2
b) CO2 + C → 2CO
c) Fe2O3 + 3CO → 2Fe + 3CO2
From the reaction above : 1 mol CaCO₃ = 2 mol Fe
mol CaCO₃ :
1340 : 100 g/mol = 13.4
mol Fe :
2 x 13.4 = 26.8
mass Fe :
26.8 x 56 g/mol=1500.8 g⇒1.5 kg